This document provides definitions and properties related to probability theory and statistics. It defines key concepts such as probability spaces, random variables, distribution functions, and probability density functions. It also covers conditional probability, independence, random vectors, and other statistical topics. The document presents the concepts concisely using mathematical notation.
Model Selection with Piecewise Regular GaugesGabriel Peyré
Talk given at Sampta 2013.
The corresponding paper is :
Model Selection with Piecewise Regular Gauges (S. Vaiter, M. Golbabaee, J. Fadili, G. Peyré), Technical report, Preprint hal-00842603, 2013.
http://hal.archives-ouvertes.fr/hal-00842603/
Solvability of Matrix Riccati Inequality Talk SlidesKevin Kissi
15min presentation slides. It goes beyond Beamer latex to showcase the best use of color and design in a Mathematical talk slide.
The paper itself is archived at arxiv.org with pdf at: https://arxiv.org/pdf/1505.04861.pdf
How to find a cheap surrogate to approximate Bayesian Update Formula and to a...Alexander Litvinenko
We suggest the new vision for classical Bayesian Update formula. We expand all ingredients in Polynomial Chaos Expansion and write out a new formula for Bayesian* update of PCE coefficients. This formula is derived from Minimum Mean Square Estimation. One starts with prior PCE, take measurements into account, and obtain posterior PCE coefficients, without any MCMC sampling.
Solution Manual for Linear Models – Shayle Searle, Marvin GruberHenningEnoksen
https://www.book4me.xyz/solution-manual-for-elementary-differential-equations-diprima/
Solution Manual for Linear Models - 2nd Edition
Author(s) : Shayle R. Searle, Marvin H.J. Gruber
This solution manual include problems of all chapters from 2nd edition's textbook.
This presentation is taken from part of a master's degree thesis in Tourism. The following work is born from the need to delineate an emerging figure that until a few years ago had no weight: the food tourist. It 'a type of tourist akin to cultural tourist, wants to visit the places of food production (wineries, oil mills, dairies, vineyards, stables ...), discover the history of the food and the community, evoke the traditional flavors and communicate heritage. Another interesting component is the experience, as a feature that goes far beyond the supply of a tourist service.The interest in food is not new, but its importance in the last five years is the basis of a change of values in society and that consequently have also affected the tourism sector. For these reasons it was necessary to conduct a careful analysis of tourists fascinated by good food, as motivation to go on vacation.
Model Selection with Piecewise Regular GaugesGabriel Peyré
Talk given at Sampta 2013.
The corresponding paper is :
Model Selection with Piecewise Regular Gauges (S. Vaiter, M. Golbabaee, J. Fadili, G. Peyré), Technical report, Preprint hal-00842603, 2013.
http://hal.archives-ouvertes.fr/hal-00842603/
Solvability of Matrix Riccati Inequality Talk SlidesKevin Kissi
15min presentation slides. It goes beyond Beamer latex to showcase the best use of color and design in a Mathematical talk slide.
The paper itself is archived at arxiv.org with pdf at: https://arxiv.org/pdf/1505.04861.pdf
How to find a cheap surrogate to approximate Bayesian Update Formula and to a...Alexander Litvinenko
We suggest the new vision for classical Bayesian Update formula. We expand all ingredients in Polynomial Chaos Expansion and write out a new formula for Bayesian* update of PCE coefficients. This formula is derived from Minimum Mean Square Estimation. One starts with prior PCE, take measurements into account, and obtain posterior PCE coefficients, without any MCMC sampling.
Solution Manual for Linear Models – Shayle Searle, Marvin GruberHenningEnoksen
https://www.book4me.xyz/solution-manual-for-elementary-differential-equations-diprima/
Solution Manual for Linear Models - 2nd Edition
Author(s) : Shayle R. Searle, Marvin H.J. Gruber
This solution manual include problems of all chapters from 2nd edition's textbook.
This presentation is taken from part of a master's degree thesis in Tourism. The following work is born from the need to delineate an emerging figure that until a few years ago had no weight: the food tourist. It 'a type of tourist akin to cultural tourist, wants to visit the places of food production (wineries, oil mills, dairies, vineyards, stables ...), discover the history of the food and the community, evoke the traditional flavors and communicate heritage. Another interesting component is the experience, as a feature that goes far beyond the supply of a tourist service.The interest in food is not new, but its importance in the last five years is the basis of a change of values in society and that consequently have also affected the tourism sector. For these reasons it was necessary to conduct a careful analysis of tourists fascinated by good food, as motivation to go on vacation.
Show that if A is a fixed event of positive probability, then the fu.pdfakshitent
Show that if A is a fixed event of positive probability, then the function Q[B]=P[B|A] taking
events B into R satisfies the three defining axioms of probability.
Here is the three defining axioms of probability.
A probability measure P is a function taking the family of events H to the real numbers such that
(i) P[Pi]=1
(ii) For all A includes in H, P[A] 0.
(iii) If A1, A2,.....is a sequence of pairwise disjoint events then
P[A1 U A2 U.....]=P[Ai]
Solution
say A1 , A2 , . . ., are called mutually disjoint or pairwise disjoint if Ai n A j = 0 for
any two of the events Ai and A j ; that is, no two of the events overlap. According to
Kolmogorov’s axioms, each event A has a probability P(A), which is a number. These numbers
satisfy three axioms: Axiom 1: For any event A, we have P(A) = 0. Axiom 2: P(S ) = 1. 4
Axiom 3: If the events A1 , A2 , . . . are pairwise disjoint, then CHAPTER 1. BASIC IDEAS
P(A1 ? A2 ? · · ·) = P(A1 ) + P(A2 ) + · · · Note that in Axiom 3, we have the union of events
and the sum of numbers. Don’t mix these up; never write P(A1 ) ? P(A2 ), for example.
