C++Write a method Node Nodereverse() which reverses a list..pdfarjunenterprises1978
C++
Write a method Node *Node::reverse() which reverses a list.
Solution
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Function to reverse the linked list */
static void reverse(struct node** head_ref)
{
struct node* prev = NULL;
struct node* current = *head_ref;
struct node* next;
while (current != NULL)
{
next = current->next;
current->next = prev;
prev = current;
current = next;
}
*head_ref = prev;
}
/* Function to push a node */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Driver program to test above function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
push(&head, 20);
push(&head, 4);
push(&head, 15);
push(&head, 85);
printf(\"Given linked list\ \");
printList(head);
reverse(&head);
printf(\"\ Reversed Linked list \ \");
printList(head);
getchar();
}.
A linked list is a data structure made up of nodes that are connected to each other. Each node contains data and a link to the next node. Linked lists can grow and shrink dynamically as nodes are added or removed. There are several types of linked lists including single linked lists where navigation is forward only, doubly linked lists where navigation is bidirectional, and circular linked lists where the last node links back to the first node. Common operations on linked lists include appending nodes to add to the end, inserting nodes in a sorted manner, and deleting nodes by value. These operations involve allocating memory for new nodes, linking nodes together, and removing nodes by adjusting pointers.
This assignment and the next (#5) involve design and development of a.pdfEricvtJFraserr
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
This program implements a doubly linked list to print the list forward and backward. It defines a Node struct with data, next and prev pointers. It inserts nodes at the head of the list using InsertAtHead() and prints the list forward using Print() and backward using ReversePrint(). It initially inserts two nodes and prints the list both ways. It then inserts three more nodes at the head and prints the list again forward and backward.
I am Andrew O. I am a C Homework Expert at programminghomeworkhelp.com. I hold a master’s in Programming from, the University of Southampton, UK. I have been helping students with their homework for the past 10 years. I solve homework related to C.
Visit programminghomeworkhelp.com or email support@programminghomeworkhelp.com.
You can also call on +1 678 648 4277 for any assistance with C Homework.
The document summarizes key concepts about linked lists including different types like singly linked lists, doubly linked lists, and circular linked lists. It provides code examples for creating nodes and performing operations like insertion, deletion, and traversal for each type of linked list. Specifically, it shows code for inserting nodes at the head, tail, and middle of singly, doubly, and circular linked lists. It also includes code for deleting nodes from singly, doubly, and circular linked lists.
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED .pdffathimahardwareelect
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED
HELP FIXING THIS CODE?
THIS IS THE PROBLEM
Write a program that allows the user to enter two positive integers and outputs their sum. Sounds
simple? Here\'s the catch: The numbers may be any size! They may be way too large to store in a
single variable. You may not assume any particular maximum number of digits.
HERE IS THE CODE
#include
#include
struct node /* Linked list node*/
{
int data;
struct node* next;
};
struct node *newNode(int data) /* Function to create a new node with giving the data*/
{
struct node *new_node = (struct node *) malloc(sizeof(struct node));
new_node->data = data;
new_node->next = NULL;
return new_node;
}
void push(struct node** head_ref, int new_data) /* Function to insert a node at the beginning of
the Doubly Linked List*/
{
struct node* new_node = newNode(new_data); /*allocate a node*/
new_node->next = (*head_ref); /* link the old list off to the new node*/
(*head_ref) = new_node; /*move the head to point to the new node*/
}
/* Adding the contents of two linked lists and return the head node of resultant list*/
struct node* addTwoLists (struct node* first, struct node* second)
{
struct node* res = NULL; /* res is head node of the resultant list*/
struct node *temp, *prev = NULL;
int carry = 0, sum;
while (first != NULL || second != NULL) /*while both the lists exists*/
{
/* Calculate value of next digit in resultant list.
// The next digit is sum of following things
// (i) Carry
// (ii) Next digit of first list (if there is a next digit)
// (ii) Next digit of second list (if there is a next digit)*/
sum = carry + (first? first->data: 0) + (second? second->data: 0);
carry = (sum >= 10)? 1 : 0; /* update carry for next calulation*/
sum = sum % 10; /*update sum if it is greater than 10*/
temp = newNode(sum); /*Create a new node with sum as data*/
if(res == NULL) /*if this is the first node then set it as head of the resultant list*/
res = temp;
else /* If this is not the first node then connect it to the rest.*/
prev->next = temp;
prev = temp; /* Set prev for next insertion*/
if (first) first = first->next; /* Move first pointers to next node*/
if (second) second = second->next; /*Move second pointer to the next node*/
}
if (carry > 0)
temp->next = newNode(carry);
return res; /* return head of the resultant list*/
}
void printList(struct node *node) /* function to print a linked list*/
{
while(node != NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
printf(\"\ \");
}
int main(void) /* program to test above function*/
{
struct node* res = NULL;
struct node* first = NULL;
struct node* second = NULL;
printf(\"Enter first positive integer: \");
scanf(\"%d\",&first);
printList(first);
printf(\"Enter second positive integer: \");
scanf(\"%d\",&second);
printList(second);
/*Add the two lists and see result*/
res = addTwoLists(first, second);
printf(\"Sum is: %d\");
printList(res);
return 0;
}
Solution
#include
#include
typedef struct Node
{
int da.
C++Write a method Node Nodereverse() which reverses a list..pdfarjunenterprises1978
C++
Write a method Node *Node::reverse() which reverses a list.
Solution
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Function to reverse the linked list */
static void reverse(struct node** head_ref)
{
struct node* prev = NULL;
struct node* current = *head_ref;
struct node* next;
while (current != NULL)
{
next = current->next;
current->next = prev;
prev = current;
current = next;
}
*head_ref = prev;
}
/* Function to push a node */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Driver program to test above function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
push(&head, 20);
push(&head, 4);
push(&head, 15);
push(&head, 85);
printf(\"Given linked list\ \");
printList(head);
reverse(&head);
printf(\"\ Reversed Linked list \ \");
printList(head);
getchar();
}.
A linked list is a data structure made up of nodes that are connected to each other. Each node contains data and a link to the next node. Linked lists can grow and shrink dynamically as nodes are added or removed. There are several types of linked lists including single linked lists where navigation is forward only, doubly linked lists where navigation is bidirectional, and circular linked lists where the last node links back to the first node. Common operations on linked lists include appending nodes to add to the end, inserting nodes in a sorted manner, and deleting nodes by value. These operations involve allocating memory for new nodes, linking nodes together, and removing nodes by adjusting pointers.
This assignment and the next (#5) involve design and development of a.pdfEricvtJFraserr
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
This program implements a doubly linked list to print the list forward and backward. It defines a Node struct with data, next and prev pointers. It inserts nodes at the head of the list using InsertAtHead() and prints the list forward using Print() and backward using ReversePrint(). It initially inserts two nodes and prints the list both ways. It then inserts three more nodes at the head and prints the list again forward and backward.
I am Andrew O. I am a C Homework Expert at programminghomeworkhelp.com. I hold a master’s in Programming from, the University of Southampton, UK. I have been helping students with their homework for the past 10 years. I solve homework related to C.
Visit programminghomeworkhelp.com or email support@programminghomeworkhelp.com.
You can also call on +1 678 648 4277 for any assistance with C Homework.
The document summarizes key concepts about linked lists including different types like singly linked lists, doubly linked lists, and circular linked lists. It provides code examples for creating nodes and performing operations like insertion, deletion, and traversal for each type of linked list. Specifically, it shows code for inserting nodes at the head, tail, and middle of singly, doubly, and circular linked lists. It also includes code for deleting nodes from singly, doubly, and circular linked lists.
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED .pdffathimahardwareelect
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED
HELP FIXING THIS CODE?
THIS IS THE PROBLEM
Write a program that allows the user to enter two positive integers and outputs their sum. Sounds
simple? Here\'s the catch: The numbers may be any size! They may be way too large to store in a
single variable. You may not assume any particular maximum number of digits.
