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L18b-1
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Review: Growth of Silicon Film by CVD
Write out elementary reactions and assume a rate-limiting step
 
2 2
SiH g S SiH S
 
1. Adsorption
Rate of adsorption = rate of attachment – rate of detachment
AD SiH SiH v SiH SiH
2 2 2 2
r k P f k f

  SiH2
AD SiH SiH v
2 2
SiH2
f
r k P f
K
 
  
 
 
 
2. Surface reaction:  
2 2
SiH S Si S H g
  
S S SiH S Si H v
2 2
r k f k C P f

 
Si H v
2
S S SiH2
S
C C f
r k f
K
 
  
 
 
Si Si Si Si
Si
H
H
Si Si Si Si
Si
H
H
Si Si Si Si
Si
adsorption
Surface
reaction
fv & fSiH2: fraction of the surface covered by vacant sites or SiH2, respectively
Surface coverage is in terms of fraction of surface, not conc of active sites
L18b-2
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Gas-phase dissociation 4(g) 2(g) 2(g)
GeCl GeCl Cl

Adsorption (1)
kA
2(g) 2
k A
GeCl S GeCl S

 
Adsorption (2)
kH
2(g) k H
H 2S 2H S

 
Surface reaction    
kS
2
GeCl S 2H S Ge s 2HCl g 2S
   
  
Surface reaction is believed to be the rate-limiting step:
ks: surface specific reaction rate (nm/s)
fH2: Fraction on the surface occupied by H2
fGeCl2: fraction of the surface covered by GeCl2
Review: Growth of Germanium Films
by CVD
Germanium films have applications in microelectronics & solar cell fabrication
" 2
Dep S GeCl H
2
r k f f

Rate of Ge deposition (nm/s):
*Surface coverage is in terms of fraction of surface, not conc of active sites
L18b-3
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Review: Catalyst Deactivation Kinetics
• Adjustments for catalyst decay need to be made in the design of reactors
• Catalyst activity a(t) is used as a quantitative specification
 
'
A
'
A t 0
r (t)
a t
r 



Catalyst activity at time t:
Reaction rate for catalyst used for time t
Reaction rate for fresh, unused catalyst
For fresh, unused catalyst, t 0
a 1


 
0 a t 1
 
     
A A, B
r' a t k T fn C C ,....etc
 
Rate of consumption of reactant A on catalyst used for time t is:
a(t): time-dependent catalyst activity k(T): T-dependent specific rate constant
fn(CA, CB…etc): function of gas-phase conc. of reactants, products &
contaminants
Rate of catalyst decay:      
d d A B
da
r p a t k T h C ,C ,...,etc
dt
    
 
Function of activity
Temperature-dependent specific decay constant
Functionality of rd on reacting
species conc. h=1: no conc
dependence; h=Cj: linearly
dependent on concentration
L18b-4
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Review: Types of Catalyst Deactivation
3. Poisoning: molecules (product, reactant or impurity) irreversibly bind
to the active site
1. Sintering (aging): loss of active surface due to high temperature
Second-order decay of reaction rate with respect to present activity:
2
d d
r k a

 
d
1
a t
1 k t


Catalyst activity at time t:
  d
d d 0
0
E 1 1
k k T exp
R T T
 
 
 
 
 
 
 
Sintering decay constant:
2. Coking or fouling: carbonaceous material (coke) deposits on surface
n
C
C At

Concentration of carbon
on surface (g/m2):   m
1
a t
1 k't


Catalyst activity at time t:
A, n & m: fouling parameters
'
kd
P S N S
 
 
 