Sometimes we sep- arate Axiom 3 into two parts: Axiom 3a if there are only ?nitely many events
A1 , A2 , . . . , An , so that we have P(A1 ? · · · ? An ) = ? P(Ai ), n i=1 and Axiom 3b for
in?nitely many. We will only use Axiom 3a, but 3b is important later on. Notice that we write n
? P(Ai) i=1 for P(A1 ) + P(A2 ) + · · · + P(An ). 1.4 Proving things from the axioms You can
prove simple properties of probability from the axioms. That means, every step must be justi?ed
by appealing to an axiom. These properties seem obvious, just as obvious as the axioms; but the
point of this game is that we assume only the axioms, and build everything else from that. Here
are some examples of things proved from the axioms. There is really no difference between a
theorem, a proposition, and a corollary; they all have to be proved. Usually, a theorem is a big,
important statement; a proposition a rather smaller statement; and a corollary is something that
follows quite easily from a theorem or proposition that came before. Proposition 1.1 If the event
A contains only a ?nite number of outcomes, say A = {a1 , a2 , . . . , an }, then P(A) = P(a1 ) +
P(a2 ) + · · · + P(an ). To prove the proposition, we de?ne a new event Ai containing only the
out- come ai , that is, Ai = {ai }, for i = 1, . . . , n. Then A1 , . . . , An are mutually disjoint 1.4.
PROVING THINGS FROM THE AXIOMS (each contains only one element which is in none
of the others), and A1 ? A2 ? · · · ? An = A; so by Axiom 3a, we have P(A) = P(a1 ) + P(a2 ) + · ·
· + P(an ). Corollary 1.2 If the sample space S is ?nite, say S = {a1 , . . . , an }, then P(a1 ) +
P(a2 ) + · · · + P(an ) = 1. For P(a1 ) + P(a2 ) + · · · + P(an ) = P(S ) by Proposition 1.1, and P(S )
= 1 by Axiom 2. Notice that once we have proved something, we can use it on the same basis as
an axiom to prove further facts. Now we see that, if all the n outcomes are equa.
This presentation is about the topic PROBABILITY. Details of this topic, starting from basic level and slowly moving towards advanced level , has been discussed in this presentation.
Securing your Kubernetes cluster_ a step-by-step guide to success !KatiaHIMEUR1
Today, after several years of existence, an extremely active community and an ultra-dynamic ecosystem, Kubernetes has established itself as the de facto standard in container orchestration. Thanks to a wide range of managed services, it has never been so easy to set up a ready-to-use Kubernetes cluster.
However, this ease of use means that the subject of security in Kubernetes is often left for later, or even neglected. This exposes companies to significant risks.
In this talk, I'll show you step-by-step how to secure your Kubernetes cluster for greater peace of mind and reliability.
A tale of scale & speed: How the US Navy is enabling software delivery from l...sonjaschweigert1
Rapid and secure feature delivery is a goal across every application team and every branch of the DoD. The Navy’s DevSecOps platform, Party Barge, has achieved:
- Reduction in onboarding time from 5 weeks to 1 day
- Improved developer experience and productivity through actionable findings and reduction of false positives
- Maintenance of superior security standards and inherent policy enforcement with Authorization to Operate (ATO)
Development teams can ship efficiently and ensure applications are cyber ready for Navy Authorizing Officials (AOs). In this webinar, Sigma Defense and Anchore will give attendees a look behind the scenes and demo secure pipeline automation and security artifacts that speed up application ATO and time to production.
We will cover:
- How to remove silos in DevSecOps
- How to build efficient development pipeline roles and component templates
- How to deliver security artifacts that matter for ATO’s (SBOMs, vulnerability reports, and policy evidence)
- How to streamline operations with automated policy checks on container images
UiPath Test Automation using UiPath Test Suite series, part 4DianaGray10
Welcome to UiPath Test Automation using UiPath Test Suite series part 4. In this session, we will cover Test Manager overview along with SAP heatmap.
The UiPath Test Manager overview with SAP heatmap webinar offers a concise yet comprehensive exploration of the role of a Test Manager within SAP environments, coupled with the utilization of heatmaps for effective testing strategies.
Participants will gain insights into the responsibilities, challenges, and best practices associated with test management in SAP projects. Additionally, the webinar delves into the significance of heatmaps as a visual aid for identifying testing priorities, areas of risk, and resource allocation within SAP landscapes. Through this session, attendees can expect to enhance their understanding of test management principles while learning practical approaches to optimize testing processes in SAP environments using heatmap visualization techniques
What will you get from this session?
1. Insights into SAP testing best practices
2. Heatmap utilization for testing
3. Optimization of testing processes
4. Demo
Topics covered:
Execution from the test manager
Orchestrator execution result
Defect reporting
SAP heatmap example with demo
Speaker:
Deepak Rai, Automation Practice Lead, Boundaryless Group and UiPath MVP
Encryption in Microsoft 365 - ExpertsLive Netherlands 2024Albert Hoitingh
In this session I delve into the encryption technology used in Microsoft 365 and Microsoft Purview. Including the concepts of Customer Key and Double Key Encryption.
GraphRAG is All You need? LLM & Knowledge GraphGuy Korland
Guy Korland, CEO and Co-founder of FalkorDB, will review two articles on the integration of language models with knowledge graphs.
