Match the words in the left column to the appropriate blanks in the se.docx
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Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. Reset Help hydrogen bonding influences Given the molecules phosgene (Cl2 CO) and formaldehyde (H2CO). has the higher reduced polarity and strongerboiling point mainly due to dispersion forces phosgene (C2 CO) its greater molar mass and Given the molecules sulfur dioxide (SO2) and sulfur trioxide (SOs). has the higher boiling point mainly due to stronger dispersion forces sulfur dioxide (SO2) molecule shape and stronger dipole-dipole interactions sulfur trioxide (SOs) formaldehyde (H2CO) Solution 1. Phosgene has the higher boiling point than formaldehyde. This is mainly due to phosgene\'s (Cl2CO) greater molar mass and stronger dispersion forces. Explanation: For molecules that do not participate in hydrogen bonding, the majority of the attraction between those molecules is due to London dispersion forces. Even though dipole-dipole interactions are stronger, they apply to specific orientations of the interacting molecules. The ability to form an instantaneous dipole is referred to as polarizability. Molecules that are more polarizable, owing to their size and number of electrons, experience greater intermolecular attractions because those interactions are much less dependent on the molecular orientations. 2. Sulfur trioxide (SO3) has a higher boiling point than sulfur dioxide (SO2) mainly due to its greater molar mass and stronger dispersion forces. Explanation: There can be multiple types of interactions that occur between molecules, but comparing the boiling points of substances should mostly be based on polarizability (with the exception of hydrogen bonding). Both sulfur trioxide and phosgene would experience much greater attractions due to London dispersion forces than sulfur dioxide and formaldehyde, respectively. The contributions of dipole-dipole interactions in sulfur dioxide and formaldehyde are too insignificant in both cases. .
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Hi!For hydrogen fluoride the predominant intermolecular force is .pdf
Hi!
For hydrogen fluoride: the predominant intermolecular force is hydrogen bonding. In hydrogen
bonding, fluorine acts as a \"bridge\" (the middle atom) between two hydrogen molecules. The
only other atoms that can participate in hydrogen bonding are nitrogen, oxygen and sulfur. The
other intermolecular forces are present in hydrogen fluoride as well, but they are not as
significant as hydrogen bonding.
For carbon tetrafluoride: the predominant intermolecular force is dispersion (also called London
dispersion or van der waals forces) due to the fact that this is a non-polar, symmetrical molecule
and the difference in electronegativity between carbon and hydrogen is not great enough for the
bond to be considered truly polar.
For hydrogen chloride: the predominant intermolecular force is dipole-dipole. Chlorine cannot
participate in hydrogen bonding, however, the chlorine atom has a considerable difference in
electronegativity relative to hydrogen so the covalent bond is considered polar. There are also
dispersion forces present, but they are not as significant as the dipole-dipole forces here.
I hope this helps! Please don\'t forget to rate : )
Solution
Hi!
For hydrogen fluoride: the predominant intermolecular force is hydrogen bonding. In hydrogen
bonding, fluorine acts as a \"bridge\" (the middle atom) between two hydrogen molecules. The
only other atoms that can participate in hydrogen bonding are nitrogen, oxygen and sulfur. The
other intermolecular forces are present in hydrogen fluoride as well, but they are not as
significant as hydrogen bonding.
For carbon tetrafluoride: the predominant intermolecular force is dispersion (also called London
dispersion or van der waals forces) due to the fact that this is a non-polar, symmetrical molecule
and the difference in electronegativity between carbon and hydrogen is not great enough for the
bond to be considered truly polar.
For hydrogen chloride: the predominant intermolecular force is dipole-dipole. Chlorine cannot
participate in hydrogen bonding, however, the chlorine atom has a considerable difference in
electronegativity relative to hydrogen so the covalent bond is considered polar. There are also
dispersion forces present, but they are not as significant as the dipole-dipole forces here.
I hope this helps! Please don\'t forget to rate : ).
Hydrogen bonding pdf.pdf
1.Weak forces of attraction
2.Concepts of Hydrogen bonding
3.Types of hydrogen bonding
4.Properties of hydrogen bond.
5.Methods of detection of hydrogen bond.
6.Importance of Hydrogen bonding.
7.Vander walls forces
a.Ion-dipole
b.Dipole-dipole
c.London forces.
8.Origin of hydrogen bonds.
9.Consequences of hydrogen bonding.
10.Ice has less density than water.
11.Intermolecular forces.
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Hi!For hydrogen fluoride the predominant intermolecular force is .pdf
Hi!
