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The answer is
c. SrCO3
Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the
CO32- ions
%Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50%
Solution
The answer is
c. SrCO3
Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the
CO32- ions
%Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50%

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The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf

  • 1. The answer is c. SrCO3 Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the CO32- ions %Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50% Solution The answer is c. SrCO3 Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the CO32- ions %Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50%