The document discusses different crystal structures and their properties. It defines a unit cell as the smallest component of a crystal structure and describes four common crystal structures: simple cubic (SC), body centered cubic (BCC), face centered cubic (FCC), and hexagonal close packed (HCP). It calculates the average number of atoms per unit cell (Nav) for each as well as the packing efficiency or atomic packing factor (APF), with SC having the lowest efficiency at 52% and BCC, FCC, and HCP all having the highest at 74%.
Dear aspirants,
This presentation includes basic terms of crystallography, a brief note on unit cell and its type With derivation of its properties: APF, Coordination no., No. of atoms per unit cell and also its atomic radius. I also added 7 Crystal System, Bravais Lattice and finally Miller Indices concept.
Hope this presentation is helpful.
Any questions or clarifications are welcomed.
Crystal Material, Non-Crystalline Material, Crystal Structure, Space Lattice, Unit Cell, Crystal Systems, and Bravais Lattices, Simple Cubic Lattice, Body-Centered Cubic Structure, Face centered cubic structure, No of Atoms per Unit Cell, Atomic Radius, Atomic Packing Factor, Coordination Number, Crystal Defects, Point Defects, Line Defects, Planar Defects, Volume Defects.
Dear aspirants,
This presentation includes basic terms of crystallography, a brief note on unit cell and its type With derivation of its properties: APF, Coordination no., No. of atoms per unit cell and also its atomic radius. I also added 7 Crystal System, Bravais Lattice and finally Miller Indices concept.
Hope this presentation is helpful.
Any questions or clarifications are welcomed.
Crystal Material, Non-Crystalline Material, Crystal Structure, Space Lattice, Unit Cell, Crystal Systems, and Bravais Lattices, Simple Cubic Lattice, Body-Centered Cubic Structure, Face centered cubic structure, No of Atoms per Unit Cell, Atomic Radius, Atomic Packing Factor, Coordination Number, Crystal Defects, Point Defects, Line Defects, Planar Defects, Volume Defects.
undamentals of Crystal Structure: BCC, FCC and HCP Structures, coordination number and atomic packing factors, crystal imperfections -point line and surface imperfections. Atomic Diffusion: Phenomenon, Fick’s laws of diffusion, factors affecting diffusion.
The study of crystal geometry helps to understand the behaviour of solids and their
mechanical,
electrical,
magnetic
optical and
Metallurgical properties
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undamentals of Crystal Structure: BCC, FCC and HCP Structures, coordination number and atomic packing factors, crystal imperfections -point line and surface imperfections. Atomic Diffusion: Phenomenon, Fick’s laws of diffusion, factors affecting diffusion.
The study of crystal geometry helps to understand the behaviour of solids and their
mechanical,
electrical,
magnetic
optical and
Metallurgical properties
Online aptitude test management system project report.pdfKamal Acharya
The purpose of on-line aptitude test system is to take online test in an efficient manner and no time wasting for checking the paper. The main objective of on-line aptitude test system is to efficiently evaluate the candidate thoroughly through a fully automated system that not only saves lot of time but also gives fast results. For students they give papers according to their convenience and time and there is no need of using extra thing like paper, pen etc. This can be used in educational institutions as well as in corporate world. Can be used anywhere any time as it is a web based application (user Location doesn’t matter). No restriction that examiner has to be present when the candidate takes the test.
Every time when lecturers/professors need to conduct examinations they have to sit down think about the questions and then create a whole new set of questions for each and every exam. In some cases the professor may want to give an open book online exam that is the student can take the exam any time anywhere, but the student might have to answer the questions in a limited time period. The professor may want to change the sequence of questions for every student. The problem that a student has is whenever a date for the exam is declared the student has to take it and there is no way he can take it at some other time. This project will create an interface for the examiner to create and store questions in a repository. It will also create an interface for the student to take examinations at his convenience and the questions and/or exams may be timed. Thereby creating an application which can be used by examiners and examinee’s simultaneously.
Examination System is very useful for Teachers/Professors. As in the teaching profession, you are responsible for writing question papers. In the conventional method, you write the question paper on paper, keep question papers separate from answers and all this information you have to keep in a locker to avoid unauthorized access. Using the Examination System you can create a question paper and everything will be written to a single exam file in encrypted format. You can set the General and Administrator password to avoid unauthorized access to your question paper. Every time you start the examination, the program shuffles all the questions and selects them randomly from the database, which reduces the chances of memorizing the questions.
