C. Nitrosomonas, Nitrosolobus, and NitrosovibrioNitrifiers are che.pdf
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C. Nitrosomonas, Nitrosolobus, and Nitrosovibrio Nitrifiers are chemolithotropic organisms which obtains energy by oxidating inorganic nitrogen compounds. These three organisms convert Ammonia to Nitrites which inturn converted into nitrate by other organisms such as Nitrobacter or Nitrospina. False: Neisseria gonorrhoeae - responsible for causing sexually transmitted disease Gonorrhea Neisseria meningitidis- responsible for causing meningitis and sepsis Thiobacillus spp- It belongs to Hydrogenophilaceae family and mostly responsible for oxidizing hydrogen. Solution C. Nitrosomonas, Nitrosolobus, and Nitrosovibrio Nitrifiers are chemolithotropic organisms which obtains energy by oxidating inorganic nitrogen compounds. These three organisms convert Ammonia to Nitrites which inturn converted into nitrate by other organisms such as Nitrobacter or Nitrospina. False: Neisseria gonorrhoeae - responsible for causing sexually transmitted disease Gonorrhea Neisseria meningitidis- responsible for causing meningitis and sepsis Thiobacillus spp- It belongs to Hydrogenophilaceae family and mostly responsible for oxidizing hydrogen..
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Biological nitrogen fixation by kader mullah
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Rhizobia are symbiotic diazotrophs (prokaryotic organisms that carry out dinitrogen fixation) that form a symbiotic association with legumes. This association is symbiotic in that both the plant and rhizobia benefit. The plant supplies the rhizobia with energy in the form of amino acids and the rhizobia fix nitrogen from the atmosphere for plant uptake. The reduction of atmospheric dinitrogen into ammonia is the second most important biological process on earth after photosynthesis (Sylvia, 2005). The actual process of dinitrogen fixation can only be carried out by diazotrophs that contain the enzyme dinitrogenase. Nitrogen is the most critical nutrient needed to support plant growth. Unfortunately, atmospheric dinitrogen (78% of air we breathe) is extremely stable due to triple bonds which can only be broken by energy intensive ways. These include electrical N2 fixation by lightning where oxides of N come to ground with rain, the Haber-Bosch process in industrial fertilizer production, and biological N2 fixation in legumes by bacterial symbionts such as Rhizobium etli. Biological fixation of nitrogen was the leading form of annual nitrogen input until the last decade of the 20th century (Russelle, 2008). It is gaining attention once again as sustainability becomes a central focus to feed a world population of over 7 billion people.
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I made this one, hope you like it. If you have any suggestions, feel free to comment.
304 subrata paul
i am student of assam university silchar ,, i want to share my presentation ,whatever i have prepared, & ready to deliver.
Biological nitrogen fixation by kader mullah
biological nitrogen fixation. this slide is prepared to provide a unique concept about biological nitrogen fixation.
Rhizobium
Rhizobia are symbiotic diazotrophs (prokaryotic organisms that carry out dinitrogen fixation) that form a symbiotic association with legumes. This association is symbiotic in that both the plant and rhizobia benefit. The plant supplies the rhizobia with energy in the form of amino acids and the rhizobia fix nitrogen from the atmosphere for plant uptake. The reduction of atmospheric dinitrogen into ammonia is the second most important biological process on earth after photosynthesis (Sylvia, 2005). The actual process of dinitrogen fixation can only be carried out by diazotrophs that contain the enzyme dinitrogenase. Nitrogen is the most critical nutrient needed to support plant growth. Unfortunately, atmospheric dinitrogen (78% of air we breathe) is extremely stable due to triple bonds which can only be broken by energy intensive ways. These include electrical N2 fixation by lightning where oxides of N come to ground with rain, the Haber-Bosch process in industrial fertilizer production, and biological N2 fixation in legumes by bacterial symbionts such as Rhizobium etli. Biological fixation of nitrogen was the leading form of annual nitrogen input until the last decade of the 20th century (Russelle, 2008). It is gaining attention once again as sustainability becomes a central focus to feed a world population of over 7 billion people.
nitrogen fixing mo.pptx
Nitrogen-fixing bacteria, microorganisms capable of transforming atmospheric nitrogen into fixed nitrogen (inorganic compounds usable by plants). More than 90 percent of all nitrogen fixation is effected by these organisms, which thus play an important role in the nitrogen cycle.
