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MICROWAVE ENGINEERING
Introduction.
Microwave: range of frequencies included in electromagnetic spectrum.
Electromagnetic spectrum: range of frequencies for electromagnetic signals.
Electromagnetic – a form of signal energy that that combines the interaction of electric and magnetic
energy.
Electromagnetic energy results from accelerating electrons while electric energy is resultant of static
charge
π‘žβ‚ ⟡⟢ π‘žβ‚‚
𝐹 =
π‘žβ‚π‘žβ‚‚
4πœ‹π‘ŸΒ²
𝐹 =
π‘ž
4πœ‹Ι›π‘ŸΒ²
Where:
q- Charge in C.
Ι›=Ι›α΅£ Ι›β‚€.
Magnetic fields results from net magnetic moments due to spinning and revolving electrons in an atom.
Magnets have two dipoles that is N and S poles.
Magnetic diagram.
𝐻 =
𝐡
Β΅
, 𝐡 = ¡𝐻
Where H- magnetic field density.
B –magnetic flux density.
Β΅- permeability of free space.
When the two (magnetic and electric) are combined they give rise to electro-magnetism hence
electromagnetic energy.
Electromagnetic spectrum comprises the following signals or form of energy.
οƒΌ Gamma rays.
οƒΌ X-rays.
οƒΌ Ultraviolet light (UV).
οƒΌ Infrared.
οƒΌ Microwave.
οƒΌ Radio wave.
Tabulate the EM spectrum.
EM Freq. wavelength Energy Application
Gamma rays 300 EHz 1 pm 1.24MeN Checking cracks in metals, building,
railway tracks..
Hard X-rays 30EHz 10pm 124KeN -medicine (cancer)
-Security –metal detectors.
Microwave
(EHF)
300GHz 1mm 1.24meV Communication –WiMAX, Radar,
-imaging.
Radio
(ELF)
3Hz 100Β΅m 12.4Β΅eV -communication.
-navigation.
Table.
Microwave spectrum.
Initial bands. Freq. GHz wavelength Energy Application
L 1-2 30-15 1800MHz GSM
Microwave links, waveguide.
S 2-4 15-7.5 2100MHz UMTS, WIFI, Bluetooth, Zigbee.
C 4-8 7.5-3.8 satellite
X 8-12 3.8-2.5 satellite
Ku 12-18 2.5-1.7 satellite
K 18-27 1.7-1.1 satellite
Ka 27-40 1.1-0.75
V 40-75 0.75-0.4
W 75-110 0.4-0.27
Table. Microwave spectrum.
E=hf
Where h-planks constant (6.62X10-38
Js).
Application of microwave.
οƒΌ GSM.
οƒΌ Microwave links- waveguides.
οƒΌ Satellite.
οƒΌ Remote sensing.
οƒΌ Microwave heating.
οƒΌ Radar system.
οƒΌ WLANS- Wi-Fi, Bluetooth, ZigBee, WiMAX.
Differential equation.
1. Gauss’ law of electricity.
βˆ‡. 𝐸 =
π‘ž
Ι›
2. Gauss law of magnetism.
βˆ‡. 𝐻 = 0
3. Faradays law
βˆ‡ Γ— 𝐸 = βˆ’
πœ•π΅
πœ•π‘‘
4. Ampere/Maxwell law.
βˆ‡ Γ— 𝐻=JC+JD= 𝜎𝐸 +
πœ•π·
πœ•π‘‘
These equation expressed in free space.
βˆ‡. 𝐸 =
π‘žβ‚’
Ι›β‚’
βˆ‡. 𝐻 = 0
βˆ‡ Γ— 𝐸 = βˆ’
πœ•π΅
πœ•π‘‘
βˆ‡ Γ— 𝐻 =
πœ•π·
πœ•π‘‘
Divergence.
βˆ‡=
𝛿
𝛿π‘₯
+
𝛿
𝛿𝑦
+
𝛿
𝛿𝑧
Curl
βˆ‡Γ— 𝐸 = |
Γ’β‚“ Ò𝑦 Ò𝑧
πœ•
πœ•π‘₯
πœ•
πœ•π‘¦
πœ•
πœ•π‘§
𝐸π‘₯ 𝐸𝑦 𝐸𝑧
|
Determinant.
=αΊ­x(
πœ•πΈπ‘§
πœ•π‘¦
βˆ’
πœ•πΈπ‘¦
πœ•π‘§
)-αΊ­y((
πœ•πΈπ‘§
πœ•π‘₯
) βˆ’
πœ•πΈπ‘₯
πœ•π‘§
)-αΊ­z(
πœ•πΈπ‘¦
πœ•π‘₯
βˆ’
πœ•πΈπ‘₯
πœ•π‘¦
)
Example.
Given.
E=Emcos(Ο‰t + Ξ²z)
βˆ‡Γ— 𝐸 = |
Γ’β‚“ Ò𝑦 Ò𝑧
πœ•
πœ•π‘₯
πœ•
πœ•π‘¦
πœ•
πœ•π‘§
0 𝐸𝑦 0
|
=αΊ­x(0 βˆ’
πœ•πΈπ‘¦
πœ•π‘§
)
=-αΊ­x
πœ•πΈπ‘¦
πœ•π‘§
=-αΊ­x
πœ•πΈπ‘šπ‘π‘œπ‘ (πœ”π‘‘+𝛽𝑧)
πœ•π‘§
= 𝛽Em sin(Ο‰t + Ξ²z) αΊ­x
But
βˆ‡ Γ— 𝐸 = βˆ’
πœ•π΅
πœ•π‘‘
∫ βˆ’
πœ•π΅
πœ•π‘‘
= ∫ Ξ²Emsin(Ο‰t + Ξ²z)αΊ­x
B=
𝛽
πœ”
Emcos(Ο‰t + Ξ²z)αΊ­x TESLA.
D=Ι›O E
=Ι›O Emcos(Ο‰t + Ξ²z)
𝐢
𝑀²
H=
𝐡
Β΅
=
𝛽
πœ”Β΅
Emcos(Ο‰t + Ξ²z) αΊ­x
𝐴
𝑀
.
Impedance.
Z=
𝐸
𝐻
.𝜴
=
πœ”Β΅
𝛽
𝜴.
Appling the same theorem, find B, E and D. given.
H=HM 𝑒(πœ”π‘‘βˆ’π›½π‘§)
αΊ­x .
Exercise.
Given
H=20𝑒 𝑗(109 𝑑+𝛽𝑧)
αΊ­y
π‘šπ΄
𝑀
.