For hydrogen fluoride: the predominant intermolecular force is hydrogen bonding. In hydrogen
bonding, fluorine acts as a \"bridge\" (the middle atom) between two hydrogen molecules. The
only other atoms that can participate in hydrogen bonding are nitrogen, oxygen and sulfur. The
other intermolecular forces are present in hydrogen fluoride as well, but they are not as
significant as hydrogen bonding.
For carbon tetrafluoride: the predominant intermolecular force is dispersion (also called London
dispersion or van der waals forces) due to the fact that this is a non-polar, symmetrical molecule
and the difference in electronegativity between carbon and hydrogen is not great enough for the
bond to be considered truly polar.
For hydrogen chloride: the predominant intermolecular force is dipole-dipole. Chlorine cannot
participate in hydrogen bonding, however, the chlorine atom has a considerable difference in
electronegativity relative to hydrogen so the covalent bond is considered polar. There are also
dispersion forces present, but they are not as significant as the dipole-dipole forces here.
I hope this helps! Please don\'t forget to rate : )
Solution
Hi!
For hydrogen fluoride: the predominant intermolecular force is hydrogen bonding. In hydrogen
bonding, fluorine acts as a \"bridge\" (the middle atom) between two hydrogen molecules. The
only other atoms that can participate in hydrogen bonding are nitrogen, oxygen and sulfur. The
other intermolecular forces are present in hydrogen fluoride as well, but they are not as
significant as hydrogen bonding.
For carbon tetrafluoride: the predominant intermolecular force is dispersion (also called London
dispersion or van der waals forces) due to the fact that this is a non-polar, symmetrical molecule
and the difference in electronegativity between carbon and hydrogen is not great enough for the
bond to be considered truly polar.
For hydrogen chloride: the predominant intermolecular force is dipole-dipole. Chlorine cannot
participate in hydrogen bonding, however, the chlorine atom has a considerable difference in
electronegativity relative to hydrogen so the covalent bond is considered polar. There are also
dispersion forces present, but they are not as significant as the dipole-dipole forces here.
I hope this helps! Please don\'t forget to rate : ).
Hydrogen bonding pdf.pdf
1.Weak forces of attraction
2.Concepts of Hydrogen bonding
3.Types of hydrogen bonding
4.Properties of hydrogen bond.
5.Methods of detection of hydrogen bond.
6.Importance of Hydrogen bonding.
7.Vander walls forces
a.Ion-dipole
b.Dipole-dipole
c.London forces.
8.Origin of hydrogen bonds.
9.Consequences of hydrogen bonding.
10.Ice has less density than water.
11.Intermolecular forces.
Regarding intermolecular forces Sometimes London dispersion forces ou.docx
Regarding intermolecular forces
Sometimes London dispersion forces outweighs that of hydrogen bonding
Can someone give me a brief explanation, if one compound is packed with O-H bonds but the other molecular weights is 2x greater than the compound with O-H bonds
Regarding intermolecular forces
Sometimes London dispersion forces outweighs that of hydrogen bonding
Can someone give me a brief explanation, if one compound is packed with O-H bonds but the other molecular weights is 2x greater than the compound with O-H bonds
Sometimes London dispersion forces outweighs that of hydrogen bonding
Can someone give me a brief explanation, if one compound is packed with O-H bonds but the other molecular weights is 2x greater than the compound with O-H bonds
Solution
I think your question would be bit more different. According to your question, the answer could be as simple as water weighs less than benzene, though water has O-H bond! I think my following answer from the perspective of intermolecular force will be helpful.
London dispersion force is the weakest intermolecular force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles. This force is sometimes called an induced dipole-induced dipole attraction. London forces are the attractive forces that cause nonpolar substances to condense to liquids and to freeze into solids when the temperature is lowered sufficiently. (Several molecules aggregate due to the attractive force)
Dispersion forces are present between any two molecules (even polar molecules). Larger and heavier atoms and molecules exhibit stronger dispersion forces than smaller and lighter ones because:
In a larger atom or molecule, the valence electrons are, on average, farther from the nuclei than in a smaller atom or molecule. They are less tightly held and can more easily form temporary dipoles.
Thus whether, O-H present or not, if the molecule is sufficient large enough to show remarkable dispersion force, it could be of higher weights than O-H compounds.
.
