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1
Mendelelian
Genetics
copyright cmassengale
2
Gregor Mendel
(1822-1884)
Responsible
for the Laws
governing
Inheritance of
Traits
copyright cmassengale
3
Gregor Johann Mendel
Austrian monk
Studied the
inheritance of
traits in pea plants
Developed the laws
of inheritance
Mendel's work was
not recognized until
the turn of the
20th century
copyright cmassengale
4
Gregor Johann Mendel
Between 1856 and
1863, Mendel
cultivated and
tested some 28,000
pea plants
He found that the
plants' offspring
retained traits of
the parents
Called the “Father
of Genetics"
copyright cmassengale
5
Site of
Gregor
Mendel’s
experimental
garden in the
Czech
Republic
copyright cmassengale
6
Mendel stated that
physical traits are
inherited as “particles”
Mendel did not know
that the “particles”
were actually
Chromosomes & DNA
Particulate Inheritance
copyright cmassengale
7
Genetic Terminology
 Trait - any characteristic that
can be passed from parent to
offspring
 Heredity - passing of traits
from parent to offspring
 Genetics - study of heredity
copyright cmassengale
8
Types of Genetic Crosses
 Monohybrid cross - cross
involving a single trait
e.g. flower color
 Dihybrid cross - cross involving
two traits
e.g. flower color & plant height
copyright cmassengale
9
Punnett Square
Used to help
solve genetics
problems
copyright cmassengale
10
copyright cmassengale
11
Designer “Genes”
 Alleles - two forms of a gene
(dominant & recessive)
 Dominant - stronger of two genes
expressed in the hybrid;
represented by a capital letter (R)
 Recessive - gene that shows up less
often in a cross; represented by a
lowercase letter (r)
copyright cmassengale
12
More Terminology
 Genotype - gene combination
for a trait (e.g. RR, Rr, rr)
 Phenotype - the physical
feature resulting from a
genotype (e.g. red, white)
copyright cmassengale
13
Genotype & Phenotype in Flowers
Genotype of alleles:
R = red flower
r = yellow flower
All genes occur in pairs, so 2
alleles affect a characteristic
Possible combinations are:
Genotypes RR Rr rr
Phenotypes RED RED YELLOW
copyright cmassengale
14
Genotypes
 Homozygous genotype - gene
combination involving 2 dominant
or 2 recessive genes (e.g. RR or
rr); also called pure
 Heterozygous genotype - gene
combination of one dominant &
one recessive allele (e.g. Rr);
also called hybrid
copyright cmassengale
15
Genes and Environment
Determine Characteristics
copyright cmassengale
16
Mendel’s Pea Plant
Experiments
copyright cmassengale
17
Why peas, Pisum sativum?
Can be grown in a
small area
Produce lots of
offspring
Produce pure plants
when allowed to
self-pollinate
several generations
Can be artificially
cross-pollinated
copyright cmassengale
18
Reproduction in Flowering Plants
Pollen contains sperm
Produced by the
stamen
Ovary contains eggs
Found inside the
flower
Pollen carries sperm to the
eggs for fertilization
Self-fertilization can
occur in the same flower
Cross-fertilization can
occur between flowers
copyright cmassengale
19
Mendel’s Experimental
Methods
Mendel hand-pollinated
flowers using a paintbrush
He could snip the
stamens to prevent
self-pollination
Covered each flower
with a cloth bag
He traced traits through
the several generations
copyright cmassengale
20
How Mendel Began
Mendel
produced
pure
strains by
allowing the
plants to
self-
pollinate
for several
generations
copyright cmassengale
21
Eight Pea Plant Traits
Seed shape --- Round (R) or Wrinkled (r)
Seed Color ---- Yellow (Y) or Green (y)
Pod Shape --- Smooth (S) or wrinkled (s)
Pod Color --- Green (G) or Yellow (g)
Seed Coat Color ---Gray (G) or White (g)
Flower position---Axial (A) or Terminal (a)
Plant Height --- Tall (T) or Short (t)
Flower color --- Purple (P) or white (p)
copyright cmassengale
22
copyright cmassengale
23
copyright cmassengale
24
Mendel’s Experimental Results
copyright cmassengale
25
Did the observed ratio match
the theoretical ratio?