Determine D, H, and B then draw the waveform.
For the analysis above obtain the actual values in the microwave range. (Microwave range 300MHz-
300GHz), but 1-10GHz are commonly used.
Electromagnetic wave analysis based on Maxwell’s equation in time varying form in space.
βˆ‡ Γ— 𝐸 = βˆ’π‘—πœ”Β΅π»
βˆ‡ Γ— 𝐻 = 𝜎𝐸 + π‘—πœ”Ι›πΈ
βˆ‡. 𝐡 = 0
βˆ‡. 𝐷 = 0
Where:
B=Β΅H, J= 𝜎E, D=Ι›E.
Taking the curl of both expressions.
The curl of E.
βˆ‡ Γ— (βˆ‡ Γ— 𝐸) = βˆ’π‘—πœ”Β΅(𝛻 Γ— 𝐻)
= βˆ’π‘—πœ”Β΅(𝜎𝐸 + π‘—πœ”Ι›πΈ)
From curl identity, this can expressed as,
𝛻2
𝐸 = π‘—πœ”Β΅(𝜎𝐸 + π‘—πœ”Ι›πΈ)
= π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)𝐸
The curl of H.
βˆ‡ Γ— (βˆ‡ Γ— 𝐸) = 𝛻 Γ— (𝜎𝐸 + π‘—πœ”Ι›πΈ)
= πœŽπ›» Γ— 𝐸 + π‘—πœ”Ι›π›» Γ— 𝐸
𝛻2
𝐻 = 𝜎(βˆ’π‘—πœ”Β΅π») + π‘—πœ”Ι›(βˆ’π‘—πœ”Β΅π»)
= π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)𝐻
By taking, =𝛻, where 𝛢-gamma. We have.
Ξ₯2
𝐻 = π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)𝐻
Ξ₯2
= π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)
𝛢 = √(π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›))
Or
𝛢2
𝐸 = π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)𝐸
𝛢2
= π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)
𝛢 = √(π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›))
𝛢 = 𝛼 + 𝑗𝛽
𝛼 = πœ”βˆš(
Β΅Ι›
2
((√1 + (
𝜎
πœ”Ι›
)
2
) βˆ’ 1)
𝛽 = πœ”βˆš(
Β΅Ι›
2
√𝐻 (
𝜎
πœ”Ι›
) Β² + 1)
The above equation are for partially medium.
Perfect dielectric
For a perfect dielectric.
𝜎=0,
𝛼=0,
𝛽=πœ”βˆšΒ΅πœ”
Perfect conductor.
For a perfect conductor.
𝜎 >>πœ”Ι›. Which can be expressed as (
𝜎
πœ”Ι›
) Β² >> 1.
𝛼 = 𝛽 = πœ”βˆš(
Β΅Ι›
2
.
𝜎
πœ”Ι›
)
= πœ”βˆš
¡𝜎
2πœ”
= √
πœ”Β΅πœŽ
2
But πœ”=2πœ‹f.
Therefore.
= βˆšπœ‹π‘“Β΅πœŽ
Skin depth of a conductor, which is how far can signal penetrate into a conductor, is expressed in the
form.
𝛿 =
1
𝛽
=
1
βˆšπœ‹π‘“Β΅πœŽ
Exercise.
Determine the microwave skin depth of a waveguide F=10GHz, Β΅r=2 (Cu, Al, Fe). Also find the mostly
used material for waveguides and why.
Effects on EM as they propagate through media.
οƒΌ Reflection
οƒΌ Refraction
οƒΌ Attenuation
οƒΌ Scattering
οƒΌ Diffraction
οƒΌ Absorption
οƒΌ Depolarization
οƒΌ Fading
οƒΌ Losses
οƒΌ Dispersion
Reflection.
Bouncing back when they are in contact with an obstacle. In free space this can be buildings, vehicles,
flying objects, mountains etc. in waveguide transmission is done by reflection, metallic objects are
mostly used because are considered perfect reflectors.
Obeys laws of reflection, depends on Β΅ and Ι› but mostly permittivity.
Related by:
sin πœƒβ‚
sin πœƒβ‚‚
= √(
Ι›β‚‚Β΅β‚‚
ɛ₁¡₁
)
For free space, (air) ¡₁=Β΅β‚‚=1
Refraction.
This bending of waves during propagation as they travel from one medium to the other. Obeys
Snell’s law.
𝑛₁ sin πœƒβ‚ = 𝑛₂ sin πœƒβ‚‚
Where n1 and n2 are the refractive indexes.
Refractive index, n, depends on the permittivity of the medium.
In waveguides different air density can affect the signal. Fiber as a waveguide has material with different
n.
Attenuation.
Process when the wave losses power/energy as it propagates. Depends on attenuation constants, which
also depends on material type/medium.
𝛢 = 𝛼 + 𝑗𝛽
↕
E=EM 𝑒 𝛢𝑑+π‘—πœ”π‘§
=EM 𝑒 𝑗(𝛢𝑑+𝛽𝑧)
where 𝛢=j𝛽
=EMcos(πœ”π‘‘ + 𝛽𝑧) π‘œπ‘Ÿ E=EMsin(πœ”π‘‘ + 𝛽𝑧)
Affected by frequency.
Scattering
Reflection from non-uniform surfaces. In contact with particles with wavelength close to the
surface/object size. In wave guides it can be caused by minute particles and irregular surface.
Diffraction.
When the waves comes into contact with a sharp object/edge. It’s observed at the ends of the
waveguides.
Diagram.
Depends on the waveguides of the EM wave.
Dispersion.
Signal/wave spreads as it propagates making the signal weaker or cancellation sometime signal addition.
Depolarization
Polarization orientation of the EM wave. There are three types
ο‚· Linear (vertical and horizontal )
ο‚· Circular
ο‚· Elliptical
Depolarization- change of alignment vertical to horizontal or viceversa.in waveguide, its cause variation
of ionization level due to density variation.
Absorption.
Transfer of energy to obstacles or medium material resulting in change to other form of energy e.g.
heat.
Exercise: discuss the difference between absorption and attenuation.
Fading
Reduction of signal strength due to variations as it propagates.
Losses.
ο‚· Free space losses.
ο‚· Feeder losses due to misalignment.
ο‚· Obstacle losses.
Passive microwave devices.
Passive devices do not require external power source to operate e.g. resistor. Do not increase the
strength of the signal. Most waveguides are in this category.
A waveguide is a device that directs an EM wave through it as it move from source to destination.