HERE IS THE CODE
#include
#include
struct node /* Linked list node*/
{
int data;
struct node* next;
};
struct node *newNode(int data) /* Function to create a new node with giving the data*/
{
struct node *new_node = (struct node *) malloc(sizeof(struct node));
new_node->data = data;
new_node->next = NULL;
return new_node;
}
void push(struct node** head_ref, int new_data) /* Function to insert a node at the beginning of
the Doubly Linked List*/
{
struct node* new_node = newNode(new_data); /*allocate a node*/
new_node->next = (*head_ref); /* link the old list off to the new node*/
(*head_ref) = new_node; /*move the head to point to the new node*/
}
/* Adding the contents of two linked lists and return the head node of resultant list*/
struct node* addTwoLists (struct node* first, struct node* second)
{
struct node* res = NULL; /* res is head node of the resultant list*/
struct node *temp, *prev = NULL;
int carry = 0, sum;
while (first != NULL || second != NULL) /*while both the lists exists*/
{
/* Calculate value of next digit in resultant list.
// The next digit is sum of following things
// (i) Carry
// (ii) Next digit of first list (if there is a next digit)
// (ii) Next digit of second list (if there is a next digit)*/
sum = carry + (first? first->data: 0) + (second? second->data: 0);
carry = (sum >= 10)? 1 : 0; /* update carry for next calulation*/
sum = sum % 10; /*update sum if it is greater than 10*/
temp = newNode(sum); /*Create a new node with sum as data*/
if(res == NULL) /*if this is the first node then set it as head of the resultant list*/
res = temp;
else /* If this is not the first node then connect it to the rest.*/
prev->next = temp;
prev = temp; /* Set prev for next insertion*/
if (first) first = first->next; /* Move first pointers to next node*/
if (second) second = second->next; /*Move second pointer to the next node*/
}
if (carry > 0)
temp->next = newNode(carry);
return res; /* return head of the resultant list*/
}
void printList(struct node *node) /* function to print a linked list*/
{
while(node != NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
printf(\"\ \");
}
int main(void) /* program to test above function*/
{
struct node* res = NULL;
struct node* first = NULL;
struct node* second = NULL;
printf(\"Enter first positive integer: \");
scanf(\"%d\",&first);
printList(first);
printf(\"Enter second positive integer: \");
scanf(\"%d\",&second);
printList(second);
/*Add the two lists and see result*/
res = addTwoLists(first, second);
printf(\"Sum is: %d\");
printList(res);
return 0;
}
Solution
#include
#include
typedef struct Node
{
int da.
I am Gabriel C. I am a C Exam Expert at programmingexamhelp.com. I hold a PhD. in Business analyst of Information Technology, Montreal College of Information Technology, Canada. I have been helping students with their exams for the past 8 years. You can hire me to take your exam in C.
Visit programmingexamhelp.com or email support@programmingexamhelp.com. You can also call on +1 678 648 4277 for any assistance with the C Exam.
Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdffortmdu
Assignment is:
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp
file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then
\'paste\' in MS-Word)\"
How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *firs.
Data Structures in C++I am really new to C++, so links are really .pdfrohit219406
Data Structures in C++
I am really new to C++, so links are really hard topic for me. It would be nice if you can provide
explanations of what doubly linked lists are and of some of you steps... Thank you
In this assignment, you will implement a doubly-linked list class, together with some list
operations. To make things easier, you’ll implement a list of int, rather than a template class.
Solution
A variable helps us to identify the data. For ex: int a = 5; Here 5 is identified through variable a.
Now, if we have collection of integers, we need some representation to identify them. We call it
array. For ex: int arr[5]
This array is nothing but a Data Structure.
So, a Data Structure is a way to group the data.
There are many Data Structures available like Arrays, Linked List, Doubly-Linked list, Stack,
Queue, etc.
Doubly-Linked list are the ones where you can traverse from the current node both in left and
right directions.
Why so many different types of Data Structures are required ?
Answer is very simple, grouping of data, storage of data and accessing the data is different.
For example, in case of Arrays we store all the data in contiguous locations.
What if we are not able to store the data in contiguous locations because we have huge data.
Answer is go for Linked List/Doubly-Linked list.
Here we can store the data anywhere and link the data through pointers.
I will try to provide comments for the code you have given. May be this can help you.
#pragma once
/*
dlist.h
Doubly-linked lists of ints
*/
#include
class dlist {
public:
dlist() { }
// Here we are creating a NODE, it has a integer value and two pointers.
// One pointer is to move to next node and other to go back to previous node.
struct node {
int value;
node* next;
node* prev;
};
// To return head pointer, i.e. start of the Doubly-Linked list.
node* head() const { return _head; }
// To return Tail pointer, i.e. end of the Doubly-Linked list.
node* tail() const { return _tail; }
// **** Implement ALL the following methods ****
// Returns the node at a particular index (0 is the head).
node* at(int index){
int cnt = 0;
struct node* tmp = head();
while(tmp!=NULL)
{
if (cnt+1 == index)
return tmp;
tmp = tmp->next;
}
}
// Insert a new value, after an existing one
void insert(node *previous, int value){
// check if the given previous is NULL
if (previous == NULL)
{
printf(\"the given previous node cannot be NULL\");
return;
}
// allocate new node
struct node* new_node =(struct node*) malloc(sizeof(struct node));
// put in the data
new_node->data = new_data;
// Make next of new node as next of previous
new_node->next = previous->next;
// Make the next of previous as new_node
previous->next = new_node;
// Make previous as previous of new_node
new_node->prev = previous;
// Change previous of new_node\'s next node
if (new_node->next != NULL)
new_node->next->prev = new_node;
}
// Delete the given node
void del(node* which){
struct node* head_ref = head();
/* base case */
if(*head_ref == NUL.
coding in C- Create a function called reverseList that takes the head.docxtienlivick
coding in C;
Create a function called reverseList that takes the head of a linked list, reverses the order of all the nodes. For example, if the list contained 1, 2, 3, 4 in its nodes, the list will now contain 4, 3, 2, 1.
please add a main test.
Solution
Please find the required program below:
#include<stdio.h>
#include<stdlib.h>
struct node
{
int data;
struct node* next;
};
void push(struct node** head, int new_element)
{
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
new_node->data = new_element;
new_node->next = (*head);
(*head) = new_node;
}
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
void reverseList(struct node** head)
{
struct node* prev = NULL;
struct node* current = *head;
struct node* next;
while (current != NULL)
{
next = current->next;
current->next = prev;
prev = current;
current = next;
}
*head = prev;
}
int main()
{
struct node* head = NULL;
push(&head, 12);
push(&head, 14);
push(&head, 5);
push(&head, 8);
printf(\"\ Linked list Before Reversing :\ \");
printList(head);
reverseList(&head);
printf(\"\ Linked list After Reversing :\ \");
printList(head);
}
--------------------------------------------------------------------------------
OUTPUT:
Linked list Before Reversing :
8Â Â 5Â Â 14Â Â 12
Linked list After Reversing :
12Â Â 14Â Â 5Â Â 8
.
