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1)It capture leaving on the purpose of the CA documentation it have.pdf
1)It capture leaving on the purpose of the CA documentation: it have near decide involving
excellent accessed awful entrance
2)through sufficient crack, some cryptographic system container be there attack effectively. This
can cause crash attack
3)since the fundamental vulnerability occur in a cryptographic primordial, explicit development
scenario contrast usually depending on the scenery of the data the enemy have the talent to spoof
and how it is validate by software
4)sure, Cryptosystem ME 6 9.21it is a Windows program encrypt information in either a only
file or in several files therefore to it cannot be understand writing by persons not expressive the
key. Data is encrypted use a key 16 to 64 characters lengthy, and a progression of 64 casual bytes
5)The machine be able to exist reconfigured to make use of a extra protected hash algorithm
6)sure and rejection. rejection, since it will entail our Cisco hardware be replace through newer
hardware competent of with added safe algorithms. Our present software can be improve though
is at rest able of creature compromise lastly. sure, if we create property accessible, we can
improve our hardware and software with extra safe gear, and algorithms These would allow to
improved make sure we are secure our system
7)No develop has been unconstrained. Researchers cover bent exploit, but they will not release
the in sequence as of yet. The examine was planned to supply information to encourage people to
upgrade.
8)small, except achievable. An exploit is a part of software, a portion of information, or a order
of instructions
9)If attack be to be conduct the answer might be obtain password for user, their individual in
sequence, and more. Once provided that genuine but fake certificate to our user they might
capture any in sequence they give, as well as provide for them in sequence.
10)MD5 is quickly being replaced. MD5 is an algorithm to is use to confirm information truth
during the making of a 128-bit significance process starting information input that is claim to be
as sole to that exact information as fingerprint is to exact creature
11)sure, one time it is busted the course can be duplicate noticeably and no spot or official
document might really be trust not including intense, exorbitant analysis.
12)Simple figure screening the MD5 course, and the course of its altered form.
13)extra full explanation of the abbreviation, and vocabulary use. full diagram presentation the
course MD5 use and how it might be dishonored. use conditions, and reference in a way to
narrate the notion to nontechnical experience
14)Vulnerability in this background can be definite as the diminish capability of an personality
oppose and get well starting the contact of a usual or man-made dangerimportant and classify
network or system property.conveying relation levels of significance to the capital.identify
probable pressure to each supply.increasing a policy to deal with the mainly grave possible
troubles first.important.
1). Na+K+ ATPase pump plays an important role in maintaining membra.pdf
1). Na+/K+ ATPase pump plays an important role in maintaining membrane potential. Sodium-
potassium ATPase (Na+/K+ ATPase) allows the influx of sodium ions and efflux of potassium
ions, which results in increased intracellular positive charge. Increased expression of sodium-
potassium ATPase (Na+/K+ ATPase) causes decreased extracellular sodium and increased
extracellular potassium levels.
2).
Substances move into and out of the cell by means of transport vesicles. Exocytosis is the
transport of substances or molecules through transport vesicles that cannot pass through the cell
membrane. For example, the neurotransmitters present within the synaptic vesicles are released
out by exocytosis. This sac like structure id formed from the layer of cell membrane.
The transport of larger molecules or other substances into the cell by means of transport vesicles
in known as endocytosis. For example, larger vesicles carry liquid or solid material from outside
to the inside of the cell. They are formed from the part of cell membrane; they pinch off to
release the molecules into the cell interior.
Solution
1). Na+/K+ ATPase pump plays an important role in maintaining membrane potential. Sodium-
potassium ATPase (Na+/K+ ATPase) allows the influx of sodium ions and efflux of potassium
ions, which results in increased intracellular positive charge. Increased expression of sodium-
potassium ATPase (Na+/K+ ATPase) causes decreased extracellular sodium and increased
extracellular potassium levels.
2).
Substances move into and out of the cell by means of transport vesicles. Exocytosis is the
transport of substances or molecules through transport vesicles that cannot pass through the cell
membrane. For example, the neurotransmitters present within the synaptic vesicles are released
out by exocytosis. This sac like structure id formed from the layer of cell membrane.
The transport of larger molecules or other substances into the cell by means of transport vesicles
in known as endocytosis. For example, larger vesicles carry liquid or solid material from outside
to the inside of the cell. They are formed from the part of cell membrane; they pinch off to
release the molecules into the cell interior..
total number of moles of the copund remains same .pdf
total number of moles of the copund remains same when we dilute moles =
molarity * volume intial = final M1* V1= M2* v2 M1=6.3 V1= 27.5 ml M2=1.5 V2= 6.3*
27.5/1.5=115.5 ml is the total volume
Solution
total number of moles of the copund remains same when we dilute moles =
molarity * volume intial = final M1* V1= M2* v2 M1=6.3 V1= 27.5 ml M2=1.5 V2= 6.3*
27.5/1.5=115.5 ml is the total volume.