EM waves directed includes:
ο‚· TEM- Transverse Electric and Magnetic wave
ο‚· TE -Transverse Electric wave
ο‚· TM- Transverse magnetic wave.
TEM. Has both magnetic and electric properties as components of the wave being propagated.
TE- has electric energy only.
TM. Has the magnetic energy only.
The wave results in different modes of propagation through the waveguides. They can be analyzed and
determined using Maxwell’s equations. The equation are given by: Faradays’ law of magnetism and
Amperes’ law of electricity.
Using Faraday’s law.
Note all equation are in vector form.
βˆ‡ Γ— 𝐸 = βˆ’π‘—πœ”Β΅π»
βˆ‡Γ— 𝐸 = |
Γ’β‚“ Ò𝑦 Ò𝑧
πœ•
πœ•π‘₯
πœ•
πœ•π‘¦
πœ•
πœ•π‘§
𝐸π‘₯ 𝐸𝑦 𝐸𝑧
|=βˆ’π‘—πœ”Β΅π»
αΊ­x:(
πœ•πΈπ‘§
πœ•π‘¦
βˆ’
πœ•πΈπ‘¦
πœ•π‘§
) = βˆ’π‘—πœ”Β΅π»x
αΊ­y:(
πœ•πΈπ‘₯
πœ•π‘₯
βˆ’
πœ•πΈπ‘§
πœ•π‘§
)=π‘—πœ”Β΅π»y
αΊ­z:(
πœ•πΈπ‘¦
πœ•π‘₯
βˆ’
πœ•πΈπ‘₯
πœ•π‘¦
) =βˆ’π‘—πœ”Β΅π»z
Taking the waveform in z-direction to be given by π‘’βˆ’π‘—π΅π‘
and substituting in the above equation.
αΊ­x.(
πœ•πΈπ‘§
πœ•π‘¦
βˆ’
πœ•πΈπ‘¦
πœ•π‘§
) = βˆ’π‘—πœ”Β΅π»x
βˆ’π‘—πœ”Β΅π»x =
πœ•πΈπ‘§
πœ•π‘¦
+ 𝑗𝐡𝐸y
π‘—πœ”Β΅π»y =
πœ•πΈπ‘§
πœ•π‘§
+ 𝑗𝐡𝐸x
αΊ­z:(
πœ•πΈπ‘¦
πœ•π‘₯
βˆ’
πœ•πΈπ‘₯
πœ•π‘¦
) =βˆ’π‘—πœ”Β΅π»z
Using Amperes equation.
βˆ‡ Γ— Δ€ = π‘—πœ”Β΅π»
βˆ‡Γ— 𝐻 = |
Γ’β‚“ Ò𝑦 Ò𝑧
πœ•
πœ•π‘₯
πœ•
πœ•π‘¦
πœ•
πœ•π‘§
𝐻π‘₯ 𝐻𝑦 𝐻𝑧
|=π‘—πœ”Ι›πΈ
αΊ­x :(
πœ•π»π‘§
πœ•π‘¦
βˆ’
πœ•π»π‘¦
πœ•π‘§
) = π‘—πœ”Β΅πΈx
πœ•π»π‘§
πœ•π‘¦
βˆ’
πœ•π‘’βˆ’π‘—π΅π‘
πœ•π‘§
= π‘—πœ”Β΅πΈx
πœ•π»π‘§
πœ•π‘¦
+ 𝑗𝐡𝐻y= π‘—πœ”Β΅πΈx
αΊ­y :(
πœ•π»π‘§
πœ•π‘₯
βˆ’
πœ•π»π‘₯
πœ•π‘§
)=π‘—πœ”Β΅πΈy
πœ•π‘’βˆ’π‘—π΅π‘
πœ•π‘₯
βˆ’
πœ•π»π‘₯
πœ•π‘§
= π‘—πœ”Β΅πΈy
=
πœ•π»π‘§
πœ•π‘§
+ 𝑗𝐡Hx
αΊ­z :(
πœ•π»π‘¦
πœ•π‘₯
βˆ’
πœ•π»π‘₯
πœ•π‘¦
) =π‘—πœ”Β΅πΈz
Manipulating the above equation. We can get the transverse components of Δ’ and Δ€, i.e. the x and y
components.
Taking the first expression and making Hx the subject of the formula we obtain.
Hx =βˆ’ (
πœ•πΈπ‘§
πœ•π‘¦
+𝑗𝐡𝐸y
π‘—πœ”Β΅
)
=
𝑗
πœ”Β΅
(
πœ•πΈπ‘§
πœ•π‘¦
+ 𝑗𝐡𝐸y)
=
𝑗
πœ”Β΅
πœ•πΈπ‘§
πœ•π‘¦
βˆ’
𝐡𝐸y
πœ”Β΅
But.
Ey=
πœ•π»π‘§
πœ•π‘₯
+
𝛽
πœ”Ι›
Hx
Therefore.
Hx=
𝑗
πœ”Β΅
πœ•πΈπ‘§
πœ•π‘¦
βˆ’
𝐡
πœ”2Β΅
πœ•π»π‘§
πœ•π‘₯
+
𝛽²
πœ”Β²Β΅Ι›
Hx
=
(
𝑗
πœ”Β΅
πœ•πΈπ‘§
πœ•π‘¦
βˆ’
𝐡
πœ”2Β΅
πœ•π»π‘§
πœ•π‘₯
)
1βˆ’
𝛽²
πœ”Β²Β΅Ι›
Let, πœ”Β²Β΅Ι›= kΒ²
Hx =
𝑗
kΒ²βˆ’Ξ²Β²
(πœ”Ι›
πœ•πΈπ‘§
πœ•π‘¦
βˆ’ 𝛽
πœ•π»π‘§
πœ•π‘₯
)
And kCΒ²= kΒ²-𝛽²
Using the same procedure obtain: Hy, Ex and Ey
Hy =βˆ’
𝑗
kcΒ²
( πœ”Ι› πœ•πΈπ‘§
πœ•π‘₯
+ 𝛽 πœ•π»π‘§
πœ•π‘¦
)
Ex =βˆ’
𝑗
kcΒ²
( 𝛽 πœ•πΈπ‘§
πœ•π‘₯
+ πœ”Β΅ πœ•π»π‘§
πœ•π‘¦
)
Ey =
𝑗
kcΒ²
(βˆ’π›½ πœ•πΈπ‘§
πœ•π‘¦
+ πœ”Β΅ πœ•π»π‘§
πœ•π‘₯
)
All the above equation are TEM such that the electric and magnetic exist in z-direction, thus longitudinal
with the direction of propagation and therefore both of them exist i.e. EZ and HZ.
