This slide is contains the important concept of java Literals. so plz read this slide for getting the standard knowledge.and give the feedback also.

1. Literals:
A constant value which can be assigned to the variable is called Literals.
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2.  For the Integral data types (byte, short, int, long) the following are various
ways to specify Literal value.
Decimal Literals :-
 Allowed digit are 0 to 9
Example: int x=10;
Integral Literals:
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3. 2) Octal Literals :-
 Allowed digit are 0 to 7
 Literal value should be prefixed with 0 [zero]
Example: int x= 010;
3) Hexadecimal Literals :-
 Allowed digit are 0 to 9 , a to f [OR] A to F
 For the extra digits we can use both upper case & lower case this is one of very few places where java is not case
sensitive.
 Literal value should be prefixed with 0x [OR] 0X
Example: int x= 0x10;
[OR]
Int x=0X10;
 These are the only possible ways to specify integral Literal.
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4. Example:
class TestLiterals
{
public static void main(String args[])
{
int x=10;
int y=010;
int z=0X10;
System.out.println(x+"---"+y+"-----"+z);
}
}
Output:- (10)8 = (?)10
0*80 +1*81 =8
(10)16 = (?)10
0*160 +1*161 =16
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5. Que-) which of the following declarations are valid.
1.int x=10;
2.int x=066;
3.int x=0786; CE: integer number too large: 0786
4.int x=0XFACE; // 64206
5.int x=0xBea; // 3050
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6. By default every integral Literal is of int type but we can specify explicitly as long type by
suffixing with l or L
Example;
1)int i=10; // Valid
2) int i=10l; CE: possible loss of precision
int i=10l;
^ required: int
found: long
1)long l=10l; // Valid
2)long l=10; // Valid
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7.  There is no way to specify integral Literal is of byte & short types explicitly.
 If we are assigning integral Literal to the byte variable & that integral literal is within the
range of byte then it treats as byte literal automatically. Similarly short Literal also.
byte b=10; Valid
byte b=130;
CE: possible loss of precision
int i=10l;
^ required: byte
found: int
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8. By default the decimal point values represent double type & hence
we cannot assign directly to float variable.
 So if we want to assign the floating point values to the variables
we must attach the suffix F or f to the number. If we are not providing
the number we will get compilation error possible loss of precision.
Floating point literal & double literal:-
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9.  Example-
float f=123.456;
CE: possible loss of precision
Found: double
Required: float
float f=123.456f; // valid
double d=123.456; //valid
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10.  We can specify floating point literal explicitly as double type by suffixing
with d or D.
Ex- double d=123.456D; // valid
float f=123.4567d; // Invalid
CE: possible loss of precision
Found: double
Required: float
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11.  We can specify floating point literal only in decimal form & we can’t specify
in octal & hexadecimal form.
Example:
double d=123.456;(valid)
double d=0123.456;(valid) //it is treated as decimal value but not octal
double d=0x123.456; //C. E: malformed floating point literal(invalid)
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12. Which of the following floating point declarations are valid?
float f=123.456; //C.E:possible loss of precision(invalid)
float f=123.456D; //C.E:possible loss of precision(invalid)
double d=0x123.456; //C.E:malformed floating point literal(invalid)
double d=0xFace; (valid)
double d=0xBeef; (valid)
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13. We can assign integral literal directly to the floating point data types and that integral literal can
be specified in decimal, octal and Hexa decimal form also.
Example:
double d=0xBeef;
System.out.println(d);//48879.0
But we can't assign floating point literal directly to the integral types.
Example:
int x=10.0;//C.E:possible loss of precision
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14. A char literal can be represented as single character within single quotes.
Example:
char ch='a';(valid)
char ch=a;//C.E:cannot find symbol(invalid)
char ch="a";//C.E:incompatible types(invalid)
char ch='ab';//C.E:unclosed character literal(invalid)
Char literals:-
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15.  We can specify a char literal as integral literal which represents Unicode of that
character.
 We can specify that integral literal either in decimal or octal or hexadecimal
form but allowed values range is 0 to 65535.
 Example:
char ch=97; (valid)
char ch=0xFace; (valid)
System.out.println(ch); //?
char ch=65536; //C.E: possible loss of precision(invalid)
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16.  The only allowed values for the boolean type are true (or) false where
case is important. i.e., lower case
Example:
boolean b=true; (valid)
boolean b=0; //C.E:incompatible types(invalid)
boolean b=True; //C.E:cannot find symbol(invalid)
boolean b="true"; //C.E:incompatible types(invalid)
Boolean literal:-
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18. The following 2 are enhancements
1. Binary Literals
2. Usage of '_' in Numeric Literals
• Binary Literals:
 For the integral data types until 1.6v we can specified literal value in the following
ways
1. Decimal
2. Octal
3. Hexa decimal
1.7 Version enhancements with respect to Literals:
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19.  But from 1.7v onwards we can have specified literal value in binary form also.
 The allowed digits are 0 to 1.
 Literal value should be prefixed with Ob or OB
int x = 0b111;
System.out.println(x); // 7
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20. Usage of _ symbol in numeric literals:
 From 1.7v onwards we can use underscore (_) symbol in numeric literals.
double d = 123456.789; //valid
double d = 1_23_456.7_8_9; //valid
double d = 123_456.7_8_9; //valid
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21. The main advantage of this approach is readability of the code will be improved at the time of
compilation ' _ ' symbols will be removed automatically, hence after compilation the above
lines will become double d = 123456.789
We can use more than one underscore symbol also between the digits.
Ex: double d = 1_23_ _456.789;
We should use underscore symbol only between the digits.
double d=_1_23_456.7_8_9; //invalid
double d=1_23_456.7_8_9_; //invalid
double d=1_23_456_.7_8_9; //invalid
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