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File PrintCoded.java (shown above) contains an incomplete program. The goal of the program is to take as input strings from the user, and then print out coded (encrypted) versions of those strings, by replacing each letter with another letter. Complete that program, by defining a printCoded function, that satisfies the following specs: Function printCoded takes three arguments, called word, sources, targets. They are all strings. Function printCoded processes the letters of word one by one, in the order in which they appear in word. For every such letter X, the function processes X as follows: If X is equal to the character at position P of sources, then the function prints the character at position P of targets. Otherwise, the function prints X. Note that arguments sources and targets are hardcoded in the main function, the user cannot change those values. The user can only specify the value of word. IMPORTANT: you are NOT allowed to modify in any way the main function. This is an example run of the complete program: Solution PrintCoded.java import java.util.Scanner; public class PrintCoded { public static void main(String[] args) { Scanner in = new Scanner(System.in); String sources = \"abcdefghijklmnopqrstuvwxyz\"; String targets = \"bcdefghijklmnopqrstuvwxyza\"; while (true) { System.out.printf(\"Enter some word, or q to quit: \"); String word = in.next(); if (word.equals(\"q\")) { System.out.printf(\"Exiting...\ \"); System.exit(0); } printCoded(word, sources, targets); System.out.printf(\"\ \ \"); } } public static void printCoded(String word, String sources, String targets){ for(int i=0; i.
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![File PrintCoded.java (shown above) contains an incomplete program. The goal of the program is
to take as input strings from the user, and then print out coded (encrypted) versions of those
strings, by replacing each letter with another letter. Complete that program, by defining a
printCoded function, that satisfies the following specs:
Function printCoded takes three arguments, called word, sources, targets. They are all strings.
Function printCoded processes the letters of word one by one, in the order in which they appear
in word. For every such letter X, the function processes X as follows:
If X is equal to the character at position P of sources, then the function prints the character at
position P of targets.
Otherwise, the function prints X.
Note that arguments sources and targets are hardcoded in the main function, the user cannot
change those values. The user can only specify the value of word.
IMPORTANT: you are NOT allowed to modify in any way the main function.
This is an example run of the complete program:
Solution
PrintCoded.java
import java.util.Scanner;
public class PrintCoded
{
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
String sources = "abcdefghijklmnopqrstuvwxyz";
String targets = "bcdefghijklmnopqrstuvwxyza";
while (true)
{
System.out.printf("Enter some word, or q to quit: ");
String word = in.next();](https://image.slidesharecdn.com/fileprintcoded-230707032551-be32564c/85/File-PrintCoded-java-shown-above-contains-an-incomplete-program-T-pdf-1-320.jpg)
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PROJECT IN C LANGUAGE FOR O LEVEL
CONTACT ME FOR ZIP FILE (WITH SOURCE CODE)
EMAIL- ss1079@yahoo.in
Recommended
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this material will help the engineering students in understanding the concepts of C language
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CONTACT ME FOR ZIP FILE (WITH SOURCE CODE)
EMAIL- ss1079@yahoo.in
import java.util.Scanner;Henry Cutler ID 1234 7202.docx
import java.util.Scanner;
/*
Henry Cutler ID 1234 7/20/2015
Assignment #5, 3 features in 1 program
Solution
for Assignment#5 COP2800
Pseudocode:
Program has three features, all in a single program that are user selectable.
Prompt with options and get user choice inside a while statement ( true )
If 1 is entered:
Using a while and for loop, print out the ASCII table from ! to ~.
If 2 is entered:
Prompt the user for number of times to flip for head or tails using the random method. Count number of each and when the request times are done, print out the results.
If 3 is entered:
Prompt the user for a strings and print back the count of vowels and letters
Any other input entered program will exit using a break statement, otherwise loops back to prompt user for feature selection.
*/
public class Module5 {
public static void main(String[] args) {
// prompt the user
System.out.println("Welcome to Henry\'s 3 in 1 Programming Assignment for Module 5\n");
// create Scanner Object
Scanner input = new Scanner(System.in);
// loop until break
while(true){
// new lines for readability
System.out.print("\n");
// Prompt user for choices
System.out.print("Enter 1 for ASCII Table \nEnter 2 for Heads or Tails\nEnter 3 for Count Vowels & Letters\nAny other input will exit");
int choice = input.nextInt();
// Consume newline left-over
input.nextLine();
// first feature
if(choice == 1){
// start value is !