1. Unifying Large Language Models and Knowledge Graphs: A Roadmap.
https://arxiv.org/abs/2306.08302
2. Microsoft Research's GraphRAG paper and a review paper on various uses of knowledge graphs:
https://www.microsoft.com/en-us/research/blog/graphrag-unlocking-llm-discovery-on-narrative-private-data/
State of ICS and IoT Cyber Threat Landscape Report 2024 previewPrayukth K V
The IoT and OT threat landscape report has been prepared by the Threat Research Team at Sectrio using data from Sectrio, cyber threat intelligence farming facilities spread across over 85 cities around the world. In addition, Sectrio also runs AI-based advanced threat and payload engagement facilities that serve as sinks to attract and engage sophisticated threat actors, and newer malware including new variants and latent threats that are at an earlier stage of development.
The latest edition of the OT/ICS and IoT security Threat Landscape Report 2024 also covers:
State of global ICS asset and network exposure
Sectoral targets and attacks as well as the cost of ransom
Global APT activity, AI usage, actor and tactic profiles, and implications
Rise in volumes of AI-powered cyberattacks
Major cyber events in 2024
Malware and malicious payload trends
Cyberattack types and targets
Vulnerability exploit attempts on CVEs
Attacks on counties – USA
Expansion of bot farms – how, where, and why
In-depth analysis of the cyber threat landscape across North America, South America, Europe, APAC, and the Middle East
Why are attacks on smart factories rising?
Cyber risk predictions
Axis of attacks – Europe
Systemic attacks in the Middle East
Download the full report from here:
https://sectrio.com/resources/ot-threat-landscape-reports/sectrio-releases-ot-ics-and-iot-security-threat-landscape-report-2024/
Welocme to ViralQR, your best QR code generator.ViralQR
Welcome to ViralQR, your best QR code generator available on the market!
At ViralQR, we design static and dynamic QR codes. Our mission is to make business operations easier and customer engagement more powerful through the use of QR technology. Be it a small-scale business or a huge enterprise, our easy-to-use platform provides multiple choices that can be tailored according to your company's branding and marketing strategies.
Our Vision
We are here to make the process of creating QR codes easy and smooth, thus enhancing customer interaction and making business more fluid. We very strongly believe in the ability of QR codes to change the world for businesses in their interaction with customers and are set on making that technology accessible and usable far and wide.
Our Achievements
Ever since its inception, we have successfully served many clients by offering QR codes in their marketing, service delivery, and collection of feedback across various industries. Our platform has been recognized for its ease of use and amazing features, which helped a business to make QR codes.
Our Services
At ViralQR, here is a comprehensive suite of services that caters to your very needs:
Static QR Codes: Create free static QR codes. These QR codes are able to store significant information such as URLs, vCards, plain text, emails and SMS, Wi-Fi credentials, and Bitcoin addresses.
Dynamic QR codes: These also have all the advanced features but are subscription-based. They can directly link to PDF files, images, micro-landing pages, social accounts, review forms, business pages, and applications. In addition, they can be branded with CTAs, frames, patterns, colors, and logos to enhance your branding.
Pricing and Packages
Additionally, there is a 14-day free offer to ViralQR, which is an exceptional opportunity for new users to take a feel of this platform. One can easily subscribe from there and experience the full dynamic of using QR codes. The subscription plans are not only meant for business; they are priced very flexibly so that literally every business could afford to benefit from our service.
Why choose us?
ViralQR will provide services for marketing, advertising, catering, retail, and the like. The QR codes can be posted on fliers, packaging, merchandise, and banners, as well as to substitute for cash and cards in a restaurant or coffee shop. With QR codes integrated into your business, improve customer engagement and streamline operations.
Comprehensive Analytics
Subscribers of ViralQR receive detailed analytics and tracking tools in light of having a view of the core values of QR code performance. Our analytics dashboard shows aggregate views and unique views, as well as detailed information about each impression, including time, device, browser, and estimated location by city and country.
So, thank you for choosing ViralQR; we have an offer of nothing but the best in terms of QR code services to meet business diversity!
UiPath Test Automation using UiPath Test Suite series, part 3DianaGray10
Welcome to UiPath Test Automation using UiPath Test Suite series part 3. In this session, we will cover desktop automation along with UI automation.
Topics covered:
UI automation Introduction,
UI automation Sample
Desktop automation flow
Pradeep Chinnala, Senior Consultant Automation Developer @WonderBotz and UiPath MVP
Deepak Rai, Automation Practice Lead, Boundaryless Group and UiPath MVP
Essentials of Automations: Optimizing FME Workflows with ParametersSafe Software
Are you looking to streamline your workflows and boost your projects’ efficiency? Do you find yourself searching for ways to add flexibility and control over your FME workflows? If so, you’re in the right place.
Join us for an insightful dive into the world of FME parameters, a critical element in optimizing workflow efficiency. This webinar marks the beginning of our three-part “Essentials of Automation” series. This first webinar is designed to equip you with the knowledge and skills to utilize parameters effectively: enhancing the flexibility, maintainability, and user control of your FME projects.
Here’s what you’ll gain:
- Essentials of FME Parameters: Understand the pivotal role of parameters, including Reader/Writer, Transformer, User, and FME Flow categories. Discover how they are the key to unlocking automation and optimization within your workflows.
- Practical Applications in FME Form: Delve into key user parameter types including choice, connections, and file URLs. Allow users to control how a workflow runs, making your workflows more reusable. Learn to import values and deliver the best user experience for your workflows while enhancing accuracy.
- Optimization Strategies in FME Flow: Explore the creation and strategic deployment of parameters in FME Flow, including the use of deployment and geometry parameters, to maximize workflow efficiency.
- Pro Tips for Success: Gain insights on parameterizing connections and leveraging new features like Conditional Visibility for clarity and simplicity.
We’ll wrap up with a glimpse into future webinars, followed by a Q&A session to address your specific questions surrounding this topic.
Don’t miss this opportunity to elevate your FME expertise and drive your projects to new heights of efficiency.