#include stdio.h #include stdlib.h #include unistd.h #in.pdf
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include \"header.h\"
#include \"chrrecksum.h\"
#define BCKLG 10
void sgchrrldHndlr(int s)
{
while(waitpid(-1, NULL, WNOHANG) > 0);
}
void *get_in_addr(struct sockaddr *sa)
{
if (sa->SaFamly == AF_INET) {
return &(((struct Sckadr_in*)sa)->sin_addr);
}
return &(((struct Sckadr_in6*)sa)->sin6_addr);
}
int main(int arc, chrrar**arv)
{
int prt = 69;
chrrar chrr;
while ((chrr = gtOpt(arc, arv, \"p:\")) != -1) {
switchrr (chrr) {
case \'p\':
prt = atoi(optarg);
break;
case \'?\':
exit(1);
}
}
chrrar prt[10];
sprintf(prt,\"%d\",prt);
int sockfd, newdv; // listen on sock_fd, new connection on newdv
struct addrinfo hints, *servinfo, *p;
struct sockaddr_storage their_addr; // connector\'s address information
socklen_t sin_size;
struct sigaction sa;
int yes=1;
chrrar s[INET6_ADDRSTRLEN];
int rv;
memset(&hints, 0, sizeof hints);
hints.ai_family = AF_UNSPEC;
hints.ai_socktype = SOCK_STREAM;
hints.ai_flags = AI_PASSIVE;
if ((rv = getaddrinfo(NULL, prt, &hints, &servinfo)) != 0) {
fprintf(stderr, \"getaddrinfo: %s\ \", gai_strerror(rv));
return 1;
}
for(p = servinfo; p != NULL; p = p->ai_next) {
if ((sockfd = socket(p->ai_family, p->ai_socktype,
p->ai_protocol)) == -1) {
perror(\"server: socket\");
continue;
}
if (setsockopt(sockfd, SOL_SOCKET, SO_REUSEADDR, &yes,
sizeof(int)) == -1) {
perror(\"setsockopt\");
exit(1);
}
if (bind(sockfd, p->ai_addr, p->ai_addrlen) == -1) {
close(sockfd);
perror(\"server: bind\");
continue;
}
break;
}
if (p == NULL) {
fprintf(stderr, \"server: failed to bind\ \");
return 2;
}
freeaddrinfo(servinfo);
if (listen(sockfd, BCKLG) == -1) {
perror(\"listen\");
exit(1);
}
sa.sa_handler = sgchrrldHndlr;
sigemptyset(&sa.sa_mask);
sa.sa_flags = SA_RESTART;
if (sigaction(SIGchrrLD, &sa, NULL) == -1) {
perror(\"sigaction\");
exit(1);
}
printf(\"server: looking for connections...\ \");
while(1) { accept() loop
sin_size = sizeof their_addr;
newdv = accept(sockfd, (struct sockaddr *)&their_addr, &sin_size);
if (newdv == -1) {
perror(\"accept\");
continue;
}
inet_ntop(their_addr.ss_family,
get_in_addr((struct sockaddr *)&their_addr),
s, sizeof s);
printf(\"server: got connection from %s\ \", s);
if (!fork()) {
close(sockfd);
chrrar buf[PACKET_SIZE];
chrrar databuf[PAYLOAD_SIZE];
int numbytes, ack_bytes;
header_t head;
packet_t packet;
packet_t ackr;
int getfilename = 1;
chrrar *filename = (chrrar*) \"recvfile.txt\";
FILE * filefd;
bzero(buf, PACKET_SIZE);
bzero(databuf, PAYLOAD_SIZE);
while(getfilename) {
if ((numbytes = recv(newdv, buf, PACKET_SIZE, 0)) == -1) {
perror(\"recv\");
exit(1);
}
if(numbytes > 0)
{
read_header(&head, (packet_t *)buf);
read_packet((u_chrrar*) databuf, (packet_t *)buf, (u_short) (numbytes -
HEADER_SIZE));
printf(\"Packet \'%d\' received\ \", (int)(head.seq));
if(add_chrrecksum(numbytes, numbytes%2, (u_short *)buf) == 0) {
printf(\"chrrecksum OK\ \");
fill_hdr((int)(head.seq).
18O is an important precursor for the production offlourodeoxyglucose.pdf
18O is an important precursor for the production offlourodeoxyglucose(FDG) used in
PETscans./ PET scans are atechnique which produces a three-dimensional image or picture
offunctional processes in the body. In Paleoclimatology they are usedto find out what
temperature of earths climate was in the past bycomparing the ratio of oxygen 18 to oxygen 16.
Solution
18O is an important precursor for the production offlourodeoxyglucose(FDG) used in
PETscans./ PET scans are atechnique which produces a three-dimensional image or picture
offunctional processes in the body. In Paleoclimatology they are usedto find out what
temperature of earths climate was in the past bycomparing the ratio of oxygen 18 to oxygen 16..
observed expected O - E (O - E) Solution observed expect.pdf
observed expected O - E (O - E)
Solution
observed expected O - E (O - E).
no hydrogen atom is present because its pure carb.pdf
no hydrogen atom is present because its pure carbon compound
Solution
no hydrogen atom is present because its pure carbon compound.
Recommended
1)It capture leaving on the purpose of the CA documentation it have.pdf
1)It capture leaving on the purpose of the CA documentation: it have near decide involving
excellent accessed awful entrance
2)through sufficient crack, some cryptographic system container be there attack effectively. This
can cause crash attack
3)since the fundamental vulnerability occur in a cryptographic primordial, explicit development
scenario contrast usually depending on the scenery of the data the enemy have the talent to spoof
and how it is validate by software
4)sure, Cryptosystem ME 6 9.21it is a Windows program encrypt information in either a only
file or in several files therefore to it cannot be understand writing by persons not expressive the
key. Data is encrypted use a key 16 to 64 characters lengthy, and a progression of 64 casual bytes
5)The machine be able to exist reconfigured to make use of a extra protected hash algorithm
6)sure and rejection. rejection, since it will entail our Cisco hardware be replace through newer
hardware competent of with added safe algorithms. Our present software can be improve though
is at rest able of creature compromise lastly. sure, if we create property accessible, we can
improve our hardware and software with extra safe gear, and algorithms These would allow to
improved make sure we are secure our system
7)No develop has been unconstrained. Researchers cover bent exploit, but they will not release
the in sequence as of yet. The examine was planned to supply information to encourage people to
upgrade.
8)small, except achievable. An exploit is a part of software, a portion of information, or a order
of instructions
9)If attack be to be conduct the answer might be obtain password for user, their individual in
sequence, and more. Once provided that genuine but fake certificate to our user they might
capture any in sequence they give, as well as provide for them in sequence.
10)MD5 is quickly being replaced. MD5 is an algorithm to is use to confirm information truth
during the making of a 128-bit significance process starting information input that is claim to be
as sole to that exact information as fingerprint is to exact creature
11)sure, one time it is busted the course can be duplicate noticeably and no spot or official
document might really be trust not including intense, exorbitant analysis.
12)Simple figure screening the MD5 course, and the course of its altered form.
13)extra full explanation of the abbreviation, and vocabulary use. full diagram presentation the
course MD5 use and how it might be dishonored. use conditions, and reference in a way to
narrate the notion to nontechnical experience
14)Vulnerability in this background can be definite as the diminish capability of an personality
oppose and get well starting the contact of a usual or man-made dangerimportant and classify
network or system property.conveying relation levels of significance to the capital.identify
probable pressure to each supply.increasing a policy to deal with the mainly grave possible
troubles first.important.