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2- In each of the following pairs of substances- predict which one wou.docx
2. In each of the following pairs of substances, predict which one would have the higher boiling point (if done on this sheet, circle the correct answer): a) He or Ar c) GeH4 or SiH4 e) hexane or heptane b) Ar or N20 d) HF or HCI f) F2 or I2
Solution
a) He or Ar: He and Ar are both noble gases and the only kind of intermolecularforces that exist in them are the london dispersion forces.The size of the atom increases as you go down the periodic table, and so will be the number of electrons. As number of electrons increase, the polarizability also increases, resulting in greater London Dispersion forces. So Ar which is down in the group has more london dispersion forces as compared to He and hence will have ahigher boiling. Ar has a higher boiling point.
b) NO 2 or Ar: Ar, is a noble gases and the only kind of intermolecularforces that exist in Ar are the london dispersion forces. NO 2 on the other hand has a strong dipole which leads to dipole-dipole interactions along with london dispersion forces. These extra intra-molecuar forces bind NO 2 molecules together, making it difficult to break these bonds, there by leading to a higer boiling point, So NO 2 has higher boiling point.
c) GeH 4 orSiH 4: Ge is below Si in the group which means that GeH 4 has more electrons than SiH 4. Therefore GeH 4 has more London dispersion forces and hence needs more energy to break these forces; leading to higher boiling point. GeH 4 has higher boiling point.
d) HF or HCl: HF and HCl are both acids of anions from group VII (halides). However Floride is more electroegative comapred to Chloride. Being more electronegative the floirde is very strongly attracted to hydrogen than chloride would do. So it is more diffult to break an HF bond compared to HCl and hence HF has a higher boiling point.
.
The graph of temperature versus molar mass is given for the hydrides o.docx
The graph of temperature versus molar mass is given for the hydrides of oxygen, sulfur, selenium, and tellurium. The points given are the melting (Mp) and boiling (Bp) points of the hydrides.
The melting and boiling points decrease from hydrogen telluride, H2Te, to hydrogen sulfide, H2S; however, we find an abrupt increase in the melting and boiling points for water. Water shows an abrupt increase in its melting and boiling points because the water molecule has stronger intermolecular forces than the hydrides of sulfur, selenium, and tellurium.
Which of the following statements explain this anomalous behavior of water?
Check all that apply.
View Available Hint(s)
Check all that apply.
H20 HoTe Bp 25 Mp Molar mass (g/mol)
Solution
Options (b) and (c) explains the anomalous behaviour.
Due to stronger intermolecular hydrogen bonding apart from weak London forces (e.g, Vander Waals forces) that exists in other compounds also there is an abrupt increase in melting and boiling point of water. London forces are weakest forces and therefore, it requires more energy to break hydrogen bonds than to break them.
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Name four services that might allow you to control a VM in an IaaS env.docx
Name four services that might allow you to control a VM in an IaaS environment. What entity controls each service?
Solution
Four services that might allow you to control a VM in an IaaS environment
Software as a Service
Platform as a Service
Infrasrtucture as a Service
Software as a Service
Software as a Service (SaaS) delivers business processes and applications, such as CRM, collaboration, and e-mail, as standardized capabilities for a usage-based cost at an agreed, business-relevant service level. SaaS provides significant efficiencies in cost and delivery in exchange for minimal customization and represents a shift of operational risks from the consumer to the provider. All infrastructure and IT operational functions are abstracted away from the consumer.
Platform as a Service
Platform as a Service (PaaS) delivers application execution services, such as application runtime, storage, and integration, for applications written for a pre-specified development framework. PaaS provides an efficient and agile approach to operate scale-out applications in a predictable and cost-effective manner. Service levels and operational risks are shared because the consumer must take responsibility for the stability, architectural compliance, and overall operations of the application while the provider delivers the platform capability (including the infrastructure and operation al functions) at a predictable service level and cost.
Infrasrtucture as a Service
Infrastructure as a Service (IaaS) abstracts hardware (server, storage, and network infrastructure) into a pool of computing, storage, and connectivity capabilities that are delivered as services for a usage-based (metered) cost. Its goal is to provide a flexible, standard, and virtualized operating environment that can become a foundation for PaaS and SaaS.
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mus101 What musical techniques did Vivaldi use in La Primavera to depi.docx
mus101
What musical techniques did Vivaldi use in La Primavera to depict the imagery of spring? Does he continue with similar techniques in the Summer, Fall, and Winter movements? Cite one additional example in each of the movements. (PLEASE NO PLAGIARISM; PAPERS ARE GRADED THROUGH SAFE-LINK; PLEASE IN YOUR OWN WORDS, THANK YOU FOR YOUR COOPERATION) CITED AND REFERENCE.