d d P
da
r a t k' C
dt
  
a(t): time-dependent catalyst activity
kd: specific decay constant
CP: concentration of the poison
L18b-5
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
•Reactant & catalyst enter at top of reactor
•Reactant & catalyst flow down the length of
the reactor together as a plug
•Product and spent catalyst (black) flow out of
reactor outlet
•Spent catalyst is regenerated by passing it
through a separate regeneration unit, and
newly regenerated catalyst is fed back into
the top of the reactor
Review: Moving-Bed Reactor
• When catalyst decay occurs at a significant rate, they require frequent
regeneration or replacement of the catalyst
• Moving-bed reactor enables continuous regeneration of spent catalyst
• Operates in the steady state, like a PBR
L18b-6
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Review: Moving-Bed Reactor Design
Reactants
u0 (dm3/s)
fresh
catalyst
US (g/s)
Z
Z + DZ
W
W + DW
Products & coked catalyst
Catalyst flow US << reactant flow u0
As far as the reactants are concerned,
the reactor acts like a PBR:
A
A0 A
dX
F r'
dW
 
n
d
da
Assume the decay rate law is: k a
dt


Find -da/dW and dXA/dW. Will need dt/dW.
Relate t to US:
S
W
t
U

S
dW
dt
U
 
Multiply dt/dW by -da/dt to get –da/dW:
S
dt 1
dW U
 
n
d
S
da dt 1
k a
dt dW U
 
  

   
   
n
d
S
k
da
a
dW U

 
If the rate of consumption of A for catalyst used for time t:      
A j
r' a W k T fn C
 
A A
A0
dX r '
dW F


    j
A
A0
a W k T fnC
dX
dW F
 
 
 
X W
A
A0 A
j
0 0
F dX
a W dW
k T fnC
 
 
L18b-7
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Guidelines for Deducing Mechanisms
• More than 70% of heterogeneous reaction mechanisms are surface
reaction limited
• If a species appears in the numerator of the rate law, it is probably a
reactant
• If a species appears in the denominator of the rate law, it is probably
adsorbed in the surface
L18b-8
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
Suggest a mechanism and rate-limiting step that is consistent with the rate law
E
E
E
E
H
kP P
r '
1 K P
 

The overall reaction for the hydrogenation (H) of ethylene (E) over a cobalt-
molybdenum catalyst to form ethane (A) is H2(g) + C2H4(g) → C2H6 (g) and the
observed rate law is:
PE appears in the denominator of the observed rate eq, so PE is adsorbed on
the surface. Neither PH or PA are in the denominator, so neither H or A are
adsorbed on the surface.
We’ll assume that the surface reaction is rate limiting
E S
AD A E V
AD
C
Adsorption: E S E S r k P C
K

 
   
 
 
E
S S
S H
Surface rxn: E S H A S r k C P

    
No desorption step - PA isn’t in the
denominator. Eliminate conc of
occupied & vacant sites on surface:
AD
E
A AD
E S
V
C
0 P
k
C
r
K

   V S
AD E
EC
K P C 
 
V E
t S
site balance: C
C C 
  A V
t D E
V K C
C C P
  
t
V
AD E
C
C
1 K P
 

E
S H
S
SC
r k P

 S t
AD
E H
E
AD
S
k P C
1 K
P
r
P
K

  t
S AD E
ADC
K
k k & K K
  E H
S
E E
kP P
r
1 K P
 

L18b-9
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
The experimental data for
the gas-phase, catalytic,
irreversible reaction A +
B→C is given in the table.
Suggest a rate law &
mechanism consistent with
the data.
Run PA (atm) PB (atm) PC (atm) -r’A(mol/g∙s)
1 0.1 1 2 0.073
2 1 10 2 3.42
3 10 1 2 0.54
4 1 20 2 6.80
5 1 20 10 2.88
6 20 1 2 0.56
7 1 1 2 0.34
8 1 20 5 4.5
Approach: Use graphs to
show how -r’A varies with
Pi when Pj and Pk are held
constant
0
0.2
0.4
0.6
0 10 20
-r'
A
PA (atm)
0
2
4
6
8
0 10 20
-r'
A
PB (atm)
0
2
4
6
8
0 5 10
-r'
A
PC (atm)
We need to use these graphs to determine whether A, B, & C are in
the numerator, denominator, or both.
L18b-10
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
The experimental data for
the gas-phase, catalytic,
irreversible reaction A +
B→C is given in the table.
Suggest a rate law &
mechanism consistent with
the data.
Run PA (atm) PB (atm) PC (atm) -r’A(mol/g∙s)
1 0.1 1 2 0.073
2 1 10 2 3.42
3 10 1 2 0.54
4 1 20 2 6.80
5 1 20 10 2.88
6 20 1 2 0.56
7 1 1 2 0.34
8 1 20 5 4.5
Approach: Use graphs to
show how -r’A varies with
Pi when Pj and Pk are held
constant
0
0.2
0.4
0.6
0 10 20
-r'
A
PA (atm)
-r’A increases rapidly at low PA (means its in the
numerator), but it levels off at high PA (means its in
the denominator)→ PA in numerator & denominator
of -r’A
A
A
A
kP ...
r '
1 kP ...
 

