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Probability
Problems
Tutorial on Probability
Class 9
Quiz
Question 1: A coin is tossed 1000 times; we get
499 times head and 501 times
1) What is the empirical probability of getting
head ?
2) What is the empirical probability of getting
tail?
3) Does the sum of above two probability equals
1?
Solution
Total number of trials =1000
No of trails which head came =499
So No of trails where tail came=1000-499=501
a) Now Empirical probability of getting
head=(No of trails which heads
came)/(Total Number of trials)
empirical probability of getting
head=499/1000
So empirical or experimental probability
of getting head P(H) is calculated as
=.499
Solution
b) empirical probability of getting tail
=(No of trails which tails came)/(Total
Number of trials)
Sp empirical probability of getting
head=501/1000
So empirical or experimental probability
of getting head P(T) is calculated as
=.501
c) Now P(H) +P(T)= .499+.501=1
Question-2
In a cricket match, a batswoman hits a
boundary 6 times out of 30 balls she plays. Find
the probability that she did not hit a boundary.
Solution:
Let P is the event of hitting the boundary
n(P)=6
Let Q be the event of not hitting the boundary
n(Q)= 30- n(P)=24
Probability of not hitting the
boundary= n(Q)/30= 24/30=4/5
For more notes and study
material please visit our
website
http://physicscatalyst.com

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Probability Problems

  • 2. Quiz Question 1: A coin is tossed 1000 times; we get 499 times head and 501 times 1) What is the empirical probability of getting head ? 2) What is the empirical probability of getting tail? 3) Does the sum of above two probability equals 1?
  • 3. Solution Total number of trials =1000 No of trails which head came =499 So No of trails where tail came=1000-499=501 a) Now Empirical probability of getting head=(No of trails which heads came)/(Total Number of trials) empirical probability of getting head=499/1000 So empirical or experimental probability of getting head P(H) is calculated as =.499
  • 4. Solution b) empirical probability of getting tail =(No of trails which tails came)/(Total Number of trials) Sp empirical probability of getting head=501/1000 So empirical or experimental probability of getting head P(T) is calculated as =.501 c) Now P(H) +P(T)= .499+.501=1
  • 5. Question-2 In a cricket match, a batswoman hits a boundary 6 times out of 30 balls she plays. Find the probability that she did not hit a boundary. Solution: Let P is the event of hitting the boundary n(P)=6 Let Q be the event of not hitting the boundary n(Q)= 30- n(P)=24 Probability of not hitting the boundary= n(Q)/30= 24/30=4/5
  • 6. For more notes and study material please visit our website http://physicscatalyst.com