int value = (int) '!';
// newline for formating
System.out.println("You Selected ASCII Table!\n");
// start at ~ which is 33 decimal
while( value <= '~')
{
// print out 20 in a line
for( int count = 0; count < 20; count ++ ){
if( value <= '~'){
// print single value
System.out.print( (char) value++ );
}
else {
// break when we are at last char to print
break;
}
}
// New line every 10
System.out.print("\n");
}
// New line at exit
System.out.print("\n");
}
else if(choice == 2){
// Prompt user
System.out.println("You Selected Head or Tails!");
System.out.println("\nHow many flips would you like to try?");
// get value
int count = input.nextInt();
// clear
input.nextLine();
int headCount = 0;
int tailCount = 0;
// run for a count provided by user
for (int i = 0; i < count; i++) {
// get random number
if (Math.random() > 0.5){
// increment heads
headCount++;
}
else {
// increment tails
tailCount++;
}
}
System.out.println("Head count: " + headCount + " tail count: " + tailCount);
}
else if(choice == 3){
// Prompt user
Sys.
COMPILER DESIGN- Introduction & Lexical Analysis:
COMPILER DESIGN- Introduction & Lexical Analysis: Jyothishmathi Institute of Technology and Science Karimnagar
Introduction: Language Processors, the structure of a compiler, the science of building a compiler, programming language basics.
Lexical Analysis: The Role of the Lexical Analyzer, Input Buffering, Recognition of Tokens, The Lexical-Analyzer Generator Lex, Finite Automata, From Regular Expressions to Automata, Design of a Lexical-Analyzer Generator, Optimization of DFA-Based Pattern Matchers
Your 1ab8 c file is doe by Friday 1159pm to be submitted.pdf
Your 1ab8. c file is doe by Friday, 11.59pm, to be submitted on Gradescope. Overview This week,
you will start with last week's program and create your own functions for some of the tasks. You'll
have a printmenu () function, printarray () function and a convertcase () function. Just like you saw
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shown below in the Lab Assignment section. All the functions will be in one file, called lab8.c.
Background Information For this lab, you will use last week's program to start with. Copy it and
rename it lab8.c. Again, you will be adding more code to this program in the future, so make sure
you get this one working. Functions and Reminders 1. As you saw in class, functions perform
(usually) one task, or a couple of smaller tasks that combined perform a task. 2. Some functions
return a value (the retum type being specified in the functon header/signature and a return
statement at the bottom of the function): int printmenu() & and some functions do not return any
value (the retum type then being specified as void and no return statement at the bottom of the
function): void convertCase (char text [MAX_LINE] [MAX_LINE_LEN] ) i 3. When arguments are
being sent to the function, the function then has "parameters" specified in the function
header/signature. The parameters that are specified indicate the type and the name: void
printarray (char text[MAX_LINE] [MAX_LINE_LEN], int size) { If a function is not being sent any
arguments, then the parameter list will be empty (meaning nothing in the parentheses). int
printMenu() f / / empty parentheses 4. When sending a 1-D array to a function, the parameter can
be specified with empty square brackets: int findLowest (int theArray[], int size) f // from in-class
exercise When a 2-D array is sent to a function, however, the parameter has to at least specify the
number of columns. So the parameter can be specified as: void f1 (int array [][12]) If a variable is
being used for the dimension(s) of the array, then the variable must appear first in the list of
parameters: void 11 (int numRows, int numCols, int array 1 [numRows] [numCols]) For this lab,
since the number of rows and number of columns are either idefine or constants, defined outside
of the main0 function, the parameter showing the array can use those names for the dimensions
without including them in the parameter list: void convertCase (char text[MAX_LINE]
[MAX_LINE_LEN]) I 5. As discussed in class, to eliminate chances of confusion, you should
ensure that there is no variable shadowing (the argument being sent to the function has a different
name than the parameter). 6. Function prototypes should be at the top of the file, EVFN IF THE
MAINO FUNCTION IS AT THE BOTTOM OF5. Function prototypes should be at the top of the file,
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Instructions Write a program whose main function is merely a.pdf
Instructions
Write a program whose main function is merely a collection of variable declarations and function
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below in the function printResult. (There can be no global variables! All information must be
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names of the input and output files.
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must be passed as a parameter, and the file identifier must also be passed as a parameter.
Function printResult: Prints the number of capital letters and small letters, as well as the
percentage of capital letters for every letter A-Z and the percentage of small letters for every letter
a-z. The percentages should look like this: "25%".This information must come from an array of
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Which of the following properties best describes pentoses? Pentoses provide a significant
amount of energy; Pentoses are key constituents of NADP+; Pentoses are used for synthesis of
hexoses; Pentoses are prevalent in diet; Pentoses are aldoses.
Solution
correct answer is :
a.Pentoses produce a significant amount of energy.
pentoses have a group of sugars like fructose, ribose, xylose etc, which help in the prodution of
energy through various nmetabol,ic processes..