The theoretical or expected ratio of
plants producing round or wrinkled seeds
is 3 round :1 wrinkled
Mendel’s observed ratio was 2.96:1
The discrepancy is due to statistical
error
The larger the sample the more nearly
the results approximate to the
theoretical ratio
copyright cmassengale
26
Generation “Gap”
Parental P1 Generation = the parental
generation in a breeding experiment.
F1 generation = the first-generation
offspring in a breeding experiment. (1st
filial generation)
From breeding individuals from the P1
generation
F2 generation = the second-generation
offspring in a breeding experiment.
(2nd filial generation)
From breeding individuals from the F1
generation
copyright cmassengale
27
Following the Generations
Cross 2
Pure
Plants
TT x tt
Results
in all
Hybrids
Tt
Cross 2 Hybrids
get
3 Tall & 1 Short
TT, Tt, tt
copyright cmassengale
28
Monohybrid
Crosses
copyright cmassengale
29
Trait: Seed Shape
Alleles: R – Round r – Wrinkled
Cross: Round seeds x Wrinkled seeds
RR x rr
P1 Monohybrid Cross
R
R
r
r
Rr
Rr
Rr
Rr
Genotype: Rr
Phenotype: Round
Genotypic
Ratio: All alike
Phenotypic
Ratio: All alike
copyright cmassengale
30
P1 Monohybrid Cross Review
 Homozygous dominant x Homozygous
recessive
 Offspring all Heterozygous
(hybrids)
 Offspring called F1 generation
 Genotypic & Phenotypic ratio is ALL
ALIKE
copyright cmassengale
31
Trait: Seed Shape
Alleles: R – Round r – Wrinkled
Cross: Round seeds x Round seeds
Rr x Rr
F1 Monohybrid Cross
R
r
r
R
RR
rr
Rr
Rr
Genotype: RR, Rr, rr
Phenotype: Round &
wrinkled
G.Ratio: 1:2:1
P.Ratio: 3:1
copyright cmassengale
32
F1 Monohybrid Cross Review
 Heterozygous x heterozygous
 Offspring:
25% Homozygous dominant RR
50% Heterozygous Rr
25% Homozygous Recessive rr
 Offspring called F2 generation
 Genotypic ratio is 1:2:1
 Phenotypic Ratio is 3:1
copyright cmassengale
33
What Do the Peas Look Like?
copyright cmassengale
34
…And Now the Test Cross
Mendel then crossed a pure & a
hybrid from his F2 generation
This is known as an F2 or test
cross
There are two possible
testcrosses:
Homozygous dominant x Hybrid
Homozygous recessive x Hybrid
copyright cmassengale
35
Trait: Seed Shape
Alleles: R – Round r – Wrinkled
Cross: Round seeds x Round seeds
RR x Rr
F2 Monohybrid Cross (1st)
R
R
r
R
RR
Rr
RR
Rr
Genotype: RR, Rr
Phenotype: Round
Genotypic
Ratio: 1:1
Phenotypic
Ratio: All alike
copyright cmassengale
36
Trait: Seed Shape
Alleles: R – Round r – Wrinkled
Cross: Wrinkled seeds x Round seeds
rr x Rr
F2 Monohybrid Cross (2nd)
r
r
r
R
Rr
rr
Rr
rr
Genotype: Rr, rr
Phenotype: Round &
Wrinkled
G. Ratio: 1:1
P.Ratio: 1:1
copyright cmassengale
37
F2 Monohybrid Cross Review
 Homozygous x heterozygous(hybrid)
 Offspring:
50% Homozygous RR or rr
50% Heterozygous Rr
 Phenotypic Ratio is 1:1
 Called Test Cross because the
offspring have SAME genotype as
parents
copyright cmassengale
38
Practice Your Crosses
Work the P1, F1, and both
F2 Crosses for each of the
other Seven Pea Plant
Traits
copyright cmassengale
39
Mendel’s Laws
copyright cmassengale
40
Results of Monohybrid Crosses
Inheritable factors or genes are
responsible for all heritable
characteristics
Phenotype is based on Genotype
Each trait is based on two genes,
one from the mother and the
other from the father
True-breeding individuals are
homozygous ( both alleles) are the
same
copyright cmassengale
41
Law of Dominance
In a cross of parents that are
pure for contrasting traits, only
one form of the trait will appear in
the next generation.
All the offspring will be
heterozygous and express only the
dominant trait.
