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Common Addition and Subtraction Situations (pg 88 in CCSS)
Shading taken from OA progression
Result Unknown Change Unknown Start Unknown
Add to
Two bunnies sat on the
grass.
Three more bunnies
hopped there. How many
bunnies are on the grass
now?
2 + 3 = ?
Two bunnies were sitting
on the grass. Some more
bunnies hopped there.
Then there were five
bunnies. How many
bunnies hopped over to
the first two?
2 + ? = 5
Some bunnies were sitting
on the grass. Three more
bunnies hopped there.
Then there were five
bunnies. How many
bunnies were on the grass
before?
? + 3 = 5
Taken from
Five apples were on the
table. I ate two apples.
How many apples are on
the table now?
5 – 2 = ?
Five apples were on the
table. I ate some apples.
Then there were three
apples. How many
apples did
I eat?
5 – ? = 3
Some apples were on the
table. I ate two apples.
Then there were three
apples. How many apples
were on the table before?
? – 2 = 3
Put
Together/
Take Apart2
Total Unknown Addend Unknown Both Addends Unknown1
Three red apples and
two green apples are on
the table. How many
apples are on the table?
3 + 2 = ?
Five apples are on the
table.
Three are red and the
rest are green. How
many apples are green?
3 + ? = 5, 5 – 3 = ?
Grandma has five flowers.
How many can she put in
her red vase and how
many in her blue vase?
5 = 0 + 5, 5 = 5 + 0
5 = 1 + 4, 5 = 4 + 1
5 = 2 + 3, 5 = 3 + 2
Compare3
Difference Unknown Bigger Unknown Smaller Unknown
(“How many more?”
version):
Lucy has two apples.
Julie has five apples.
How many more apples
does Julie have than
Lucy?
(“How many fewer?”
version):
Lucy has two apples.
Julie has five apples.
How many fewer apples
does Lucy have than
Julie?
2 + ? = 5, 5 – 2 = ?
(Version with “more”):
Julie has three more
apples than Lucy. Lucy
has two apples. How
many apples does Julie
have?
(Version with “fewer”):
Lucy has 3 fewer apples
than Julie. Lucy has two
apples.
How many apples does
Julie have?
2 + 3 = ?, 3 + 2 = ?
(Version with “more”):
Julie has three more apples
than Lucy. Julie has five
apples. How many apples
does Lucy have?
(Version with “fewer”):
Lucy has 3 fewer apples
than Julie. Julie has five
apples.
How many apples does
Lucy have?
5 – 3 = ?, ? + 3 = 5
Blue shading indicates the four Kindergarten problem subtypes. Students in grades 1 and 2 work with all
subtypes and variants (blue and green). Yellow indicates problems that are the difficult four problem
subtypes or variants that students in Grade 1 work with but do not need to master until Grade 2.
1
T hese take apart situations can be used to show all the decompositions of a given number. T he associated equations, which have the total on the left of
the equal sign, help children understand that the = sign does not always mean makes or results in but always does mean is the same number as.
2
Either addend can be unknown, so there are three variations of these problem situations. Both A ddends U nknown is a productive extension of this basic
situation, especially for small numbers less than or equal to 10.
3
For the Bigger U nknown or Smaller U nknown situations, one version directs the correct operation (the version using more for the bigger unknown and
using less for the smaller unknown). T he other versions are more difficult.

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Common addition and subtraction situation shaded

  • 1. Common Addition and Subtraction Situations (pg 88 in CCSS) Shading taken from OA progression Result Unknown Change Unknown Start Unknown Add to Two bunnies sat on the grass. Three more bunnies hopped there. How many bunnies are on the grass now? 2 + 3 = ? Two bunnies were sitting on the grass. Some more bunnies hopped there. Then there were five bunnies. How many bunnies hopped over to the first two? 2 + ? = 5 Some bunnies were sitting on the grass. Three more bunnies hopped there. Then there were five bunnies. How many bunnies were on the grass before? ? + 3 = 5 Taken from Five apples were on the table. I ate two apples. How many apples are on the table now? 5 – 2 = ? Five apples were on the table. I ate some apples. Then there were three apples. How many apples did I eat? 5 – ? = 3 Some apples were on the table. I ate two apples. Then there were three apples. How many apples were on the table before? ? – 2 = 3 Put Together/ Take Apart2 Total Unknown Addend Unknown Both Addends Unknown1 Three red apples and two green apples are on the table. How many apples are on the table? 3 + 2 = ? Five apples are on the table. Three are red and the rest are green. How many apples are green? 3 + ? = 5, 5 – 3 = ? Grandma has five flowers. How many can she put in her red vase and how many in her blue vase? 5 = 0 + 5, 5 = 5 + 0 5 = 1 + 4, 5 = 4 + 1 5 = 2 + 3, 5 = 3 + 2 Compare3 Difference Unknown Bigger Unknown Smaller Unknown (“How many more?” version): Lucy has two apples. Julie has five apples. How many more apples does Julie have than Lucy? (“How many fewer?” version): Lucy has two apples. Julie has five apples. How many fewer apples does Lucy have than Julie? 2 + ? = 5, 5 – 2 = ? (Version with “more”): Julie has three more apples than Lucy. Lucy has two apples. How many apples does Julie have? (Version with “fewer”): Lucy has 3 fewer apples than Julie. Lucy has two apples. How many apples does Julie have? 2 + 3 = ?, 3 + 2 = ? (Version with “more”): Julie has three more apples than Lucy. Julie has five apples. How many apples does Lucy have? (Version with “fewer”): Lucy has 3 fewer apples than Julie. Julie has five apples. How many apples does Lucy have? 5 – 3 = ?, ? + 3 = 5 Blue shading indicates the four Kindergarten problem subtypes. Students in grades 1 and 2 work with all subtypes and variants (blue and green). Yellow indicates problems that are the difficult four problem subtypes or variants that students in Grade 1 work with but do not need to master until Grade 2. 1 T hese take apart situations can be used to show all the decompositions of a given number. T he associated equations, which have the total on the left of the equal sign, help children understand that the = sign does not always mean makes or results in but always does mean is the same number as. 2 Either addend can be unknown, so there are three variations of these problem situations. Both A ddends U nknown is a productive extension of this basic situation, especially for small numbers less than or equal to 10. 3 For the Bigger U nknown or Smaller U nknown situations, one version directs the correct operation (the version using more for the bigger unknown and using less for the smaller unknown). T he other versions are more difficult.