1). Na+K+ ATPase pump plays an important role in maintaining membra.pdf
1). Na+/K+ ATPase pump plays an important role in maintaining membrane potential. Sodium-
potassium ATPase (Na+/K+ ATPase) allows the influx of sodium ions and efflux of potassium
ions, which results in increased intracellular positive charge. Increased expression of sodium-
potassium ATPase (Na+/K+ ATPase) causes decreased extracellular sodium and increased
extracellular potassium levels.
2).
Substances move into and out of the cell by means of transport vesicles. Exocytosis is the
transport of substances or molecules through transport vesicles that cannot pass through the cell
membrane. For example, the neurotransmitters present within the synaptic vesicles are released
out by exocytosis. This sac like structure id formed from the layer of cell membrane.
The transport of larger molecules or other substances into the cell by means of transport vesicles
in known as endocytosis. For example, larger vesicles carry liquid or solid material from outside
to the inside of the cell. They are formed from the part of cell membrane; they pinch off to
release the molecules into the cell interior.
Solution
1). Na+/K+ ATPase pump plays an important role in maintaining membrane potential. Sodium-
potassium ATPase (Na+/K+ ATPase) allows the influx of sodium ions and efflux of potassium
ions, which results in increased intracellular positive charge. Increased expression of sodium-
potassium ATPase (Na+/K+ ATPase) causes decreased extracellular sodium and increased
extracellular potassium levels.
2).
Substances move into and out of the cell by means of transport vesicles. Exocytosis is the
transport of substances or molecules through transport vesicles that cannot pass through the cell
membrane. For example, the neurotransmitters present within the synaptic vesicles are released
out by exocytosis. This sac like structure id formed from the layer of cell membrane.
The transport of larger molecules or other substances into the cell by means of transport vesicles
in known as endocytosis. For example, larger vesicles carry liquid or solid material from outside
to the inside of the cell. They are formed from the part of cell membrane; they pinch off to
release the molecules into the cell interior..
total number of moles of the copund remains same .pdf
total number of moles of the copund remains same when we dilute moles =
molarity * volume intial = final M1* V1= M2* v2 M1=6.3 V1= 27.5 ml M2=1.5 V2= 6.3*
27.5/1.5=115.5 ml is the total volume
Solution
total number of moles of the copund remains same when we dilute moles =
molarity * volume intial = final M1* V1= M2* v2 M1=6.3 V1= 27.5 ml M2=1.5 V2= 6.3*
27.5/1.5=115.5 ml is the total volume.
#include stdio.h #include stdlib.h #include unistd.h #in.pdf
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include
#include \"header.h\"
#include \"chrrecksum.h\"
#define BCKLG 10
void sgchrrldHndlr(int s)
{
while(waitpid(-1, NULL, WNOHANG) > 0);
}
void *get_in_addr(struct sockaddr *sa)
{
if (sa->SaFamly == AF_INET) {
return &(((struct Sckadr_in*)sa)->sin_addr);
}
return &(((struct Sckadr_in6*)sa)->sin6_addr);
}
int main(int arc, chrrar**arv)
{
int prt = 69;
chrrar chrr;
while ((chrr = gtOpt(arc, arv, \"p:\")) != -1) {
switchrr (chrr) {
case \'p\':
prt = atoi(optarg);
break;
case \'?\':
exit(1);
}
}
chrrar prt[10];
sprintf(prt,\"%d\",prt);
int sockfd, newdv; // listen on sock_fd, new connection on newdv
struct addrinfo hints, *servinfo, *p;
struct sockaddr_storage their_addr; // connector\'s address information
socklen_t sin_size;
struct sigaction sa;
int yes=1;
chrrar s[INET6_ADDRSTRLEN];
int rv;
memset(&hints, 0, sizeof hints);
hints.ai_family = AF_UNSPEC;
hints.ai_socktype = SOCK_STREAM;
hints.ai_flags = AI_PASSIVE;
if ((rv = getaddrinfo(NULL, prt, &hints, &servinfo)) != 0) {
fprintf(stderr, \"getaddrinfo: %s\ \", gai_strerror(rv));
return 1;
}
for(p = servinfo; p != NULL; p = p->ai_next) {
if ((sockfd = socket(p->ai_family, p->ai_socktype,
p->ai_protocol)) == -1) {
perror(\"server: socket\");
continue;
}
if (setsockopt(sockfd, SOL_SOCKET, SO_REUSEADDR, &yes,
sizeof(int)) == -1) {
perror(\"setsockopt\");
exit(1);
}
if (bind(sockfd, p->ai_addr, p->ai_addrlen) == -1) {
close(sockfd);
perror(\"server: bind\");
continue;
}
break;
}
if (p == NULL) {
fprintf(stderr, \"server: failed to bind\ \");
return 2;
}
freeaddrinfo(servinfo);
if (listen(sockfd, BCKLG) == -1) {
perror(\"listen\");
exit(1);
}
sa.sa_handler = sgchrrldHndlr;
sigemptyset(&sa.sa_mask);
sa.sa_flags = SA_RESTART;
if (sigaction(SIGchrrLD, &sa, NULL) == -1) {
perror(\"sigaction\");
exit(1);
}
printf(\"server: looking for connections...\ \");
while(1) { accept() loop
sin_size = sizeof their_addr;
newdv = accept(sockfd, (struct sockaddr *)&their_addr, &sin_size);
if (newdv == -1) {
perror(\"accept\");
continue;
}
inet_ntop(their_addr.ss_family,
get_in_addr((struct sockaddr *)&their_addr),
s, sizeof s);
printf(\"server: got connection from %s\ \", s);
if (!fork()) {
close(sockfd);
chrrar buf[PACKET_SIZE];
chrrar databuf[PAYLOAD_SIZE];
int numbytes, ack_bytes;
header_t head;
packet_t packet;
packet_t ackr;
int getfilename = 1;
chrrar *filename = (chrrar*) \"recvfile.txt\";
FILE * filefd;
bzero(buf, PACKET_SIZE);
bzero(databuf, PAYLOAD_SIZE);
while(getfilename) {
if ((numbytes = recv(newdv, buf, PACKET_SIZE, 0)) == -1) {
perror(\"recv\");
exit(1);
}
if(numbytes > 0)
{
read_header(&head, (packet_t *)buf);
read_packet((u_chrrar*) databuf, (packet_t *)buf, (u_short) (numbytes -
HEADER_SIZE));
printf(\"Packet \'%d\' received\ \", (int)(head.seq));
if(add_chrrecksum(numbytes, numbytes%2, (u_short *)buf) == 0) {
printf(\"chrrecksum OK\ \");
fill_hdr((int)(head.seq).