Program to insert in a sorted list #includestdio.h#include.pdfsudhirchourasia86
* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* function to insert a new_node in a list. Note that this
function expects a pointer to head_ref as this can modify the
head of the input linked list (similar to push())*/
void sortedInsert(struct node** head_ref, struct node* new_node)
{
struct node* current;
/* Special case for the head end */
if (*head_ref == NULL || (*head_ref)->data >= new_node->data)
{
new_node->next = *head_ref;
*head_ref = new_node;
}
else
{
/* Locate the node before the point of insertion */
current = *head_ref;
while (current->next!=NULL &&
current->next->data < new_node->data)
{
current = current->next;
}
new_node->next = current->next;
current->next = new_node;
}
}
/* BELOW FUNCTIONS ARE JUST UTILITY TO TEST sortedInsert */
/* A utility function to create a new node */
struct node *newNode(int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
new_node->next = NULL;
return new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Drier program to test count function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
struct node *new_node = newNode(5);
sortedInsert(&head, new_node);
new_node = newNode(10);
sortedInsert(&head, new_node);
new_node = newNode(7);
sortedInsert(&head, new_node);
new_node = newNode(3);
sortedInsert(&head, new_node);
new_node = newNode(1);
sortedInsert(&head, new_node);
new_node = newNode(9);
sortedInsert(&head, new_node);
printf(\"\ Created Linked List\ \");
printList(head);
return 0;
}
public class Listnode {
//*** fields ***
private Object data;
private Listnode next;
//*** methods ***
// 2 constructors
public Listnode(Object d) {
this(d, null);
}
public Listnode(Object d, Listnode n) {
data = d;
next = n;
}
// access to fields
public Object getData() {
return data;
}
public Listnode getNext() {
return next;
}
// modify fields
public void setData(Object ob) {
data = ob;
}
public void setNext(Listnode n) {
next = n;
}
}
Thsi below program print out all the varibles in SLL
#include
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Given a reference (pointer to pointer) to the head
of a list and an int, push a new node on the front
of the list. */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Takes head pointer of the linked list and index
as arguments and return data at index*/
int GetNth(struct node* head, int index)
{
struct node* current = head;
int .
could you implement this function please, im having issues with it..pdfferoz544
could you implement this function please, im having issues with it.
void makeList (const ListNode::value_type [],const size_t& count)
class ListNode
{
public:
typedef int value_type;
ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum () const { return datum; }
ListNode const* getNext () const { return next; }
//Mutator
void setDatum (const value_type& d) {datum = d; }
ListNode* getNext () { return next; }
void setNext (ListNode* new_link) {next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList ();
virtual ~LinkedList ();
void insertItem (ListNode::value_type);
void makeList (const ListNode::value_type [],const size_t& count);
void deleteList ();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
This is the pseudocode, but i still have a hard time undertanding it.
Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function
receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head
node, index n will be the last node.
First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to
the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next
node. While more nodes to add { Create a new node initialized with the data value and a NULL
pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to
point to the new node. Get a data value for the next node. }
Thanks.
Solution
//linkedList.h
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
#include
#include
class ListNode
{
public:
typedef int value_type;
ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum() const { return datum; }
ListNode const* getNext() const { return next; }
//Mutator
void setDatum(const value_type& d) { datum = d; }
ListNode* getNext() { return next; }
void setNext(ListNode* new_link) { next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList();
virtual ~LinkedList();
void insertItem(ListNode::value_type);
void makeList(const ListNode::value_type[], const size_t& count);
void deleteList();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
#endif
-------------------------------------------------------------
//linkedList.cpp
#include \"linkedlist.h\"
LinkedList::LinkedList()
{
head = NULL;
}
LinkedList::~LinkedList()
{
ListNode *tmp = head;
while (tmp != NULL)
{
head = head->getNext();
delete tmp;
tmp = head;
}
}
void LinkedList::insertItem(ListNode::value_type item)
{
ListNode *newNode,*cur = head;
newNode = new ListNode;
newNode->setDatum(item);
newNode->setNext(NULL);.
Below is a depiction of a doubly-linked list implementation of the bag.docxgilliandunce53776
Below is a depiction of a doubly-linked list implementation of the bag ADT with two sentinels -one at the head and one at the tail. Strict DLink { TYPE value; strict DLink * next; struct DLink * prev;}; strict linked List { int size; struct DLink *frontSentinel; struct DLink *backSentinel;}; Write a function that at first reverses the list and then prints the values of the links in the list from front to back. Don\'t redirect to any other function. You must use assertions if necessary.
Solution
/* Program to reverse a doubly linked list */
#include <stdio.h>
#include <stdlib.h>
/* a node of the doubly linked list */
struct node
{
int data;
struct node *n;
struct node *pr;
};
/* Function to reverse a Doubly Linked List */
void reverse(struct node **head_r)
{
struct node *t = NULL;
struct node *cur = *head_r;
/* swap next and prev for all nodes of
doubly linked list */
while (cur != NULL)
{
t = cur->pr;
cur->pr = cur->n;
cur->n = t;
cur = cur->pr;
}
/* Before changing head, check for the cases like empty
list and list with only one node */
if(t != NULL )
*head_r = t->pr;
}
/* UTILITY FUNCTIONS */
/* Function to insert a node at the beginging of the Doubly Linked List */
void push(struct node** head_r, int new_data)
{
/* allocate node */
struct node* n_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
n_node->data = n_data;
/* since we are adding at the begining,
prev is always NULL */
n_node->pr = NULL;
/* link the old list off the new node */
n_node->n = (*head_r);
/* change prev of head node to new node */
if((*head_r) != NULL)
(*head_r)->pr = n_node ;
/* move the head to point to the new node */
(*head_r) = n_node;
}
/* Function to print nodes in a given doubly linked list
This function is same as printList() of singly linked lsit */
void printList(struct node *node)
{
while(node!=NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
}
/* Drier program to test above functions*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
/* Let us create a sorted linked list to test the functions
Created linked list will be 10->8->4->2 */
push(&head, 2);
push(&head, 4);
push(&head, 8);
push(&head, 10);
printf(\"\ Original Linked list \");
printList(head);
/* Reverse doubly linked list */
reverse(&head);
printf(\"\ Reversed Linked list \");
printList(head);
getchar();
}
.
In the class we extensively discussed a node class called IntNode in.pdfarjunstores123
In the class we extensively discussed a node class called IntNode in which each linked list node
contains an integer and each node is linked forward to the next element in the list. Implement a
node class called DoublyIntNode in which each node contains an integer number and each node
is linked not only forward to the next element in the list but also backward to the previous
element in the list. Your implementation of DoublyIntNode should adapt and implement all the
methods of IntNode including the following methods:
Constructor for DoublyIntNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
IntNode and Node classes:
public class IntNode{
private int data;
private IntNode link;
// methods here
}
public class Node {
private E data;
private Node link;
// methods here
}
Solution
program
#include
using namespace std;
struct list
{
struct list *prev;
int data;
struct list *next;
}
*node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class Dlist
{
public:
void insert_beg() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
void insert_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
void display() {
node = first;
cout << \"List of data in Linked list in Ascending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->next;
}
node = last;
cout << \"List of data in Linked list in Descending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->prev;
}
}
void del()
{
int count = 0, number, i;
node = node1 = node2 = first;
for(node = first; node != NULL; node = node->next)
cout << \"Enter value for the node:\" << endl;
count++;
display();
cout << count << \" nodes available here!\" << endl;
cout << \"Enter the node number which you want to delete:\" << endl;
cin >> number;
if(number != 1)
{
if(number < count && number > 0)
{
for(i = 2; i <= number; i++)
node = node->next;
for(i = 2; i <= number-1; i++)
node1 = node1->next;
for(i = 2; i <= number+1; i++)
node2 = node2->next;
node2->prev = node1;
node1->next = node2;
node->prev = NULL;
node->next = NULL;
node = NULL;
}
else if(number == count)
{
node = last;
last = node->prev;
last->next = NULL;
node = NULL;
}
else
cout << \"Invalid node.
C++ Doubly-Linked ListsThe goal of the exercise is to implement a.pdfpoblettesedanoree498
C++: Doubly-Linked Lists
The goal of the exercise is to implement a class List of doubly- linked lists.
My goal is to implement the class in a file doubly-linked.cpp.
