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Module PMR
CHAPTER 6 : INDICES
NUMBERS IN INDEX FORM
Example:
Express in the form
of repeated
multiplication.
aaaaa ×××=4
1) 5
h 2) ( )3
h−
3)
2






e
d
4) 4
5 5) ( )3
1−
6)
4
3
2






7)
2
4
3






−
Example:
Write in index
notation.
h x h x h x h x h x h
=
8) g x g x g x g 9).
( ) ( ) ( )
( ) ( )dd
ddd
−×−
×−×−×− 10) 

















n
e
n
e
n
e
11) 7 x 7 x7 x 7 x 7 12)
(-11)(-11)(-11) 13) 























7
2
7
2
7
2
7
2
14) 





−





−
9
7
9
7
Example:
Evaluate
2222225
××××=
= 32
15) 3
10 16) ( )4
3−
17)
2
4
3






18)
3
4
1





−
19)
3
2
1
3 




 20) ( )3
4.0 21) ( )2
05.0−
LAWS OF INDICES
Indices 64
Module PMR
LAW 1 nmnm
aaa +
=×
Example:
Simplify
35
bb ×
35+
=b
8
b=
1) 62
gg × 2) 693
hhh ×× 3) ( ) ( )32
ee −×−
Example:
Simplify
43
22 ×
43
2 +
=
7
2=
4) 62
55 × 5) 683
666 ×× 6)( ) ( )45
33 −×−
Example:
Simplify
32
43 bb ×
( ) 32
43 +
×= b
5
12b=
7) 62
54 yy × 8) 43
310 ss ×
9)
45
8
3
2 kk ×
Example:
Simplify
7265
94 shsh ××
( ) 7675
94 ++
×= sh
1312
36 sh=
10) 232
37 mbm ××
11)
234
9
3
2
vvv ×× 12) papa ××− 443
36
LAW 2 nmnm
aaa −
=÷
Example:
Simplify
47
jj ÷
47−
= j
3
j=
1) 49
nn ÷
2) 2
5
a
a 3) 34
4 tt ÷
Example:
Simplify 45
÷ 42
= 45 - 2
= 43
4) 54
÷ 53
5) 2
4
7
7 6) 57
1010 −
÷
Example:
Simplify
35
412 aa ÷
35
4
12 −
= a
2
3a=
7) 45
540 gg ÷
8) 2
8
4
20
y
y 9) 510
2718 nn ÷
Example:
Simplify
10) 85
210 −
÷ uu
11) 2
4
2
18
−
w
w 12)
48
9
2
3 −
÷ mm
Indices 65
Module PMR
( )
9
36
36
36
2
2
6
12
612
z
z
z
zz
=
=
=
÷
+
−−
−
LAW 3 ( ) nmnm
aa ×
=
Example:
Simplify
( )
15
53
53
h
h
h
=
= ×
1) ( )24
k 2) ( ) 52 −
g 3) ( )27−
v
Example:
Simplify
( )
12
42
42
3
3
3
=
= ×
4) ( )35
4 5) ( ) 52
6
−
6) ( )35
7−
Example:
Simplify
( )
2015
5453
543
2
2
2
m
m
m
=
= ××
7) ( )234
ed 8) ( ) 423
52
−
9) ( )264
3 −
g
LAW 4 n
n
a
a
1
=−
Example:
Simplify
r
l −
r
l
1
=
1) k
c−
2) p
m−
3 3) t
dv−
Example:
Simplify
3
2−
= 3
2
1
4) 3
4−
5) 1
7−
6) 2
3−
Indices 66
Module PMR
8
1
=
Example:
Simplify
5
8
4
1
4 ×
= 58
44 −
×
= ( )58
4 −+
= 58
4 −
= 3
4
= 64
7) 2
3
8
1
8 × 8) ( )22
3
10
10
1
× 9)
( )32
8 1
m
m ×
LAW 5 10
=a
Example:
120
=
1)
0
3
2






