There are two major groups of seed plants, gymnosperms (Exercise 24) .pdf
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There are two major groups of seed plants, gymnosperms (Exercise 24) and angiosperms. Compare these two groups of seed plants with respect to the following features: Gymnosperms Angio sperms Feature a. type of reproductive structure b. source of nutrition for developing embryo c. enclosure of mature seed Solution Feature Gymnospersm Angiosperms Type of reproductive structure Cones Flowers Source of nutrition for developing embryo Female gametophyte tissue (X) Endosperm (3X) Enclosure of mature seed Seed integuments are present, but ovary is absent, so seeds exposed directly. Seed integument is present, All ovules are present in Ovary, later Ovary turns in to fruit. Feature Gymnospersm Angiosperms Type of reproductive structure Cones Flowers Source of nutrition for developing embryo Female gametophyte tissue (X) Endosperm (3X) Enclosure of mature seed Seed integuments are present, but ovary is absent, so seeds exposed directly. Seed integument is present, All ovules are present in Ovary, later Ovary turns in to fruit..
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Cones in gymnosprems are homologous to gametophyte of seedless plant
Seedless plants do not produce flowers or grow from seeds. They have two stages in their
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having pollens.
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(ovule) are not inside an ovary rather they are present on scales or leaves often modified to cone.
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What is going to be the output of the following program: #include voidfM (int m[10]) {for
(int i = 0; i
Solution
#include
void fM(int m[10])
{int i;
for( i=0;i<10;i+=2)
{
m[i]=m[i]+2;
}
}
int main()
{
int iarray[10]={2,4,7,9,11,23};
fM(iarray);
printf(\"%d %d %d\ \",iarray[0],iarray[1],iarray[2] );
return 0;
}
=============================
output:
4 4 9
It simply adde 2 to number at even position for 2 to 10;.
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MODES OF REPRODUCTION IN CROP PLANTS.PDF
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Cones in gymnosprems are homologous to gametophyte of seedless plant.pdf
Cones in gymnosprems are homologous to gametophyte of seedless plant
Seedless plants do not produce flowers or grow from seeds. They have two stages in their
lifecycle
1) spores producing
2) sex cells (sperm and eggs) producing stage
Gymnosperms (greek meaning naked seeds) are seed-bearing vascular plants in which the seeds
(ovule) are not inside an ovary rather they are present on scales or leaves often modified to cone.
Eg. Pine tree.
When you see a pine tree the main plant is sporophyte (diploid stage). The gametophyte (haploid
stage) form is confined to the cones which are either female cones having ovule or male cones
having pollens.
Solution
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Cones in gymnosprems are homologous to gametophyte of seedless plant.pdf
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#include
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Please fill in the code, which only need to add code in the adju.pdf
//Please fill in the code, which only need to add code in the \"adjustHeap\" function.
#ifndef HEAP_H
#define HEAP_H
#include
#include // std::out_of_range
using namespace std;
template
class Heap
{
private:
vector _items;
void buildHeap()
{
for (int i = _items.size() / 2; i >= 0; i--)
{
adjustHeap(i);
}
}
//MA TODO: Implement adjustHeap!
//Percolates the item specified at by index down into its proper location within a heap.
// Used for dequeue operations and array to heap conversions
void adjustHeap(int index)
{
// The ONLY code you\'d need to do for this MA would be in this function call
}
public:
Heap()
{
}
Heap(const vector &unsorted)
{
for (int i = 0; i < unsorted.size(); i++)
{
_items.push(unsorted[i]);
}
buildHeap();
}
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void insert(T item)
{
//calculate positions
int current_position = _items.size();
int parent_position = (current_position - 1) / 2;
//insert element (note: may get erased if we hit the WHILE loop)
_items.push_back(item);
//get parent element if it exists
T *parent = nullptr;
if (parent_position >= 0)
{
parent = &_items[parent_position];
}
//only continue if we have a non-null parent
if (parent != nullptr)
{
//bubble up
while (current_position > 0 && item < *parent)
{
_items[current_position] = *parent;
current_position = parent_position;
parent_position = (current_position - 1) / 2;
if (parent_position >= 0)
{
parent = &_items[parent_position];
}
}
//after finding the correct location, we can finally place our item
_items[current_position] = item;
}
}
//Returns the top-most item in our heap without actually removing the item from the heap
T& getFirst()
{
if( size() > 0 )
return _items[0];
else
throw std::out_of_range(\"No elements in Heap.\");
}
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T deleteMin()
{
int last_position = _items.size() - 1;
T last_item = _items[last_position];
T top = _items[0];
_items[0] = last_item;
_items.erase(_items.begin() + last_position);
//percolate down
adjustHeap(0);
return top;
}
// Returns true if heap is empty, false otherwise
bool isEmpty() const
{
return _items.size() == 0;
}
// Return size (N) of the Heap
int size() const
{
return _items.size();
}
// Simple debugging print out
void printAll() const
{
for(int i = 0; i < _items.size(); i++)
{
cout << \" [x] Heap element [\" << i << \"]. key=\" << _items[i] << endl;
}
}
};
#endif
Solution
void adjustHeap(int index) { int largest,left,right; Map.Entry temp = null;
while(true){ left = 2*index+1; right = 2*index+2; if(left < size &&
elements[index].getValue() < elements[left].getValue()){ largest = left;
if(right < size && elements[left].getValue() < elements[right].getValue()){ largest =
right; } } else if(right < size && elements[index].getValue() <
elements[right].getValue()){ largest = right; } else break; // swapping
temp = elements[index]; elements[index] = elements[largest];
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Linear Algebra
Hello. I need help with my practice final. I am not trying to copy. I want to see If I am doing it
right So please help. Thank you very much!