Solution
What musical techniques did Vivaldi use in La Primavera to depict the imagery of spring?
ans)
Musical techniques used by Vivaldi in La Primavera to depict the imagery of spring are:-
---> Concerto No.1 in E Major, RV 269, \"SPRING\"
Allegro / Largo / Allegro (Pastorale dance)
-----> Allegro
Springtime is upon us.
The birds celebrate her return with festive song,
and murmuring streams are softly caressed by the breezes.
Thunderstorms, those heralds of Spring, roar, casting their dark mantle over heaven,
Then they die away to silence, and the birds take up their charming songs once more.
Largo
On the flower-strewn meadow, with leafy branches rustling overhead, the goat-herd sleeps, his faithful dog beside him.
Allegro (Pastorale dance)
Led by the festive sound of rustic bagpipes, nymphs and shepherds lightly dance beneath the brilliant canopy of spring.
Does he continue with similar techniques in the Summer, Fall, and Winter movements? Cite one additional example in each of the movements.
------>No, there is difference in techniques used by him in the Summer,Fall,Winter movements.
--->In Summer for example:-
Presto (Summer Storm) :- Alas, his worst fears were justified, as the heavens roar and great hailstones beat down upon the proudly standing corn.
---->In Fall for example:-
Adagio molto (Sleeping Drunkards):-
The singing and the dancing die away as cooling breezes fan the pleasant air,
inviting all to sleep without a care.
--->In Winter for example:-
Allegro non molto:-
Shivering, frozen mid the frosty snow in biting, stinging winds;
running to and fro to stamp one\'s icy feet, teeth chattering in the bitter chill.
.
More Related Content
Similar to Match the words in the left column to the appropriate blanks in the se.docx
Regarding intermolecular forces Sometimes London dispersion forces ou.docx
Regarding intermolecular forces
Sometimes London dispersion forces outweighs that of hydrogen bonding
Can someone give me a brief explanation, if one compound is packed with O-H bonds but the other molecular weights is 2x greater than the compound with O-H bonds
Regarding intermolecular forces
Sometimes London dispersion forces outweighs that of hydrogen bonding
Can someone give me a brief explanation, if one compound is packed with O-H bonds but the other molecular weights is 2x greater than the compound with O-H bonds
Sometimes London dispersion forces outweighs that of hydrogen bonding
Can someone give me a brief explanation, if one compound is packed with O-H bonds but the other molecular weights is 2x greater than the compound with O-H bonds
Solution
I think your question would be bit more different. According to your question, the answer could be as simple as water weighs less than benzene, though water has O-H bond! I think my following answer from the perspective of intermolecular force will be helpful.
London dispersion force is the weakest intermolecular force that results when the electrons in two adjacent atoms occupy positions that make the atoms form temporary dipoles. This force is sometimes called an induced dipole-induced dipole attraction. London forces are the attractive forces that cause nonpolar substances to condense to liquids and to freeze into solids when the temperature is lowered sufficiently. (Several molecules aggregate due to the attractive force)
Dispersion forces are present between any two molecules (even polar molecules). Larger and heavier atoms and molecules exhibit stronger dispersion forces than smaller and lighter ones because:
In a larger atom or molecule, the valence electrons are, on average, farther from the nuclei than in a smaller atom or molecule. They are less tightly held and can more easily form temporary dipoles.
Thus whether, O-H present or not, if the molecule is sufficient large enough to show remarkable dispersion force, it could be of higher weights than O-H compounds.
.
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2- In each of the following pairs of substances- predict which one wou.docx
2. In each of the following pairs of substances, predict which one would have the higher boiling point (if done on this sheet, circle the correct answer): a) He or Ar c) GeH4 or SiH4 e) hexane or heptane b) Ar or N20 d) HF or HCI f) F2 or I2
Solution
a) He or Ar: He and Ar are both noble gases and the only kind of intermolecularforces that exist in them are the london dispersion forces.The size of the atom increases as you go down the periodic table, and so will be the number of electrons. As number of electrons increase, the polarizability also increases, resulting in greater London Dispersion forces. So Ar which is down in the group has more london dispersion forces as compared to He and hence will have ahigher boiling. Ar has a higher boiling point.
b) NO 2 or Ar: Ar, is a noble gases and the only kind of intermolecularforces that exist in Ar are the london dispersion forces. NO 2 on the other hand has a strong dipole which leads to dipole-dipole interactions along with london dispersion forces. These extra intra-molecuar forces bind NO 2 molecules together, making it difficult to break these bonds, there by leading to a higer boiling point, So NO 2 has higher boiling point.