18O is an important precursor for the production offlourodeoxyglucose.pdf
18O is an important precursor for the production offlourodeoxyglucose(FDG) used in
PETscans./ PET scans are atechnique which produces a three-dimensional image or picture
offunctional processes in the body. In Paleoclimatology they are usedto find out what
temperature of earths climate was in the past bycomparing the ratio of oxygen 18 to oxygen 16.
Solution
18O is an important precursor for the production offlourodeoxyglucose(FDG) used in
PETscans./ PET scans are atechnique which produces a three-dimensional image or picture
offunctional processes in the body. In Paleoclimatology they are usedto find out what
temperature of earths climate was in the past bycomparing the ratio of oxygen 18 to oxygen 16..
observed expected O - E (O - E) Solution observed expect.pdf
observed expected O - E (O - E)
Solution
observed expected O - E (O - E).
no hydrogen atom is present because its pure carb.pdf
no hydrogen atom is present because its pure carbon compound
Solution
no hydrogen atom is present because its pure carbon compound.
Mg and NaH react with water to give H2. Mg + 2H2.pdf
Mg and NaH react with water to give H2. Mg + 2H2O ---> Mg(OH)2 + H2 NaH +
H2O ---> NaOH + H2
Solution
Mg and NaH react with water to give H2. Mg + 2H2O ---> Mg(OH)2 + H2 NaH +
H2O ---> NaOH + H2.
in case of A and D there will be resonance betwee.pdf
in case of A and D there will be resonance between N-O and O-O . so these are
week base. and compared to OH NH2 will be strong base, also C is a alcohol and thus it has
more tendancy to release H+ and not to donate its lone pair. HEnce B is the correct answer.
ALSO its primary amine. so it has more tendancy to donate so answer is B
Solution
in case of A and D there will be resonance between N-O and O-O . so these are
week base. and compared to OH NH2 will be strong base, also C is a alcohol and thus it has
more tendancy to release H+ and not to donate its lone pair. HEnce B is the correct answer.
ALSO its primary amine. so it has more tendancy to donate so answer is B.
For half life to be independent of Concentration .pdf
For half life to be independent of Concentration is when n - 1 = 0, that is first order
reaction. t(1/2) = 0.693/K NOOOO you can not apply this expression for it because when you
have integrated the expression how concentration of A varies with t, then we had a condition that
n is not equal to 1. and thus you can not apply this expression.!!! HAVE FUN!!
Solution
For half life to be independent of Concentration is when n - 1 = 0, that is first order
reaction. t(1/2) = 0.693/K NOOOO you can not apply this expression for it because when you
have integrated the expression how concentration of A varies with t, then we had a condition that
n is not equal to 1. and thus you can not apply this expression.!!! HAVE FUN!!.
Mode because mode gives the number which occurs maximum number of .pdf
Mode
because mode gives the number which occurs maximum number of time
it doesnot give the location of any distribution
Solution
Mode
because mode gives the number which occurs maximum number of time
it doesnot give the location of any distribution.
Need more clear picturesSolutionNeed more clear pictures.pdf
Need more clear pictures
Solution
Need more clear pictures.
public class RectangleDemo { private class Rectangle { .pdf
public class RectangleDemo {
private class Rectangle {
private double height;
private double width;
private String color;
public Rectangle(double wid, double high){
height = high;
width = wid;
}
public Rectangle(){
height = 1;
width = 1;
color = \"White\";
}
public void setHeight(double high){
height = high;
}
public void setWidth(double wid){
width = wid;
}
public void setColor(String col){
color = col;
}
public double getArea(){
return height*width;
}
public double getPerimeter(){
return 2*(height + width);
}
public void getColor(){
System.out.println(\"Color is: \" + color +\"\ \");
return;
}
}
Solution
public class RectangleDemo {
private class Rectangle {
private double height;
private double width;
private String color;
public Rectangle(double wid, double high){
height = high;
width = wid;
}
public Rectangle(){
height = 1;
width = 1;
color = \"White\";
}
public void setHeight(double high){
height = high;
}
public void setWidth(double wid){
width = wid;
}
public void setColor(String col){
color = col;
}
public double getArea(){
return height*width;
}
public double getPerimeter(){
return 2*(height + width);
}
public void getColor(){
System.out.println(\"Color is: \" + color +\"\ \");
return;
}
}.
Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
Total assets=Total liabilities+Total equity
Hence Total assets=(7970+1920)=$9890
Total assets=Long term assets+Current assets
Current assets=(9890-6036)=$3854(million).
Solution
Total assets=Total liabilities+Total equity
Hence Total assets=(7970+1920)=$9890
Total assets=Long term assets+Current assets
Current assets=(9890-6036)=$3854(million)..
The products would be sodium chloride, water and carbon dioxide, and.pdf
The products would be sodium chloride, water and carbon dioxide, and the equation is
NaHCO3(s) + HCl(aq)=> NaCl(aq) +H2O(l) +CO2(g).
Solution
The products would be sodium chloride, water and carbon dioxide, and the equation is
NaHCO3(s) + HCl(aq)=> NaCl(aq) +H2O(l) +CO2(g)..
The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf
The answer is
c. SrCO3
Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the
CO32- ions
%Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50%
Solution
The answer is
c. SrCO3
Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the
CO32- ions
%Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50%.
Technologies would you use to assist in migrationSolutionTechn.pdf
Technologies would you use to assist in migration
Solution
Technologies would you use to assist in migration.
Role of biotechnology in bioterrorismBiotechnology can be employe.pdf
Role of biotechnology in bioterrorism:
Biotechnology can be employed by terrorist groups to produce microorganisms that are capable
of large scale morbidity and mortality resulting in bioterrorism. Techniques used for the
development of pathogens and toxins as weapons include different branches of biotechnology
like genetic engineering, protein engineering, functional genomics and artificial viruses.
Following are the essential characteristics of microorganisms which are used as weapons
Techniques used in bioterrorism try to enhance these characteristics (above) of microorganisms.