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Crystal Structure.pptx
1. Engineering Material Science
Sharad Institute of Technology, College of
Engineering, Yadrav-Ichalkaranji.
By : Mr.Swapnil B Herwade
Asst. Professor, A&R Dept.
2. Sub Topics of Lecture:
•Unit cell and Space Lattice
•Parameters of Unit Cell
•Crystal Structure
•Types of Crystal Structure-
1. Simple Cubic Structure(SC)
2. Body Centred Cubic Structure(BCC)
3. Face Centred Cubic Structure(FCC)
4. Hexagonal Close Packed Structure(HCP)
•Average number of atoms per unit cell (Nav)
•Packing Efficiency or Atomic Packing Factor(APF)
3. Unit Cell and Space Lattice:
Unit Cell: The Smallest component or unit of crystal structure.
Space Lattice: Three dimensional pattern of atoms in space.
So, entire crystal can be constructed by translational
repetition of unit cell in three dimension.
Unit Cell Space Lattice Atom
4. •If each atom in a lattice is replaced by a point, then each
point is called lattice point.
•Every point has identical or similar surrounding to the
other point.
•The space lattice of various materials differ in size and
shape of their unit cell
5. Parameters of Unit Cell:
Primitive: The edges of unit cell like length,
breadth, height.
In figure a(-axis), b(Y-axis), c(Z-axis) are
called primitives
Interfacial Angles: Angle between the edges,
as in figure we have angles like α,β,γ.
These three lengths (a,b,c) and three
interfacial angles (α,β,γ) of unit cell are
called Lattice Parameters or Geometrical
Constants of crystal system.
Thus by giving the value for axial length
and angles, we can form unit cell of various
shapes.
6. Crystal Structure:
• Simple Cubic Structure(SC)
• Body Centred Cubic Structure(BCC)
• Face Centred Cubic Structure(FCC)
• Hexagonal Close Packed Structure(HCP)
7. Simple Cubic Structure(SC):
•In these type of structure , atoms are
located at the corners of the unit cell or
cube.
•Total no. of corner atoms are 8.
•E.g. Polonium.
Corner
Atom
Cross
sectional view
8. Body Centred Cubic Structure(BCC):
•In this type of structure, atoms are located at
the corners of the unit cell or cube and one
atom at its centre.
•Total corner Atoms= 08
•Total Body centre atom= 01
•E.g. Lithium, Sodium, Potassium, tungsten,
Molybdenum etc.
Corner Atom
Body Center Atom
9. Face Centred Cubic Structure(FCC):
•In these type of structure, atoms are located at the corner of the
unit cell or cube and one atom on centre of each face.
•Total no. of corner atom= 08
•Total no. of Face centred atom= 06
•E.g. Copper, Silver, Gold, Aluminium, Lead etc.
Corner Atoms
Face Centre
10. Hexagonal Close Packed Structure(HCP):
•In this type of structure atom is placed at
twelve corner of hexagonal cell, one atom at
centre of each hexagonal faces and three atom in
the body of the unit cell.
•Total Corner Atoms = 12
•Total Face centre atom= 02
•Total body centre atom= 03
•E.g. Zinc, Magnesium, Lithium, Beryllium etc.
Face Center
Corner Atom
Body center
11. Comparison:
For SC :
Corner: 08
For BCC:
Corner: 08
Body centre: 01
For FCC:
Corner: 08
Face Centre: 06
For HCP:
Corner: 12
Body Centre:03
Face Centre: 02
12. Average number of Atoms per Unit Cell(Nav):
In Cubic structures ,
Corner atom is shared by 8 unit cells(4 from below and 4 from above).
Face centre atom is shared by 2 unit cells.
Body centre atom is shared by only 1 unit cell.
So, we can formulate it as,
Nav= Nc/8 + Nf/2 + Nb/1
where,
•Nav= Average number of atoms per
unit cell
•Nc= Number of corner atoms
•Nf= Number of face centre atom
•Nb= Number of body centre atom
13. SITP, Yadrav-Ichalkaranji.
For Hexagonal structure,
Corner atom is shared by 6 unit cells(3 from below and 3 from above).
Face centre atom is shared by 2 unit cells.
Body centre atom is shared by only 1 unit cell.