What is going to be the output of the following program #include .pdf
What is going to be the output of the following program: #include voidfM (int m[10]) {for
(int i = 0; i
Solution
#include
void fM(int m[10])
{int i;
for( i=0;i<10;i+=2)
{
m[i]=m[i]+2;
}
}
int main()
{
int iarray[10]={2,4,7,9,11,23};
fM(iarray);
printf(\"%d %d %d\ \",iarray[0],iarray[1],iarray[2] );
return 0;
}
=============================
output:
4 4 9
It simply adde 2 to number at even position for 2 to 10;.
More Related Content
Similar to File PrintCoded.java (shown above) contains an incomplete program. T.pdf
import java.util.Scanner;Henry Cutler ID 1234 7202.docx
import java.util.Scanner;
/*
Henry Cutler ID 1234 7/20/2015
Assignment #5, 3 features in 1 program
Solution
for Assignment#5 COP2800
Pseudocode:
Program has three features, all in a single program that are user selectable.
Prompt with options and get user choice inside a while statement ( true )
If 1 is entered:
Using a while and for loop, print out the ASCII table from ! to ~.
If 2 is entered:
Prompt the user for number of times to flip for head or tails using the random method. Count number of each and when the request times are done, print out the results.
If 3 is entered:
Prompt the user for a strings and print back the count of vowels and letters
Any other input entered program will exit using a break statement, otherwise loops back to prompt user for feature selection.
*/
public class Module5 {
public static void main(String[] args) {
// prompt the user
System.out.println("Welcome to Henry\'s 3 in 1 Programming Assignment for Module 5\n");
// create Scanner Object
Scanner input = new Scanner(System.in);
// loop until break
while(true){
// new lines for readability
System.out.print("\n");
// Prompt user for choices
System.out.print("Enter 1 for ASCII Table \nEnter 2 for Heads or Tails\nEnter 3 for Count Vowels & Letters\nAny other input will exit");
int choice = input.nextInt();
// Consume newline left-over
input.nextLine();
// first feature
if(choice == 1){
// start value is !
int value = (int) '!';
// newline for formating
System.out.println("You Selected ASCII Table!\n");
// start at ~ which is 33 decimal
while( value <= '~')
{
// print out 20 in a line
for( int count = 0; count < 20; count ++ ){
if( value <= '~'){
// print single value
System.out.print( (char) value++ );
}
else {
// break when we are at last char to print
break;
}
}
// New line every 10
System.out.print("\n");
}
// New line at exit
System.out.print("\n");
}
else if(choice == 2){
// Prompt user
System.out.println("You Selected Head or Tails!");
System.out.println("\nHow many flips would you like to try?");
// get value
int count = input.nextInt();
// clear
input.nextLine();
int headCount = 0;
int tailCount = 0;
// run for a count provided by user
for (int i = 0; i < count; i++) {
// get random number
if (Math.random() > 0.5){
// increment heads
headCount++;
}
else {
// increment tails
tailCount++;
}
}
System.out.println("Head count: " + headCount + " tail count: " + tailCount);
}
else if(choice == 3){
// Prompt user
Sys.
COMPILER DESIGN- Introduction & Lexical Analysis:
COMPILER DESIGN- Introduction & Lexical Analysis: Jyothishmathi Institute of Technology and Science Karimnagar
Introduction: Language Processors, the structure of a compiler, the science of building a compiler, programming language basics.
Lexical Analysis: The Role of the Lexical Analyzer, Input Buffering, Recognition of Tokens, The Lexical-Analyzer Generator Lex, Finite Automata, From Regular Expressions to Automata, Design of a Lexical-Analyzer Generator, Optimization of DFA-Based Pattern Matchers
Your 1ab8 c file is doe by Friday 1159pm to be submitted.pdf
Your 1ab8. c file is doe by Friday, 11.59pm, to be submitted on Gradescope. Overview This week,
you will start with last week's program and create your own functions for some of the tasks. You'll
have a printmenu () function, printarray () function and a convertcase () function. Just like you saw
in class, the code from the main () function that performs each of those tasks will be moved from
the the main () function and into their respective functions. More details about those functions are
shown below in the Lab Assignment section. All the functions will be in one file, called lab8.c.