Solution
Role of biotechnology in bioterrorism:
Biotechnology can be employed by terrorist groups to produce microorganisms that are capable
of large scale morbidity and mortality resulting in bioterrorism. Techniques used for the
development of pathogens and toxins as weapons include different branches of biotechnology
like genetic engineering, protein engineering, functional genomics and artificial viruses.
Following are the essential characteristics of microorganisms which are used as weapons
Techniques used in bioterrorism try to enhance these characteristics (above) of microorganisms..
pure water dissociates with a reversible reaction forming H+ and OH-.pdf
pure water dissociates with a reversible reaction forming H+ and OH-
now this H+ gets H-Bonded to H2O to form H3O+
Now a base is added to pure water
the concentration of OH- increases
by common ion effect and Le-Chatelier\'s principle
the reverse reaction is favored and H+ and OH- are converted back to H2O thereby decreasing
the net H+ conc.
As H+ conc decreases H3O+ decreases.
Solution
pure water dissociates with a reversible reaction forming H+ and OH-
now this H+ gets H-Bonded to H2O to form H3O+
Now a base is added to pure water
the concentration of OH- increases
by common ion effect and Le-Chatelier\'s principle
the reverse reaction is favored and H+ and OH- are converted back to H2O thereby decreasing
the net H+ conc.
As H+ conc decreases H3O+ decreases..
Polymers are constructed from relatively small molecular fragments k.pdf
Polymers are constructed from relatively small molecular fragments known as monomers that are
joined together.
Chemistry:
Properties:
Applications:
Physical properties of polymers
The physical properties of a polymer such as its strength and flexibility depend on:
Other substances ( besides monomers ) are often needed for polymerisation to occur, for instance
initiators, catalysts, and depending on manufacturing process, solvents may also be used. The
resulting plastic polymer can be blended with different additives, for instance plasticisers, flame
retardants, heat stabilisers, antioxidants, light stabilisers, lubricants, acid scavengers,
antimicrobial agents, anti-static agents, pigments, blowing agents and fillers, and is finally
processed into a plastic product. There are many different plastic polymers and several thousand
different additives, which results in an extremely large variation in chemical composition of
plastic products ( Rosato, 1998 ).
Inthe polymeric material, however, non-polymeric components such as residual monomers,
oligomers, low molecular weight fragments, catalyst remnants, polymerisation solvents and a
wide range of additives can be present ( Crompton, 2007 ). Several of these are hazardous to
human health and the environment, for instance carcinogenic, mutagenic, toxic for reproduction,
sensitising and hazardous to the aquatic environment with long lasting effects. Since the non-
polymeric compounds usually are of low molecular weight and are either weakly bound or not
bound at all to the polymeric macro-molecules, they, or their degradation products, can be
emitted from the plastic product (Crompton, 2007; OECD, 2004) to air, water or other contact
media (e.g. food).
Many additives are hazardous for human health and the environment. Some are especially
hazardous, for instance brominated flame retardants used to retard ignition and prevent fire from
spreading; some phthalate plasticizers mainly used to make PVC flexible; and lead heat
stabilizers used to prevent degradation of PVC during processing ( Murphy, 2001 ). Several
polybrominated flame retardants are very persistent, very bioaccumulating and toxic, and are
listed in the Stockholm Convention on Persistent Organic Pollutants (POPs) (Secretary - general
UN, 2009). Among the phthalate plasticisers the most hazardous ones, i.e. BBP, DEHP and
DBP, are classified as toxic for reproduction (category 1B). BBP is also very toxic to aquatic
organisms with long lasting effects ( European Parliament and Council, 2008; European
Commission, 2009 ). In addition, these phthalates, as well as DEP ( diethylphthtalate ) and
DCHP ( dicyclohexyl phthalate ), are being evaluated for endocrine disrupting properties (
Groshart and Okkerman, 2000; Okkerman and vander Putte, 2002 ). The lead compounds used in
heat stabilizers are classified as toxic for reproduction (category 1A), very toxic to the aquatic
environment with long lasting effects (both acute and chronic), and may caus.
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
One of 2 principles of genetic heredity first formulated by Gregor Mendel, elucidated on his
genetic experiments with pea plants.
He finally described that the homologous chromosomes segregate during meiosis and are
distributed to different gametes, thereby the offspring acquires one chromosome from each
parent. The chromosomal segregation occurs during anaphase -II of meiosis. The segregated
chromosomes reunite randomly during the fertilization process.
Solution
One of 2 principles of genetic heredity first formulated by Gregor Mendel, elucidated on his
genetic experiments with pea plants.
He finally described that the homologous chromosomes segregate during meiosis and are
distributed to different gametes, thereby the offspring acquires one chromosome from each
parent. The chromosomal segregation occurs during anaphase -II of meiosis. The segregated
chromosomes reunite randomly during the fertilization process..
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
Maturity-risk premium = 5.2% - (1.4% + 1.1%)
Maturity-risk premium = 2.7%
The maturity-risk premium for this 2-year Treasury note is 2.7%
Solution
Maturity-risk premium = 5.2% - (1.4% + 1.1%)
Maturity-risk premium = 2.7%
The maturity-risk premium for this 2-year Treasury note is 2.7%.
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
Intrinsic muscles of the eye are responsible for accommodation. During accommodation, we can
observe three adjustments in the eye balls.
Convergence is the medial movement of eyeballs and is an important step in accommodation of
eye to focus on any object. This convergence reflex is helpful for focussing the eyes on a near
object (near vision) present, and helps to observe the nearby surroundings clearly (binocular
vision). Over convergence and under convergence causes visual problems.
Solution
Intrinsic muscles of the eye are responsible for accommodation. During accommodation, we can
observe three adjustments in the eye balls.
Convergence is the medial movement of eyeballs and is an important step in accommodation of
eye to focus on any object. This convergence reflex is helpful for focussing the eyes on a near
object (near vision) present, and helps to observe the nearby surroundings clearly (binocular
vision). Over convergence and under convergence causes visual problems..
it is a right that comes under property. - the right saves each an.pdf
it is a right that comes under property.
- the right saves each and every individual people in the world from doing harm to others by
their name or sometimes use the others for non legal purpose.