L18b-11
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
The experimental data for
the gas-phase, catalytic,
irreversible reaction A +
B→C is given in the table.
Suggest a rate law &
mechanism consistent with
the data.
Run PA (atm) PB (atm) PC (atm) -r’A(mol/g∙s)
1 0.1 1 2 0.073
2 1 10 2 3.42
3 10 1 2 0.54
4 1 20 2 6.80
5 1 20 10 2.88
6 20 1 2 0.56
7 1 1 2 0.34
8 1 20 5 4.5
Approach: Use graphs to
show how -r’A varies with
Pi when Pj and Pk are held
constant
0
0.2
0.4
0.6
0 10 20
-r'
A
PA (atm)
0
2
4
6
8
0 10 20
-r'
A
PB (atm)
-r’A increases linearly as
PB increases → PB is
only in the numerator
A B
A
A
kP P ...
r '
1 kP ...
 

A
A
A
kP ...
r '
1 kP ...
 

L18b-12
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
The experimental data for
the gas-phase, catalytic,
irreversible reaction A +
B→C is given in the table.
Suggest a rate law &
mechanism consistent with
the data.
Run PA (atm) PB (atm) PC (atm) -r’A(mol/g∙s)
1 0.1 1 2 0.073
2 1 10 2 3.42
3 10 1 2 0.54
4 1 20 2 6.80
5 1 20 10 2.88
6 20 1 2 0.56
7 1 1 2 0.34
8 1 20 5 4.5
Approach: Use graphs to
show how -r’A varies with
Pi when Pj and Pk are held
constant
0
2
4
6
8
0 10 20
-r'
A
PB (atm)
0
2
4
6
8
0 5 10
-r'
A
PC (atm)
A B
A
A
kP P ...
r '
1 kP ...
 

-r’A ↓ with ↑PC→ rnx is
irreversible so PC must
be in the denominator
of -r’A. Therefore, C is
adsorbed on surface
A B
A
A A C C
kP P
r '
1 K P K P
 
 
L18b-13
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
The rate law suggested for the experimental data given for the gas-phase,
catalytic, irreversible reaction A + B→C is:
Suggest a mechanism for this rate law.
A B
A
A A C C
kP P
r '
1 K P K P
 
 
PA and PC are in the denominator. A (reactant) and C (product) must be
adsorbed on the surface, but B is not adsorbed on the surface:
A S A S
  AD A A V A A S
r k P C k C
 
  A S
AD A A V
A
C
r k P C
K

 
  
 
 
C S C S
  DC D C S D C v
r k C k P C
 
  C V
DC D C S
D
P C
r k C
K

 
  
 
 
Adsorption of reactant A:
Desorption of product C:
L18b-14
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
The rate law suggested for the experimental data given for the gas-phase,
catalytic, irreversible reaction A + B→C is:
Suggest a mechanism for this rate law.
A B
A
A A C C
kP P
r '
1 K P K P
 
 
PA and PC are in the denominator. A (reactant) and C (product) must be
adsorbed on the surface, but B is not:
A S A S
  AD A A V A A S
r k P C k C
 
  A S
AD A A V
A
C
r k P C
K

 
  