=
2) ( )0
3− = 3) ( )0
5.4 =
LAW 6 FRACTIONAL INDICES
Example:
Rewrite by using
the root and power
symbol
9
3
2
3
9 =
1) 3
1
64 2) 5
1
32 3) 3
2
8
Example:
Write in the form of
index
53
22
3
5 =
1) 3
8 2)
3
5
10 3) 16
Example:
Evaluate
1) 3
1
27 2) 5
2
32 3) 4
3
81
Indices 67
Module PMR
( )
2
2
4
2
1
2
2
1
=
=
Example:
Simplify
2
3
6
3
2
3
4
3
2
3
4
9
9
9
99
=
=
=
×
+
1) 3
5
3
2
1010 ÷ 2) ( ) 42
1
6
gg × 3) ( ) 32
1
4 −−
÷ pp
COMBINATION OF LAWS
Example:
Simplify
2
2
2
2
0
936
936
=
=
=
÷×
−+
b
b
bbb
1) 317 −
×÷ ggg
2) 4
59
m
mm × 3) 435
232 ggg ÷×
Simplify
( )
33
3612
31622
3123
4
4
2
2
yx
yx
yxyx
yxxy
=
=
÷=
÷
−+
−
−
4) ( ) 132
2 −
÷xyyx 5) ( ) 2424
3 −−
× yxxy 6) ( ) yxxy 322
÷
Evaluate
2
1
2
1
8
1
3
1
3
3
1
=














=






7)
2
1
25
1





 8)
2
1
9
4





 9)
3
1
27
8






Evaluate 10) 322
284 ÷× 11) ( )327
93 ×−
12) ( ) 5
1
2
1
4
3242 ÷×
Indices 68
Module PMR
( )
( )
32
1
2
22
22
42
5
49
229
233
=
=
×=
×=
×
−
−
−
−
13) 5
3
4
1
3
1
32168 ×× 14) 23
2
327 −
÷
15) ( ) 223
999 −
×÷ 16) ( ) 506
rr ÷
17)
( )
2
252
4
4
ab
ba 18) ( ) 2324
666 ÷×−
19) ( ) 523
xx ÷
−−
20) Given .2166
2
=
−x
Find x .
21) Given that .1255 3
=−x
Find x .
22) If
64
13
=−
y . Find y .
Common Errors
Indices 69
Module PMR
Errors Correct Steps
1. 22
22 −
×
= ( )22
2 −+
= 0
2
= 2
1. 22
22 −
×
= ( )22
2 −+
= 0
2
= 1
2. 24
55 −
÷
= 24
5 −
= 2
5
2. 24
55 −
÷
= ( )24
5 −−
= 24
5 +
= 6
5
3. 4
52
−
×
k
kk
= 452 −+
k
= 3
k
3. 4
52
−
×
k
kk
= )4(52 −−+
k
= 47+
k
= 11
k
Questions based on PMR Format
1. Evaluate
3
1
2
3
16
−








2. Evaluate ( )2
3
284 −
cba
3. Find the value of 3
2
5
3
832
−
÷
4. Given that 2
1
3
4
2
8127 ÷=k .Find the value of .k
Indices 70
Module PMR
5. If 34347
=× −
aa , find the value of .a
6. Simplify 6
5
2
1
23 pp ×
7. Simplify 27
5
33
3
−
−
×
8. Simplify 372
4
−
×× aab
a
9. Simplify
( ) 521
432
prq
rqp
×
××
−
−
10. Simplify 34
25
−
−
×
××
km
mkk
PMR past year questions
2004
1. Given that 162 2
=−x
, calculate the value of x .
( 2 marks )
Indices 71
Module PMR
2. Simplify ( ) ( ) 953242
2 kmkmk ÷× .
( 3 marks )
2005
1. Evaluate
3
2
2
1
2
1
8
123 ×
.
( 3 marks )
2. Given ( )( ),333 212 xx
=−
calculate the value of x .
( 2 marks )
2006
1. Simplify 2
4
−
×
k
kk
.
( 2 marks )
2. Find the value of 2
3
2
1
2
2183 ×× .
( 3 marks )
Indices 72
Module PMR
2007
1. a). Find the value of 2
1
2
3
55 ÷ .
b). Simplify ( ) 234
hhg × .
( 3 marks )
2008
1. Simplify 4
52
m
mm ×−
.
( 2 marks )
2. Find the value of
a). 13
22 −
÷
b). ( )3
1
63
32 ×−
( 3 marks )
CHAPTER 6 : INDICES
ANSWERS
1. hhhhh ×××× 2. ( ) ( ) ( )hhh −×−×−
3. 