Background Information For this lab, you will use last week's program to start with. Copy it and
rename it lab8.c. Again, you will be adding more code to this program in the future, so make sure
you get this one working. Functions and Reminders 1. As you saw in class, functions perform
(usually) one task, or a couple of smaller tasks that combined perform a task. 2. Some functions
return a value (the retum type being specified in the functon header/signature and a return
statement at the bottom of the function): int printmenu() & and some functions do not return any
value (the retum type then being specified as void and no return statement at the bottom of the
function): void convertCase (char text [MAX_LINE] [MAX_LINE_LEN] ) i 3. When arguments are
being sent to the function, the function then has "parameters" specified in the function
header/signature. The parameters that are specified indicate the type and the name: void
printarray (char text[MAX_LINE] [MAX_LINE_LEN], int size) { If a function is not being sent any
arguments, then the parameter list will be empty (meaning nothing in the parentheses). int
printMenu() f / / empty parentheses 4. When sending a 1-D array to a function, the parameter can
be specified with empty square brackets: int findLowest (int theArray[], int size) f // from in-class
exercise When a 2-D array is sent to a function, however, the parameter has to at least specify the
number of columns. So the parameter can be specified as: void f1 (int array [][12]) If a variable is
being used for the dimension(s) of the array, then the variable must appear first in the list of
parameters: void 11 (int numRows, int numCols, int array 1 [numRows] [numCols]) For this lab,
since the number of rows and number of columns are either idefine or constants, defined outside
of the main0 function, the parameter showing the array can use those names for the dimensions
without including them in the parameter list: void convertCase (char text[MAX_LINE]
[MAX_LINE_LEN]) I 5. As discussed in class, to eliminate chances of confusion, you should
ensure that there is no variable shadowing (the argument being sent to the function has a different
name than the parameter). 6. Function prototypes should be at the top of the file, EVFN IF THE
MAINO FUNCTION IS AT THE BOTTOM OF5. Function prototypes should be at the top of the file,
EVEN If THE MANNO FUNCTION IS AT THE.
Getting started with Microsoft Excel Macros
A macro is a series of functions written in a programming language that is grouped in a single command to perform the requested task automatically. Excel macros are used to save time and reduce the possibility of human error by automating repetitive processes.
Program by Demonstration using Version Space Algebra
Original paper: http://homes.cs.washington.edu/~pedrod/papers/mlj02.pdf
Class notes(week 5) on command line arguments
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C programming language Reference Note
Get ready to learn the best programming language called C Programming Language. This note is based on +2 HSEB Syllabus of C programming. It helps you to get idea on the concept of C Programming Language. You get detail explanations on operators, looping, switch case, history, many more.
Instructions Write a program whose main function is merely a.pdf
Instructions
Write a program whose main function is merely a collection of variable declarations and function
calls. This program reads a text and outputs the letters, together with their counts, as explained
below in the function printResult. (There can be no global variables! All information must be
passed in and out of the functions. Use a structure to store the information.) Your program must
consist of at least the following functions:
Function openFile: Opens the input and output files. You must pass the file streams as parameters
(by reference, of course). If the file does not exist, the program should print an appropriate
message ("The input file does not exist.") and exit. The program must ask the user for the
names of the input and output files.
Function count: Counts every occurrence of capital letters A-Z and small letters a-z in the text file
opened in the function openFile. This information must go into an array of structures. The array
must be passed as a parameter, and the file identifier must also be passed as a parameter.
Function printResult: Prints the number of capital letters and small letters, as well as the
percentage of capital letters for every letter A-Z and the percentage of small letters for every letter
a-z. The percentages should look like this: "25%".This information must come from an array of
structures, and this array must be passed as a parameter.
Your program should prompt the user for name of the input file, then the name of the output file..
Introduction To Programming with Python-1
Slides for Lecture 1 of the course: Introduction to Programming with Python offered at ICCBS.
It covers the following topics:
1.) Variables, Statements and Expressions
2.) Functions
3.) Flow Control
Similar to File PrintCoded.java (shown above) contains an incomplete program. T.pdf (20)
import java.util.Scanner;Henry Cutler ID 1234 7202.docx
import java.util.Scanner;Henry Cutler ID 1234 7202.docx
Your 1ab8 c file is doe by Friday 1159pm to be submitted.pdf
Your 1ab8 c file is doe by Friday 1159pm to be submitted.pdf
Program by Demonstration using Version Space Algebra
Program by Demonstration using Version Space Algebra
Instructions Write a program whose main function is merely a.pdf
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What is going to be the output of the following program #include .pdf
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#include
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{
m[i]=m[i]+2;
}
}
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{
int iarray[10]={2,4,7,9,11,23};
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return 0;
}
=============================
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It simply adde 2 to number at even position for 2 to 10;.
What competencies underpin successful management in implementing org.pdf
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Solution
The force that resist relative motion of solid surfaces ,layers of fluid and material elements that
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sure to happen : 1.0
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20. Experimental variable.