Le nuove frontiere dell'AI nell'RPA con UiPath Autopilot™UiPathCommunity
In questo evento online gratuito, organizzato dalla Community Italiana di UiPath, potrai esplorare le nuove funzionalità di Autopilot, il tool che integra l'Intelligenza Artificiale nei processi di sviluppo e utilizzo delle Automazioni.
📕 Vedremo insieme alcuni esempi dell'utilizzo di Autopilot in diversi tool della Suite UiPath:
Autopilot per Studio Web
Autopilot per Studio
Autopilot per Apps
Clipboard AI
GenAI applicata alla Document Understanding
👨🏫👨💻 Speakers:
Stefano Negro, UiPath MVPx3, RPA Tech Lead @ BSP Consultant
Flavio Martinelli, UiPath MVP 2023, Technical Account Manager @UiPath
Andrei Tasca, RPA Solutions Team Lead @NTT Data
Le nuove frontiere dell'AI nell'RPA con UiPath Autopilot™
Lecture 01
1. Bibliography
Agratini, O., Blaga, P., Coman, Gh., Lectures on Wavelets,
Numerical Methods and Statistics, Casa C˘rtii de Stiint˘,
a¸ ¸ ¸a
Cluj-Napoca, 2005.
Blaga, P., Calculul probabilit˘¸ilor ¸i statistic˘ matematic˘.
at s a a
Vol. II. Curs ¸i culegere de probleme, Universitatea
s
Babe¸-Bolyai, Cluj-Napoca, 1994.
s
Blaga, P., Statistic˘. . . prin Matlab, Presa Universitar˘
a a
Clujean˘, Cluj-Napoca, 2002.
a
Blaga, P., R˘dulescu, M., Calculul probabilit˘¸ilor,
a at
Universitatea Babe¸-Bolyai, Cluj-Napoca, 2002.
s
Lisei, H., Probability theory, Casa C˘rtii de Stiint˘,
a¸ ¸ ¸a
Cluj-Napoca, 2004.
Lisei, H., Micula, S., Soos, A., Probability Theory trough
Problems and Applications, Cluj University Press, 2006.
Shiryaev, A. N., Probability (2nd ed.), Springer, New York
1995.
2. Probability space
E (Experiment) −→ Ω (Outcomes - results of the experiment)
Ω is called sample space
Definition
A non-empty subset K ⊂ P (Ω) is a σ-algebra (σ-field) if it
satisfies the following conditions:
1o if A ∈ K, then A ∈ K (contrary event),
2o if Ai ∈ K, i ∈ I , then the union Ai ∈ K,
i∈I
and the pair (Ω, K) is called the space of events (measurable space
of events).
3. Definition
Let (Ω, K) be a measurable space of events.
The set function
P : K −→ R,
is called probability, if it satisfies the conditions:
1o P (A) 0, ∀ A ∈ K,
2o P (Ω) = 1, Ω is the certain event,
3o P is σ–additive, i.e. for any subset of events Ai ∈ K, i ∈ I ,
pairwise disjoint events (mutually exclusive events),
Ai ∩ Aj = ∅ (impossible event), i = j, it is satisfied
P Ai = P (Ai ) ,
i∈I i∈I
and the triple (Ω, K, P) is called probability space.
4. Proposition
(1) P (∅) = 0,
¯
(2) P A = 1 − P (A),
A) = P (B) − P (A ∩ B),
(3) P (B
A) = P (B) − P (A), if A ⊂ B,
(4) P (B
P (B) , if A ⊂ B,
(5) P (A)
(6) P (A ∪ B) = P (A) + P (B) − P (A ∩ B),
n n
(7) P Ai P (Ai ).
i=1 i=1
5. Property (Poincar´)
e
n n n
P (Ai ) − P (Ai ∩ Aj ) +
P Ai =
i=1 i=1 i,j=1
i<j
n n
n−1
P (Ai ∩ Aj ∩ Ak ) − · · · + (−1)
+ P Ai .
i=1
i,j,k=1
i<j<k
6. Conditional Probability
Definition
Let (Ω, K, P) be a probability space and an event B ∈ K,
P (B) > 0, it is called conditional probability of the event A with
respect to the event B the ratio
P (A ∩ B)
PB (A) = P (A | B) = ·
P (B)
7. Proposition
Let (Ω, K, P) be a probability space, then
(1) for B ∈ K, with P (B) > 0, the function set PB : K −→ R,
defined by
P (A ∩ B)
PB (A) = P (A | B) = , ∀A ∈ K,
P (B)
is a probability, and the triple (Ω, K, PB ) is a probability
space,
(2) ∀A, B ∈ K, satisfying the condition P (A) P (B) > 0, we have
P (A ∩ B) = P (A) P (B | A) = P (B) P (A | B) ,
(3) ∀A ∈ K, satisfying the condition 0 < P (A) < 1, we have
¯ ¯
P (B) = P (A) P (B | A) + P A P B | A , ∀B ∈ K.
8. Property (Multiplication Formula for Probabilities)
Let us consider the events Ai ∈ K, i = 1, n, satisfying
P (∩n Ai ) > 0, then
i=1
n n−1
= P (A1 ) P (A2 | A1 ) P (A3 | A1 ∩ A2 ) . . . P An
P Ai Ai .
i=1 i=1
9. Property (Formula for Total Probability)
Let A ∈ K be an event and a complete set of disjoint events,
(Ai )i∈I , Ai ∈ K, then
P (Ai ) P (A | Ai ) .
P (A) =
i∈I
Property (Bayes’s Formula)
Let us consider (Ai )i∈I , Ai ∈ K, a complete set of disjoint events,
and the event A ∈ K, with P (A) > 0, then
P (Ai ) P (A | Ai )
P (Ai | A) = , for all i ∈ I .