×





e
d
e
d 4. 5555 ×××
Indices 73
Module PMR
5. ( ) ( ) ( )111 −×−×−
6. 





×





×





×





3
2
3
2
3
2
3
2
7. 





−×





−
4
3
4
3 8. 4
g
9. ( )5
d−
10.
3






n
e 11. 5
7 12. ( )3
11−
13.
4
7
2






14.
2
9
7






−
15. 1000 16. 81
17.
16
9
18.
64
1
− 19.
8
343
or
8
7
42
20. 0.064
21. 0.0025
LAW 1
1. 8
g 2. 18
h 3. ( )5
e− 4. 8
5
5. 17
6 6. ( )9
3− 7. 8
20y 8. 7
30s
9.
9
4
3
k 10. 34
21 bm 11. ( )35
7−
12. 57
18 pa−
LAW 2
1. 5
n 2. 3
a 3. t4 4. 5
5. 72
6. 12
10 7. g8 8. 6
5y
9.
5
3
2
n
10. 5 u13
11. 6
9w
12.
12
2
27
m
LAW 3
1. 8
k 2. 10−
g 3. 14−
v
4. 15
4 5. 10
6−
6. 15
7−
7. 68
ed 8. 812
52 −−
9. 128
3 −
g
LAW 4
1. k
c
1
2. p
m
3
3. t
v
d
4. 3
4
1
5.
7
1
6. 2
3
1
7. 8 8. 10 9. 2
m
LAW 5
1. 1 2. 1 3. 1
LAW 6
1. 3
64 2. 5
32 3.
2
3
8
1. 3
1
8 2. 5
3
10 3. 2
1
16
1. 3 2. 4 3. 27
4.
10
1 5. 7
g 6. p
COMBINATION OF LAWS
Indices 74
Module PMR
1. 3
g 2. 10
m 3. 4
3g 4. 45
8 yx
5. 62
9 yx−
6. 31
yx−
7.
5
1
5 1
=−
8.
3
2
9.
3
2 10. 128 11. 243 12. 8
13. 32 14. 81 15. 81 16. 5−
r
17. 83
4 ba 18. 1 19. x 20. 5=x
21. 6 22. 4
Questions Based on PMR Format
1.
4
1 2. 3126 −
cba 3. 32 4. 3
5. 7 6. 3
4
6 p 7. 10
3
1 8. 2−
b
9. qr
p
10. 2
1
km
PMR QUESTIONS
YEAR SOLUTION AND MARK SCHEME
SUB
MARK
FULL
MARK
2004 42
22 =−x
x or 42 =−x
6=x
1
1 2
2004 956844
2 kmkkm ÷×
96854
16 −+−
km
51
16 km −
1
1
1 3
2005
( )
( )
2
3
4
6
2
6
2
6
8
36
2
1
3
2
3
2
1
2
3
2
2
1










1
1
1
3
2005 212 +=− xx
122 +=− xx
3=x
1
1 2
Indices 75
Module PMR
2006
7
)2(14
k
k −−+
1
1 2
2006
( )
( ) 2
1
2
1
2
1
22
2
3
2
1
2
2233
2293
×××
×××
108
427
23 23
×
×
1
1
1
3
2007 a) 1
55 or
b) 123
3123
gh
horgh
1
1
1
3
2008
m
orm
mormormorm
12
45263
−
−+−−
1
1
2
2008 a) 1624
=
b) =
××−
× 3
1
6
3
1
3
32
4
9
9
2
1
32 21
=×
×−
1
1
1
3
Indices 76