There are two major groups of seed plants, gymnosperms (Exercise 24) .pdf
There are two major groups of seed plants, gymnosperms (Exercise 24) and angiosperms.
Compare these two groups of seed plants with respect to the following features: Gymnosperms
Angio sperms Feature a. type of reproductive structure b. source of nutrition for developing
embryo c. enclosure of mature seed
Solution
Feature
Gymnospersm
Angiosperms
Type of reproductive structure
Cones
Flowers
Source of nutrition for developing embryo
Female gametophyte tissue (X)
Endosperm (3X)
Enclosure of mature seed
Seed integuments are present, but ovary is absent, so seeds exposed directly.
Seed integument is present, All ovules are present in Ovary, later Ovary turns in to fruit.
Feature
Gymnospersm
Angiosperms
Type of reproductive structure
Cones
Flowers
Source of nutrition for developing embryo
Female gametophyte tissue (X)
Endosperm (3X)
Enclosure of mature seed
Seed integuments are present, but ovary is absent, so seeds exposed directly.
Seed integument is present, All ovules are present in Ovary, later Ovary turns in to fruit..
The steps in the closing process are (1) close credit balances in re.pdf
The steps in the closing process are (1) close credit balances in revenue accounts to Income
Summary; (2) close debit balances in expense accounts to Income Summary; (3) close Income
Summary to Retained Earnings; (4) close Dividends to Retained Earnings.
Solution
Answer is 3
close Income Summary to Retained Earnings
balance of income summary is transferred to retained earning and income summary account is
closed at year end..
The positron decay of ^15 O goes directly to the ground state of ^15 .pdf
The positron decay of ^15 O goes directly to the ground state of ^15 N; no excited states of ^15
N are populated and no gamma rays follow beta decay. Yet a source of ^15 O is found to emit
gamma rays of about 0.5 MeV. Explain the origin of these rays.
Solution
gamma rays almost always accompanies other radioactive emmissions because it represents
energy loss when the remaining nucleons reorganise into more stable arrangements. thus here in
this problem the origin of gamma rays arise due to mass defect as per Einesteins theory of
relativity..
The disease bullous pemphigoid results in the destruction of protein.pdf
The disease bullous pemphigoid results in the destruction of proteins within the basement
membrane that hold the epidermis and dermis together. How would this likely affect the
epidermis?
Solution
Bullous pemphigoid is an autoimmune disease.
Due to the nature of the disease, the cohesion between the dermis and the epidermis is destroyed.
The epidermis tends to separate from the dermis and in the intervening space, body fluids fill up,
giving the appearance of lesions. The colour and size of the lesions vary. In some patients they
may cover large parts of the anatomy. The lesions when disturbed burst, spilling their contents.
This may further lead to secondary infections and provide a pathway for pathogens to enter the
body..
Student Outcome f the broad education necessary to understand th.pdf
Student Outcome \"f\": the broad education necessary to understand the impact of engineering
solutions in a global, economic, environmental, and societal context. Topics Cyberspace
Security Transportation Infrastructure You may suggest an engineering topic other than the two
listed, but prior approval is needed from the professor. Other topics cannot be \"clean water\" and
\"global warming.\" For each of the topics abuse, you are to do the following State the
engineering problem. Discuss engineering solutions #1. Describe the pros and cons of the
engineering solution. Describe the societal impact of engineering solution #1. Describe the
global impart of engineering solution #1. Describe the environmental impact of engineering
solution #1. Describe the economic impact of engineering solution #1. Discuss engineering
solution #2. Describe the pros and cons of the engineering solution. Describe die societal
impact of engineering solution #2. Describe the global impart of engineering solution #2.
Describe the environmental impact of engineering solution #2. Describe the economic impact of
engineering solution #2. All of the above items are to the addressed for each topic separately.
Solution
CYBER SPCE SECURITY
1)STATEMENT OF ENGINEERING PROBLEM
Internet security problems are becoming more conspicuous with each passing day. Online
information such as pornography and obscenities are seriously harming the physical and mental
health of minors. Criminal activities such as online fraud and theft are seriously harming public
security. Computer viruses and hacker attacks are posing serious threats to the security of the
operation of the Internet. Leaking of secrets via the Internet is posing serious threats to national
security and interests.”
DESCRIBE THE SOCIAL IMPACT OF CYBER SPACE SECURITY
Due to cyber space technology it is easy to make cyber crimes,people who are not having
knowledge about cyber security they are easily traped and cheated examples hacking ATM
USER ID AND PASSWORD,un authorised shopping with our bank accounts etc.large number
of crimials are made,
women harasement also [pssible in cyber space
DESCRIBE THE GLOBAL IMPACT OF CYBER SPACE SECURITY
With the increasing proliferation of information and communication technologies (ICTs) and the
growing opportunity for real-time borderless exchange, cybersecurity is a complex transnational
issue that requires global cooperation for ensuring a safe Internet. According to a 2011 Norton
study, threats to cyberspace have increased dramatically in the past year afflicting 431 million
adult victims globally – or 14 adults victims every second, one million cybercrime victims every
day.