 
 
C S C S
  DC D C S D C v
r k C k P C
 
  C V
DC D C S
D
P C
r k C
K

 
  
 
 
Adsorption of reactant A:
Desorption of product C:
Surface reaction step: B is not adsorbed on the surface, so B must be in the
gas phase when it reacts with A adsorbed on the surface.
The overall reaction is irreversible, so this step is likely irreversible.
A S B C S
    S S A S B
r k C P


L18b-15
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
The rate law suggested for the experimental data given on slide 14 for the
gas-phase, catalytic, irreversible reaction A + B→C is:
Suggest a mechanism for this rate law.
A B
A
A A C C
kP P
r '
1 K P K P
 
 
A S A S
 
A S
AD A A V
A
C
r k P C
K

 
 
 
 
C S C S
  C V
DC D C S
D
P C
r k C
K

 
 
 
 
Adsorption of reactant A:
Desorption of product C:
A S B C S
    S S A S B
r k C P


Surface reaction:
Postulate that the surface reaction is the rate limiting step since that is true
the majority of the time. Check if that is consistent with the observed kinetics
A S S B
A S
r ' r k C P

   Eliminate CA∙S & Cv
from rate eq
AD
A V
A A
A S
r
0 P
k K
C
C 
   A
A
A
S
V
C
P
K
C 
  V
A A A S
C
K P C 
 
A C S
t v S
C C
C
C  
  
C
DC C
D D
V
S
C
r C
P
0
k K

   C
C
D
V
S
P
C
K
C

  Insert into site balance
and solve for Cv
L18b-16
Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign.
The rate law suggested for the experimental data given on slide 13 for the gas-
phase, catalytic, irreversible reaction A + B→C is:
Suggest a mechanism for this rate law.
A B
A
A A C C
kP P
r '
1 K P K P
 
 
A S A S
 
A S
AD A A V
A
C
r k P C
K

 
 
 
 
C S C S
 
C V
DC D C S
D
P C
r k C
K

 
 
 
 
Adsorption of reactant A: Desorption of product C:
A S B C S
   
S S A S B
r k C P


Surface reaction:
Postulated surface
reaction is rate limiting
A S
A S S B S V
A B
A
r ' r k P
C K P C
k P

    A A V
S A
C K P C
 
A C S
t v S
C C
C
C  
  
C S C V D
C P C K
 
A A
t
D
v V
C V
C C
K
C
C
P
K
P
   
t
v
A A C D
C
C
1 K P P K




S t
A A
B
C D
A
S
A
k P
C
1 K P K
P
r
K
P
 
 
A S
A S S B S V
A B
A
r ' r k P
C K P C
k P

   
C
D
1
K
K
 S t
A
k k K C
 A B
S
A A C C
P P
r
1 K P K P
k
 
 

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L18b Deducing mechanisms example problems.pptx