The class List implements lists using the following structures for list ele- ments:
struct Node { int val ;
Node next;
Node prev; };
Each Node contains a value (an integer) and two pointers: one meant to point to the next element
of the list and one meant to point to the previous element in the list. The class provides the
following methods that you need to implement:
• A constructor and a destructor, with no arguments;
• void insert(int n): insert an integer at the end of the list;
• void reverse(): reverse the list;
• void print(): print the list to cout in the same format as the input (i.e. integers separated by
spaces);
doubly-linked.h
#ifndef __dll__
#define __dll__
#include
using namespace std;
// Basic structure to store elements of a list
struct Node {
int val; // contains the value
Node * next; // pointer to the next element in the list
Node * prev; // pointer to the previous element in the list
};
// Class List
class List {
public:
List(void); // Constructor
~List(void); // Destructor
void insert(int n); // This should insert n in the list
void reverse(void); // This should reverse the list
void print(void); // This shoiuld print the list
private:
Node * first; // Pointer to the first (if any) element in the list
};
#endif
main.cpp
#include
#include \"doubly-linked.h\"
using namespace std;
int main(void){
List l;
int n;
while(cin >> n){
l.insert(n);
}
// Print list as read from cin
l.print();
// Reverse the list and print it
l.reverse();
l.print();
// Reverse again and print it
l.reverse();
l.print();
return 0;
}
Solution
#include
using namespace std;
/* Linked list structure */
struct list {
struct list *prev;
int data;
struct list *next;
} *node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class linkedlist {
public:
/* Function for create/insert node at the beginning of Linked list */
void insrt_frnt() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
/* Function for create/insert node at the end of Linked list */
void insrt_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
/* Function for Display Linked list */
void display() {
node = first;
cout << \"List of data in L.
Write a C++ function that delete nodes in a doubly linkedlist- It shou.docxnoreendchesterton753
Write a C++ function that delete nodes in a doubly linkedlist.
It should delete all nodes that have that specific value. Finally, return the head of the linkedlist.
node * DN(node *head, int value) {
}
The linkedlist structure:
struct n {
int value;
node *next;
node *previous;
};
Solution
#include<stdio.h>
#include<stdlib.h>
#include<assert.h>
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Function to delete the entire linked list */
void deleteList(struct node** head_ref)
{
/* deref head_ref to get the real head */
struct node* current = *head_ref;
struct node* next;
while (current != NULL)
{
next = current->next;
free(current);
current = next;
}
/* deref head_ref to affect the real head back
in the caller. */
*head_ref = NULL;
}
/* Given a reference (pointer to pointer) to the head
of a list and an int, push a new node on the front
of the list. */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref)Â Â Â = new_node;
}
/* Drier program to test count function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
/* Use push() to construct below list
1->12->1->4->1 */
push(&head, 1);
push(&head, 4);
push(&head, 1);
push(&head, 12);
push(&head, 1);
printf(\"\ Deleting linked list\");
deleteList(&head);
printf(\"\ Linked list deleted\");
}
.
- Data structures allow for efficient handling of large volumes of data through logical organization and relationships between data elements. Common linear data structures include arrays, lists, stacks, and queues, while trees and graphs are examples of non-linear data structures.
- Abstract data types (ADTs) define a set of complex data objects and operations that can be performed on those objects without specifying their implementation. Data structures provide a way to implement the logical relationships and operations defined in an ADT.
- Linked lists provide an alternative to arrays for storing data by linking each data element to the next using pointers, rather than requiring contiguous memory locations. This allows for more flexible insertion and deletion compared to arrays.
How do you stop infinite loop Because I believe that it is making a.pdffeelinggift
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
Data structures cs301 power point slides lecture 03Nasir Mehmood
The document discusses linked lists and C++ code for implementing a linked list. It includes definitions of a Node class to represent individual nodes, with fields for storing data and pointers to other nodes. It also defines a List class for managing the overall linked list, including functions for adding new nodes to the list. Diagrams show how nodes are linked and stored non-contiguously in memory. The code provided implements adding new nodes to the front or end of the linked list by updating pointer references between nodes.
C++ please put everthing after you answer it- thanks Complete the stub.docxMatthPYNashd
C++ please put everthing after you answer it, thanks
Complete the stub file for the DoublyLinkedList implementation.
Please note: Any changes to the NodeType struct, not using the NodeType struct, or changing from template Type to using a specific data type will all be cause for deductions.
You are required to implement the methods:
insertFirst
insertLast
insertNode - (insert an item at a given index)
deleteNode - (remove a specific item)
The stub file contains the basic class format to implement the virtual methods from ListType. You should only need to complete the code for these four functions. Your code must maintain (or add) the node connections both forward and backward. In the double link list class these are called next and prev.
Your code must also maintain the count variable.
\} template Type ListType : : back ( ) const \{ assert(tail != NULL); //confirm tail exists return tail->data; //return the data of the tail node \} template void ListType >: :copyList (const ListType > \& otherList) \{ NodeType *newNode; //pointer to create a node NodeType current; //pointer to traverse the list if (head ! = NULL) //if the list is nonempty, make it empty destroyList(); if (otherList. head == NULL) //otherList is empty \{ head = NULL; tail = NULL; count = 0 ; \} else \{ current = otherList. head; // current points to the count = otherList . count; // list to be copied //copy the head node head = new NodeType < Type > ; / / create the node head->data = current > data; // copy the data head->next = NULL; // set the link field of tail = head; // the node to NULL // the next node //copy the remaining list while (current != NULL) \{ newNode = new NodeType < Type > ; // create a node newNode > data = current > data; // copy the data newNode->next = NULL; // set the link of // newNode to NULL tail->next = newNode; //attach newNode after tail tail = newNode; // make tail point to //the actual tail node current = current > next; 1/ make current point //to the next node \}/ /end while \}/lend else \}//end copylist
.
C++ Please write the whole code that is needed for this assignment- wr.docxBrianGHiNewmanv
Brianca plans to save $5,000, $1,000, and $42,000 a year over the next three years, respectively. How much would you need to deposit in one lump sum today to have the same amount as Brianca three years from now if you both earn 10.9 percent, compounded annually? $36,115 $35,192 $43,282 $41,635 $35,372
.
This document provides information about linked lists. It defines a linked list as a linear data structure where nodes are linked using pointers. Each node contains a data field and a pointer to the next node. It compares linked lists to arrays, noting that linked lists can dynamically allocate memory as needed, while arrays have fixed sizes. It describes the two main types of linked lists - singly linked and doubly linked. It provides examples of basic linked list operations like insertion, deletion and traversal for both singly and doubly linked lists. It also discusses some applications of linked lists like implementing stacks, queues and representing polynomials.
This C++ code defines a linked stack data structure using classes. The Lstack class implements a linked stack with methods to push values onto the stack, pop values off the stack, and display the stack. A main function tests the stack by pushing multiple values, displaying the stack, popping a value, and displaying the modified stack.
Write java program using linked list to get integer from user and.docxajoy21
This document provides the code for a Java program that uses a linked list to count even and odd numbers entered by the user. The program defines a Node class to create nodes for the linked list. It also defines methods to push nodes onto the front of the list, segregate the even and odd nodes, and print the list. The main method tests the program by pushing sample integers onto a linked list, segregating the even and odd nodes, and printing the modified list.
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Assignment isPage 349-350 #4 and #5 Use the Linked List lab.pdffortmdu
Assignment is:
\"Page 349-350 #4 and #5 Use the \"Linked List lab\" you have been working on in class and add
the two functions the questions are asking you to develop: divideMid and divideAt. Be sure to
include comments Use meaningful identifier names (constants where appropriate) Turn in .cpp
file AND Turn in a \"print-screen\' of your output (press \"print-screen\' on keyboard, then
\'paste\' in MS-Word)\"
How do you solve QUESTION #4 in the book data structures using c++ by D.S. Malik in Visiual
Studios using the linked list below with what is being asked? Please need help
Linked list :
#include
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *first, *last;
int num;
createList(first, last);
int choice;
while(true)
{
cout<<\"1. Insert Front.\ 2. Insert Last.\ 3. Delete Front.\ 4. Delete Last.\ 5. Print List.\ 6. Exit.\
\";
cout<<\"Enter your choice: \";
cin>>choice;
switch(choice)
{
case 1: insertFront(first); break;
case 2: insertBack(last); break;
case 3: deleteFirst(first); break;
case 4: deleteLast(last, first); break;
case 5: printList(first); break;
case 6: return 0;
default: cout<<\"Invalid menu option. Try again.\"<>number;
while (number != -999)
{
newNode = new nodeType; // create new node
newNode->info = number;
newNode->link = NULL;
if (first == NULL)
{
first = newNode;
last = newNode;
}
else
{
last->link = newNode;
last = newNode;
}
cout<<\"Enter an integer (-999 to stop): \";
cin>>number;
} // end of while-loop
} // end of build list function
void deleteFirst(nodeType*& first)
{
nodeType *temp;
temp= first;
first= temp->link;
delete temp;
return;
}
void deleteLast(nodeType*& last, nodeType* current)
{
nodeType *temp;
while(current->link != NULL)
{
temp=current;
current=current->link;
}
temp=last;
current->link=NULL;
delete temp;
last = current;
return;
}
void insertFront(nodeType*& front)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= front;
front= newNode;
return;
}
void insertBack(nodeType*& last)
{
int num;
cout<<\"\ Enter the number to insert: \";
cin>>num;
nodeType *newNode = new nodeType;
newNode->info=num;
newNode->link= NULL;
last->link= newNode;
last = newNode;
return;
}
void printList(nodeType*& first)
{
cout<<\"Inside printList...printing linked list...\ \"<info << \" \";
current = current->link;
}
cout<
#include
using namespace std;
struct nodeType
{
int info;
nodeType *link;
};
void createList(nodeType*& first, nodeType*& last);
void printList(nodeType*& first);
void insertFront(nodeType*& first);
void insertBack(nodeType*& last);
void deleteFirst(nodeType*& first);
void deleteLast(nodeType*& last, nodeType* first);
int main()
{
nodeType *firs.