Cybercrime has now become a business which exceeds a trillion dollars a year in online fraud,
identity theft, and lost intellectual property, affecting millions of people around the world, as
well as countless businesses and the Governments of every nation.
DESCRIBE ENVIRONMENTAL IMPACT OF CYBER SPACE SECURITY
Cybercr.
QUESTION 8 1.00000 P Financial intermediaries are different from inve.pdf
QUESTION 8 1.00000 P Financial intermediaries are different from investment banking houses
in that financial intermediaries issue their securities to obtain funds from savers and then use the
fund to purchase other business\'s securities, while investment banking houses do not issue their
securities. Instead, savers\' money merely passes through investment banking houses. e True
False
Solution
Answer: This statement is false.
Financial Intermediaries- These are the financial institutions that work as mediator between two
parties, they include commercial banks, investment bank, mutual funds, NBFCs, pension fund
etc. These intermediaries channel funds from those who have it in excess to those who need
funds.
Investment banking- It is special branch of banking that provides many services like
underwriting, broking, portfolio management, M&A, restructuring, consultancy etc. These help
the new firms to raise capital from the market and go public by issuing shares to the general
public..
Post your response to the following focus questionsDescribe a sol.pdf
Post your response to the following focus questions:
Describe a sole proprietorship and discuss its advantages and disadvantages.
Describe a partnership and discuss its advantages and disadvantages.
Describe a corporation and discuss its advantages and disadvantages.
Describe an S corporation and discuss its advantages and disadvantages.
Solution
Broadly speaking for conducting any type of Business activity we require to have a Business
entity. If the Business entity is owned and operated and managed by a single paerson then such
Business entity is called a sole Proprietorship. It is most simple and subjected to least terms &
conditions governing the business activities. The main disadvantages includes personal liability
of the owner/ propreitor, which is unlimited. A single person being at the helm of affairs poses
limitations on the development and growth of the business. Propreitorship has its death with the
death of the owner.
A Partnership as the word suggest is that form of Business entity which is owned by two or more
persons and formed under an agreement signed by all owners for some common purpose/ goal
and or objectives. A partnership firm is more complicated than the sole propreitorships, two or
more persons as owners may give advatages of sharing resources, knowledge, skills which are
essential for setting up of businesses of sizes unmanageable by a single person. Pooling diversity
of partners helps in the development and growth of the Business entity. Like sole propreitorship,
the partners under partnerships may be subjected to unlimited liabilities under or arising out of
the business activities of the Partnership firm. There are additional set of rules & regulations
under the law of the land governing the partnership firms.
The third and the most prefered form of business entity is an incorporated firm called corporation
and or company. A corporation/ company is different from its owners. This form of business
entity draws difference between the owner and management of the business entity. Unlike the
earlier set ups of Sole Propreitor and Partnership, the business activies are conducted neither by
sole owner nor by partners but managers who are considered to be having different identity than
the business entity which is also considered as a legal person. A corporation can be sued and it
can also sue others in the court of law.A corporation comes into existence with its incorporation
documents such as Memorandum of Understanding, Articles of Associations, Delegation of
Powers etc. These documents required for giving birth to the corporation varies from state to
state, nation to nation, lews of the land under whose jurisdiction it falls. The main advantage of a
corporation is to give limited liability to its owners who are called share holders and its business
activities are conducted by the professionals having required qualifications and skills. Just like its
birth, its death is not related to that of its share holders (owners).
Please fill in the code, which only need to add code in the adju.pdf
//Please fill in the code, which only need to add code in the \"adjustHeap\" function.
#ifndef HEAP_H
#define HEAP_H
#include
#include // std::out_of_range
using namespace std;
template
class Heap
{
private:
vector _items;
void buildHeap()
{
for (int i = _items.size() / 2; i >= 0; i--)
{
adjustHeap(i);
}
}
//MA TODO: Implement adjustHeap!
//Percolates the item specified at by index down into its proper location within a heap.