P (Ai ) P (A | Ai )
i∈I
10. Independence
Definition
The events A, B ∈ K are called independent, if
P (A ∩ B) = P (A) P (B) .
Property
Let (Ω, K, P) be a probability space and the events A, B ∈ K,
(1) if P (A) = 0 or P (A) = 1, then the events A and B are
independent,
(2) if the events A and B are independent, then
P (A | B) = P (A), and P (B | A) = P (B),
(3) if the events A and B are independent, then pairs of events
¯ ¯ ¯¯
A, B , A, B and A, B are independent.
11. Definition
The events (Ai )i=1,n are called independent, if for all
1 i1 < i2 < · · · < ik n, and k = 2, n, the following relations are
satisfied
P (Ai1 ∩ Ai2 ∩ · · · ∩ Aik ) = P (Ai1 ) P (Ai2 ) . . . P (Aik ) .
Definition
Let (Ω, K, P) be a probability space. The events of the subset
(Ai )i∈I , Ai ∈ K, are called independent, if
P Aj = P (Aj ) ,
j∈J j∈J
for all finite subsets of indices J ⊂ I .
12. Random Variables
Let (Ω, K, P) a probability space.
Definition
A real function X : Ω −→ R, is called random variable, if
X −1 ((−∞, x)) = (X < x) = ω ∈ Ω X (ω) < x ∈ K,
for all x ∈ R.
Remarks
If |X (Ω)| denotes the cardinal of the range of random variable
X , then the random variable is called:
Discrete random variable, if |X (Ω)| ℵ0 , i.e. it is a
countable (denumerable) set;
Simple random variable, if |X (Ω)| < ℵ0 , i.e. it is a finite
set;
Continuous random variable, if |X (Ω)| = ℵ, i.e. it is a
non-numerable (uncountable) set.
13. Random Vector
Definition
A real valued vector function
X = (X1 , . . ., Xn ) : Ω −→ Rn
is a random vector (n–dimensional random vector), if
(X < x) = (X1 < x1 , . . . , Xn < xn )
= ω∈Ω X1 (ω) < x1 , . . . , Xn (ω) < xn ∈ K,
for all x ∈ Rn .
14. Distribution Function
Let us consider the probability space (Ω, K, P) and a random
variable X : Ω → R.
Definition
The real function
F : R −→ R,
defined by
∀x ∈ R,
F (x) = P (X < x) , (1)
is called the (cumulative) distribution function of X .
Remark
Some books consider this definition for distribution function,
others (Matlab) use the definition given by
∀x ∈ R.
F (x) = P (X x) ,
15. Proposition
Let X be a random variable with the corresponding distribution
function F . Then we have:
(1) ∀ x ∈ R, 0 F (x) 1,
(2) ∀ a, b ∈ R, a < b,
X < b) = F (b) − F (a),
P (a
P (a < X < b) = F (b) − F (a) − P (X = a),
b) = F (b) − F (a) − P (X = a) + P (X = b),
P (a < X
b) = F (b) − F (a) + P (X = b),
P (a X
(3) ∀ x1 , x2 ∈ R, x1 < x2 ,
F (x1 ) F (x2 ) (F is undecreasing function),
(4) lim F (x) = F (−∞) = 0,
x→−∞
(5) lim F (x) = F (+∞) = 1,
x→+∞
(6) ∀ x ∈ R,
F (y ) = F (x − 0) = F (x) (F is left-continuous).
limy x
16. Remark
If F is piecewise constant, then the points of discontinuity xi ,
i ∈ I , are the values of a discrete random variable X , and the
corresponding values of jumps are given by the probability
distribution of X ,
i ∈ I.
pi = P (X = xi ) ,
17. Definition
Let X = (X1 , . . ., Xn ) a random vector.
The real function
F : Rn −→ R,
defined by
∀x ∈ Rn .
F (x) = F (x1 , . . . , xn ) = P (X1 < x1 , . . . , Xn < xn ) ,
is called the (cumulative) distribution function of the random
vector X.
Definition
Let X = (X1 , . . ., Xn ) be a random vector.
All distribution functions of the random vectors (Xi1 , . . ., Xik ),
1 i1 < . . . < ik n, k = 1, n − 1, are called marginal
distribution functions of the random vector X.
Property
If F is the distribution function of random vector X, then the
distribution function of random vector (Xi1 , . . ., Xik ) is given by
Fi1 ,...,ik (xi1 , . . ., xik ) = lim F (x1 , . . ., xn ) .
xj →∞
j=i1 ,...,ik
18. Probability Density Function
Definition
A random variable X is called (absolutely) continuous if the
corresponding distribution function F is absolutely continuous, i.e.
there exists a function f : R → R, such that
x
for all x ∈ R.
F (x) = f (t) dt,
−∞
The function f is called (probability) density function.
Proposition
If the random variable X is continuous, having the distribution
function F and density function f , then:
∀ x ∈ R, f (x)
(1) 0,
(2) F (x) = f (x), a.e. (almost everywhere) on R,
b
(3) for a < b, P (a X < b) = f (x) dx,
a
+∞
(4) f (x) dx = 1.
−∞
19. Remarks
Let X be a continous random variable, then P (X = a) = 0, for
each a ∈ R.
It follows, in this case, that
P (a X < b) = P (a < X b) = P (a < X < b)
b
= P (a X b) = f (x) dx.
a
If the continuous random variable X has the distribution
function F and the density function f , then we have successively
F (x + ∆x) − F (x)
f (x) = F (x) = lim
∆x
∆x→0
P (x X < x + ∆x)
·
= lim
∆x
∆x→0
Therefore, for small values of ∆x, we have
X < x + ∆x) ≈ f (x) ∆x.