Data Structures in C++I am really new to C++, so links are really .pdfrohit219406
Data Structures in C++
I am really new to C++, so links are really hard topic for me. It would be nice if you can provide
explanations of what doubly linked lists are and of some of you steps... Thank you
In this assignment, you will implement a doubly-linked list class, together with some list
operations. To make things easier, you’ll implement a list of int, rather than a template class.
Solution
A variable helps us to identify the data. For ex: int a = 5; Here 5 is identified through variable a.
Now, if we have collection of integers, we need some representation to identify them. We call it
array. For ex: int arr[5]
This array is nothing but a Data Structure.
So, a Data Structure is a way to group the data.
There are many Data Structures available like Arrays, Linked List, Doubly-Linked list, Stack,
Queue, etc.
Doubly-Linked list are the ones where you can traverse from the current node both in left and
right directions.
Why so many different types of Data Structures are required ?
Answer is very simple, grouping of data, storage of data and accessing the data is different.
For example, in case of Arrays we store all the data in contiguous locations.
What if we are not able to store the data in contiguous locations because we have huge data.
Answer is go for Linked List/Doubly-Linked list.
Here we can store the data anywhere and link the data through pointers.
I will try to provide comments for the code you have given. May be this can help you.
#pragma once
/*
dlist.h
Doubly-linked lists of ints
*/
#include
class dlist {
public:
dlist() { }
// Here we are creating a NODE, it has a integer value and two pointers.
// One pointer is to move to next node and other to go back to previous node.
struct node {
int value;
node* next;
node* prev;
};
// To return head pointer, i.e. start of the Doubly-Linked list.
node* head() const { return _head; }
// To return Tail pointer, i.e. end of the Doubly-Linked list.
node* tail() const { return _tail; }
// **** Implement ALL the following methods ****
// Returns the node at a particular index (0 is the head).
node* at(int index){
int cnt = 0;
struct node* tmp = head();
while(tmp!=NULL)
{
if (cnt+1 == index)
return tmp;
tmp = tmp->next;
}
}
// Insert a new value, after an existing one
void insert(node *previous, int value){
// check if the given previous is NULL
if (previous == NULL)
{
printf(\"the given previous node cannot be NULL\");
return;
}
// allocate new node
struct node* new_node =(struct node*) malloc(sizeof(struct node));
// put in the data
new_node->data = new_data;
// Make next of new node as next of previous
new_node->next = previous->next;
// Make the next of previous as new_node
previous->next = new_node;
// Make previous as previous of new_node
new_node->prev = previous;
// Change previous of new_node\'s next node
if (new_node->next != NULL)
new_node->next->prev = new_node;
}
// Delete the given node
void del(node* which){
struct node* head_ref = head();
/* base case */
if(*head_ref == NUL.
coding in C- Create a function called reverseList that takes the head.docxtienlivick
coding in C;
Create a function called reverseList that takes the head of a linked list, reverses the order of all the nodes. For example, if the list contained 1, 2, 3, 4 in its nodes, the list will now contain 4, 3, 2, 1.
please add a main test.
Solution
Please find the required program below:
#include<stdio.h>
#include<stdlib.h>
struct node
{
int data;
struct node* next;
};
void push(struct node** head, int new_element)
{
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
new_node->data = new_element;
new_node->next = (*head);
(*head) = new_node;
}
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
void reverseList(struct node** head)
{
struct node* prev = NULL;
struct node* current = *head;
struct node* next;
while (current != NULL)
{
next = current->next;
current->next = prev;
prev = current;
current = next;
}
*head = prev;
}
int main()
{
struct node* head = NULL;
push(&head, 12);
push(&head, 14);
push(&head, 5);
push(&head, 8);
printf(\"\ Linked list Before Reversing :\ \");
printList(head);
reverseList(&head);
printf(\"\ Linked list After Reversing :\ \");
printList(head);
}
--------------------------------------------------------------------------------
OUTPUT:
Linked list Before Reversing :
8Â Â 5Â Â 14Â Â 12
Linked list After Reversing :
12Â Â 14Â Â 5Â Â 8
.
Program to insert in a sorted list #includestdio.h#include.pdfsudhirchourasia86
* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* function to insert a new_node in a list. Note that this
function expects a pointer to head_ref as this can modify the
head of the input linked list (similar to push())*/
void sortedInsert(struct node** head_ref, struct node* new_node)
{
struct node* current;
/* Special case for the head end */
if (*head_ref == NULL || (*head_ref)->data >= new_node->data)
{
new_node->next = *head_ref;
*head_ref = new_node;
}
else
{
/* Locate the node before the point of insertion */
current = *head_ref;
while (current->next!=NULL &&
current->next->data < new_node->data)
{
current = current->next;
}
new_node->next = current->next;
current->next = new_node;
}
}
/* BELOW FUNCTIONS ARE JUST UTILITY TO TEST sortedInsert */
/* A utility function to create a new node */
struct node *newNode(int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
new_node->next = NULL;
return new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Drier program to test count function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
struct node *new_node = newNode(5);
sortedInsert(&head, new_node);
new_node = newNode(10);
sortedInsert(&head, new_node);
new_node = newNode(7);
sortedInsert(&head, new_node);
new_node = newNode(3);
sortedInsert(&head, new_node);
new_node = newNode(1);
sortedInsert(&head, new_node);
new_node = newNode(9);
sortedInsert(&head, new_node);
printf(\"\ Created Linked List\ \");
printList(head);
return 0;
}
public class Listnode {
//*** fields ***
private Object data;
private Listnode next;
//*** methods ***
// 2 constructors
public Listnode(Object d) {
this(d, null);
}
public Listnode(Object d, Listnode n) {
data = d;
next = n;
}
// access to fields
public Object getData() {
return data;
}
public Listnode getNext() {
return next;
}
// modify fields
public void setData(Object ob) {
data = ob;
}
public void setNext(Listnode n) {
next = n;
}
}
Thsi below program print out all the varibles in SLL
#include
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Given a reference (pointer to pointer) to the head
of a list and an int, push a new node on the front
of the list. */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Takes head pointer of the linked list and index
as arguments and return data at index*/
int GetNth(struct node* head, int index)
{
struct node* current = head;
int .
could you implement this function please, im having issues with it..pdfferoz544
could you implement this function please, im having issues with it.
void makeList (const ListNode::value_type [],const size_t& count)
class ListNode
{
public:
typedef int value_type;
ListNode (value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum () const { return datum; }
ListNode const* getNext () const { return next; }
//Mutator
void setDatum (const value_type& d) {datum = d; }
ListNode* getNext () { return next; }
void setNext (ListNode* new_link) {next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList ();
virtual ~LinkedList ();
void insertItem (ListNode::value_type);
void makeList (const ListNode::value_type [],const size_t& count);
void deleteList ();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
This is the pseudocode, but i still have a hard time undertanding it.