c) GeH 4 orSiH 4: Ge is below Si in the group which means that GeH 4 has more electrons than SiH 4. Therefore GeH 4 has more London dispersion forces and hence needs more energy to break these forces; leading to higher boiling point. GeH 4 has higher boiling point.
d) HF or HCl: HF and HCl are both acids of anions from group VII (halides). However Floride is more electroegative comapred to Chloride. Being more electronegative the floirde is very strongly attracted to hydrogen than chloride would do. So it is more diffult to break an HF bond compared to HCl and hence HF has a higher boiling point.
.
The graph of temperature versus molar mass is given for the hydrides o.docx
The graph of temperature versus molar mass is given for the hydrides of oxygen, sulfur, selenium, and tellurium. The points given are the melting (Mp) and boiling (Bp) points of the hydrides.
The melting and boiling points decrease from hydrogen telluride, H2Te, to hydrogen sulfide, H2S; however, we find an abrupt increase in the melting and boiling points for water. Water shows an abrupt increase in its melting and boiling points because the water molecule has stronger intermolecular forces than the hydrides of sulfur, selenium, and tellurium.
Which of the following statements explain this anomalous behavior of water?
Check all that apply.
View Available Hint(s)
Check all that apply.
H20 HoTe Bp 25 Mp Molar mass (g/mol)
Solution
Options (b) and (c) explains the anomalous behaviour.
Due to stronger intermolecular hydrogen bonding apart from weak London forces (e.g, Vander Waals forces) that exists in other compounds also there is an abrupt increase in melting and boiling point of water. London forces are weakest forces and therefore, it requires more energy to break hydrogen bonds than to break them.
.
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Chemistry of alkali and alkaline earth metals and halogen compounds including their
Pharmaceutical applications.
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A brief discussion on Chemical Bonds for hyrogen bonding, metallic bonding and dative bonding. the formation of each bonding is illustrated by using the molecular formula which shows the electrons involved in the bonding.
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Name four services that might allow you to control a VM in an IaaS env.docx
Name four services that might allow you to control a VM in an IaaS environment. What entity controls each service?
Solution
Four services that might allow you to control a VM in an IaaS environment
Software as a Service
Platform as a Service
Infrasrtucture as a Service
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Software as a Service (SaaS) delivers business processes and applications, such as CRM, collaboration, and e-mail, as standardized capabilities for a usage-based cost at an agreed, business-relevant service level. SaaS provides significant efficiencies in cost and delivery in exchange for minimal customization and represents a shift of operational risks from the consumer to the provider. All infrastructure and IT operational functions are abstracted away from the consumer.
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Platform as a Service (PaaS) delivers application execution services, such as application runtime, storage, and integration, for applications written for a pre-specified development framework. PaaS provides an efficient and agile approach to operate scale-out applications in a predictable and cost-effective manner. Service levels and operational risks are shared because the consumer must take responsibility for the stability, architectural compliance, and overall operations of the application while the provider delivers the platform capability (including the infrastructure and operation al functions) at a predictable service level and cost.
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mus101 What musical techniques did Vivaldi use in La Primavera to depi.docx
mus101
What musical techniques did Vivaldi use in La Primavera to depict the imagery of spring? Does he continue with similar techniques in the Summer, Fall, and Winter movements? Cite one additional example in each of the movements. (PLEASE NO PLAGIARISM; PAPERS ARE GRADED THROUGH SAFE-LINK; PLEASE IN YOUR OWN WORDS, THANK YOU FOR YOUR COOPERATION) CITED AND REFERENCE.
Solution
What musical techniques did Vivaldi use in La Primavera to depict the imagery of spring?
ans)
Musical techniques used by Vivaldi in La Primavera to depict the imagery of spring are:-
---> Concerto No.1 in E Major, RV 269, \"SPRING\"
Allegro / Largo / Allegro (Pastorale dance)
-----> Allegro
Springtime is upon us.
The birds celebrate her return with festive song,
and murmuring streams are softly caressed by the breezes.
Thunderstorms, those heralds of Spring, roar, casting their dark mantle over heaven,
Then they die away to silence, and the birds take up their charming songs once more.
Largo
On the flower-strewn meadow, with leafy branches rustling overhead, the goat-herd sleeps, his faithful dog beside him.