RR x rr yields all Rr (round seeds)
copyright cmassengale
42
Law of Dominance
copyright cmassengale
43
Law of Segregation
During the formation of gametes
(eggs or sperm), the two alleles
responsible for a trait separate
from each other.
Alleles for a trait are then
"recombined" at fertilization,
producing the genotype for the
traits of the offspring.
copyright cmassengale
44
Applying the Law of Segregation
copyright cmassengale
45
Law of Independent
Assortment
Alleles for different traits are
distributed to sex cells (&
offspring) independently of one
another.
This law can be illustrated using
dihybrid crosses.
copyright cmassengale
46
Dihybrid Cross
A breeding experiment that tracks
the inheritance of two traits.
Mendel’s “Law of Independent
Assortment”
a. Each pair of alleles segregates
independently during gamete formation
b. Formula: 2n (n = # of heterozygotes)
copyright cmassengale
47
Question:
How many gametes will be produced
for the following allele arrangements?
Remember: 2n (n = # of heterozygotes)
1. RrYy
2. AaBbCCDd
3. MmNnOoPPQQRrssTtQq
copyright cmassengale
48
Answer:
1. RrYy: 2n = 22 = 4 gametes
RY Ry rY ry
2. AaBbCCDd: 2n = 23 = 8 gametes
ABCD ABCd AbCD AbCd
aBCD aBCd abCD abCD
3. MmNnOoPPQQRrssTtQq: 2n = 26 = 64
gametes
copyright cmassengale
49
Dihybrid Cross
Traits: Seed shape & Seed color
Alleles: R round
r wrinkled
Y yellow
y green
RrYy x RrYy
RY Ry rY ry RY Ry rY ry
All possible gamete combinations
copyright cmassengale
50
Dihybrid Cross
RY Ry rY ry
RY
Ry
rY
ry
copyright cmassengale
51
Dihybrid Cross
RRYY
RRYy
RrYY
RrYy
RRYy
RRyy
RrYy
Rryy
RrYY
RrYy
rrYY
rrYy
RrYy
Rryy
rrYy
rryy
Round/Yellow: 9
Round/green: 3
wrinkled/Yellow: 3
wrinkled/green: 1
9:3:3:1 phenotypic
ratio
RY Ry rY ry
RY
Ry
rY
ry
copyright cmassengale
52
Dihybrid Cross
Round/Yellow: 9
Round/green: 3
wrinkled/Yellow: 3
wrinkled/green: 1
9:3:3:1
copyright cmassengale
53
Test Cross
A mating between an individual of unknown
genotype and a homozygous recessive
individual.
Example: bbC__ x bbcc
BB = brown eyes
Bb = brown eyes
bb = blue eyes
CC = curly hair
Cc = curly hair
cc = straight hair
bC b___
bc
copyright cmassengale
54
Test Cross
Possible results:
bC b___
bc bbCc bbCc
C bC b___
bc bbCc bbcc
or
c
copyright cmassengale
55
Summary of Mendel’s laws
LAW
PARENT
CROSS
OFFSPRING
DOMINANCE TT x tt
tall x short
100% Tt
tall
SEGREGATION
Tt x Tt
tall x tall
75% tall
25% short
INDEPENDENT
ASSORTMENT
RrGg x RrGg
round & green
x
round & green
9/16 round seeds & green
pods
3/16 round seeds & yellow
pods
3/16 wrinkled seeds & green
pods
1/16 wrinkled seeds & yellow
pods
copyright cmassengale
56
Incomplete Dominance
and
Codominance
copyright cmassengale
57
Incomplete Dominance
F1 hybrids have an appearance somewhat
in between the phenotypes of the two
parental varieties.
Example: snapdragons (flower)
red (RR) x white (rr)
RR = red flower
rr = white flower
R
R
r r
copyright cmassengale
58
Incomplete Dominance
Rr
Rr
Rr
Rr
R
R
r
All Rr = pink
(heterozygous pink)
produces the
F1 generation
r
copyright cmassengale
59
Incomplete Dominance
copyright cmassengale
60
Codominance
Two alleles are expressed (multiple
alleles) in heterozygous individuals.