  • 1. L18b-1 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Review: Growth of Silicon Film by CVD Write out elementary reactions and assume a rate-limiting step   2 2 SiH g S SiH S   1. Adsorption Rate of adsorption = rate of attachment – rate of detachment AD SiH SiH v SiH SiH 2 2 2 2 r k P f k f    SiH2 AD SiH SiH v 2 2 SiH2 f r k P f K            2. Surface reaction:   2 2 SiH S Si S H g    S S SiH S Si H v 2 2 r k f k C P f    Si H v 2 S S SiH2 S C C f r k f K          Si Si Si Si Si H H Si Si Si Si Si H H Si Si Si Si Si adsorption Surface reaction fv & fSiH2: fraction of the surface covered by vacant sites or SiH2, respectively Surface coverage is in terms of fraction of surface, not conc of active sites
  • 2. L18b-2 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Gas-phase dissociation 4(g) 2(g) 2(g) GeCl GeCl Cl  Adsorption (1) kA 2(g) 2 k A GeCl S GeCl S    Adsorption (2) kH 2(g) k H H 2S 2H S    Surface reaction     kS 2 GeCl S 2H S Ge s 2HCl g 2S        Surface reaction is believed to be the rate-limiting step: ks: surface specific reaction rate (nm/s) fH2: Fraction on the surface occupied by H2 fGeCl2: fraction of the surface covered by GeCl2 Review: Growth of Germanium Films by CVD Germanium films have applications in microelectronics & solar cell fabrication " 2 Dep S GeCl H 2 r k f f  Rate of Ge deposition (nm/s): *Surface coverage is in terms of fraction of surface, not conc of active sites
  • 3. L18b-3 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Review: Catalyst Deactivation Kinetics • Adjustments for catalyst decay need to be made in the design of reactors • Catalyst activity a(t) is used as a quantitative specification   ' A ' A t 0 r (t) a t r     Catalyst activity at time t: Reaction rate for catalyst used for time t Reaction rate for fresh, unused catalyst For fresh, unused catalyst, t 0 a 1     0 a t 1         A A, B r' a t k T fn C C ,....etc   Rate of consumption of reactant A on catalyst used for time t is: a(t): time-dependent catalyst activity k(T): T-dependent specific rate constant fn(CA, CB…etc): function of gas-phase conc. of reactants, products & contaminants Rate of catalyst decay:       d d A B da r p a t k T h C ,C ,...,etc dt        Function of activity Temperature-dependent specific decay constant Functionality of rd on reacting species conc. h=1: no conc dependence; h=Cj: linearly dependent on concentration
  • 4. L18b-4 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Review: Types of Catalyst Deactivation 3. Poisoning: molecules (product, reactant or impurity) irreversibly bind to the active site 1. Sintering (aging): loss of active surface due to high temperature Second-order decay of reaction rate with respect to present activity: 2 d d r k a    d 1 a t 1 k t   Catalyst activity at time t:   d d d 0 0 E 1 1 k k T exp R T T               Sintering decay constant: 2. Coking or fouling: carbonaceous material (coke) deposits on surface n C C At  Concentration of carbon on surface (g/m2):   m 1 a t 1 k't   Catalyst activity at time t: A, n & m: fouling parameters ' kd P S N S       d d P da r a t k' C dt    a(t): time-dependent catalyst activity kd: specific decay constant CP: concentration of the poison
  • 5. L18b-5 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. •Reactant & catalyst enter at top of reactor •Reactant & catalyst flow down the length of the reactor together as a plug •Product and spent catalyst (black) flow out of reactor outlet •Spent catalyst is regenerated by passing it through a separate regeneration unit, and newly regenerated catalyst is fed back into the top of the reactor Review: Moving-Bed Reactor • When catalyst decay occurs at a significant rate, they require frequent regeneration or replacement of the catalyst • Moving-bed reactor enables continuous regeneration of spent catalyst • Operates in the steady state, like a PBR