// Used for dequeue operations and array to heap conversions
void adjustHeap(int index)
{
// The ONLY code you\'d need to do for this MA would be in this function call
}
public:
Heap()
{
}
Heap(const vector &unsorted)
{
for (int i = 0; i < unsorted.size(); i++)
{
_items.push(unsorted[i]);
}
buildHeap();
}
//Adds a new item to the heap
void insert(T item)
{
//calculate positions
int current_position = _items.size();
int parent_position = (current_position - 1) / 2;
//insert element (note: may get erased if we hit the WHILE loop)
_items.push_back(item);
//get parent element if it exists
T *parent = nullptr;
if (parent_position >= 0)
{
parent = &_items[parent_position];
}
//only continue if we have a non-null parent
if (parent != nullptr)
{
//bubble up
while (current_position > 0 && item < *parent)
{
_items[current_position] = *parent;
current_position = parent_position;
parent_position = (current_position - 1) / 2;
if (parent_position >= 0)
{
parent = &_items[parent_position];
}
}
//after finding the correct location, we can finally place our item
_items[current_position] = item;
}
}
//Returns the top-most item in our heap without actually removing the item from the heap
T& getFirst()
{
if( size() > 0 )
return _items[0];
else
throw std::out_of_range(\"No elements in Heap.\");
}
//Removes the top-most item from the heap and returns it to the caller
T deleteMin()
{
int last_position = _items.size() - 1;
T last_item = _items[last_position];
T top = _items[0];
_items[0] = last_item;
_items.erase(_items.begin() + last_position);
//percolate down
adjustHeap(0);
return top;
}
// Returns true if heap is empty, false otherwise
bool isEmpty() const
{
return _items.size() == 0;
}
// Return size (N) of the Heap
int size() const
{
return _items.size();
}
// Simple debugging print out
void printAll() const
{
for(int i = 0; i < _items.size(); i++)
{
cout << \" [x] Heap element [\" << i << \"]. key=\" << _items[i] << endl;
}
}
};
#endif
Solution
void adjustHeap(int index) { int largest,left,right; Map.Entry temp = null;
while(true){ left = 2*index+1; right = 2*index+2; if(left < size &&
elements[index].getValue() < elements[left].getValue()){ largest = left;
if(right < size && elements[left].getValue() < elements[right].getValue()){ largest =
right; } } else if(right < size && elements[index].getValue() <
elements[right].getValue()){ largest = right; } else break; // swapping
temp = elements[index]; elements[index] = elements[largest];
elements[largest] = temp; index = largest; } } } }.
Linear AlgebraHello. I need help with my practice final. I am not .pdf
Linear Algebra
Hello. I need help with my practice final. I am not trying to copy. I want to see If I am doing it
right So please help. Thank you very much!
Here\'s the problem Let V and W be (finite-dimensional) vector spaces. In fact, unless otherwise
stated in one of the problems or definitions below you may assume that dim V n and dimW m.
Also, unless otherwise stated, let T V W be a linear transformation. Definitions and Basic
Results 1. The kernel of T, written ker T, is the set of vectors UE v such that T(i) 30w. 2. The
range of T, written range T is the set of vectors i e W such that T(i) if for some i E V. 3. T is
injective means that whenever i E V then T(ii) T(i2) if and only if ii J v2 4. T is surjective means
range T W 5. T is bijective if and only if it is both injective and surjective. 6. T is called a linear
operator if V W 7. Let T be a linear operator in V and let u be subspace of V. u is said to be
invariant under T if T(ii) Eu for every i Eu 8. Let u and u be aces of V (a) The sum of these
subspaces, written uitu2, is the set of vectors i EV that can be written as a sum of vectors ii ii2
where ii E uh and ii2 Eu2. (b) V is said to be a direct sum of u and up, written V Juh Du2, if and
only if for every if E V there exists a unique pair of vectors iii E ui and ii2 Eur such that if ii ii2.
Examples R2 z-axis) (y-axis). Ra (ary-plane) axis A) span span Fact V u if and only if v un +uo
and un nu
Solution
if T is injective then there should be a map of v in w for every v belonging to V and w belonging
to W. Consider the basis of W as all elements are maped then the dim of W should be at least
equal to the dimension of V as linear transformation map each basis element of V to some basis
element in W
If T is surjective then same argument above applies to just opposite because now mapping covers
all the elements of W.
if T is bijective then it is both injective and surjective .So now only equality can hold hence
dim(V) = dim(W).
Many nations, including the US, already maintain a national DNA data.pdf
Many nations, including the US, already maintain a national DNA database of samples collected
during criminal investigations, but there are often questions of whether such databases should be
expanded to include more individuals, or whether their use is ethical at all. What arguments can
you make for and against \"banking\" DNA profiles (i.e. \"genetic fingerprints\" based on STRs,
not necessarily full genome sequences) in a database? Do you believe such databases are ethical
or an invasion of privacy? Should it be mandatory for some or all individuals? What restrictions
would you place on it?