Modes
TE Mode.
Transverse electric: indicates that electric field is cross with direction of propagation hence EZ=0 but
HZ≠0.
The above expressions becomes:
Hx =
𝑗
kcΒ²
(βˆ’π›½
πœ•π»π‘§
πœ•π‘₯
)
Hx =βˆ’
𝑗
kcΒ²
𝛽 πœ•π»π‘§
πœ•π‘₯
Ex =βˆ’
𝑗
kcΒ²
( πœ”Β΅ πœ•π»π‘§
πœ•π‘¦
)
=βˆ’
𝑗
kcΒ²
πœ”Β΅ πœ•π»π‘§
πœ•π‘¦
Ey =
𝑗
kcΒ²
( πœ”Β΅ πœ•π»π‘§
πœ•π‘₯
)
=
𝑗
kc2 πœ”Β΅ πœ•π»π‘§
πœ•π‘₯
Hy =βˆ’
𝑗
kcΒ²
𝛽 πœ•π»π‘§
πœ•π‘¦
TM Mode.
Transverse magnetic: the magnetic fields is cross to the direction of propagation, hence EZ≠0 but
HZ=0.
The above expression becomes.
Hx =
𝑗
kcΒ²
πœ”Ι›
πœ•πΈπ‘§
πœ•π‘¦
Hy =βˆ’
𝑗
kcΒ²
πœ”Ι› πœ•πΈπ‘§
πœ•π‘₯
Ex =βˆ’
𝑗
kcΒ²
𝛽 πœ•πΈπ‘§
πœ•π‘₯
Ey =βˆ’
𝑗
kcΒ²
𝛽 πœ•πΈπ‘§
πœ•π‘¦
TEM Mode
The E and H are both transverse i.e. perpendicular to the direction of propagation, both EZ and HZ
are zero. HX, HY, EX and Ey do not exist.
The waveguides that can propagate TEM should have two lines for instance coaxial, microstrip and
coplanar.
Types of waveguides.
There are several types classified according to the following features.
ο‚· Number of lines.
ο‚· Material –conductor, dielectric.
ο‚· Types of modes of propagation TE, TM, TEM, and hybrid.
ο‚· Cut of frequency.
ο‚· Shape: Rectangular, Cylindrical and Elliptical.
ο‚· Material type. Level of permittivity.
ο‚· Technology.
Based on the above, the types includes:
ο‚· Metallic waveguides.
ο‚· Metallic TEM and quasi TEM.
ο‚· Dielectric.
Metallic waveguides.
Are constructed from metallic material, are in different shapes including:
1. Rectangular.
Supports TE and TM but not TEM. It’s has a cut off frequency.
2. Cylindrical.
The face is circular with a given length, radius is the main consideration in its design.
R
Diagram.
Supports TE and TM.
3. Elliptical.
Width
Diagram.
Supports TE and TM.
Quasi TEM.
Have more than a single line. Includes:
ο‚· Coaxial,
ο‚· Strip-line
ο‚· Coaxial rectangular.
Coaxial.
Inner core.
Outer conductor
insulator
Diagram
It has an inner core, conductor that is insulated and separated from the outer conductor. At the top
there is an insulator referred as outer jacket. The two radii, inner and outer radii, are considered is its
design.
Coaxial rectangular.
Has rectangular dimensions.
Inner core.
Outer conductor
dielectric
Diagram.
Strip-line
Construction.
Ground
w
b
Ι›α΅£
Strip-line
Diagram.
Constructed by etching a conductor with width of W on a dielectric material with Ι›r in the middle of the
dielectric as shown above.
The most important parameter are the width of the conductor (w) and the height of the dielectric (b).
The conductor appears at
𝑏
2
distance from either side upper or lower. This parameter b and w will
directly affect the capacitive and inductive properties of the line which together with Ι›r also affects the
plane, group velocities, propagation constant and the impedance of the device.
Vg =
𝑐
βˆšΙ›α΅£
c- Velocity of light.
The fields will appear as follows.
Diagram.
It supports TEM mode.
Other lines include.
ο‚· Slot lone
ο‚· Coplanar.
ο‚· Microstrip.
Microstrip line.
microstrip
Diagram.
Constructed by etching a conductor at the top of a dielectric material with a ground running across the
bottom of the dielectric.
The important parameter include w-width of the line, b the separation between the ground and the line
and the dielectric material constant Ι›r. These will affect capacitive and inductive properties as well as vp,
vg, πœ‚ and 𝛽.
The fields are given by
Diagram.
Impedance matching two port network.
NW
2
NW
1
High
impedance
Low
impedance
Connecting in this form causes reflection of signal, it should be connected as below.
NW
2
NW
1
High
impedance
Low
impedance
Transistor can be used for impedance matching.
Covered microstrip.
Similar to the microstrip the difference being that strip is covered.
Cover (dielectric
material) microstrip
Diagram.
The cover has an effect which can be negative in that it can introduce losses.
Slot line.
Construction.
Slot line
Diagram.
Constructed by etching a metallic material at the top of the dielectric creating a section without the
conductor, this forms the slot.
Coplanar.
Construction.
Has two slots.
Diagram.
Obtained by etching two sessions on a metal conductor then coating done on dielectric.
Additional devices.
οƒΌ Ridge waveguides.
οƒΌ Dielectric waveguides.
i) Fiber waveguide.
ii) Plain dielectric.
Ridge waveguide.
Ridges are developed by a dielectric material.
Ridges (ɛᡣ₁ )
Diagram
Ridges are developed on a dielectric material.
Fiber waveguide.
Construction.
Ι›β‚‚
ɛ₁
Diagram.
It developed from two materials with different dielectric properties.
Reflection and refraction can be principles can be applied in their applications.
Plain dielectric.
Ι›α΅£
Diagram.
Developed using single material type with specific dielectric properties. Supports TE and TM.
Active Microwave devices.
Require power to operate and can increase the strength of a signal actually includes electronics devices
semiconductor, Diodes, Transistors, Integrated circuits.
Diodes.
Types:-
ο‚· Schotty diode.
ο‚· PIN diode.
ο‚· Tunnel diode.
Transistors include BJT, FETs.
Integrated circuits includes:
οƒΌ BJT based technology
οƒΌ FET based technology.
Others are; semiconductor resistor and capacitor.
Exercise.