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Chapter 6 indices

  • 1. Module PMR CHAPTER 6 : INDICES NUMBERS IN INDEX FORM Example: Express in the form of repeated multiplication. aaaaa ×××=4 1) 5 h 2) ( )3 h− 3) 2       e d 4) 4 5 5) ( )3 1− 6) 4 3 2       7) 2 4 3       − Example: Write in index notation. h x h x h x h x h x h = 8) g x g x g x g 9). ( ) ( ) ( ) ( ) ( )dd ddd −×− ×−×−×− 10)                   n e n e n e 11) 7 x 7 x7 x 7 x 7 12) (-11)(-11)(-11) 13)                         7 2 7 2 7 2 7 2 14)       −      − 9 7 9 7 Example: Evaluate 2222225 ××××= = 32 15) 3 10 16) ( )4 3− 17) 2 4 3       18) 3 4 1      − 19) 3 2 1 3       20) ( )3 4.0 21) ( )2 05.0− LAWS OF INDICES Indices 64
  • 2. Module PMR LAW 1 nmnm aaa + =× Example: Simplify 35 bb × 35+ =b 8 b= 1) 62 gg × 2) 693 hhh ×× 3) ( ) ( )32 ee −×− Example: Simplify 43 22 × 43 2 + = 7 2= 4) 62 55 × 5) 683 666 ×× 6)( ) ( )45 33 −×− Example: Simplify 32 43 bb × ( ) 32 43 + ×= b 5 12b= 7) 62 54 yy × 8) 43 310 ss × 9) 45 8 3 2 kk × Example: Simplify 7265 94 shsh ×× ( ) 7675 94 ++ ×= sh 1312 36 sh= 10) 232 37 mbm ×× 11) 234 9 3 2 vvv ×× 12) papa ××− 443 36 LAW 2 nmnm aaa − =÷ Example: Simplify 47 jj ÷ 47− = j 3 j= 1) 49 nn ÷ 2) 2 5 a a 3) 34 4 tt ÷ Example: Simplify 45 ÷ 42 = 45 - 2 = 43 4) 54 ÷ 53 5) 2 4 7 7 6) 57 1010 − ÷ Example: Simplify 35 412 aa ÷ 35 4 12 − = a 2 3a= 7) 45 540 gg ÷ 8) 2 8 4 20 y y 9) 510 2718 nn ÷ Example: Simplify 10) 85 210 − ÷ uu 11) 2 4 2 18 − w w 12) 48 9 2 3 − ÷ mm Indices 65
  • 3. Module PMR ( ) 9 36 36 36 2 2 6 12 612 z z z zz = = = ÷ + −− − LAW 3 ( ) nmnm aa × = Example: Simplify ( ) 15 53 53 h h h = = × 1) ( )24 k 2) ( ) 52 − g 3) ( )27− v Example: Simplify ( ) 12 42 42 3 3 3 = = × 4) ( )35 4 5) ( ) 52 6 − 6) ( )35 7− Example: Simplify ( ) 2015 5453 543 2 2 2 m m m = = ×× 7) ( )234 ed 8) ( ) 423 52 − 9) ( )264 3 − g LAW 4 n n a a 1 =− Example: Simplify r l − r l 1 = 1) k c− 2) p m− 3 3) t dv− Example: Simplify 3 2− = 3 2 1 4) 3 4− 5) 1 7− 6) 2 3− Indices 66