Example: blood type
1. type A = IAIA or IAi
2. type B = IBIB or IBi
3. type AB = IAIB
4. type O = ii
copyright cmassengale
61
Codominance Problem
Example:homozygous male Type B (IBIB)
x
heterozygous female Type A (IAi)
IAIB IBi
IAIB IBi
1/2 = IAIB
1/2 = IBi
IB
IA i
IB
copyright cmassengale
62
Another Codominance Problem
• Example: male Type O (ii)
x
female type AB (IAIB)
IAi IBi
IAi IBi
1/2 = IAi
1/2 = IBi
i
IA IB
i
copyright cmassengale
63
Codominance
Question:
If a boy has a blood type O and
his sister has blood type
AB, what are the genotypes
and phenotypes of their
parents?
boy - type O (ii) X girl - type
AB (IAIB)
copyright cmassengale
64
Codominance
Answer:
IAIB
ii
Parents:
genotypes = IAi and IBi
phenotypes = A and B
IB
IA i
i
copyright cmassengale
65
Sex-linked Traits
Traits (genes) located on the sex
chromosomes
Sex chromosomes are X and Y
XX genotype for females
XY genotype for males
Many sex-linked traits carried on
X chromosome
copyright cmassengale
66
Sex-linked Traits
Sex Chromosomes
XX chromosome - female Xy chromosome - male
fruit fly
eye color
Example: Eye color in fruit flies
copyright cmassengale
67
Sex-linked Trait Problem
Example: Eye color in fruit flies
(red-eyed male) x (white-eyed female)
XRY x XrXr
Remember: the Y chromosome in males
does not carry traits.
RR = red eyed
Rr = red eyed
rr = white eyed
XY = male
XX = female
XR
Xr Xr
Y
copyright cmassengale
68
Sex-linked Trait Solution:
XR Xr
Xr Y
XR Xr
Xr Y
50% red eyed
female
50% white eyed
male
XR
Xr Xr
Y
copyright cmassengale
69
Female Carriers
copyright cmassengale
70
Genetic Practice
Problems
copyright cmassengale
71
Breed the P1 generation
tall (TT) x dwarf (tt) pea plants
T
T
t t
copyright cmassengale
72
Solution:
T
T
t t
Tt
Tt
Tt
Tt All Tt = tall
(heterozygous tall)
produces the
F1 generation
tall (TT) vs. dwarf (tt) pea plants
copyright cmassengale
73
Breed the F1 generation
tall (Tt) vs. tall (Tt) pea plants
T
t
T t
copyright cmassengale
74
Solution:
TT
Tt
Tt
tt
T
t
T t
produces the
F2 generation
1/4 (25%) = TT
1/2 (50%) = Tt
1/4 (25%) = tt
1:2:1 genotype
3:1 phenotype
tall (Tt) x tall (Tt) pea plants
copyright cmassengale
75
copyright cmassengale

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Mendelian_Genetics Variation_and_Inheritance.ppt

  • 2. 2 Gregor Mendel (1822-1884) Responsible for the Laws governing Inheritance of Traits copyright cmassengale
  • 3. 3 Gregor Johann Mendel Austrian monk Studied the inheritance of traits in pea plants Developed the laws of inheritance Mendel's work was not recognized until the turn of the 20th century copyright cmassengale
  • 4. 4 Gregor Johann Mendel Between 1856 and 1863, Mendel cultivated and tested some 28,000 pea plants He found that the plants' offspring retained traits of the parents Called the “Father of Genetics" copyright cmassengale
  • 5. 5 Site of Gregor Mendel’s experimental garden in the Czech Republic copyright cmassengale
  • 6. 6 Mendel stated that physical traits are inherited as “particles” Mendel did not know that the “particles” were actually Chromosomes & DNA Particulate Inheritance copyright cmassengale
  • 7. 7 Genetic Terminology  Trait - any characteristic that can be passed from parent to offspring  Heredity - passing of traits from parent to offspring  Genetics - study of heredity copyright cmassengale
  • 8. 8 Types of Genetic Crosses  Monohybrid cross - cross involving a single trait e.g. flower color  Dihybrid cross - cross involving two traits e.g. flower color & plant height copyright cmassengale
  • 9. 9 Punnett Square Used to help solve genetics problems copyright cmassengale