1. Derive the cut-off frequency for all the above waveguides discussed. Obtain: vp, vg, impedance (πœ‚),
propagation constant (𝛽), for all the waveguide above.
2. Discuss the different active microwave devices. Discussion should include: definition, symbol,
construction, features, operation and applications.
3. Do the same for passive microwave devices.

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MICROWAVE ENGINEERING FUNDAMENTALS

  • 1. MICROWAVE ENGINEERING Introduction. Microwave: range of frequencies included in electromagnetic spectrum. Electromagnetic spectrum: range of frequencies for electromagnetic signals. Electromagnetic – a form of signal energy that that combines the interaction of electric and magnetic energy. Electromagnetic energy results from accelerating electrons while electric energy is resultant of static charge π‘žβ‚ ⟡⟢ π‘žβ‚‚ 𝐹 = π‘žβ‚π‘žβ‚‚ 4πœ‹π‘ŸΒ² 𝐹 = π‘ž 4πœ‹Ι›π‘ŸΒ² Where: q- Charge in C. Ι›=Ι›α΅£ Ι›β‚€. Magnetic fields results from net magnetic moments due to spinning and revolving electrons in an atom. Magnets have two dipoles that is N and S poles. Magnetic diagram. 𝐻 = 𝐡 Β΅ , 𝐡 = ¡𝐻 Where H- magnetic field density. B –magnetic flux density. Β΅- permeability of free space.
  • 2. When the two (magnetic and electric) are combined they give rise to electro-magnetism hence electromagnetic energy. Electromagnetic spectrum comprises the following signals or form of energy. οƒΌ Gamma rays. οƒΌ X-rays. οƒΌ Ultraviolet light (UV). οƒΌ Infrared. οƒΌ Microwave. οƒΌ Radio wave. Tabulate the EM spectrum. EM Freq. wavelength Energy Application Gamma rays 300 EHz 1 pm 1.24MeN Checking cracks in metals, building, railway tracks.. Hard X-rays 30EHz 10pm 124KeN -medicine (cancer) -Security –metal detectors. Microwave (EHF) 300GHz 1mm 1.24meV Communication –WiMAX, Radar, -imaging. Radio (ELF) 3Hz 100Β΅m 12.4Β΅eV -communication. -navigation. Table. Microwave spectrum. Initial bands. Freq. GHz wavelength Energy Application L 1-2 30-15 1800MHz GSM Microwave links, waveguide. S 2-4 15-7.5 2100MHz UMTS, WIFI, Bluetooth, Zigbee. C 4-8 7.5-3.8 satellite X 8-12 3.8-2.5 satellite Ku 12-18 2.5-1.7 satellite K 18-27 1.7-1.1 satellite Ka 27-40 1.1-0.75 V 40-75 0.75-0.4 W 75-110 0.4-0.27 Table. Microwave spectrum. E=hf
  • 3. Where h-planks constant (6.62X10-38 Js). Application of microwave. οƒΌ GSM. οƒΌ Microwave links- waveguides. οƒΌ Satellite. οƒΌ Remote sensing. οƒΌ Microwave heating. οƒΌ Radar system. οƒΌ WLANS- Wi-Fi, Bluetooth, ZigBee, WiMAX. Differential equation. 1. Gauss’ law of electricity. βˆ‡. 𝐸 = π‘ž Ι› 2. Gauss law of magnetism. βˆ‡. 𝐻 = 0 3. Faradays law βˆ‡ Γ— 𝐸 = βˆ’ πœ•π΅ πœ•π‘‘ 4. Ampere/Maxwell law. βˆ‡ Γ— 𝐻=JC+JD= 𝜎𝐸 + πœ•π· πœ•π‘‘ These equation expressed in free space. βˆ‡. 𝐸 = π‘žβ‚’ Ι›β‚’ βˆ‡. 𝐻 = 0 βˆ‡ Γ— 𝐸 = βˆ’ πœ•π΅ πœ•π‘‘
  • 4. βˆ‡ Γ— 𝐻 = πœ•π· πœ•π‘‘ Divergence. βˆ‡= 𝛿 𝛿π‘₯ + 𝛿 𝛿𝑦 + 𝛿 𝛿𝑧 Curl βˆ‡Γ— 𝐸 = | Γ’β‚“ Ò𝑦 Ò𝑧 πœ• πœ•π‘₯ πœ• πœ•π‘¦ πœ• πœ•π‘§ 𝐸π‘₯ 𝐸𝑦 𝐸𝑧 | Determinant. =αΊ­x( πœ•πΈπ‘§ πœ•π‘¦ βˆ’ πœ•πΈπ‘¦ πœ•π‘§ )-αΊ­y(( πœ•πΈπ‘§ πœ•π‘₯ ) βˆ’ πœ•πΈπ‘₯ πœ•π‘§ )-αΊ­z( πœ•πΈπ‘¦ πœ•π‘₯ βˆ’ πœ•πΈπ‘₯ πœ•π‘¦ ) Example. Given. E=Emcos(Ο‰t + Ξ²z) βˆ‡Γ— 𝐸 = | Γ’β‚“ Ò𝑦 Ò𝑧 πœ• πœ•π‘₯ πœ• πœ•π‘¦ πœ• πœ•π‘§ 0 𝐸𝑦 0 | =αΊ­x(0 βˆ’ πœ•πΈπ‘¦ πœ•π‘§ ) =-αΊ­x πœ•πΈπ‘¦ πœ•π‘§ =-αΊ­x πœ•πΈπ‘šπ‘π‘œπ‘ (πœ”π‘‘+𝛽𝑧) πœ•π‘§ = 𝛽Em sin(Ο‰t + Ξ²z) αΊ­x But βˆ‡ Γ— 𝐸 = βˆ’ πœ•π΅ πœ•π‘‘
  • 5. ∫ βˆ’ πœ•π΅ πœ•π‘‘ = ∫ Ξ²Emsin(Ο‰t + Ξ²z)αΊ­x B= 𝛽 πœ” Emcos(Ο‰t + Ξ²z)αΊ­x TESLA. D=Ι›O E =Ι›O Emcos(Ο‰t + Ξ²z) 𝐢 𝑀² H= 𝐡 Β΅ = 𝛽 πœ”Β΅ Emcos(Ο‰t + Ξ²z) αΊ­x 𝐴 𝑀 . Impedance. Z= 𝐸 𝐻 .𝜴 = πœ”Β΅ 𝛽 𝜴. Appling the same theorem, find B, E and D. given. H=HM 𝑒(πœ”π‘‘βˆ’π›½π‘§) αΊ­x . Exercise. Given H=20𝑒 𝑗(109 𝑑+𝛽𝑧) αΊ­y π‘šπ΄ 𝑀 . Determine D, H, and B then draw the waveform. For the analysis above obtain the actual values in the microwave range. (Microwave range 300MHz- 300GHz), but 1-10GHz are commonly used.