Creating a List (makeList(const ListNode::value_type [],const size_t& count)) This function
receives an array in the order that we want to add it to the linkedlist. Index 0 will be the head
node, index n will be the last node.
First, create a node initialized with a data value and a NULL pointer. Set the \"head\" to point to
the first node. Set up a current-pointer to the first node (or \"head\"). Get a data value for the next
node. While more nodes to add { Create a new node initialized with the data value and a NULL
pointer. Set the current-pointer link member (\"next\") to the new node. Set the current-pointer to
point to the new node. Get a data value for the next node. }
Thanks.
Solution
//linkedList.h
#ifndef LINKEDLIST_H
#define LINKEDLIST_H
#include
#include
class ListNode
{
public:
typedef int value_type;
ListNode(value_type d = value_type(), ListNode* n = NULL) { datum = d; next = n; }
//Assessor
value_type getDatum() const { return datum; }
ListNode const* getNext() const { return next; }
//Mutator
void setDatum(const value_type& d) { datum = d; }
ListNode* getNext() { return next; }
void setNext(ListNode* new_link) { next = new_link; }
private:
value_type datum;
ListNode* next;
};
class LinkedList
{
public:
LinkedList();
virtual ~LinkedList();
void insertItem(ListNode::value_type);
void makeList(const ListNode::value_type[], const size_t& count);
void deleteList();
//The following friend function is implemented in lablinklist.cpp
friend std::ostream& operator<<(std::ostream&, const LinkedList&);
private:
ListNode* head;
};
#endif
-------------------------------------------------------------
//linkedList.cpp
#include \"linkedlist.h\"
LinkedList::LinkedList()
{
head = NULL;
}
LinkedList::~LinkedList()
{
ListNode *tmp = head;
while (tmp != NULL)
{
head = head->getNext();
delete tmp;
tmp = head;
}
}
void LinkedList::insertItem(ListNode::value_type item)
{
ListNode *newNode,*cur = head;
newNode = new ListNode;
newNode->setDatum(item);
newNode->setNext(NULL);.
Below is a depiction of a doubly-linked list implementation of the bag.docxgilliandunce53776
Below is a depiction of a doubly-linked list implementation of the bag ADT with two sentinels -one at the head and one at the tail. Strict DLink { TYPE value; strict DLink * next; struct DLink * prev;}; strict linked List { int size; struct DLink *frontSentinel; struct DLink *backSentinel;}; Write a function that at first reverses the list and then prints the values of the links in the list from front to back. Don\'t redirect to any other function. You must use assertions if necessary.
Solution
/* Program to reverse a doubly linked list */
#include <stdio.h>
#include <stdlib.h>
/* a node of the doubly linked list */
struct node
{
int data;
struct node *n;
struct node *pr;
};
/* Function to reverse a Doubly Linked List */
void reverse(struct node **head_r)
{
struct node *t = NULL;
struct node *cur = *head_r;
/* swap next and prev for all nodes of
doubly linked list */
while (cur != NULL)
{
t = cur->pr;
cur->pr = cur->n;
cur->n = t;
cur = cur->pr;
}
/* Before changing head, check for the cases like empty
list and list with only one node */
if(t != NULL )
*head_r = t->pr;
}
/* UTILITY FUNCTIONS */
/* Function to insert a node at the beginging of the Doubly Linked List */
void push(struct node** head_r, int new_data)
{
/* allocate node */
struct node* n_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
n_node->data = n_data;
/* since we are adding at the begining,
prev is always NULL */
n_node->pr = NULL;
/* link the old list off the new node */
n_node->n = (*head_r);
/* change prev of head node to new node */
if((*head_r) != NULL)
(*head_r)->pr = n_node ;
/* move the head to point to the new node */
(*head_r) = n_node;
}
/* Function to print nodes in a given doubly linked list
This function is same as printList() of singly linked lsit */
void printList(struct node *node)
{
while(node!=NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
}
/* Drier program to test above functions*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
/* Let us create a sorted linked list to test the functions
Created linked list will be 10->8->4->2 */
push(&head, 2);
push(&head, 4);
push(&head, 8);
push(&head, 10);
printf(\"\ Original Linked list \");
printList(head);
/* Reverse doubly linked list */
reverse(&head);
printf(\"\ Reversed Linked list \");
printList(head);
getchar();
}
.
In the class we extensively discussed a node class called IntNode in.pdfarjunstores123
In the class we extensively discussed a node class called IntNode in which each linked list node
contains an integer and each node is linked forward to the next element in the list. Implement a
node class called DoublyIntNode in which each node contains an integer number and each node
is linked not only forward to the next element in the list but also backward to the previous
element in the list. Your implementation of DoublyIntNode should adapt and implement all the
methods of IntNode including the following methods:
Constructor for DoublyIntNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
IntNode and Node classes:
public class IntNode{
private int data;
private IntNode link;
// methods here
}
public class Node {
private E data;
private Node link;
// methods here
}
Solution
program
#include
using namespace std;
struct list
{
struct list *prev;
int data;
struct list *next;
}
*node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class Dlist
{
public:
void insert_beg() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
void insert_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
void display() {
node = first;
cout << \"List of data in Linked list in Ascending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->next;
}
node = last;
cout << \"List of data in Linked list in Descending order!\" << endl;
while(node != NULL) {
cout << node->data << endl;
node = node->prev;
}
}
void del()
{
int count = 0, number, i;
node = node1 = node2 = first;
for(node = first; node != NULL; node = node->next)
cout << \"Enter value for the node:\" << endl;
count++;
display();
cout << count << \" nodes available here!\" << endl;
cout << \"Enter the node number which you want to delete:\" << endl;
cin >> number;
if(number != 1)
{
if(number < count && number > 0)
{
for(i = 2; i <= number; i++)
node = node->next;
for(i = 2; i <= number-1; i++)
node1 = node1->next;
for(i = 2; i <= number+1; i++)
node2 = node2->next;
node2->prev = node1;
node1->next = node2;
node->prev = NULL;
node->next = NULL;
node = NULL;
}
else if(number == count)
{
node = last;
last = node->prev;
last->next = NULL;
node = NULL;
}
else
cout << \"Invalid node.
C++ Doubly-Linked ListsThe goal of the exercise is to implement a.pdfpoblettesedanoree498
C++: Doubly-Linked Lists
The goal of the exercise is to implement a class List of doubly- linked lists.
My goal is to implement the class in a file doubly-linked.cpp.
The class List implements lists using the following structures for list ele- ments:
struct Node { int val ;
Node next;
Node prev; };
Each Node contains a value (an integer) and two pointers: one meant to point to the next element
of the list and one meant to point to the previous element in the list. The class provides the
following methods that you need to implement:
• A constructor and a destructor, with no arguments;
• void insert(int n): insert an integer at the end of the list;
• void reverse(): reverse the list;
• void print(): print the list to cout in the same format as the input (i.e. integers separated by
spaces);
doubly-linked.h
#ifndef __dll__
#define __dll__
#include
using namespace std;
// Basic structure to store elements of a list
struct Node {
int val; // contains the value
Node * next; // pointer to the next element in the list
Node * prev; // pointer to the previous element in the list
};
// Class List
class List {
public:
List(void); // Constructor
~List(void); // Destructor
void insert(int n); // This should insert n in the list
void reverse(void); // This should reverse the list
void print(void); // This shoiuld print the list
private:
Node * first; // Pointer to the first (if any) element in the list
};
#endif
main.cpp
#include
#include \"doubly-linked.h\"
using namespace std;
int main(void){
List l;
int n;
while(cin >> n){
l.insert(n);
}
// Print list as read from cin
l.print();
// Reverse the list and print it
l.reverse();
l.print();
// Reverse again and print it
l.reverse();
l.print();
return 0;
}
Solution
#include
using namespace std;
/* Linked list structure */
struct list {
struct list *prev;
int data;
struct list *next;
} *node = NULL, *first = NULL, *last = NULL, *node1 = NULL, *node2 = NULL;
class linkedlist {
public:
/* Function for create/insert node at the beginning of Linked list */
void insrt_frnt() {
list *addBeg = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addBeg->data;
if(first == NULL) {
addBeg->prev = NULL;
addBeg->next = NULL;
first = addBeg;
last = addBeg;
cout << \"Linked list Created!\" << endl;
}
else {
addBeg->prev = NULL;
first->prev = addBeg;
addBeg->next = first;
first = addBeg;
cout << \"Data Inserted at the beginning of the Linked list!\" << endl;
}
}
/* Function for create/insert node at the end of Linked list */
void insrt_end() {
list *addEnd = new list;
cout << \"Enter value for the node:\" << endl;
cin >> addEnd->data;
if(first == NULL) {
addEnd->prev = NULL;
addEnd->next = NULL;
first = addEnd;
last = addEnd;
cout << \"Linked list Created!\" << endl;
}
else {
addEnd->next = NULL;
last->next = addEnd;
addEnd->prev = last;
last = addEnd;
cout << \"Data Inserted at the end of the Linked list!\" << endl;
}
}
/* Function for Display Linked list */
void display() {
node = first;
cout << \"List of data in L.