P (x
20. Definition
A random vector X = (X1 , . . ., Xn ) is called (absolutely)
continuous if the corresponding distribution function F is
absolutely continuous, i.e. there exists a function f : Rn → R,
called (probability) density function, such that
x1 xn
F (x) = F (x1 , . . ., xn ) = ... f (t1 , . . ., tn ) dt1 . . .dtn ,
−∞ −∞
for all x = (x1 , . . ., xn ) ∈ Rn .
Proposition
Let X = (X1 , . . ., Xn ) be a continuous random vector, having the
distribution function F and the density function f , then
f (x) 0, for all x ∈ Rn ,
(1)
∂ n F (x1 , . . ., xn )
(2) = f (x1 , . . ., xn ), a.e. (almost everywhere)
∂x1 . . . ∂xn
on Rn ,
if D ⊂ Rn , we have P (X ∈ D) =
(3) f (x) dx,
D
21. Definition
Let X = (X1 , . . ., Xn ) a continuous random vector. All densities
functions of the random vectors (Xi1 , . . ., Xik ),
1 i1 < . . . < ik n, k = 1, n − 1, are called marginal densities
functions of X.
Property
Let f be the density function of the continous random vector X,
then the density function of random vector (Xi1 , . . ., Xik ) is given by
···
fi1 ,...,ik (xi1 , . . ., xik ) = f (x1 , . . ., xn ) dxj1 . . .dxjn−k ,
Rn−k
where {j1 , . . ., jn−k } = {1, . . ., n} {i1 , . . ., ik }.
Remark
The density function of Xi is given by
··· xi ∈ R.
fi (xi ) = f (x1 , . . ., xn ) dx1 . . .dxi−1 dxi+1 . . .dxn ,
Rn−1
22. Independence
Definition
Let X = (X1 , . . ., Xn ) be a random vector having distribution
function F . The random variables X1 , . . ., Xn are independent if
F (x) = F (x1 , . . ., xn ) = FX1 (x1 ) . . .FXn (xn ) ,
for all x = (x1 , . . ., xn ) ∈ Rn , FXi being the distribution function of
random variable Xi .
23. Remarks
If X = (X1 , . . ., Xn ) is a discrete random vector, then the
random variables X1 , . . ., Xn are independent if and only if
P (X1 = x1 , . . ., Xn = xn ) = P (X1 = x1 ) . . .P (Xn = xn ) ,
for all xi ∈ Xi (Ω), i = 1, n.
If X = (X1 , . . ., Xn ) is a continuous random vector, then the
random variables X1 , . . ., Xn are independent if and only if the
density function of random vector X satisfies the relation
f (x) = f (x1 , . . ., xn ) = fX1 (x1 ) . . .fXn (xn ) ,
for all x = (x1 , . . ., xn ) ∈ Rn , fXi being the density function of
random variable Xi .
24. Proposition
If the continuous random vector (X , Y ) has the density function f ,
then the density functions for the random variables sum, product,
and ratio are respectively:
+∞
f (u, x − u) du, x ∈ R,
fX +Y (x) =
−∞
+∞
x du
x ∈ R,
fXY (x) = f u, ,
|u|
u
−∞
+∞
f (xu, u) |u| du, x ∈ R.
fX /Y (x) =
−∞
If the random variables X and Y are independent, then
+∞
fX (u) fY (x − u) du, x ∈ R,
fX +Y (x) =
−∞
+∞
x du
x ∈ R,
fXY (x) = fX (u) fY ,
|u|
u
−∞
+∞
fX (xu) fY (u) |u| du, x ∈ R.
fX /Y (x) =
−∞
25. Discrete Uniform Distribution
The random variable X has discrete uniform distribution, when the
distribution is
x 1
where N ∈ N;
X , f (x) = f (x; N) = , x = 1, N.
1 N
N x=1,N
The distribution function is
0, if x 1,
k
F (x) = F (x; N) = , if k < x k + 1, k = 1, N − 1,
N
1, if x > N,
26. The distribution of random variable X is given by
f(x)
1/N
• • •
0 1 2 3 4 N−1 N x
f(x)=1/N, pentru x=1,...,N
The graph of distribution function F is
F(x)
1
(N−1)/N
• •
•
•
•
•
2/N
1/N
• • •
0 1 2 3 N−1 N x
27. Binomial Distribution
The random variable X has binomial distribution, we denote
B (n, p), when the distribution is
x n x n−x
X , f (x) = f (x; n, p) = pq , x = 0, n,
x
f (x) x=0,n
and p ∈ (0, 1), q = 1 − p.
The random variable X represents the number of successes in n
independent trials of an experiment.
Binomial distribution was descovered by James Bernoulli, and was
presented in his book Ars Conjectandi (1713).
1
Pascal considered the particular case p = 2 ·
The distribution function is given by
0, if x 0,
k−1
n i n−i
F (x) = F (x; n, p) = p q , if k − 1 < x k, k = 1, n,
i
i=0
1, if x > n,
28. In Figure, the vertical bars represent the probabilities of binomial
distribution B (5, 0.4) and the corresponding distribution function.
f(x) F(x)
•
•
•
•
•
•
0 1 2 3 4 5 x
0 1 2 3 4 5 x
f(x)=(n)pxqn−x, pentru x=0,...,n
x
29. Poisson Distribution
The random variable X has Poisson distribution, we denote
Po (λ), when distribution is given by
x λx −λ
X , where f (x) = f (x; λ) = e , and λ > 0.
x!
f (x) x=0,1,2,...
The random variable X , having Poisson distribution, gives the
number of occurrences of a fixed event in a time interval, on a
distance, on an area, and so on.
Poisson (1837) proved that this distribution is a limit case of
binomial distribution.
Namely, when p = p (n) and np → λ, for n → ∞, one obtains that
λx λ
n x n−x
f (x; n, p) = pq e.
x x!