- save preserves even after the peoples death and finally that shall be given to their heirs or sold.
with the advancements in the science and technology in this digital age all the information can be
stored in a computers and can be used in their future.but the problem with this is due to the cyber
crime .
when we use social media for investigation there may lead to advantages and disadvantages
situations
because sometimes the provided information may be truth or it may be fake that has to be deeply
invested carefully to protect the right people from the criminal cases.
Solution
it is a right that comes under property.
- the right saves each and every individual people in the world from doing harm to others by
their name or sometimes use the others for non legal purpose.
- save preserves even after the peoples death and finally that shall be given to their heirs or sold.
with the advancements in the science and technology in this digital age all the information can be
stored in a computers and can be used in their future.but the problem with this is due to the cyber
crime .
when we use social media for investigation there may lead to advantages and disadvantages
situations
because sometimes the provided information may be truth or it may be fake that has to be deeply
invested carefully to protect the right people from the criminal cases..
I think that cos(2x)SolutionI think that cos(2x).pdf
I think that cos(2x)
Solution
I think that cos(2x).
A bond is ionic if it contains a metal (Group I, .pdf
A bond is ionic if it contains a metal (Group I, II, and the transition metals, some in
Group 3, some in Group 4) and a nonmetal. A bond is polar covalent if it contains two different
nonmetals (H, some in Group 3, some in Group 4, Group 5, Group 6, Group 7). A bond is
covalent if it contains two similar nonmetals (for example, C-C, N-N). Actually, a covalent bond
is defined as a bond where both molecules have similar electronegativities. It is very seldom
(although in rare cases, it does happen) that two different nonmetals have similar
electronegativities, so as a general rule two different nonmetals are usually polar covalent. If you
want to know what the rare cases are, you might want to consult a table that lists all the
electronegativities (found in some chemistry textbooks).
Solution
A bond is ionic if it contains a metal (Group I, II, and the transition metals, some in
Group 3, some in Group 4) and a nonmetal. A bond is polar covalent if it contains two different
nonmetals (H, some in Group 3, some in Group 4, Group 5, Group 6, Group 7). A bond is
covalent if it contains two similar nonmetals (for example, C-C, N-N). Actually, a covalent bond
is defined as a bond where both molecules have similar electronegativities. It is very seldom
(although in rare cases, it does happen) that two different nonmetals have similar
electronegativities, so as a general rule two different nonmetals are usually polar covalent. If you
want to know what the rare cases are, you might want to consult a table that lists all the
electronegativities (found in some chemistry textbooks)..
Chapter 3 - Islamic Banking Products and Services.pptx
Chapter 3 - Islamic Banking Products and Services.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
This slide is prepared for master's students (MIFB & MIBS) UUM. May it be useful to all.How libraries can support authors with open access requirements for UKRI fund...
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
More Related Content
More from contact34
Mg and NaH react with water to give H2. Mg + 2H2.pdf
Mg and NaH react with water to give H2. Mg + 2H2O ---> Mg(OH)2 + H2 NaH +
H2O ---> NaOH + H2
Solution
Mg and NaH react with water to give H2. Mg + 2H2O ---> Mg(OH)2 + H2 NaH +
H2O ---> NaOH + H2.
in case of A and D there will be resonance betwee.pdf
in case of A and D there will be resonance between N-O and O-O . so these are
week base. and compared to OH NH2 will be strong base, also C is a alcohol and thus it has
more tendancy to release H+ and not to donate its lone pair. HEnce B is the correct answer.
ALSO its primary amine. so it has more tendancy to donate so answer is B
Solution
in case of A and D there will be resonance between N-O and O-O . so these are
week base. and compared to OH NH2 will be strong base, also C is a alcohol and thus it has
more tendancy to release H+ and not to donate its lone pair. HEnce B is the correct answer.
ALSO its primary amine. so it has more tendancy to donate so answer is B.
For half life to be independent of Concentration .pdf
For half life to be independent of Concentration is when n - 1 = 0, that is first order
reaction. t(1/2) = 0.693/K NOOOO you can not apply this expression for it because when you
have integrated the expression how concentration of A varies with t, then we had a condition that
n is not equal to 1. and thus you can not apply this expression.!!! HAVE FUN!!
Solution
For half life to be independent of Concentration is when n - 1 = 0, that is first order
reaction. t(1/2) = 0.693/K NOOOO you can not apply this expression for it because when you
have integrated the expression how concentration of A varies with t, then we had a condition that
n is not equal to 1. and thus you can not apply this expression.!!! HAVE FUN!!.
Mode because mode gives the number which occurs maximum number of .pdf
Mode
because mode gives the number which occurs maximum number of time
it doesnot give the location of any distribution
Solution
Mode
because mode gives the number which occurs maximum number of time
it doesnot give the location of any distribution.
Need more clear picturesSolutionNeed more clear pictures.pdf
Need more clear pictures
Solution
Need more clear pictures.
public class RectangleDemo { private class Rectangle { .pdf
public class RectangleDemo {
private class Rectangle {
private double height;
private double width;
private String color;
public Rectangle(double wid, double high){
height = high;
width = wid;
}
public Rectangle(){
height = 1;
width = 1;
color = \"White\";
}
public void setHeight(double high){
height = high;
}
public void setWidth(double wid){
width = wid;
}
public void setColor(String col){
color = col;
}
public double getArea(){
return height*width;
}
public double getPerimeter(){
return 2*(height + width);
}
public void getColor(){
System.out.println(\"Color is: \" + color +\"\ \");
return;
}
}
Solution
public class RectangleDemo {
private class Rectangle {
private double height;
private double width;
private String color;
public Rectangle(double wid, double high){
height = high;
width = wid;
}
public Rectangle(){
height = 1;
width = 1;
color = \"White\";
}
public void setHeight(double high){
height = high;
}
public void setWidth(double wid){
width = wid;
}
public void setColor(String col){
color = col;
}
public double getArea(){
return height*width;
}
public double getPerimeter(){
return 2*(height + width);
}
public void getColor(){
System.out.println(\"Color is: \" + color +\"\ \");
return;
}
}.
Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
Total assets=Total liabilities+Total equity
Hence Total assets=(7970+1920)=$9890
Total assets=Long term assets+Current assets
Current assets=(9890-6036)=$3854(million).