Allegro (Pastorale dance)
Led by the festive sound of rustic bagpipes, nymphs and shepherds lightly dance beneath the brilliant canopy of spring.
Does he continue with similar techniques in the Summer, Fall, and Winter movements? Cite one additional example in each of the movements.
------>No, there is difference in techniques used by him in the Summer,Fall,Winter movements.
--->In Summer for example:-
Presto (Summer Storm) :- Alas, his worst fears were justified, as the heavens roar and great hailstones beat down upon the proudly standing corn.
---->In Fall for example:-
Adagio molto (Sleeping Drunkards):-
The singing and the dancing die away as cooling breezes fan the pleasant air,
inviting all to sleep without a care.
--->In Winter for example:-
Allegro non molto:-
Shivering, frozen mid the frosty snow in biting, stinging winds;
running to and fro to stamp one\'s icy feet, teeth chattering in the bitter chill.
.
Must every revolution end in tyranny (as suggested by Ignazio Silone)-.docx
Must every revolution end in tyranny (as suggested by Ignazio Silone)? Can you identify a revolution that, by the criteria you establish, can be viewed as a success?
Solution
Ignazio Silone 1 st May 1990 in Pescina,a small town in montainous region of the abruzzi. In 1915 an earth quake shatterd central Italy.Around 50,00 people were killed among them silone\'s mother.In 1917,as political agitation against the government and the war grew up rapidly.
Silone became regional secretary for rural works of the Abruzzi.He was arrested on a demonstration against the war. Three articles he wrote for the socialist party AVANTHI resulted in the editions being supressed by the authoroties.He had denounced the divertion of funds supposedly destined for earthquake relife.
Over next three years the revolution swept across Europe,Silone identified firmly with the militant left of the socialist movement,centred on the factory councils of turin.It was this group led to Antonio Gramsci which split from the socialist party to form the Italiyam Communist Party in Jan 1921.
Silone immediatley took an important role in the new party.He was appointed as editor of the paper for the city of Trieste and then,as the fascist threat grew and Mussoline came to power, went underground.Over the next three years he was sent as a communist party deligate to Germany,France,Spain and Russia.In 1925 he was brought to the publications department of the PCI to work withGramci and became responsible for party propaganda and agitation.
Silone\'s life was moulded by the two great forces in 20th century.First he was inspired and steeled by the hopes of new world which formed the great war and Russian revoulution.Then he experienced the disullution for 1930s as facism and Stalinism reigned trumphant.But he never dispared.He saw clearly as much as early possible,the consequences and the degeneration formed.And he depiced what facism reallu mean in a way the whole world could understand.
.
Multiple Choice Question The information in the following table is fro.docx
Multiple Choice Question
The information in the following table is from the statement of cash flows for a company at four different points in time (Period 1, Period 2, Period 3, and Period 4). Negative values are presented in parentheses.
Period 1
Period 2
Period 3
Period 4
Cash provided by operations
$(180,000)
$90,000
$360,000
$50,000
Cash provided by investing
(300,000)
75,000
90,000
(120,000)
Cash provided by financing
290,000
(220,000)
($170,000)
$420,000
Net income
(120,000)
30,000
300,000
(15,000)
Based on this information, which of the following answers most likely corresponds with the introductory phase, growth phase, maturity phase, or decline phase?
Period 2, Period 1, Period 3, Period 4.
Period 3, Period 4, Period 1, Period 2.
Period 4, Period 3, Period 2, Period 1.
Period 1, Period 4, Period 3, Period 2.
Multiple Choice Question The information in the following table is from the statement of cash flows for a company at four different points in time (Period 1, Period 2, Period 3, and Period 4). Negative values are presented in parentheses. Based on this information, which of the following answers most likely corresponds with the introductory phase, growth phase, maturity phase, or decline phase?
Solution
ans is
Period 1, Period 4, Period 3, Period 2.
Period 1 = Introductory phase as company is new in the market and therefore incurred losses from operations and therefore net income is negative
Period4 = Growth phase as company has postive cash flows from operating activities in this phase.
Period 3 = Maturity phase as company has reached a stage where it has maximised cash flows from operating activities and net income.
Period 2= Decline phase as compnays operating cash flows have started decling as compared to maturity phase
.
Mips assembly language Generate the quadruples for the program code fr.docx
Mips assembly language
Generate the quadruples for the program code fragment and include details. Please see the attached photo below.