  • 11. 11 Designer “Genes”  Alleles - two forms of a gene (dominant & recessive)  Dominant - stronger of two genes expressed in the hybrid; represented by a capital letter (R)  Recessive - gene that shows up less often in a cross; represented by a lowercase letter (r) copyright cmassengale
  • 12. 12 More Terminology  Genotype - gene combination for a trait (e.g. RR, Rr, rr)  Phenotype - the physical feature resulting from a genotype (e.g. red, white) copyright cmassengale
  • 13. 13 Genotype & Phenotype in Flowers Genotype of alleles: R = red flower r = yellow flower All genes occur in pairs, so 2 alleles affect a characteristic Possible combinations are: Genotypes RR Rr rr Phenotypes RED RED YELLOW copyright cmassengale
  • 14. 14 Genotypes  Homozygous genotype - gene combination involving 2 dominant or 2 recessive genes (e.g. RR or rr); also called pure  Heterozygous genotype - gene combination of one dominant & one recessive allele (e.g. Rr); also called hybrid copyright cmassengale
  • 15. 15 Genes and Environment Determine Characteristics copyright cmassengale
  • 17. 17 Why peas, Pisum sativum? Can be grown in a small area Produce lots of offspring Produce pure plants when allowed to self-pollinate several generations Can be artificially cross-pollinated copyright cmassengale
  • 18. 18 Reproduction in Flowering Plants Pollen contains sperm Produced by the stamen Ovary contains eggs Found inside the flower Pollen carries sperm to the eggs for fertilization Self-fertilization can occur in the same flower Cross-fertilization can occur between flowers copyright cmassengale
  • 19. 19 Mendel’s Experimental Methods Mendel hand-pollinated flowers using a paintbrush He could snip the stamens to prevent self-pollination Covered each flower with a cloth bag He traced traits through the several generations copyright cmassengale
  • 20. 20 How Mendel Began Mendel produced pure strains by allowing the plants to self- pollinate for several generations copyright cmassengale
  • 21. 21 Eight Pea Plant Traits Seed shape --- Round (R) or Wrinkled (r) Seed Color ---- Yellow (Y) or Green (y) Pod Shape --- Smooth (S) or wrinkled (s) Pod Color --- Green (G) or Yellow (g) Seed Coat Color ---Gray (G) or White (g) Flower position---Axial (A) or Terminal (a) Plant Height --- Tall (T) or Short (t) Flower color --- Purple (P) or white (p) copyright cmassengale
  • 25. 25 Did the observed ratio match the theoretical ratio? The theoretical or expected ratio of plants producing round or wrinkled seeds is 3 round :1 wrinkled Mendel’s observed ratio was 2.96:1 The discrepancy is due to statistical error The larger the sample the more nearly the results approximate to the theoretical ratio copyright cmassengale
  • 26. 26 Generation “Gap” Parental P1 Generation = the parental generation in a breeding experiment. F1 generation = the first-generation offspring in a breeding experiment. (1st filial generation) From breeding individuals from the P1 generation F2 generation = the second-generation offspring in a breeding experiment. (2nd filial generation) From breeding individuals from the F1 generation copyright cmassengale
  • 27. 27 Following the Generations Cross 2 Pure Plants TT x tt Results in all Hybrids Tt Cross 2 Hybrids get 3 Tall & 1 Short TT, Tt, tt copyright cmassengale
  • 29. 29 Trait: Seed Shape Alleles: R – Round r – Wrinkled Cross: Round seeds x Wrinkled seeds RR x rr P1 Monohybrid Cross R R r r Rr Rr Rr Rr Genotype: Rr Phenotype: Round Genotypic Ratio: All alike Phenotypic Ratio: All alike copyright cmassengale
  • 30. 30 P1 Monohybrid Cross Review  Homozygous dominant x Homozygous recessive  Offspring all Heterozygous (hybrids)  Offspring called F1 generation  Genotypic & Phenotypic ratio is ALL ALIKE copyright cmassengale