So, we can formulate it as,
Nav= Nc/6 + Nf/2 + Nb/1
where,
•Nav= Average number of atoms
per unit cell
•Nc= Number of corner atoms
•Nf= Number of face centre atom
•Nb= Number of body centre atom
14. We can calculate the Nav:
We have formula for cubic structure as,
Nav= Nc/8 + Nf/2 + Nb/1
For SC-
Nc- 8, Nf-0, Nb-0
Nav= Nc/8 + Nf/2 + Nb/1= 8/8+0/2+0/1 =1+0+0 = 1
For BCC-
Nc- 8, Nf-0, Nb-1
Nav= Nc/8 + Nf/2 + Nb/1= 8/8+0/2+1/1 =1+0+1 = 2
For FCC-
Nc- 8, Nf-6, Nb-00
Nav= Nc/8 + Nf/2 + Nb/1= 8/8+6/2+0/1 =1+3+0 = 4
15. We can calculate the Nav:
We have formula for Hexagonal structure as,
Nav= Nc/6 + Nf/2 + Nb/1
For HCP-
Nc- 12, Nf-2, Nb-3
Nav= Nc/6 + Nf/2 + Nb/1= 12/6+2/2+3/1 =2+1+3 = 6
Summary:
Nav(Average No. Of Atoms per Unit Cell)
For SC= 1
For BCC= 2
For FCC= 4
For HCP= 6
16. Packing Efficiency or Atomic Packing Factor(APF)
The space occupied by atoms in an unit cell is called Atomic Packing
Factor or Packing Efficiency.
APF= (Nav*Volume of Atom) / Volume of Unit cell
= (Nav* 4/3 Πr3) / a3
Where,
Nav = Average no. Of atoms per unit cell
r = Radius of Atom
a = Edge of cube
In this equation, we have only two variables are ‘r’ and ‘a’. So to get the
value of packing efficiency we must get relation between ‘r’ and ‘a’.
17. Packing Efficiency or APF of Simple Cubic Structure(SC):
Note-In this we assume that one corner atom
touches with adjacent corner atoms.
We have formula,
APF= (Nav*Volume of Atom) / Volume of Unit cell
= (Nav* 4/3 Πr3) / a3
From diagram, we can write,
a=2r
We can put above value in APF equation,
APF= (1* 4/3 Πr3) / (2r)3
=4/3 Πr3/ 8r3 = (4/3)Π / 8 = Π/6
APF= 0.52 or Packing Efficiency= 52%
18. Packing Efficiency or APF of Body Centred Cubic Structure
(BCC):
Note-In this we assume that one body centred atom
touches with all corner atoms.
We have formula,
APF= (Nav*Volume of Atom) / Volume of Unit cell
= (Nav* 4/3 Πr3) / a3
From diagram, we can write,
a=4r/√3
We can put above value in APF equation,
APF= (2* 4/3 Πr3) / (4r/√3)3
=(8/3 Πr3)/ (64r3/3√3) = √3Π / 8=0.68
APF= 0.68 or Packing Efficiency= 68%
19. Packing Efficiency or APF of Face Centred Cubic Structure
(FCC):
Note-In this we assume that face centred atom
touches with adjacent face corner atoms.
We have formula,
APF= (Nav*Volume of Atom) / Volume of Unit cell
= (Nav* 4/3 Πr3) / a3
From diagram, we can write,
a=4r/√2
We can put above value in APF equation,
APF= (4* 4/3 Πr3) / (4r/√2)3
=(16/3 Πr3)/ (64r3/2√2) = √2 Π/6=0.74
APF= 0.74 or Packing Efficiency= 74%
Note : Packing Efficiency of HCP is 74% or Atomic Packing Factor is 0.74.
20. Summary:
Relation between Edge of cube(a) and radius of atom(r):
a) Simple Cubic Structure(SC): a=2r or r=a/2
b) Body centred cubic structure(BCC): a=4r/√3 or r=√3a/4
c) Face centred cubic Structure(FCC): a=2√2r or r= a/2√2
Packing efficiency or Atomic Packing Factor(APF):
a) Simple cubic Structure(SC): 52% or 0.52
b) Body Centred Cubic Structure(BCC): 68% or 0.68
c) Face Centred Cubic Structure(FCC): 74% or 0.74
d) Hexagonal Close Packed Structure(HCP): 74% or 0.74
21. Overall Summary
For SC :
Nc=08,Nb=00,Nf=00
Nav= 01
APF= 0.52 or 52%
For BCC:
Nc=08,Nb=01,Nf=00
Nav=2
APF= 0.68 or 68%
For FCC:
Nc=08,Nb=00,Nf=06
Nav=4
APF= 0.74 or 74%
For HCP:
Nc=12,Nb=3,Nf=2
Nav=6
APF= 0.74 or 74%