One remarks that for high values of n, p has to be small, to hold
on the product np constant (λ). Thus, the probability p of
considered event is small, when n is high.
It is the reason that this distribution to be called the distribution of
rare events.
30. The Figure illustrates this remark.
It was considered binomial distribution B (100, 0.1) and
corresponding Poisson distribution Po (10), because np = 10.
Probabilitatile distributiilor
0.14
Legea binomiala
Legea lui Poisson
0.12
0.1
0.08
0.06
0.04
0.02
4 6 8 10 12 14 16 18
We also remark a known result, which establishes the connection
between the Poisson distribution and exponential distribution!
When Poisson distribution gives the number of occurrences in a
time interval, the exponential distribution gives the length of the
interval between two successsive occurrences of events.
31. Uniform distribution
The random variable aleatoare X has a uniform distribution on the
interval [a, b], we denote by U (a, b), when the density function is
1 , if x ∈ [a, b],
f (x) = f (x; a, b) = b − a (2)
if x ∈ [a, b].
0, /
The distribution function of X is
0, if x < a,
x
x − a
, if a x b,
F (x) = F (x; a, b) = f (t; a, b) dt =
b − a
−∞
1, if x > b.
The name is in connection with the fact that if one considers
subintervals of the interval [a, b] with the same length , then the
probability that X belongs to such intervals is / (b − a).
32. The Figure contains the graphs of density function and distribution
function.
f(x) F(x)
1
1/(b−a)
a b x a b x
We remark that distribution function is continuous.
Thus, the values x = a and x = b in formula (2) can be attached
to the cases F (x) = 0 and F (x) = 1, respectively.
It follows that density function can be considered non-zero on [a, b]
or (a, b] or [a, b) or (a, b).
In all cases we have uniform distribution U (a, b).
33. Normal Distribution
The random variable X has normal distribution (Gauss-Laplace
distribution) with the parameters µ ∈ R and σ > 0, we denote
N (µ, σ), when the density function is
(x−µ)2
1 −
f (x) = f (x; µ, σ) = √ e 2σ2 , for all x ∈ R.
σ 2π
The corresponding distribution function is given by
x x (t−µ)2
1 −
f (t; µ, σ) dt = √
F (x) = F (x; µ, σ) = e dt,
2σ 2
σ 2π
−∞ −∞
for all x ∈ R.
34. The graphs of density function and distribution function are given
in the Figure.
The curve which represents the graph of density function f is
called the curve of Gauss.
f(x) F(x)
fm
F(µ+σ)
fi
F(µ)=0.5
F(µ−σ)
µ−σ µ µ+σ
µ−σ µ µ+σ x
x
1
For x = µ is obtained the maximum of f , fm = σ√2π .
The inflexion points of f are x = µ ± σ with the corresponding
value f (µ ± σ) = fi = σ√1 ·
2πe
35. The distribution function of standard normal distribution, N (0, 1),
is x
1 2
− t2
Φ (x) = √ e dt, x ∈ R,
2π −∞
and is called Laplace function.
We remark that the function
x
1 2
− t2
˜ (x) = √ e dt, x ∈ R,
Φ
2π 0
is also called Laplace function.
Between the two Laplace functions the following relation
1˜
Φ (x) = + Φ (x) ,
2
holds.
Using the two Laplace functions we have:
x x (t−µ)2
1 −
f (t; µ, σ) dt = √
F (x; µ, σ) = e 2σ2 dt
σ 2π −∞
−∞
x −µ 1 ˜ x −µ
=Φ = +Φ .
σ 2 σ
36. χ2 distribution (Helmert-Pearson)
The random variable X has χ2 distribution or Helmert-Pearson
distribution, and one denotes χ2 (n), when the density function is
1
n x
x 2 −1 e− 2 , if x > 0,
n
n
22 Γ
f (x) = f (x; n) = 2
0, if x 0,
where n ∈ N represents the number of degrees of freedom.
37. The Figure contains the graphs of density function of χ2 (n)
distribution, for some values of parameter n.
f(x;n) n=5
n=10
n=20
f(x;5)
f(x;10)
f(x;20)
3 8 18 x
Property
If the random variables X1 , . . . , Xn are independent, each of them
having the same normal distribution with the parameters µ = 0
and σ = 1, then the random variable
n
2
Yn = Xk ,
k=1
is χ2 (n) distrubuted.
38. t distribution (Student)
The random variable X is t-distributed (Student) distributed,
denoted by T (n), when it has the density function
− n+1
n+1
x2
Γ 2
2
x ∈ R,
f (x) = f (x; n) = √ 1+ ,
n n
nπΓ 2
where n ∈ N represents the number of degrees of freedom.
Gosset (1908) descovered this distribution.
The result was not published at the first time, but using the
pseudonym Student, then it was published.
For n = 1, it is obtained Cauchy distribution:
1
x ∈ R.
f (x) = ,
π (1 + x 2 )
39. The Figure contains the graphs of density of T (n), for some values
of n.
f(x) n=1
n=3
n=20
−5 −4 −3 −2 −1 0 1 2 3 4 5 x
Property
If the random varibales X and Y are independent, X is normally
distributed, and Y having χ2 distribution with n degrees of
freedom, then the random variable
X
T=
Y /n
has the Student distribution with n degrees of freedom.
40. F distribution (Fisher–Snedecor)
The random variable X has F (Fisher-Snedecor) distribution,
denoted by F (m, n), when the density function is
Γ m+n m m m −1 m − m+n
2 2
2
x2 1+ x , x > 0,
Γ mΓ n n n
f (x) = f (x; m, n) = 2 2
0, x 0,
where m, n ∈ N represent the numbers of degrees of freedom.