  • 4. Module PMR 8 1 = Example: Simplify 5 8 4 1 4 × = 58 44 − × = ( )58 4 −+ = 58 4 − = 3 4 = 64 7) 2 3 8 1 8 × 8) ( )22 3 10 10 1 × 9) ( )32 8 1 m m × LAW 5 10 =a Example: 120 = 1) 0 3 2       = 2) ( )0 3− = 3) ( )0 5.4 = LAW 6 FRACTIONAL INDICES Example: Rewrite by using the root and power symbol 9 3 2 3 9 = 1) 3 1 64 2) 5 1 32 3) 3 2 8 Example: Write in the form of index 53 22 3 5 = 1) 3 8 2) 3 5 10 3) 16 Example: Evaluate 1) 3 1 27 2) 5 2 32 3) 4 3 81 Indices 67
  • 5. Module PMR ( ) 2 2 4 2 1 2 2 1 = = Example: Simplify 2 3 6 3 2 3 4 3 2 3 4 9 9 9 99 = = = × + 1) 3 5 3 2 1010 ÷ 2) ( ) 42 1 6 gg × 3) ( ) 32 1 4 −− ÷ pp COMBINATION OF LAWS Example: Simplify 2 2 2 2 0 936 936 = = = ÷× −+ b b bbb 1) 317 − ×÷ ggg 2) 4 59 m mm × 3) 435 232 ggg ÷× Simplify ( ) 33 3612 31622 3123 4 4 2 2 yx yx yxyx yxxy = = ÷= ÷ −+ − − 4) ( ) 132 2 − ÷xyyx 5) ( ) 2424 3 −− × yxxy 6) ( ) yxxy 322 ÷ Evaluate 2 1 2 1 8 1 3 1 3 3 1 =               =       7) 2 1 25 1       8) 2 1 9 4       9) 3 1 27 8       Evaluate 10) 322 284 ÷× 11) ( )327 93 ×− 12) ( ) 5 1 2 1 4 3242 ÷× Indices 68
  • 6. Module PMR ( ) ( ) 32 1 2 22 22 42 5 49 229 233 = = ×= ×= × − − − − 13) 5 3 4 1 3 1 32168 ×× 14) 23 2 327 − ÷ 15) ( ) 223 999 − ×÷ 16) ( ) 506 rr ÷ 17) ( ) 2 252 4 4 ab ba 18) ( ) 2324 666 ÷×− 19) ( ) 523 xx ÷ −− 20) Given .2166 2 = −x Find x . 21) Given that .1255 3 =−x Find x . 22) If 64 13 =− y . Find y . Common Errors Indices 69
  • 7. Module PMR Errors Correct Steps 1. 22 22 − × = ( )22 2 −+ = 0 2 = 2 1. 22 22 − × = ( )22 2 −+ = 0 2 = 1 2. 24 55 − ÷ = 24 5 − = 2 5 2. 24 55 − ÷ = ( )24 5 −− = 24 5 + = 6 5 3. 4 52 − × k kk = 452 −+ k = 3 k 3. 4 52 − × k kk = )4(52 −−+ k = 47+ k = 11 k Questions based on PMR Format 1. Evaluate 3 1 2 3 16 −         2. Evaluate ( )2 3 284 − cba 3. Find the value of 3 2 5 3 832 − ÷ 4. Given that 2 1 3 4 2 8127 ÷=k .Find the value of .k Indices 70
  • 8. Module PMR 5. If 34347 =× − aa , find the value of .a 6. Simplify 6 5 2 1 23 pp × 7. Simplify 27 5 33 3 − − × 8. Simplify 372 4 − ×× aab a 9. Simplify ( ) 521 432 prq rqp × ×× − − 10. Simplify 34 25 − − × ×× km mkk PMR past year questions 2004 1. Given that 162 2 =−x , calculate the value of x . ( 2 marks ) Indices 71
  • 9. Module PMR 2. Simplify ( ) ( ) 953242 2 kmkmk ÷× . ( 3 marks ) 2005 1. Evaluate 3 2 2 1 2 1 8 123 × . ( 3 marks ) 2. Given ( )( ),333 212 xx =− calculate the value of x . ( 2 marks ) 2006 1. Simplify 2 4 − × k kk . ( 2 marks ) 2. Find the value of 2 3 2 1 2 2183 ×× . ( 3 marks ) Indices 72