  • 31. 31 Trait: Seed Shape Alleles: R – Round r – Wrinkled Cross: Round seeds x Round seeds Rr x Rr F1 Monohybrid Cross R r r R RR rr Rr Rr Genotype: RR, Rr, rr Phenotype: Round & wrinkled G.Ratio: 1:2:1 P.Ratio: 3:1 copyright cmassengale
  • 32. 32 F1 Monohybrid Cross Review  Heterozygous x heterozygous  Offspring: 25% Homozygous dominant RR 50% Heterozygous Rr 25% Homozygous Recessive rr  Offspring called F2 generation  Genotypic ratio is 1:2:1  Phenotypic Ratio is 3:1 copyright cmassengale
  • 33. 33 What Do the Peas Look Like? copyright cmassengale
  • 34. 34 …And Now the Test Cross Mendel then crossed a pure & a hybrid from his F2 generation This is known as an F2 or test cross There are two possible testcrosses: Homozygous dominant x Hybrid Homozygous recessive x Hybrid copyright cmassengale
  • 35. 35 Trait: Seed Shape Alleles: R – Round r – Wrinkled Cross: Round seeds x Round seeds RR x Rr F2 Monohybrid Cross (1st) R R r R RR Rr RR Rr Genotype: RR, Rr Phenotype: Round Genotypic Ratio: 1:1 Phenotypic Ratio: All alike copyright cmassengale
  • 36. 36 Trait: Seed Shape Alleles: R – Round r – Wrinkled Cross: Wrinkled seeds x Round seeds rr x Rr F2 Monohybrid Cross (2nd) r r r R Rr rr Rr rr Genotype: Rr, rr Phenotype: Round & Wrinkled G. Ratio: 1:1 P.Ratio: 1:1 copyright cmassengale
  • 37. 37 F2 Monohybrid Cross Review  Homozygous x heterozygous(hybrid)  Offspring: 50% Homozygous RR or rr 50% Heterozygous Rr  Phenotypic Ratio is 1:1  Called Test Cross because the offspring have SAME genotype as parents copyright cmassengale
  • 38. 38 Practice Your Crosses Work the P1, F1, and both F2 Crosses for each of the other Seven Pea Plant Traits copyright cmassengale
  • 40. 40 Results of Monohybrid Crosses Inheritable factors or genes are responsible for all heritable characteristics Phenotype is based on Genotype Each trait is based on two genes, one from the mother and the other from the father True-breeding individuals are homozygous ( both alleles) are the same copyright cmassengale
  • 41. 41 Law of Dominance In a cross of parents that are pure for contrasting traits, only one form of the trait will appear in the next generation. All the offspring will be heterozygous and express only the dominant trait. RR x rr yields all Rr (round seeds) copyright cmassengale
  • 43. 43 Law of Segregation During the formation of gametes (eggs or sperm), the two alleles responsible for a trait separate from each other. Alleles for a trait are then "recombined" at fertilization, producing the genotype for the traits of the offspring. copyright cmassengale
  • 44. 44 Applying the Law of Segregation copyright cmassengale
  • 45. 45 Law of Independent Assortment Alleles for different traits are distributed to sex cells (& offspring) independently of one another. This law can be illustrated using dihybrid crosses. copyright cmassengale
  • 46. 46 Dihybrid Cross A breeding experiment that tracks the inheritance of two traits. Mendel’s “Law of Independent Assortment” a. Each pair of alleles segregates independently during gamete formation b. Formula: 2n (n = # of heterozygotes) copyright cmassengale
  • 47. 47 Question: How many gametes will be produced for the following allele arrangements? Remember: 2n (n = # of heterozygotes) 1. RrYy 2. AaBbCCDd 3. MmNnOoPPQQRrssTtQq copyright cmassengale
  • 48. 48 Answer: 1. RrYy: 2n = 22 = 4 gametes RY Ry rY ry 2. AaBbCCDd: 2n = 23 = 8 gametes ABCD ABCd AbCD AbCd aBCD aBCd abCD abCD 3. MmNnOoPPQQRrssTtQq: 2n = 26 = 64 gametes copyright cmassengale
  • 49. 49 Dihybrid Cross Traits: Seed shape & Seed color Alleles: R round r wrinkled Y yellow y green RrYy x RrYy RY Ry rY ry RY Ry rY ry All possible gamete combinations copyright cmassengale
  • 50. 50 Dihybrid Cross RY Ry rY ry RY Ry rY ry copyright cmassengale