Here\'s the problem Let V and W be (finite-dimensional) vector spaces. In fact, unless otherwise
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Solution
ARGUMENTS FOR:
A DNA database covering the entire populace and each guest to the UK, as upheld by Lord
Justice Sedley, would spare huge measures of police time and help clear up violations quicker.
The individuals who do nothing incorrectly have nothing to fear and ought to be consoled.
The present framework - the DNA of each one of those captured for recordable offenses, liable
or not, is held - is specific and wasteful.
Current practice is uncalled for: ethnic minorities and youngsters are over-spoken to, making
hatred and hostile to police feeling. Two-in-five dark men have their DNA on record, as against
less than one-in-ten whites.
The world has changed: universal versatility implies that potential fear based oppressors can
travel every which way, frequently on false papers.
ARUGMENTS AGAINST:
It would be a definitive stride making progress toward a \'The government\' state: Britain would
turn into \'a country of suspects.
Whatever the utility of DNA tests, there is something inalienably exasperating about entering
each infant on a database during childbirth.
A national DNA bank would be enormously costly and bureaucratic.
It is harming to the picture of the UK - \'Welcome to Britain: now give a mouth swab\'.
DNA data could be mishandled by degenerate police and others wrongfully passing data to
unapproved individuals.
PRIVACY ISSUE:
Individual data is now held by gatherings in the private division, if individuals can believe the
private part then they ought to have the capacity to confide in the Government.
In 2010, the UK Government promised to roll out improvements to the period of time DNA tests
are kept in the UK National DNA Database. These were incorporated into the 2012 Protection of
Freedoms Act. These progressions guarantee that the DNA (and fingerprints) of people captured
yet not indicted an offense is held for a most extreme of 5 years.
The DNA Identification Act of 1994 unequivocally permits database records to be made
accessible for innovative work the length of all actually identifiable data is expelled.
It need not be mandatory for all the individuals but as a matter of national security it should be
taken into consideration.Some restrictions like the privacy issue and the information of that
should not be accessed to everyone instead the government should be in a position to give the
required information neccesary and sho.
implement the add() method for min-heappublic class Heap { .pdf
implement the add() method for min-heap
public class Heap {
private ArrayList element;
private comparator comp;
public int patent(int childIndex) {
return (childIndex - 1) / 2;
}
public void add(E element) {
code here
}
}
Solution
publicvoid add(int value) {
if (heapSize == data.length)
thrownewHeapException(\"Heap\'s underlying storage is overflow\");
else {
heapSize++;
data[heapSize - 1] = value;
shiftUp(heapSize - 1);
}
}
privatevoid shiftUp(int nodeIndex) {
int parentIndex, tmp;
if (nodeIndex != 0) {
parentIndex = getParentIndex(nodeIndex);
if (data[parentIndex] >data[nodeIndex]) {
tmp =data[parentIndex];
data[parentIndex] = data[nodeIndex];
data[nodeIndex] = tmp;
shiftUp(parentIndex);
}
}
}
}.
i need the complete answers as soon as possibleSolutionUNI.pdf
i need the complete answers as soon as possible
Solution
UNIVAC stands for Universal Automatic Computer
origon and history of UNIVAC:
->it is the first computer produced in united states for business and administrative use with fast
execution of relatively simple arithmetic and data transport operations, opposed to the complex
numerical calculations required of scientific computers.
->it was developed by J. Presper Eckert and John Mauchly, makers of ENIAC
->ENIAC, best for Electronic Numerical Integrator and Calculator and completed in 1946 at a
cost of nearly $500,000. It took up 15,000 feet, employed 17,000 vacuum tubes, and was
programmed by plugging and replugging some 6,000 switches.
-> and It was first used in a calculation for Los Alamos Laboratories in December 1945, and in
February 1946 it was formally dedicated.
->hence The first UNIVAC came on line for the U.S. Government\'s Census Bureau. The first
commercial customer to purchase a UNIVAC was the Prudential Insurance Company
->The UNIVAC was the first computer to come equipped with a magnetic tape unit and was the
first computer to use buffer memory.
strengths:
-> the Random access feature provides large file of information
-> this is readily accessible to many types of input-output devices,
->Eliminates necessity of batching items as in previous systems.Information can be fed into the
system at any time with readyaccess to balances.
->Random access feature eliminates many interim steps associatedwith other methods such as
sorting and collating. Postingscan
be made from source doczrments which are kept in their original sequence.
-> Same record filed magnetically is available to all input-output
devices simultaneously. Then all operators can post to the same
record even making entries to the same items at the same time.
->Keyboard entries can be nade directly into the system.
->Eliminates searching for a record card.
->Gives freedom in handling late items
.
->Gives freedom in handling rusk items
.
->Cirmulative total of all entries is constantly available.
->Through on-line and off-line operation, the system, can handle
weakness:
->in this systems where the reference file is large
it is necessary to accumulate batches of items for processing before the information can be
economically handled.
several applications siraultaneously and use cammon information
according to different activities.
UNIVAC with IBM:
IBM got in 1951 when it lost the Census Bureau business to UNIVAC. That setback reenergized
IBM, which had dominated pre-computer data processing.
Determined to meet the challenge—and eyeing data processing needs in the Korean War—IBM
designed its 701 computer in just one year. After that, a flurry of new models eroded UNIVAC’s
lead.
the best mechanism is
->The UNITYPER was an offline typewriter used by the programmers to write code for the
computer, while the UNISERVO could read and write the UNITYPER compatible tapes, so it
was a form of an early tape drive.
->The Tape Handlin.
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