  • 6. L18b-6 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Review: Moving-Bed Reactor Design Reactants u0 (dm3/s) fresh catalyst US (g/s) Z Z + DZ W W + DW Products & coked catalyst Catalyst flow US << reactant flow u0 As far as the reactants are concerned, the reactor acts like a PBR: A A0 A dX F r' dW   n d da Assume the decay rate law is: k a dt   Find -da/dW and dXA/dW. Will need dt/dW. Relate t to US: S W t U  S dW dt U   Multiply dt/dW by -da/dt to get –da/dW: S dt 1 dW U   n d S da dt 1 k a dt dW U               n d S k da a dW U    If the rate of consumption of A for catalyst used for time t:       A j r' a W k T fn C   A A A0 dX r ' dW F       j A A0 a W k T fnC dX dW F       X W A A0 A j 0 0 F dX a W dW k T fnC    
  • 7. L18b-7 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Guidelines for Deducing Mechanisms • More than 70% of heterogeneous reaction mechanisms are surface reaction limited • If a species appears in the numerator of the rate law, it is probably a reactant • If a species appears in the denominator of the rate law, it is probably adsorbed in the surface
  • 8. L18b-8 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. Suggest a mechanism and rate-limiting step that is consistent with the rate law E E E E H kP P r ' 1 K P    The overall reaction for the hydrogenation (H) of ethylene (E) over a cobalt- molybdenum catalyst to form ethane (A) is H2(g) + C2H4(g) → C2H6 (g) and the observed rate law is: PE appears in the denominator of the observed rate eq, so PE is adsorbed on the surface. Neither PH or PA are in the denominator, so neither H or A are adsorbed on the surface. We’ll assume that the surface reaction is rate limiting E S AD A E V AD C Adsorption: E S E S r k P C K            E S S S H Surface rxn: E S H A S r k C P       No desorption step - PA isn’t in the denominator. Eliminate conc of occupied & vacant sites on surface: AD E A AD E S V C 0 P k C r K     V S AD E EC K P C    V E t S site balance: C C C    A V t D E V K C C C P    t V AD E C C 1 K P    E S H S SC r k P   S t AD E H E AD S k P C 1 K P r P K    t S AD E ADC K k k & K K   E H S E E kP P r 1 K P   
  • 9. L18b-9 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. The experimental data for the gas-phase, catalytic, irreversible reaction A + B→C is given in the table. Suggest a rate law & mechanism consistent with the data. Run PA (atm) PB (atm) PC (atm) -r’A(mol/g∙s) 1 0.1 1 2 0.073 2 1 10 2 3.42 3 10 1 2 0.54 4 1 20 2 6.80 5 1 20 10 2.88 6 20 1 2 0.56 7 1 1 2 0.34 8 1 20 5 4.5 Approach: Use graphs to show how -r’A varies with Pi when Pj and Pk are held constant 0 0.2 0.4 0.6 0 10 20 -r' A PA (atm) 0 2 4 6 8 0 10 20 -r' A PB (atm) 0 2 4 6 8 0 5 10 -r' A PC (atm) We need to use these graphs to determine whether A, B, & C are in the numerator, denominator, or both.
  • 10. L18b-10 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. The experimental data for the gas-phase, catalytic, irreversible reaction A + B→C is given in the table. Suggest a rate law & mechanism consistent with the data. Run PA (atm) PB (atm) PC (atm) -r’A(mol/g∙s) 1 0.1 1 2 0.073 2 1 10 2 3.42 3 10 1 2 0.54 4 1 20 2 6.80 5 1 20 10 2.88 6 20 1 2 0.56 7 1 1 2 0.34 8 1 20 5 4.5 Approach: Use graphs to show how -r’A varies with Pi when Pj and Pk are held constant 0 0.2 0.4 0.6 0 10 20 -r' A PA (atm) -r’A increases rapidly at low PA (means its in the numerator), but it levels off at high PA (means its in the denominator)→ PA in numerator & denominator of -r’A A A A kP ... r ' 1 kP ...   
  • 11. L18b-11 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. The experimental data for the gas-phase, catalytic, irreversible reaction A + B→C is given in the table. Suggest a rate law & mechanism consistent with the data. Run PA (atm) PB (atm) PC (atm) -r’A(mol/g∙s) 1 0.1 1 2 0.073 2 1 10 2 3.42 3 10 1 2 0.54 4 1 20 2 6.80 5 1 20 10 2.88 6 20 1 2 0.56 7 1 1 2 0.34 8 1 20 5 4.5 Approach: Use graphs to show how -r’A varies with Pi when Pj and Pk are held constant 0 0.2 0.4 0.6 0 10 20 -r' A PA (atm) 0 2 4 6 8 0 10 20 -r' A PB (atm) -r’A increases linearly as PB increases → PB is only in the numerator A B A A kP P ... r ' 1 kP ...    A A A kP ... r ' 1 kP ...   