Write a C++ function that delete nodes in a doubly linkedlist- It shou.docxnoreendchesterton753
Write a C++ function that delete nodes in a doubly linkedlist.
It should delete all nodes that have that specific value. Finally, return the head of the linkedlist.
node * DN(node *head, int value) {
}
The linkedlist structure:
struct n {
int value;
node *next;
node *previous;
};
Solution
#include<stdio.h>
#include<stdlib.h>
#include<assert.h>
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Function to delete the entire linked list */
void deleteList(struct node** head_ref)
{
/* deref head_ref to get the real head */
struct node* current = *head_ref;
struct node* next;
while (current != NULL)
{
next = current->next;
free(current);
current = next;
}
/* deref head_ref to affect the real head back
in the caller. */
*head_ref = NULL;
}
/* Given a reference (pointer to pointer) to the head
of a list and an int, push a new node on the front
of the list. */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref)Â Â Â = new_node;
}
/* Drier program to test count function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
/* Use push() to construct below list
1->12->1->4->1 */
push(&head, 1);
push(&head, 4);
push(&head, 1);
push(&head, 12);
push(&head, 1);
printf(\"\ Deleting linked list\");
deleteList(&head);
printf(\"\ Linked list deleted\");
}
.
- Data structures allow for efficient handling of large volumes of data through logical organization and relationships between data elements. Common linear data structures include arrays, lists, stacks, and queues, while trees and graphs are examples of non-linear data structures.
- Abstract data types (ADTs) define a set of complex data objects and operations that can be performed on those objects without specifying their implementation. Data structures provide a way to implement the logical relationships and operations defined in an ADT.
- Linked lists provide an alternative to arrays for storing data by linking each data element to the next using pointers, rather than requiring contiguous memory locations. This allows for more flexible insertion and deletion compared to arrays.
How do you stop infinite loop Because I believe that it is making a.pdffeelinggift
How do you stop infinite loop? Because I believe that it is making an infinite circular list.
c++ code:
Here is the list class:
#ifndef LIN_J_LIST
#define LIN_J_LIST
typedef unsigned int uint;
#include
#include
using namespace std;
/**
* a simplified generic singly linked list class to illustrate C++ concepts
* @author Jerry Lin
* @version 2/17/17
*/
template< typename Object >
class List
{
private:
/**
* A class to store data and provide a link to the next node in the list
*/
class Node
{
public:
/**
* The constructor
* @param data the data to be stored in this node
*/
explicit Node( const Object & data )
: data{ data }, next{ nullptr } {}
Object data;
Node * next;
};
public:
/**
* The constructor for an empty list
*/
List()
: size{ 0 }, first{ nullptr }, last{ nullptr } {}
/**
* the copy constructor-creates and copy the list
*/
List( List && rhs ) = delete;
List( const List & rhs )
{
count = 0;
size = 0;
if(rhs.size != 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first;
size++;
while(current->next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op.
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode->next;
size++;
}
}
// you document and implement this method
}
/**
* the operator= method-copies the list
*/
List & operator=( List && rhs) = delete;
List & operator=( const List & rhs )
{
count = 0;
size = 0;
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
if(rhs.size!= 0)
{
push_front(rhs.front());
Node * current = rhs.first;
Node * tempNode = first; //create a temporary to store
size++;
while(current -> next != nullptr)
{
current = current->next;
Node *newNode = new Node(current->data); //transfer the data. basic op
count++;
tempNode->next = newNode;
last = newNode;
tempNode = tempNode -> next;
size++;
}
}
return *this;
// you document and implement this method
}
/**
* accessor
* @return count
*/
int get_count() const
{
return count;
}
/**
* The destructor that gets rid of everything that\'s in the list and
* resets it to empty. If the list is already empty, do nothing.
*/
~List()
{
if( size != 0 )
{
Node * current = first;
Node * temp;
while( current != nullptr )
{
temp = current;
current = current->next;
delete temp;
}
}
}
/**
* Put a new element onto the beginning of the list
* @param item the data the new element will contain
*/
void push_front( const Object& item )
{
Node * new_node = new Node( item );//basic op.
if(is_empty())
{
last = new_node;
}
else
{
new_node->next = first;
}
first = new_node;
size++;
/* you complete the rest */
}
/**
* Remove the element that\'s at the front of the list. Causes an
* assertion error if the list is empty.
*/
void pop_front()
{
assert( !is_empty() );
Node * temp = first;
if( first == last )
{
first = last = nullptr;
}
else
{
first = first->next;
}
delete temp;
size--;
}
/**
* Accessor to return the da.
Data structures cs301 power point slides lecture 03Nasir Mehmood
The document discusses linked lists and C++ code for implementing a linked list. It includes definitions of a Node class to represent individual nodes, with fields for storing data and pointers to other nodes. It also defines a List class for managing the overall linked list, including functions for adding new nodes to the list. Diagrams show how nodes are linked and stored non-contiguously in memory. The code provided implements adding new nodes to the front or end of the linked list by updating pointer references between nodes.
C++ please put everthing after you answer it- thanks Complete the stub.docxMatthPYNashd
C++ please put everthing after you answer it, thanks
Complete the stub file for the DoublyLinkedList implementation.
Please note: Any changes to the NodeType struct, not using the NodeType struct, or changing from template Type to using a specific data type will all be cause for deductions.
You are required to implement the methods:
insertFirst
insertLast
insertNode - (insert an item at a given index)
deleteNode - (remove a specific item)
The stub file contains the basic class format to implement the virtual methods from ListType. You should only need to complete the code for these four functions. Your code must maintain (or add) the node connections both forward and backward. In the double link list class these are called next and prev.
Your code must also maintain the count variable.
\} template Type ListType : : back ( ) const \{ assert(tail != NULL); //confirm tail exists return tail->data; //return the data of the tail node \} template void ListType >: :copyList (const ListType > \& otherList) \{ NodeType *newNode; //pointer to create a node NodeType current; //pointer to traverse the list if (head ! = NULL) //if the list is nonempty, make it empty destroyList(); if (otherList. head == NULL) //otherList is empty \{ head = NULL; tail = NULL; count = 0 ; \} else \{ current = otherList. head; // current points to the count = otherList . count; // list to be copied //copy the head node head = new NodeType < Type > ; / / create the node head->data = current > data; // copy the data head->next = NULL; // set the link field of tail = head; // the node to NULL // the next node //copy the remaining list while (current != NULL) \{ newNode = new NodeType < Type > ; // create a node newNode > data = current > data; // copy the data newNode->next = NULL; // set the link of // newNode to NULL tail->next = newNode; //attach newNode after tail tail = newNode; // make tail point to //the actual tail node current = current > next; 1/ make current point //to the next node \}/ /end while \}/lend else \}//end copylist
.
C++ Please write the whole code that is needed for this assignment- wr.docxBrianGHiNewmanv
Brianca plans to save $5,000, $1,000, and $42,000 a year over the next three years, respectively. How much would you need to deposit in one lump sum today to have the same amount as Brianca three years from now if you both earn 10.9 percent, compounded annually? $36,115 $35,192 $43,282 $41,635 $35,372
.
