The document presents a quadratic equation problem where a and b are roots of the equation x^2 - 6x + 4 = 0. It is given that a^2 = 6a - 4 and b^2 = 6b - 4. The value of (2a+1)*(2b+1) is calculated by using the properties that a + b = 6 and ab = 4. The final expression is simplified to 29.

1. Linear Quadratic Equation

2. Linear Quadratic Equation
a2 = 6a - 4, b2 = 6b – 4, what is the value of (2a+1)*(2b+1)
(a) 17 (b) 13
(c) 29 (d) 28
(e) 16

3. Linear Quadratic Equation
Solution:
a2 = 6a – 4
b2 = 6b – 4
a, b are roots of the equation x2 – 6x + 4 = 0
a + b = 6 ab = 4
(2a + 1)(2b + 1) = 4ab + 2(a + b) + 1
= 4 x 4 x 2 6 + 1
= 16 + 12 + 1
a2 = 6a - 4, b2 = 6b – 4, what is the value of (2a+1)*(2b+1)

4. Linear Quadratic Equation
Answer choice (C)
a2 = 6a - 4, b2 = 6b – 4, what is the value of (2a+1)*(2b+1)

5. Prepare for CAT from anywhere, at anytime, and at your
pace. Visit
Online.2iim.com