  • 6. Electromagnetic wave analysis based on Maxwell’s equation in time varying form in space. βˆ‡ Γ— 𝐸 = βˆ’π‘—πœ”Β΅π» βˆ‡ Γ— 𝐻 = 𝜎𝐸 + π‘—πœ”Ι›πΈ βˆ‡. 𝐡 = 0 βˆ‡. 𝐷 = 0 Where: B=Β΅H, J= 𝜎E, D=Ι›E. Taking the curl of both expressions. The curl of E. βˆ‡ Γ— (βˆ‡ Γ— 𝐸) = βˆ’π‘—πœ”Β΅(𝛻 Γ— 𝐻) = βˆ’π‘—πœ”Β΅(𝜎𝐸 + π‘—πœ”Ι›πΈ) From curl identity, this can expressed as, 𝛻2 𝐸 = π‘—πœ”Β΅(𝜎𝐸 + π‘—πœ”Ι›πΈ) = π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)𝐸 The curl of H. βˆ‡ Γ— (βˆ‡ Γ— 𝐸) = 𝛻 Γ— (𝜎𝐸 + π‘—πœ”Ι›πΈ) = πœŽπ›» Γ— 𝐸 + π‘—πœ”Ι›π›» Γ— 𝐸 𝛻2 𝐻 = 𝜎(βˆ’π‘—πœ”Β΅π») + π‘—πœ”Ι›(βˆ’π‘—πœ”Β΅π») = π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)𝐻 By taking, =𝛻, where 𝛢-gamma. We have. Ξ₯2 𝐻 = π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)𝐻 Ξ₯2 = π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›) 𝛢 = √(π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)) Or 𝛢2 𝐸 = π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)𝐸 𝛢2 = π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›) 𝛢 = √(π‘—πœ”Β΅(𝜎 + π‘—πœ”Ι›)) 𝛢 = 𝛼 + 𝑗𝛽
  • 7. 𝛼 = πœ”βˆš( Β΅Ι› 2 ((√1 + ( 𝜎 πœ”Ι› ) 2 ) βˆ’ 1) 𝛽 = πœ”βˆš( Β΅Ι› 2 √𝐻 ( 𝜎 πœ”Ι› ) Β² + 1) The above equation are for partially medium. Perfect dielectric For a perfect dielectric. 𝜎=0, 𝛼=0, 𝛽=πœ”βˆšΒ΅πœ” Perfect conductor. For a perfect conductor. 𝜎 >>πœ”Ι›. Which can be expressed as ( 𝜎 πœ”Ι› ) Β² >> 1. 𝛼 = 𝛽 = πœ”βˆš( Β΅Ι› 2 . 𝜎 πœ”Ι› ) = πœ”βˆš ¡𝜎 2πœ” = √ πœ”Β΅πœŽ 2 But πœ”=2πœ‹f. Therefore. = βˆšπœ‹π‘“Β΅πœŽ Skin depth of a conductor, which is how far can signal penetrate into a conductor, is expressed in the form. 𝛿 = 1 𝛽 = 1 βˆšπœ‹π‘“Β΅πœŽ
  • 8. Exercise. Determine the microwave skin depth of a waveguide F=10GHz, Β΅r=2 (Cu, Al, Fe). Also find the mostly used material for waveguides and why. Effects on EM as they propagate through media. οƒΌ Reflection οƒΌ Refraction οƒΌ Attenuation οƒΌ Scattering οƒΌ Diffraction οƒΌ Absorption οƒΌ Depolarization οƒΌ Fading οƒΌ Losses οƒΌ Dispersion Reflection. Bouncing back when they are in contact with an obstacle. In free space this can be buildings, vehicles, flying objects, mountains etc. in waveguide transmission is done by reflection, metallic objects are mostly used because are considered perfect reflectors. Obeys laws of reflection, depends on Β΅ and Ι› but mostly permittivity. Related by: sin πœƒβ‚ sin πœƒβ‚‚ = √( Ι›β‚‚Β΅β‚‚ ɛ₁¡₁ ) For free space, (air) ¡₁=Β΅β‚‚=1 Refraction. This bending of waves during propagation as they travel from one medium to the other. Obeys Snell’s law. 𝑛₁ sin πœƒβ‚ = 𝑛₂ sin πœƒβ‚‚ Where n1 and n2 are the refractive indexes. Refractive index, n, depends on the permittivity of the medium. In waveguides different air density can affect the signal. Fiber as a waveguide has material with different n.
  • 9. Attenuation. Process when the wave losses power/energy as it propagates. Depends on attenuation constants, which also depends on material type/medium. 𝛢 = 𝛼 + 𝑗𝛽 ↕ E=EM 𝑒 𝛢𝑑+π‘—πœ”π‘§ =EM 𝑒 𝑗(𝛢𝑑+𝛽𝑧) where 𝛢=j𝛽 =EMcos(πœ”π‘‘ + 𝛽𝑧) π‘œπ‘Ÿ E=EMsin(πœ”π‘‘ + 𝛽𝑧) Affected by frequency. Scattering Reflection from non-uniform surfaces. In contact with particles with wavelength close to the surface/object size. In wave guides it can be caused by minute particles and irregular surface. Diffraction. When the waves comes into contact with a sharp object/edge. It’s observed at the ends of the waveguides. Diagram. Depends on the waveguides of the EM wave. Dispersion. Signal/wave spreads as it propagates making the signal weaker or cancellation sometime signal addition. Depolarization Polarization orientation of the EM wave. There are three types ο‚· Linear (vertical and horizontal ) ο‚· Circular ο‚· Elliptical Depolarization- change of alignment vertical to horizontal or viceversa.in waveguide, its cause variation of ionization level due to density variation. Absorption.