Solution
; roots.asm segment .text global _roots _roots: enter 0,0 xor EAX,EAX fld qword[EBP+8] ; a fadd ST0 ; 2a fld qword[EBP+8] ; a,2a fld qword[EBP+24] ; c,a,2a fmulp ST1 ; ac,2a fadd ST0 ; 2ac,2a fadd st0 ; 4ac,2a fchs ; -4ac,2a fld qword[EBP+16] ; b,-4ac,2a fld qword[EBP+16] ; b,b,-4ac,2a fmulp ST1 ; b*b,-4ac,2a faddp ST1 ; b*b-4ac,2a ftst ; cmp (b*b-4ac),0 fstsw AX ; result of test in AX sahf ; store AH in flag reg jb no_real_roots ; jb tests the carry flag fsqrt ; sqrt(b*b-4ac),2a fld qword[EBP+16] ; b,sqrt(b*b-4ac),2a fchs ; -b,sqrt(b*b-4ac),2a fadd ST1 ; -b+sqrt(b*b-4ac),sqrt(b*b-4ac),2a fdiv ST2 ; -b+sqrt(b*b-4ac)/2a,sqrt(b*b-4ac),2a mov EAX,dword[EBP+32] ; EAX = -b+sqrt(b*b-4ac)/2a fstp qword[EAX] ; Store and pop fld qword[EBP+16] ; b,sqrt(b*b-4ac),2a fchs ; -b,sqrt(b*b-4ac),2a fsubp ST1 ; -b-sqrt(b*b-4ac),2a fdivrp ST1 ; -b-sqrt(b*b-4ac)/2a mov EAX,dword[EBP+36] ; EAX = -b-sqrt(b*b-4ac)/2a fstp qword[EAX] ; Store and pop mov EAX,1 ; 1 means real roots jmp short done no_real_roots: sub EAX,EAX ; 0 means no real roots done: leave ret
.
Microsoft Visual C# 2012- An introduction to object-oriented programmi.docx
Microsoft Visual C# 2012: An introduction to object-oriented programming Ch.12 Question # 7.
Create a project named Restaurant that contains a Form that allows the user to choose one item from at least three options in each of the following categories - appetizer, entree, and desert. Assign a different price to each selection and display the total when the user clicks a Button . Use the Controls that you think are best for each function. Label items appropriatelyand use fonts and colors to achieve an attractive design.
Solution
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
namespace Restuarant
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void groupBox2_Enter(object sender, EventArgs e)
{
}
private void button2_Click(object sender, EventArgs e)
{
double total = 0;
double subtotal = 0;
double tax = 0;
if (comboBox1.SelectedIndex == 0)
{
subtotal = subtotal + 400;
}
if (comboBox1.SelectedIndex == 1)
{
subtotal = subtotal + 50;
}
if (comboBox1.SelectedIndex == 2)
{
subtotal = subtotal + 300;
}
if (comboBox2.SelectedIndex == 0)
{
subtotal = subtotal + 400;
}
if (comboBox2.SelectedIndex == 1)
{
subtotal = subtotal + 50;
}
if (comboBox2.SelectedIndex == 2)
{
subtotal = subtotal + 300;
}
if (comboBox3.SelectedIndex == 0)
{
subtotal = subtotal + 400;
}
if (comboBox3.SelectedIndex == 1)
{
subtotal = subtotal + 50;
}
if (comboBox3.SelectedIndex == 2)
{
subtotal = subtotal + 300;
}
textBox7.Text = Convert.ToString(subtotal);
tax = subtotal * 0.2;
textBox8.Text = Convert.ToString(tax);
total = tax + subtotal;
textBox9.Text = Convert.ToString(total);
}
private void button1_Click(object sender, EventArgs e)
{
}
}
.
Merge sort in CSolution#include-stdio-h- #define MAX 50 void mergeSort.docx
Merge sort in C
Solution
#include<stdio.h>
#define MAX 50
void mergeSort(int arr[],int low,int mid,int high);
void partition(int arr[],int low,int high);
int main(){
int merge[MAX],i,n;
printf(\"Enter the total number of elements: \");
scanf(\"%d\",&n);
printf(\"Enter the elements which to be sort: \");
for(i=0;i<n;i++){
scanf(\"%d\",&merge[i]);
}
partition(merge,0,n-1);
printf(\"After merge sorting elements are: \");
for(i=0;i<n;i++){
printf(\"%d \",merge[i]);
}
return 0;
}
void partition(int arr[],int low,int high){
int mid;
if(low<high){
mid=(low+high)/2;
partition(arr,low,mid);
partition(arr,mid+1,high);
mergeSort(arr,low,mid,high);
}
}
void mergeSort(int arr[],int low,int mid,int high){
int i,m,k,l,temp[MAX];
l=low;
i=low;
m=mid+1;
while((l<=mid)&&(m<=high)){
if(arr[l]<=arr[m]){
temp[i]=arr[l];
l++;
}
else{
temp[i]=arr[m];
m++;
}
i++;
}
if(l>mid){
for(k=m;k<=high;k++){
temp[i]=arr[k];
i++;
}
}
else{
for(k=l;k<=mid;k++){
temp[i]=arr[k];
i++;
}
}
for(k=low;k<=high;k++){
arr[k]=temp[k];
}
}
Sample output:
Enter the total number of elements: 5
Enter the elements which to be sort: 2 5 0 9 1
After merge sorting elements are: 0 1 2 5 9
.