41. The Figure contains graphs of density function of F (m, n), for
some values of the parameters m and n.
f(x)
m=4, n=2
m=3, n=10
0.71483
m=7, n=10
0.595 x
Property
If the random variables X and Y are independent, with χ2 (m) and
χ2 (n) distributions, then the random variable
X Y
F=
m n
is F (m, n) distributed.
42. Multidimensional normal distribution
Random vector X = (X1 , . . ., Xn ) has n-dimensional
(nondegenerate) normal distribution, one denotes N (µ, V), when
the density function is
f (x) = f (x1 , . . ., xn ) = f (x; µ, V)
1 1
× exp − (x − µ) V−1 (x − µ) ,
= n 1
2
(2π) 2 [det (V)] 2
for all x ∈ Rn .
V is a positive definite matrix of order n, and µ ∈ Rn .
When n = 2, the density function of the random vector (X , Y ),
having the two-dimensional normal distribution can be put in the
form
1
√ ×
f (x, y ) =
2πσ1 σ2 1 − r 2
(x −µ1 )2 (x −µ1 ) (y −µ2 ) (y −µ2 )2
1
× exp − −2r + ,
2 2
2 (1−r 2 ) σ1 σ2
σ1 σ2
for (x, y ) ∈ R2 .
43. The Figure represents the graph of density function of
two-dimensional normal distribution with µ1 = µ2 = 0, σ1 = 1,
σ2 = 2 ¸i r = −0.5.
s
0.07
0.06
0.05
0.04
f(x,y)
0.03
0.02
0.01
0
6
4
3
2 2
0 1
0
−2
−1
−4 −2
−6 −3
y x
Property
If the random vector (X , Y ) is a two-dimensional normally
distributed, N (µ1 , µ2 ; σ1 , σ2 ; r ), then each of the components X
and Y of random vector are normally distributed: N (µ1 , σ1 ) and
N (µ2 , σ2 ) respectively.
44. Conditional distribution
Let (X , Y ) be a two-dimensional random vector, having the
distribution function F .
Definition
The conditional distribution function of the random variable X
with respect to random variable Y , is the function FX |Y : R → R,
given by
FX |Y (x|y ) = P (X < x | Y = y ) , ∀x ∈ R, y ∈ R, fixed.
Remark
We can rewrite
FX |Y (x|y ) = lim P (X < x | y Y < y + h) ,
h 0
and using the definition of conditional probability
P (X < x, y Y < y + h)
FX |Y (x|y ) = lim
P (y Y < y + h)
h0
F (x, y + h) − F (x, y )
·
= lim
h 0 FY (y + h) − FY (y )
45. Let (X , Y ) be a discret random vector, having the distribution
X Y ... yj ...
. .
. .
. .
xi ... pij ...
. .
. .
. .
with (xi , yj ) ∈ R × R, (i, j) ∈ I × J.
Definition
The conditional distribution of random variable X with respect to
random variable Y has the distribution given by
P (X = xi , Y = yj ) pij
pi|j = P (X = xi | Y = yj ) = (i, j) ∈ I ×J,
= ,
P (Y = yj ) pj
where
j ∈ J.
p j = P (Y = yj ) = pij ,
i∈I
46. We remark that the formula
for all i ∈ I ,
pi = P (X = xi ) = p j pi|j ,
j∈J
holds.
It represents the formula for total probability.
We have also the Bayes’s formula:
pi pj|i
pij
(i, j) ∈ I × J.
pi|j = = ,
pij pi pj|i
i∈I i∈I
47. Let (X , Y ) be a two-dimensional continuous random vector, having
the density function f .
Definition
The conditional density function of random variable X with respect
the random variable Y , is the function given by
f (x, y ) , if f (y ) = 0,
Y
fY (y )
fX |Y (x | y ) =
0, if fY (y ) = 0.
The formula for total probability and the Bayes’s formula hold:
+∞
∀x ∈ R,
fX (x) = fY (y ) fX |Y (x|y ) dy ,
−∞
fX (x) fY |X (y |x)
∀ (x, y ) ∈ R × R.
fX |Y (x|y ) = ,
fX (x) fY |X (y |x) dx
R
48. Example
Let (X , Y ) be a two-dimensional normally distributed random
vector, N (µ1 , µ2 ; σ1 , σ2 ; r ).
The components X and Y are normally distributed: N (µ1 , σ1 )
and N (µ2 , σ2 ) respectively.
The conditional densities of X with respect to Y and Y with
respect to X are:
(x−m1 (y ))2
1 − 22
e 2(1−r )σ1 , ∀ (x, y ) ∈ R × R,
fX |Y (x|y ) =
r 2)
2π (1 −
σ1
(y −m2 (x))2
1 −
2(1−r 2 )σ 2
fY |X (y |x) = ∀ (y , x) ∈ R × R,
e 2,
2π (1 − r 2 )
σ2
where σ1 σ2
m1 (y ) = µ1 + r (y − µ2 ) , m2 (x) = µ2 + r (x − µ1 ) .
σ2 σ1
We remark that the two conditional densities correspond to the
√
normal distribution: N m1 (y ) , σ1 1 − r 2 and
√
N m2 (x) , σ2 1 − r 2 respectively.
49. In the Figure are presented the graphs of the two conditional
densities functions, when a two-dimensional normal distribution
with µ1 = µ2 = 0, σ1 = 1, σ2 = 2, r = −0.5 is considered, for
three values of the two components: X = −2, 0, 2 and
Y = −2, 0, 2.
X = −2
Y = −2
fX|Y(x|y) X=0
Y=0 fY|X(y|x)
X=2
Y=2
x 6y
−3 −2/3 0 2/3 3 −6 −3−1.5 0 1.5 3