  • 10. Transfer of energy to obstacles or medium material resulting in change to other form of energy e.g. heat. Exercise: discuss the difference between absorption and attenuation. Fading Reduction of signal strength due to variations as it propagates. Losses. ο‚· Free space losses. ο‚· Feeder losses due to misalignment. ο‚· Obstacle losses. Passive microwave devices. Passive devices do not require external power source to operate e.g. resistor. Do not increase the strength of the signal. Most waveguides are in this category. A waveguide is a device that directs an EM wave through it as it move from source to destination. EM waves directed includes: ο‚· TEM- Transverse Electric and Magnetic wave ο‚· TE -Transverse Electric wave ο‚· TM- Transverse magnetic wave. TEM. Has both magnetic and electric properties as components of the wave being propagated. TE- has electric energy only. TM. Has the magnetic energy only. The wave results in different modes of propagation through the waveguides. They can be analyzed and determined using Maxwell’s equations. The equation are given by: Faradays’ law of magnetism and Amperes’ law of electricity. Using Faraday’s law. Note all equation are in vector form. βˆ‡ Γ— 𝐸 = βˆ’π‘—πœ”Β΅π» βˆ‡Γ— 𝐸 = | Γ’β‚“ Ò𝑦 Ò𝑧 πœ• πœ•π‘₯ πœ• πœ•π‘¦ πœ• πœ•π‘§ 𝐸π‘₯ 𝐸𝑦 𝐸𝑧 |=βˆ’π‘—πœ”Β΅π» αΊ­x:( πœ•πΈπ‘§ πœ•π‘¦ βˆ’ πœ•πΈπ‘¦ πœ•π‘§ ) = βˆ’π‘—πœ”Β΅π»x αΊ­y:( πœ•πΈπ‘₯ πœ•π‘₯ βˆ’ πœ•πΈπ‘§ πœ•π‘§ )=π‘—πœ”Β΅π»y
  • 11. αΊ­z:( πœ•πΈπ‘¦ πœ•π‘₯ βˆ’ πœ•πΈπ‘₯ πœ•π‘¦ ) =βˆ’π‘—πœ”Β΅π»z Taking the waveform in z-direction to be given by π‘’βˆ’π‘—π΅π‘ and substituting in the above equation. αΊ­x.( πœ•πΈπ‘§ πœ•π‘¦ βˆ’ πœ•πΈπ‘¦ πœ•π‘§ ) = βˆ’π‘—πœ”Β΅π»x βˆ’π‘—πœ”Β΅π»x = πœ•πΈπ‘§ πœ•π‘¦ + 𝑗𝐡𝐸y π‘—πœ”Β΅π»y = πœ•πΈπ‘§ πœ•π‘§ + 𝑗𝐡𝐸x αΊ­z:( πœ•πΈπ‘¦ πœ•π‘₯ βˆ’ πœ•πΈπ‘₯ πœ•π‘¦ ) =βˆ’π‘—πœ”Β΅π»z Using Amperes equation. βˆ‡ Γ— Δ€ = π‘—πœ”Β΅π» βˆ‡Γ— 𝐻 = | Γ’β‚“ Ò𝑦 Ò𝑧 πœ• πœ•π‘₯ πœ• πœ•π‘¦ πœ• πœ•π‘§ 𝐻π‘₯ 𝐻𝑦 𝐻𝑧 |=π‘—πœ”Ι›πΈ αΊ­x :( πœ•π»π‘§ πœ•π‘¦ βˆ’ πœ•π»π‘¦ πœ•π‘§ ) = π‘—πœ”Β΅πΈx πœ•π»π‘§ πœ•π‘¦ βˆ’ πœ•π‘’βˆ’π‘—π΅π‘ πœ•π‘§ = π‘—πœ”Β΅πΈx πœ•π»π‘§ πœ•π‘¦ + 𝑗𝐡𝐻y= π‘—πœ”Β΅πΈx αΊ­y :( πœ•π»π‘§ πœ•π‘₯ βˆ’ πœ•π»π‘₯ πœ•π‘§ )=π‘—πœ”Β΅πΈy πœ•π‘’βˆ’π‘—π΅π‘ πœ•π‘₯ βˆ’ πœ•π»π‘₯ πœ•π‘§ = π‘—πœ”Β΅πΈy = πœ•π»π‘§ πœ•π‘§ + 𝑗𝐡Hx αΊ­z :( πœ•π»π‘¦ πœ•π‘₯ βˆ’ πœ•π»π‘₯ πœ•π‘¦ ) =π‘—πœ”Β΅πΈz Manipulating the above equation. We can get the transverse components of Δ’ and Δ€, i.e. the x and y components. Taking the first expression and making Hx the subject of the formula we obtain.
  • 12. Hx =βˆ’ ( πœ•πΈπ‘§ πœ•π‘¦ +𝑗𝐡𝐸y π‘—πœ”Β΅ ) = 𝑗 πœ”Β΅ ( πœ•πΈπ‘§ πœ•π‘¦ + 𝑗𝐡𝐸y) = 𝑗 πœ”Β΅ πœ•πΈπ‘§ πœ•π‘¦ βˆ’ 𝐡𝐸y πœ”Β΅ But. Ey= πœ•π»π‘§ πœ•π‘₯ + 𝛽 πœ”Ι› Hx Therefore. Hx= 𝑗 πœ”Β΅ πœ•πΈπ‘§ πœ•π‘¦ βˆ’ 𝐡 πœ”2Β΅ πœ•π»π‘§ πœ•π‘₯ + 𝛽² πœ”Β²Β΅Ι› Hx = ( 𝑗 πœ”Β΅ πœ•πΈπ‘§ πœ•π‘¦ βˆ’ 𝐡 πœ”2Β΅ πœ•π»π‘§ πœ•π‘₯ ) 1βˆ’ 𝛽² πœ”Β²Β΅Ι› Let, πœ”Β²Β΅Ι›= kΒ² Hx = 𝑗 kΒ²βˆ’Ξ²Β² (πœ”Ι› πœ•πΈπ‘§ πœ•π‘¦ βˆ’ 𝛽 πœ•π»π‘§ πœ•π‘₯ ) And kCΒ²= kΒ²-𝛽² Using the same procedure obtain: Hy, Ex and Ey Hy =βˆ’ 𝑗 kcΒ² ( πœ”Ι› πœ•πΈπ‘§ πœ•π‘₯ + 𝛽 πœ•π»π‘§ πœ•π‘¦ ) Ex =βˆ’ 𝑗 kcΒ² ( 𝛽 πœ•πΈπ‘§ πœ•π‘₯ + πœ”Β΅ πœ•π»π‘§ πœ•π‘¦ ) Ey = 𝑗 kcΒ² (βˆ’π›½ πœ•πΈπ‘§ πœ•π‘¦ + πœ”Β΅ πœ•π»π‘§ πœ•π‘₯ ) All the above equation are TEM such that the electric and magnetic exist in z-direction, thus longitudinal with the direction of propagation and therefore both of them exist i.e. EZ and HZ. Modes TE Mode.