This document provides information about linked lists. It defines a linked list as a linear data structure where nodes are linked using pointers. Each node contains a data field and a pointer to the next node. It compares linked lists to arrays, noting that linked lists can dynamically allocate memory as needed, while arrays have fixed sizes. It describes the two main types of linked lists - singly linked and doubly linked. It provides examples of basic linked list operations like insertion, deletion and traversal for both singly and doubly linked lists. It also discusses some applications of linked lists like implementing stacks, queues and representing polynomials.
This C++ code defines a linked stack data structure using classes. The Lstack class implements a linked stack with methods to push values onto the stack, pop values off the stack, and display the stack. A main function tests the stack by pushing multiple values, displaying the stack, popping a value, and displaying the modified stack.
Write java program using linked list to get integer from user and.docxajoy21
This document provides the code for a Java program that uses a linked list to count even and odd numbers entered by the user. The program defines a Node class to create nodes for the linked list. It also defines methods to push nodes onto the front of the list, segregate the even and odd nodes, and print the list. The main method tests the program by pushing sample integers onto a linked list, segregating the even and odd nodes, and printing the modified list.
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Data Structures and Agorithm: DS 05 Doubly Linked List.pptx
1. Data Structure
Lecture No. 5
Doubly Linked List
Engr. Rashid Farid Chishti
http://youtube.com/rfchishti
http://sites.google.com/site/chishti
International Islamic University H-10, Islamabad, Pakistan
Video Lecture
2. Moving forward in a singly-linked list is easy; moving backwards is not so easy.
To move back one node, we have to start at the head of the singly-linked list
and move forward until the node before the current.
To avoid this we can use two pointers in a node: one to point to next node and
another to point to the previous node:
Need to be more careful when adding or removing a node.
Consider add: the order in which pointers are reorganized is important:
Doubly Linked List
next
prev data
3. current = current -> prev ;
dnode *temp = new dnode ;
temp -> data = num ;
temp -> prev = current ;
temp -> next = current -> next ;
temp -> next -> prev = temp ;
current -> next = temp ;
Adding a new Node
NULL
temp
head
next
prev 9
current
next
prev 6
NULL
next
prev 2 next
prev 1
4. Deleting a Node
next
prev 2
NULL next
prev 6
NULL
next
prev 2
next
prev 9
void linklist :: d_delete ( int num ){
dnode *current = head ;
while ( current != NULL ){
if ( current -> data == num ){
if ( current == head ){
head = head -> next ;
head -> prev = NULL ;
}
else{
if ( current -> next == NULL )
current -> prev -> next = NULL ;
else {
current -> prev -> next = current -> next ;
current -> next -> prev = current -> prev ;
}
delete current ;
}
return ;
}
current = current -> next ;
}
cout << num << " not found." ;
}
head
current
num = 9
If it is the first node
If it is the last node
If it is any intermediate node
5. #include <iostream>
using namespace std;
class linklist {
private :
struct dnode {
dnode *prev ;
int data ;
dnode * next ;
} *head ;
public :
linklist( ) ;
void d_append ( int num ) ;
void d_addatbeg ( int num ) ;
void d_addafter ( int loc, int num ) ;
void d_display( ) ;
int d_count( ) ;
void d_delete( int i ) ;
~linklist( ) ;
} ;
5
Example 1: Doubly Linked List
linklist :: linklist( ){
head = NULL ;
}
// adds a new node at the end
void linklist :: d_append ( int num ){
dnode *r, *current ;
current = head ;
// if the linked list is empty
if ( current == NULL ){
//create a new node
current = new dnode ;
current -> prev = NULL ;
current -> data = num ;
current -> next = NULL ;
head = current ;
}
1 2
6. else{
// traverse the linked list
while ( current -> next != NULL )
current = current -> next ;
// add a new node at the end
r = new dnode ;
r -> data = num ;
r -> next = NULL ;
r -> prev = current ;
current -> next = r ;
}
}
// adds a new node at the begining
void linklist :: d_addatbeg ( int num ){
dnode *newNode ;
// create a new node
newNode = new dnode ;
6
Example 1: Doubly Linked List
// assign data to the new node
newNode -> prev = NULL ;
newNode -> data = num ;
newNode -> next = head ;
// make new node the head node
head -> prev = newNode ;
head = newNode ;
}
// adds at a specified position
void linklist :: d_addafter ( int loc,
int num ){
dnode *current ;
current = head ;
// skip to desired portion
for ( int i = 0 ; i < loc ; i++ ){
current = current -> next ;
3 4
7. // if reached at end of list
if ( current == NULL ){
cout << "nThere are less than "
<< loc << " elements" ;
return ;
}
}
// insert new node
current = current -> prev ;
dnode *temp = new dnode ;
temp -> data = num ;
temp -> prev = current ;
temp -> next = current -> next ;
temp -> next -> prev = temp ;
current -> next = temp ;
}
7
Example 1: Doubly Linked List
// displays the the linked list
void linklist :: d_display( ){
dnode *temp = head ;
cout << endl ;
// traverse the entire linked list
while ( temp != NULL ){
cout << temp -> data << " " ;
temp = temp -> next ;
}
}
// counts the number of nodes
int linklist :: d_count( ){
int c = 0 ;
dnode *temp = head ;
// traverse the entire linked list
while ( temp != NULL ){
temp = temp -> next ; c++ ;
}
5 6
8. return c ;
}
// deletes the specified node
void linklist :: d_delete ( int num ){
dnode *current = head ;
// traverse the entire linked list
while ( current != NULL ){
// if node to be deleted is found
if ( current -> data == num ){
// if it is the first node
if ( current == head ){
head = head -> next ;
head -> prev = NULL ;
}
else{
// if it is the last node
if ( current -> next == NULL )
8
Example 1: Doubly Linked List
current -> prev -> next = NULL ;
else {
// if it is any intermediate node
current -> prev -> next =
current -> next ;
current -> next -> prev =
current -> prev ;
}
delete current ;
}
// return back after deletion
return ;
}
// go to next node
current = current -> next ;
}
cout << "n" << num << " not found." ;
}
7 8
9. // deallocates memory
linklist :: ~linklist( ){
while ( head != NULL ){
dnode *q = head;
head = head -> next ;
delete q ;
}
}
int main( ){
linklist l ;
l.d_append ( 11 ) ;
l.d_append ( 2 ) ;
l.d_append ( 14 ) ;
l.d_append ( 17 ) ;
l.d_append ( 99 ) ;
cout << "nElements in doubly linked list:
" ;
9
Example 1: Doubly Linked List
l.d_display( ) ;
cout << "nNo. of elements in the
" doubly linked list: " << l.d_count();
l.d_addatbeg ( 33 ) ;
l.d_addatbeg ( 55 ) ;
cout << "nnElements in doubly linked list
after addition at the beginning: " ;
l.d_display( ) ;
cout << "nNo. of elements in the doubly
linked list: " << l.d_count( ) ;
l.d_addafter ( 4, 66 ) ;
l.d_addafter ( 2, 96 ) ;
cout << "nnElements in doubly linked
list after addition at the given position: "
;
9 10
10. l.d_display( ) ;
cout << "nNo. of elements in the doubly
linked list: " << l.d_count( ) ;
l.d_delete ( 55 ) ;
l.d_delete ( 2 ) ;
l.d_delete ( 99 ) ;
cout << "nnElements in doubly linked
list after deletion: " ;
l.d_display( ) ;
cout << "nNo. of elements in the doubly
linked list: n" << l.d_count( )
<< endl;
system("PAUSE");
return 0;
}
10
Example 1: Doubly Linked List
11 12
12. Image viewer – Previous and next images are linked, hence can be accessed
by next and previous button.
Previous and next page in web browser – We can access previous and next url
searched in web browser by pressing back and next button since, they are
linked as linked list.
Music Player – Songs in music player are linked to previous and next song. you
can play songs either from starting or ending of the list.
Applications of Doubly Linked List