SlideShare a Scribd company logo
How to Solve the Force
Problems
physicscatalyst.com
How to Solve the Force Problems
1) First Draw Nice diagram of Situation and show all the
forces acting the system with vector
2) Draw the Free body diagram for each body in the
system and show all the forces acting on it with nice
arrows and vector
3) Choose an suitable XY Coordinate system and resolve
all the force on the X and Y direction . And apply F=ma
equation separately to x and y components
4) Check the list of known and unknown values and solve
the equations formed by Newton’s law to reach at the
value of unknown. Keep in mind, we need as many
equation as many unknown values.
5) Units could be very helpful in some cases. The equation
should have same unit on both sides.
physicscatalyst.com
Question : Consider a three body system shown in figure below
1) Find the acceleration of the each object
2) Find the contact force between all the objects
Solution
• Let a be the acceleration of the system
• Let f1 be the contact force between A and B
• Let f2 be the contact force between B and C
• Let’s draw free body diagram for each object
physicscatalyst.com
Solution continued
For object A
F- f1 = m1a ---(1)
For object B
f1 – f2 =m2 a ---(2)
For object C
f2 =m3 a ---(3)
Adding 1 ,2 and 3 we get
Substituting the value in 1 and 3 ,we get
a=
321 mmm
F
++
f1
=
321
32 )(
mmm
Fmm
++
+
f2
=
321
3
mmm
Fm
++
physicscatalyst.com
Question : A Body of mass m moves along X axis such that at time t,its
position is given by
Where a,b ,c are constant.
Find the acceleration of the body and force acting on it
ctbtattx +−= 34
)(
Solution: Velocity and acceleration could be find out using the
first and second differential
btat
dt
xd
cbtat
dt
dx
69
33
2
2
2
23
−=
+−=
According to Newton’s Law, Force is given by
F=ma
So
)23(3)69( 2
btmtbtatmF −=−= physicscatalyst.com
Question : A Body of mass m moves along X axis such that at time t,its
position is given by
Where a,b ,c are constant.
Find the acceleration of the body and force acting on it
ctbtattx +−= 34
)(
Solution: Velocity and acceleration could be find out using the
first and second differential
btat
dt
xd
cbtat
dt
dx
69
33
2
2
2
23
−=
+−=
According to Newton’s Law, Force is given by
F=ma
So
)23(3)69( 2
btmtbtatmF −=−= physicscatalyst.com

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How to Solve the Force Problems

  • 1. How to Solve the Force Problems physicscatalyst.com
  • 2. How to Solve the Force Problems 1) First Draw Nice diagram of Situation and show all the forces acting the system with vector 2) Draw the Free body diagram for each body in the system and show all the forces acting on it with nice arrows and vector 3) Choose an suitable XY Coordinate system and resolve all the force on the X and Y direction . And apply F=ma equation separately to x and y components 4) Check the list of known and unknown values and solve the equations formed by Newton’s law to reach at the value of unknown. Keep in mind, we need as many equation as many unknown values. 5) Units could be very helpful in some cases. The equation should have same unit on both sides. physicscatalyst.com
  • 3. Question : Consider a three body system shown in figure below 1) Find the acceleration of the each object 2) Find the contact force between all the objects Solution • Let a be the acceleration of the system • Let f1 be the contact force between A and B • Let f2 be the contact force between B and C • Let’s draw free body diagram for each object physicscatalyst.com
  • 4. Solution continued For object A F- f1 = m1a ---(1) For object B f1 – f2 =m2 a ---(2) For object C f2 =m3 a ---(3) Adding 1 ,2 and 3 we get Substituting the value in 1 and 3 ,we get a= 321 mmm F ++ f1 = 321 32 )( mmm Fmm ++ + f2 = 321 3 mmm Fm ++ physicscatalyst.com
  • 5. Question : A Body of mass m moves along X axis such that at time t,its position is given by Where a,b ,c are constant. Find the acceleration of the body and force acting on it ctbtattx +−= 34 )( Solution: Velocity and acceleration could be find out using the first and second differential btat dt xd cbtat dt dx 69 33 2 2 2 23 −= +−= According to Newton’s Law, Force is given by F=ma So )23(3)69( 2 btmtbtatmF −=−= physicscatalyst.com
  • 6. Question : A Body of mass m moves along X axis such that at time t,its position is given by Where a,b ,c are constant. Find the acceleration of the body and force acting on it ctbtattx +−= 34 )( Solution: Velocity and acceleration could be find out using the first and second differential btat dt xd cbtat dt dx 69 33 2 2 2 23 −= +−= According to Newton’s Law, Force is given by F=ma So )23(3)69( 2 btmtbtatmF −=−= physicscatalyst.com