  • 13. Transverse electric: indicates that electric field is cross with direction of propagation hence EZ=0 but HZβ‰ 0. The above expressions becomes: Hx = 𝑗 kcΒ² (βˆ’π›½ πœ•π»π‘§ πœ•π‘₯ ) Hx =βˆ’ 𝑗 kcΒ² 𝛽 πœ•π»π‘§ πœ•π‘₯ Ex =βˆ’ 𝑗 kcΒ² ( πœ”Β΅ πœ•π»π‘§ πœ•π‘¦ ) =βˆ’ 𝑗 kcΒ² πœ”Β΅ πœ•π»π‘§ πœ•π‘¦ Ey = 𝑗 kcΒ² ( πœ”Β΅ πœ•π»π‘§ πœ•π‘₯ ) = 𝑗 kc2 πœ”Β΅ πœ•π»π‘§ πœ•π‘₯ Hy =βˆ’ 𝑗 kcΒ² 𝛽 πœ•π»π‘§ πœ•π‘¦ TM Mode. Transverse magnetic: the magnetic fields is cross to the direction of propagation, hence EZβ‰ 0 but HZ=0. The above expression becomes. Hx = 𝑗 kcΒ² πœ”Ι› πœ•πΈπ‘§ πœ•π‘¦ Hy =βˆ’ 𝑗 kcΒ² πœ”Ι› πœ•πΈπ‘§ πœ•π‘₯ Ex =βˆ’ 𝑗 kcΒ² 𝛽 πœ•πΈπ‘§ πœ•π‘₯ Ey =βˆ’ 𝑗 kcΒ² 𝛽 πœ•πΈπ‘§ πœ•π‘¦ TEM Mode The E and H are both transverse i.e. perpendicular to the direction of propagation, both EZ and HZ are zero. HX, HY, EX and Ey do not exist.
  • 14. The waveguides that can propagate TEM should have two lines for instance coaxial, microstrip and coplanar. Types of waveguides. There are several types classified according to the following features. ο‚· Number of lines. ο‚· Material –conductor, dielectric. ο‚· Types of modes of propagation TE, TM, TEM, and hybrid. ο‚· Cut of frequency. ο‚· Shape: Rectangular, Cylindrical and Elliptical. ο‚· Material type. Level of permittivity. ο‚· Technology. Based on the above, the types includes: ο‚· Metallic waveguides. ο‚· Metallic TEM and quasi TEM. ο‚· Dielectric. Metallic waveguides. Are constructed from metallic material, are in different shapes including: 1. Rectangular. Supports TE and TM but not TEM. It’s has a cut off frequency. 2. Cylindrical. The face is circular with a given length, radius is the main consideration in its design. R Diagram. Supports TE and TM. 3. Elliptical. Width
  • 15. Diagram. Supports TE and TM. Quasi TEM. Have more than a single line. Includes: ο‚· Coaxial, ο‚· Strip-line ο‚· Coaxial rectangular. Coaxial. Inner core. Outer conductor insulator Diagram It has an inner core, conductor that is insulated and separated from the outer conductor. At the top there is an insulator referred as outer jacket. The two radii, inner and outer radii, are considered is its design. Coaxial rectangular. Has rectangular dimensions.
  • 16. Inner core. Outer conductor dielectric Diagram. Strip-line Construction. Ground w b Ι›α΅£ Strip-line Diagram. Constructed by etching a conductor with width of W on a dielectric material with Ι›r in the middle of the dielectric as shown above. The most important parameter are the width of the conductor (w) and the height of the dielectric (b). The conductor appears at 𝑏 2 distance from either side upper or lower. This parameter b and w will directly affect the capacitive and inductive properties of the line which together with Ι›r also affects the plane, group velocities, propagation constant and the impedance of the device. Vg = 𝑐 βˆšΙ›α΅£ c- Velocity of light. The fields will appear as follows.
  • 17. Diagram. It supports TEM mode. Other lines include. ο‚· Slot lone ο‚· Coplanar. ο‚· Microstrip. Microstrip line. microstrip Diagram. Constructed by etching a conductor at the top of a dielectric material with a ground running across the bottom of the dielectric. The important parameter include w-width of the line, b the separation between the ground and the line and the dielectric material constant Ι›r. These will affect capacitive and inductive properties as well as vp, vg, πœ‚ and 𝛽. The fields are given by Diagram. Impedance matching two port network. NW 2 NW 1 High impedance Low impedance Connecting in this form causes reflection of signal, it should be connected as below.
  • 18. NW 2 NW 1 High impedance Low impedance Transistor can be used for impedance matching. Covered microstrip. Similar to the microstrip the difference being that strip is covered. Cover (dielectric material) microstrip Diagram. The cover has an effect which can be negative in that it can introduce losses. Slot line. Construction. Slot line Diagram. Constructed by etching a metallic material at the top of the dielectric creating a section without the conductor, this forms the slot. Coplanar.
  • 19. Construction. Has two slots. Diagram. Obtained by etching two sessions on a metal conductor then coating done on dielectric. Additional devices. οƒΌ Ridge waveguides. οƒΌ Dielectric waveguides. i) Fiber waveguide. ii) Plain dielectric. Ridge waveguide. Ridges are developed by a dielectric material. Ridges (ɛᡣ₁ ) Diagram Ridges are developed on a dielectric material. Fiber waveguide. Construction. Ι›β‚‚ ɛ₁
  • 20. Diagram. It developed from two materials with different dielectric properties. Reflection and refraction can be principles can be applied in their applications. Plain dielectric. Ι›α΅£ Diagram. Developed using single material type with specific dielectric properties. Supports TE and TM. Active Microwave devices. Require power to operate and can increase the strength of a signal actually includes electronics devices semiconductor, Diodes, Transistors, Integrated circuits. Diodes. Types:- ο‚· Schotty diode. ο‚· PIN diode. ο‚· Tunnel diode. Transistors include BJT, FETs. Integrated circuits includes: οƒΌ BJT based technology οƒΌ FET based technology. Others are; semiconductor resistor and capacitor. Exercise. 1. Derive the cut-off frequency for all the above waveguides discussed. Obtain: vp, vg, impedance (πœ‚), propagation constant (𝛽), for all the waveguide above.
  • 21. 2. Discuss the different active microwave devices. Discussion should include: definition, symbol, construction, features, operation and applications. 3. Do the same for passive microwave devices.