Solution
ARGUMENTS FOR:
A DNA database covering the entire populace and each guest to the UK, as upheld by Lord
Justice Sedley, would spare huge measures of police time and help clear up violations quicker.
The individuals who do nothing incorrectly have nothing to fear and ought to be consoled.
The present framework - the DNA of each one of those captured for recordable offenses, liable
or not, is held - is specific and wasteful.
Current practice is uncalled for: ethnic minorities and youngsters are over-spoken to, making
hatred and hostile to police feeling. Two-in-five dark men have their DNA on record, as against
less than one-in-ten whites.
The world has changed: universal versatility implies that potential fear based oppressors can
travel every which way, frequently on false papers.
ARUGMENTS AGAINST:
It would be a definitive stride making progress toward a \'The government\' state: Britain would
turn into \'a country of suspects.
Whatever the utility of DNA tests, there is something inalienably exasperating about entering
each infant on a database during childbirth.
A national DNA bank would be enormously costly and bureaucratic.
It is harming to the picture of the UK - \'Welcome to Britain: now give a mouth swab\'.
DNA data could be mishandled by degenerate police and others wrongfully passing data to
unapproved individuals.
PRIVACY ISSUE:
Individual data is now held by gatherings in the private division, if individuals can believe the
private part then they ought to have the capacity to confide in the Government.
In 2010, the UK Government promised to roll out improvements to the period of time DNA tests
are kept in the UK National DNA Database. These were incorporated into the 2012 Protection of
Freedoms Act. These progressions guarantee that the DNA (and fingerprints) of people captured
yet not indicted an offense is held for a most extreme of 5 years.
The DNA Identification Act of 1994 unequivocally permits database records to be made
accessible for innovative work the length of all actually identifiable data is expelled.
It need not be mandatory for all the individuals but as a matter of national security it should be
taken into consideration.Some restrictions like the privacy issue and the information of that
should not be accessed to everyone instead the government should be in a position to give the
required information neccesary and sho.
implement the add() method for min-heappublic class Heap { .pdf
implement the add() method for min-heap
public class Heap {
private ArrayList element;
private comparator comp;
public int patent(int childIndex) {
return (childIndex - 1) / 2;
}
public void add(E element) {
code here
}
}
Solution
publicvoid add(int value) {
if (heapSize == data.length)
thrownewHeapException(\"Heap\'s underlying storage is overflow\");
else {
heapSize++;
data[heapSize - 1] = value;
shiftUp(heapSize - 1);
}
}
privatevoid shiftUp(int nodeIndex) {
int parentIndex, tmp;
if (nodeIndex != 0) {
parentIndex = getParentIndex(nodeIndex);
if (data[parentIndex] >data[nodeIndex]) {
tmp =data[parentIndex];
data[parentIndex] = data[nodeIndex];
data[nodeIndex] = tmp;
shiftUp(parentIndex);
}
}
}
}.
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Francesca Gottschalk - How can education support child empowerment.pptx
Unit 8 - Information and Communication Technology (Paper I).pdf
Unit 8 - Information and Communication Technology (Paper I).pdf
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
TESDA TM1 REVIEWER FOR NATIONAL ASSESSMENT WRITTEN AND ORAL QUESTIONS WITH A...
File PrintCoded.java (shown above) contains an incomplete program. T.pdf
- 1. File PrintCoded.java (shown above) contains an incomplete program. The goal of the program is to take as input strings from the user, and then print out coded (encrypted) versions of those strings, by replacing each letter with another letter. Complete that program, by defining a printCoded function, that satisfies the following specs: Function printCoded takes three arguments, called word, sources, targets. They are all strings. Function printCoded processes the letters of word one by one, in the order in which they appear in word. For every such letter X, the function processes X as follows: If X is equal to the character at position P of sources, then the function prints the character at position P of targets. Otherwise, the function prints X. Note that arguments sources and targets are hardcoded in the main function, the user cannot change those values. The user can only specify the value of word. IMPORTANT: you are NOT allowed to modify in any way the main function. This is an example run of the complete program: Solution PrintCoded.java import java.util.Scanner; public class PrintCoded { public static void main(String[] args) { Scanner in = new Scanner(System.in); String sources = "abcdefghijklmnopqrstuvwxyz"; String targets = "bcdefghijklmnopqrstuvwxyza"; while (true) { System.out.printf("Enter some word, or q to quit: "); String word = in.next();
- 2. if (word.equals("q")) { System.out.printf("Exiting... "); System.exit(0); } printCoded(word, sources, targets); System.out.printf(" "); } } public static void printCoded(String word, String sources, String targets){ for(int i=0; i