Nathanson Corporation was organized on May 1- 2014- The following even.docx
Nathanson Corporation was organized on May 1, 2014. The following events occurred during the first month.
Received $74,000 cash from the five investors who organized Nathanson Corporation. Each investor received 105 shares of $10 par value common stock.
Prepare journal entries for each transaction. (If no entry is required for a transaction/event, select \"No journal entry required\" in the first account field.)
Thanks
Solution
(A) Cash A/c Dr.74000
To Share Capital 5250 (5*105*10)
to Securities Premium 68750
(B)Fixtures A/c Dr. 14000
ToAmount Payables (expenses) A/c 14000
(C) Cash Dr. 11000
To Notes payable 11000
(D) Equipment A/c Dr 18000
To Cash 1200
To Notes Payable 16800
(E) Notes Recievables 1700
to cash 1700
(F) Amount Payables A/c (erxpense) Dr 14000
To Cash/bank 14000
THanks
.
Match the following aqueous solutions with the appropriate letter from (4).docx
Match the following aqueous solutions with the appropriate letter from the column on the right.
Solution
?T b = K b · b solute · i
Where: bsolute = molality of the solution
K b , the ebullioscopic constant, which is dependent on the properties of the solvent.
i. The Vant Hoff factor i accounts for the number of individual particles (typically ions) formed by a compound in solution
i= 3 For FeCl 2
i=3 for CuI 2
i=3 for ( NH 4 ) 2 S
i=1 sucrose
then we need to find which solution have the highest ?Tb
1 FeCl 2 ; Highest boiling point
?Tb = Kb(0.15)x(3)= 0.45 Kb
2) CuI 2 Second highest boiling point
?Tb = Kb(0.14)x(3)= 0.42 Kb
3) ( NH 4 ) 2 S Third highest boiling point
?Tb = Kb(0.12)x(3)= 0.36Kb
4) Sucrose Lowest boiling point
?Tb = Kb(0.40)x(1)= 0.40Kb
.
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- 1. Match the words in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. Reset Help hydrogen bonding influences Given the molecules phosgene (Cl2 CO) and formaldehyde (H2CO). has the higher reduced polarity and strongerboiling point mainly due to dispersion forces phosgene (C2 CO) its greater molar mass and Given the molecules sulfur dioxide (SO2) and sulfur trioxide (SOs). has the higher boiling point mainly due to stronger dispersion forces sulfur dioxide (SO2) molecule shape and stronger dipole-dipole interactions sulfur trioxide (SOs) formaldehyde (H2CO) Solution 1. Phosgene has the higher boiling point than formaldehyde. This is mainly due to phosgene's (Cl2CO) greater molar mass and stronger dispersion forces. Explanation: For molecules that do not participate in hydrogen bonding, the majority of the attraction between those molecules is due to London dispersion forces. Even though dipole-dipole interactions are stronger, they apply to specific orientations of the interacting molecules. The ability to form an instantaneous dipole is referred to as polarizability. Molecules that are more polarizable, owing to their size and number of electrons, experience greater intermolecular attractions because those interactions are much less dependent on the molecular orientations. 2. Sulfur trioxide (SO3) has a higher boiling point than sulfur dioxide (SO2) mainly due to its greater molar mass and stronger dispersion forces. Explanation: There can be multiple types of interactions that occur between molecules, but comparing the boiling points of substances should mostly be based on polarizability (with the exception of hydrogen bonding). Both sulfur trioxide and phosgene would experience much greater attractions due to London dispersion forces than sulfur dioxide and formaldehyde, respectively. The contributions of dipole-dipole interactions in sulfur dioxide and formaldehyde are too insignificant in both cases.