Solution
Total assets=Total liabilities+Total equity
Hence Total assets=(7970+1920)=$9890
Total assets=Long term assets+Current assets
Current assets=(9890-6036)=$3854(million)..
The products would be sodium chloride, water and carbon dioxide, and.pdf
The products would be sodium chloride, water and carbon dioxide, and the equation is
NaHCO3(s) + HCl(aq)=> NaCl(aq) +H2O(l) +CO2(g).
Solution
The products would be sodium chloride, water and carbon dioxide, and the equation is
NaHCO3(s) + HCl(aq)=> NaCl(aq) +H2O(l) +CO2(g)..
The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf
The answer is
c. SrCO3
Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the
CO32- ions
%Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50%
Solution
The answer is
c. SrCO3
Sr is in Group II of the periodic table and form Sr2+ ions (oxidation state +2) to balance the
CO32- ions
%Oxygen by mass = (16 x 3)/(87.6 + 12 + 16 x 3) x 100 = 32.50%.
Technologies would you use to assist in migrationSolutionTechn.pdf
Technologies would you use to assist in migration
Solution
Technologies would you use to assist in migration.
Role of biotechnology in bioterrorismBiotechnology can be employe.pdf
Role of biotechnology in bioterrorism:
Biotechnology can be employed by terrorist groups to produce microorganisms that are capable
of large scale morbidity and mortality resulting in bioterrorism. Techniques used for the
development of pathogens and toxins as weapons include different branches of biotechnology
like genetic engineering, protein engineering, functional genomics and artificial viruses.
Following are the essential characteristics of microorganisms which are used as weapons
Techniques used in bioterrorism try to enhance these characteristics (above) of microorganisms.
Solution
Role of biotechnology in bioterrorism:
Biotechnology can be employed by terrorist groups to produce microorganisms that are capable
of large scale morbidity and mortality resulting in bioterrorism. Techniques used for the
development of pathogens and toxins as weapons include different branches of biotechnology
like genetic engineering, protein engineering, functional genomics and artificial viruses.
Following are the essential characteristics of microorganisms which are used as weapons
Techniques used in bioterrorism try to enhance these characteristics (above) of microorganisms..
pure water dissociates with a reversible reaction forming H+ and OH-.pdf
pure water dissociates with a reversible reaction forming H+ and OH-
now this H+ gets H-Bonded to H2O to form H3O+
Now a base is added to pure water
the concentration of OH- increases
by common ion effect and Le-Chatelier\'s principle
the reverse reaction is favored and H+ and OH- are converted back to H2O thereby decreasing
the net H+ conc.
As H+ conc decreases H3O+ decreases.
Solution
pure water dissociates with a reversible reaction forming H+ and OH-
now this H+ gets H-Bonded to H2O to form H3O+
Now a base is added to pure water
the concentration of OH- increases
by common ion effect and Le-Chatelier\'s principle
the reverse reaction is favored and H+ and OH- are converted back to H2O thereby decreasing
the net H+ conc.
As H+ conc decreases H3O+ decreases..
Polymers are constructed from relatively small molecular fragments k.pdf
Polymers are constructed from relatively small molecular fragments known as monomers that are
joined together.
Chemistry:
Properties:
Applications:
Physical properties of polymers
The physical properties of a polymer such as its strength and flexibility depend on:
Other substances ( besides monomers ) are often needed for polymerisation to occur, for instance
initiators, catalysts, and depending on manufacturing process, solvents may also be used. The
resulting plastic polymer can be blended with different additives, for instance plasticisers, flame
retardants, heat stabilisers, antioxidants, light stabilisers, lubricants, acid scavengers,
antimicrobial agents, anti-static agents, pigments, blowing agents and fillers, and is finally
processed into a plastic product. There are many different plastic polymers and several thousand
different additives, which results in an extremely large variation in chemical composition of
plastic products ( Rosato, 1998 ).
Inthe polymeric material, however, non-polymeric components such as residual monomers,
oligomers, low molecular weight fragments, catalyst remnants, polymerisation solvents and a
wide range of additives can be present ( Crompton, 2007 ). Several of these are hazardous to
human health and the environment, for instance carcinogenic, mutagenic, toxic for reproduction,
sensitising and hazardous to the aquatic environment with long lasting effects. Since the non-
polymeric compounds usually are of low molecular weight and are either weakly bound or not
bound at all to the polymeric macro-molecules, they, or their degradation products, can be
emitted from the plastic product (Crompton, 2007; OECD, 2004) to air, water or other contact
media (e.g. food).
Many additives are hazardous for human health and the environment. Some are especially
hazardous, for instance brominated flame retardants used to retard ignition and prevent fire from
spreading; some phthalate plasticizers mainly used to make PVC flexible; and lead heat
stabilizers used to prevent degradation of PVC during processing ( Murphy, 2001 ). Several
polybrominated flame retardants are very persistent, very bioaccumulating and toxic, and are
listed in the Stockholm Convention on Persistent Organic Pollutants (POPs) (Secretary - general
UN, 2009). Among the phthalate plasticisers the most hazardous ones, i.e. BBP, DEHP and
DBP, are classified as toxic for reproduction (category 1B). BBP is also very toxic to aquatic
organisms with long lasting effects ( European Parliament and Council, 2008; European
Commission, 2009 ). In addition, these phthalates, as well as DEP ( diethylphthtalate ) and
DCHP ( dicyclohexyl phthalate ), are being evaluated for endocrine disrupting properties (
Groshart and Okkerman, 2000; Okkerman and vander Putte, 2002 ). The lead compounds used in
heat stabilizers are classified as toxic for reproduction (category 1A), very toxic to the aquatic
environment with long lasting effects (both acute and chronic), and may caus.
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
One of 2 principles of genetic heredity first formulated by Gregor Mendel, elucidated on his
genetic experiments with pea plants.
He finally described that the homologous chromosomes segregate during meiosis and are
distributed to different gametes, thereby the offspring acquires one chromosome from each
parent. The chromosomal segregation occurs during anaphase -II of meiosis. The segregated
chromosomes reunite randomly during the fertilization process.
Solution
One of 2 principles of genetic heredity first formulated by Gregor Mendel, elucidated on his
genetic experiments with pea plants.