  • 51. 51 Dihybrid Cross RRYY RRYy RrYY RrYy RRYy RRyy RrYy Rryy RrYY RrYy rrYY rrYy RrYy Rryy rrYy rryy Round/Yellow: 9 Round/green: 3 wrinkled/Yellow: 3 wrinkled/green: 1 9:3:3:1 phenotypic ratio RY Ry rY ry RY Ry rY ry copyright cmassengale
  • 52. 52 Dihybrid Cross Round/Yellow: 9 Round/green: 3 wrinkled/Yellow: 3 wrinkled/green: 1 9:3:3:1 copyright cmassengale
  • 53. 53 Test Cross A mating between an individual of unknown genotype and a homozygous recessive individual. Example: bbC__ x bbcc BB = brown eyes Bb = brown eyes bb = blue eyes CC = curly hair Cc = curly hair cc = straight hair bC b___ bc copyright cmassengale
  • 54. 54 Test Cross Possible results: bC b___ bc bbCc bbCc C bC b___ bc bbCc bbcc or c copyright cmassengale
  • 55. 55 Summary of Mendel’s laws LAW PARENT CROSS OFFSPRING DOMINANCE TT x tt tall x short 100% Tt tall SEGREGATION Tt x Tt tall x tall 75% tall 25% short INDEPENDENT ASSORTMENT RrGg x RrGg round & green x round & green 9/16 round seeds & green pods 3/16 round seeds & yellow pods 3/16 wrinkled seeds & green pods 1/16 wrinkled seeds & yellow pods copyright cmassengale
  • 57. 57 Incomplete Dominance F1 hybrids have an appearance somewhat in between the phenotypes of the two parental varieties. Example: snapdragons (flower) red (RR) x white (rr) RR = red flower rr = white flower R R r r copyright cmassengale
  • 58. 58 Incomplete Dominance Rr Rr Rr Rr R R r All Rr = pink (heterozygous pink) produces the F1 generation r copyright cmassengale
  • 60. 60 Codominance Two alleles are expressed (multiple alleles) in heterozygous individuals. Example: blood type 1. type A = IAIA or IAi 2. type B = IBIB or IBi 3. type AB = IAIB 4. type O = ii copyright cmassengale
  • 61. 61 Codominance Problem Example:homozygous male Type B (IBIB) x heterozygous female Type A (IAi) IAIB IBi IAIB IBi 1/2 = IAIB 1/2 = IBi IB IA i IB copyright cmassengale
  • 62. 62 Another Codominance Problem • Example: male Type O (ii) x female type AB (IAIB) IAi IBi IAi IBi 1/2 = IAi 1/2 = IBi i IA IB i copyright cmassengale
  • 63. 63 Codominance Question: If a boy has a blood type O and his sister has blood type AB, what are the genotypes and phenotypes of their parents? boy - type O (ii) X girl - type AB (IAIB) copyright cmassengale
  • 64. 64 Codominance Answer: IAIB ii Parents: genotypes = IAi and IBi phenotypes = A and B IB IA i i copyright cmassengale
  • 65. 65 Sex-linked Traits Traits (genes) located on the sex chromosomes Sex chromosomes are X and Y XX genotype for females XY genotype for males Many sex-linked traits carried on X chromosome copyright cmassengale
  • 66. 66 Sex-linked Traits Sex Chromosomes XX chromosome - female Xy chromosome - male fruit fly eye color Example: Eye color in fruit flies copyright cmassengale
  • 67. 67 Sex-linked Trait Problem Example: Eye color in fruit flies (red-eyed male) x (white-eyed female) XRY x XrXr Remember: the Y chromosome in males does not carry traits. RR = red eyed Rr = red eyed rr = white eyed XY = male XX = female XR Xr Xr Y copyright cmassengale
  • 68. 68 Sex-linked Trait Solution: XR Xr Xr Y XR Xr Xr Y 50% red eyed female 50% white eyed male XR Xr Xr Y copyright cmassengale
  • 71. 71 Breed the P1 generation tall (TT) x dwarf (tt) pea plants T T t t copyright cmassengale
  • 72. 72 Solution: T T t t Tt Tt Tt Tt All Tt = tall (heterozygous tall) produces the F1 generation tall (TT) vs. dwarf (tt) pea plants copyright cmassengale
  • 73. 73 Breed the F1 generation tall (Tt) vs. tall (Tt) pea plants T t T t copyright cmassengale
  • 74. 74 Solution: TT Tt Tt tt T t T t produces the F2 generation 1/4 (25%) = TT 1/2 (50%) = Tt 1/4 (25%) = tt 1:2:1 genotype 3:1 phenotype tall (Tt) x tall (Tt) pea plants copyright cmassengale

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