  • 12. L18b-12 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. The experimental data for the gas-phase, catalytic, irreversible reaction A + B→C is given in the table. Suggest a rate law & mechanism consistent with the data. Run PA (atm) PB (atm) PC (atm) -r’A(mol/g∙s) 1 0.1 1 2 0.073 2 1 10 2 3.42 3 10 1 2 0.54 4 1 20 2 6.80 5 1 20 10 2.88 6 20 1 2 0.56 7 1 1 2 0.34 8 1 20 5 4.5 Approach: Use graphs to show how -r’A varies with Pi when Pj and Pk are held constant 0 2 4 6 8 0 10 20 -r' A PB (atm) 0 2 4 6 8 0 5 10 -r' A PC (atm) A B A A kP P ... r ' 1 kP ...    -r’A ↓ with ↑PC→ rnx is irreversible so PC must be in the denominator of -r’A. Therefore, C is adsorbed on surface A B A A A C C kP P r ' 1 K P K P    
  • 13. L18b-13 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. The rate law suggested for the experimental data given for the gas-phase, catalytic, irreversible reaction A + B→C is: Suggest a mechanism for this rate law. A B A A A C C kP P r ' 1 K P K P     PA and PC are in the denominator. A (reactant) and C (product) must be adsorbed on the surface, but B is not adsorbed on the surface: A S A S   AD A A V A A S r k P C k C     A S AD A A V A C r k P C K           C S C S   DC D C S D C v r k C k P C     C V DC D C S D P C r k C K           Adsorption of reactant A: Desorption of product C:
  • 14. L18b-14 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. The rate law suggested for the experimental data given for the gas-phase, catalytic, irreversible reaction A + B→C is: Suggest a mechanism for this rate law. A B A A A C C kP P r ' 1 K P K P     PA and PC are in the denominator. A (reactant) and C (product) must be adsorbed on the surface, but B is not: A S A S   AD A A V A A S r k P C k C     A S AD A A V A C r k P C K           C S C S   DC D C S D C v r k C k P C     C V DC D C S D P C r k C K           Adsorption of reactant A: Desorption of product C: Surface reaction step: B is not adsorbed on the surface, so B must be in the gas phase when it reacts with A adsorbed on the surface. The overall reaction is irreversible, so this step is likely irreversible. A S B C S     S S A S B r k C P  
  • 15. L18b-15 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. The rate law suggested for the experimental data given on slide 14 for the gas-phase, catalytic, irreversible reaction A + B→C is: Suggest a mechanism for this rate law. A B A A A C C kP P r ' 1 K P K P     A S A S   A S AD A A V A C r k P C K          C S C S   C V DC D C S D P C r k C K          Adsorption of reactant A: Desorption of product C: A S B C S     S S A S B r k C P   Surface reaction: Postulate that the surface reaction is the rate limiting step since that is true the majority of the time. Check if that is consistent with the observed kinetics A S S B A S r ' r k C P     Eliminate CA∙S & Cv from rate eq AD A V A A A S r 0 P k K C C     A A A S V C P K C    V A A A S C K P C    A C S t v S C C C C      C DC C D D V S C r C P 0 k K     C C D V S P C K C    Insert into site balance and solve for Cv
  • 16. L18b-16 Slides courtesy of Prof M L Kraft, Chemical & Biomolecular Engr Dept, University of Illinois at Urbana-Champaign. The rate law suggested for the experimental data given on slide 13 for the gas- phase, catalytic, irreversible reaction A + B→C is: Suggest a mechanism for this rate law. A B A A A C C kP P r ' 1 K P K P     A S A S   A S AD A A V A C r k P C K          C S C S   C V DC D C S D P C r k C K          Adsorption of reactant A: Desorption of product C: A S B C S     S S A S B r k C P   Surface reaction: Postulated surface reaction is rate limiting A S A S S B S V A B A r ' r k P C K P C k P      A A V S A C K P C   A C S t v S C C C C      C S C V D C P C K   A A t D v V C V C C K C C P K P     t v A A C D C C 1 K P P K     S t A A B C D A S A k P C 1 K P K P r K P     A S A S S B S V A B A r ' r k P C K P C k P      C D 1 K K  S t A k k K C  A B S A A C C P P r 1 K P K P k    