He finally described that the homologous chromosomes segregate during meiosis and are
distributed to different gametes, thereby the offspring acquires one chromosome from each
parent. The chromosomal segregation occurs during anaphase -II of meiosis. The segregated
chromosomes reunite randomly during the fertilization process..
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
Maturity-risk premium = 5.2% - (1.4% + 1.1%)
Maturity-risk premium = 2.7%
The maturity-risk premium for this 2-year Treasury note is 2.7%
Solution
Maturity-risk premium = 5.2% - (1.4% + 1.1%)
Maturity-risk premium = 2.7%
The maturity-risk premium for this 2-year Treasury note is 2.7%.
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
Intrinsic muscles of the eye are responsible for accommodation. During accommodation, we can
observe three adjustments in the eye balls.
Convergence is the medial movement of eyeballs and is an important step in accommodation of
eye to focus on any object. This convergence reflex is helpful for focussing the eyes on a near
object (near vision) present, and helps to observe the nearby surroundings clearly (binocular
vision). Over convergence and under convergence causes visual problems.
Solution
Intrinsic muscles of the eye are responsible for accommodation. During accommodation, we can
observe three adjustments in the eye balls.
Convergence is the medial movement of eyeballs and is an important step in accommodation of
eye to focus on any object. This convergence reflex is helpful for focussing the eyes on a near
object (near vision) present, and helps to observe the nearby surroundings clearly (binocular
vision). Over convergence and under convergence causes visual problems..
it is a right that comes under property. - the right saves each an.pdf
it is a right that comes under property.
- the right saves each and every individual people in the world from doing harm to others by
their name or sometimes use the others for non legal purpose.
- save preserves even after the peoples death and finally that shall be given to their heirs or sold.
with the advancements in the science and technology in this digital age all the information can be
stored in a computers and can be used in their future.but the problem with this is due to the cyber
crime .
when we use social media for investigation there may lead to advantages and disadvantages
situations
because sometimes the provided information may be truth or it may be fake that has to be deeply
invested carefully to protect the right people from the criminal cases.
Solution
it is a right that comes under property.
- the right saves each and every individual people in the world from doing harm to others by
their name or sometimes use the others for non legal purpose.
- save preserves even after the peoples death and finally that shall be given to their heirs or sold.
with the advancements in the science and technology in this digital age all the information can be
stored in a computers and can be used in their future.but the problem with this is due to the cyber
crime .
when we use social media for investigation there may lead to advantages and disadvantages
situations
because sometimes the provided information may be truth or it may be fake that has to be deeply
invested carefully to protect the right people from the criminal cases..
I think that cos(2x)SolutionI think that cos(2x).pdf
I think that cos(2x)
Solution
I think that cos(2x).
A bond is ionic if it contains a metal (Group I, .pdf
A bond is ionic if it contains a metal (Group I, II, and the transition metals, some in
Group 3, some in Group 4) and a nonmetal. A bond is polar covalent if it contains two different
nonmetals (H, some in Group 3, some in Group 4, Group 5, Group 6, Group 7). A bond is
covalent if it contains two similar nonmetals (for example, C-C, N-N). Actually, a covalent bond
is defined as a bond where both molecules have similar electronegativities. It is very seldom
(although in rare cases, it does happen) that two different nonmetals have similar
electronegativities, so as a general rule two different nonmetals are usually polar covalent. If you
want to know what the rare cases are, you might want to consult a table that lists all the
electronegativities (found in some chemistry textbooks).
Solution
A bond is ionic if it contains a metal (Group I, II, and the transition metals, some in
Group 3, some in Group 4) and a nonmetal. A bond is polar covalent if it contains two different
nonmetals (H, some in Group 3, some in Group 4, Group 5, Group 6, Group 7). A bond is
covalent if it contains two similar nonmetals (for example, C-C, N-N). Actually, a covalent bond
is defined as a bond where both molecules have similar electronegativities. It is very seldom
(although in rare cases, it does happen) that two different nonmetals have similar
electronegativities, so as a general rule two different nonmetals are usually polar covalent. If you
want to know what the rare cases are, you might want to consult a table that lists all the
electronegativities (found in some chemistry textbooks)..
More from contact34 (20)
Mg and NaH react with water to give H2. Mg + 2H2.pdf
Mg and NaH react with water to give H2. Mg + 2H2.pdf
in case of A and D there will be resonance betwee.pdf
in case of A and D there will be resonance betwee.pdf
For half life to be independent of Concentration .pdf
For half life to be independent of Concentration .pdf
Mode because mode gives the number which occurs maximum number of .pdf
Mode because mode gives the number which occurs maximum number of .pdf
Need more clear picturesSolutionNeed more clear pictures.pdf
Need more clear picturesSolutionNeed more clear pictures.pdf
public class RectangleDemo { private class Rectangle { .pdf
public class RectangleDemo { private class Rectangle { .pdf
Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
Total assets=Total liabilities+Total equityHence Total assets=(797.pdf
The products would be sodium chloride, water and carbon dioxide, and.pdf
The products would be sodium chloride, water and carbon dioxide, and.pdf
The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf
The answer isc. SrCO3Sr is in Group II of the periodic table and.pdf
Technologies would you use to assist in migrationSolutionTechn.pdf
Technologies would you use to assist in migrationSolutionTechn.pdf
Role of biotechnology in bioterrorismBiotechnology can be employe.pdf
Role of biotechnology in bioterrorismBiotechnology can be employe.pdf
pure water dissociates with a reversible reaction forming H+ and OH-.pdf
pure water dissociates with a reversible reaction forming H+ and OH-.pdf
Polymers are constructed from relatively small molecular fragments k.pdf
Polymers are constructed from relatively small molecular fragments k.pdf
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
One of 2 principles of genetic heredity first formulated by Gregor M.pdf
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
Maturity-risk premium = 5.2 - (1.4 + 1.1)Maturity-risk premium .pdf
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
Intrinsic muscles of the eye are responsible for accommodation. Duri.pdf
it is a right that comes under property. - the right saves each an.pdf
it is a right that comes under property. - the right saves each an.pdf
I think that cos(2x)SolutionI think that cos(2x).pdf
I think that cos(2x)SolutionI think that cos(2x).pdf
A bond is ionic if it contains a metal (Group I, .pdf
A bond is ionic if it contains a metal (Group I, .pdf
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