  • 10. Module PMR 2007 1. a). Find the value of 2 1 2 3 55 ÷ . b). Simplify ( ) 234 hhg × . ( 3 marks ) 2008 1. Simplify 4 52 m mm ×− . ( 2 marks ) 2. Find the value of a). 13 22 − ÷ b). ( )3 1 63 32 ×− ( 3 marks ) CHAPTER 6 : INDICES ANSWERS 1. hhhhh ×××× 2. ( ) ( ) ( )hhh −×−×− 3.       ×      e d e d 4. 5555 ××× Indices 73
  • 11. Module PMR 5. ( ) ( ) ( )111 −×−×− 6.       ×      ×      ×      3 2 3 2 3 2 3 2 7.       −×      − 4 3 4 3 8. 4 g 9. ( )5 d− 10. 3       n e 11. 5 7 12. ( )3 11− 13. 4 7 2       14. 2 9 7       − 15. 1000 16. 81 17. 16 9 18. 64 1 − 19. 8 343 or 8 7 42 20. 0.064 21. 0.0025 LAW 1 1. 8 g 2. 18 h 3. ( )5 e− 4. 8 5 5. 17 6 6. ( )9 3− 7. 8 20y 8. 7 30s 9. 9 4 3 k 10. 34 21 bm 11. ( )35 7− 12. 57 18 pa− LAW 2 1. 5 n 2. 3 a 3. t4 4. 5 5. 72 6. 12 10 7. g8 8. 6 5y 9. 5 3 2 n 10. 5 u13 11. 6 9w 12. 12 2 27 m LAW 3 1. 8 k 2. 10− g 3. 14− v 4. 15 4 5. 10 6− 6. 15 7− 7. 68 ed 8. 812 52 −− 9. 128 3 − g LAW 4 1. k c 1 2. p m 3 3. t v d 4. 3 4 1 5. 7 1 6. 2 3 1 7. 8 8. 10 9. 2 m LAW 5 1. 1 2. 1 3. 1 LAW 6 1. 3 64 2. 5 32 3. 2 3 8 1. 3 1 8 2. 5 3 10 3. 2 1 16 1. 3 2. 4 3. 27 4. 10 1 5. 7 g 6. p COMBINATION OF LAWS Indices 74
  • 12. Module PMR 1. 3 g 2. 10 m 3. 4 3g 4. 45 8 yx 5. 62 9 yx− 6. 31 yx− 7. 5 1 5 1 =− 8. 3 2 9. 3 2 10. 128 11. 243 12. 8 13. 32 14. 81 15. 81 16. 5− r 17. 83 4 ba 18. 1 19. x 20. 5=x 21. 6 22. 4 Questions Based on PMR Format 1. 4 1 2. 3126 − cba 3. 32 4. 3 5. 7 6. 3 4 6 p 7. 10 3 1 8. 2− b 9. qr p 10. 2 1 km PMR QUESTIONS YEAR SOLUTION AND MARK SCHEME SUB MARK FULL MARK 2004 42 22 =−x x or 42 =−x 6=x 1 1 2 2004 956844 2 kmkkm ÷× 96854 16 −+− km 51 16 km − 1 1 1 3 2005 ( ) ( ) 2 3 4 6 2 6 2 6 8 36 2 1 3 2 3 2 1 2 3 2 2 1           1 1 1 3 2005 212 +=− xx 122 +=− xx 3=x 1 1 2 Indices 75
  • 13. Module PMR 2006 7 )2(14 k k −−+ 1 1 2 2006 ( ) ( ) 2 1 2 1 2 1 22 2 3 2 1 2 2233 2293 ××× ××× 108 427 23 23 × × 1 1 1 3 2007 a) 1 55 or b) 123 3123 gh horgh 1 1 1 3 2008 m orm mormormorm 12 45263 − −+−− 1 1 2 2008 a) 1624 = b) = ××− × 3 1 6 3 1 3 32 4 9 9 2 1 32 21 =× ×− 1 1 1 3 Indices 76