Two kinds of nitrogen-fixing bacteria are recognized. The first kind, the free-living (nonsymbiotic) bacteria, includes the cyanobacteria (or blue-green algae) Anabaena and Nostoc and genera such as Azotobacter, Beijerinckia, and Clostridium. The second kind comprises the mutualistic (symbiotic) bacteria; examples include Rhizobium, associated with leguminous plants (e.g., various members of the pea family); Frankia, associated with certain dicotyledonous species (actinorhizal plants); and certain Azospirillum species, associated with cereal grasses.
The symbiotic nitrogen-fixing bacteria invade the root hairs of host plants, where they multiply and stimulate formation of root nodules, enlargements of plant cells and bacteria in intimate association. Within the nodules the bacteria convert free nitrogen to ammonia, which the host plant utilizes for its development. To ensure sufficient nodule formation and optimum growth of legumes (e.g., alfalfa, beans, clovers, peas, soybeans), seeds are usually inoculated with commercial cultures of appropriate Rhizobium species, especially in soils poor or lacking in the required bacterium.
Roles of microbes in nitrogen cycle aritriya
There are many presentation on nitrogen cycle.but in my case i have to make a ppt on microbes role in nitrogen cycle.so i made it.and then upload it if anyone get help from it i will be pleased. Aritriya Jana(F.F.Sc)
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In a symbiotic relationship with the soil bacteria known as 'rhizobia', legumes form nodules on their roots (or stems, see figure below) to 'fix' nitrogen into a form usable by plants (and animals). The process of biological nitrogen fixation was discovered by the Dutch microbiologist Martinus Beijerinck. Rhizobia (e.g., Rhizobium, Mesorhizobium, Sinorhizobium) fix atmospheric nitrogen or dinitrogen, N2, into inorganic nitrogen compounds, such as ammonium, NH4+, which is then incorporated into amino acids, which can be utilized by the plant. Plants cannot fix nitrogen on their own, but need it in one form or another to make amino acids and proteins. Because legumes form nodules with rhizobia, they have high levels of nitrogen available to them. Their abundance of nitrogen is beneficial not only to the legumes themselves, but also to the plants around them. There are other sources of nitrogen in the soil, but are not always provided at the levels required by plants, making the symbiotic relationship between legumes and rhizobia highly beneficial. In return for the fixed nitrogen that they provide, the rhizobia are provided shelter inside of the plant's nodules and some of the carbon substrates and micronutrients that they need to generate energy and key metabolites for the cellular processes that sustain life (Sprent, 2001). Nodulation and nitrogen fixation by rhizobia is not exclusive to legumes; rhizobia form root nodules on Parasponis Miq., a genus of five species in the Ulmaceae (see 'Rosales').
The picture on the left shows typical root nodules, these from bur clover (Medicago). The picture on the right shows "stem" nodules on Sesbania rostrata - stem nodules are produced from lateral or adventitious roots and are typically found in those few water-tolerant legume groups (Neptunia, Sesbania) that prefer wet or water-logged soils (Goormachtig et al., 2004).
The nitrogen cycle (shown below) describes the series of processes by which the element nitrogen, which makes up about 78% of the Earth’s atmosphere, cycles between the atmosphere and the biosphere. Plants, bacteria, animals, and manmade and natural phenomena all play a role in the nitrogen cycle. The fixation of nitrogen, in which the gaseous form dinitrogen, N2) is converted into forms usable by living organisms, occurs as a consequence of atmospheric processes such as lightning, but most fixation is carried out by free-living and symbiotic bacteria. Plants and bacteria participate in symbiosis such as the one between legumes and rhizobia or contribute through decomposition and other soil reactions. Bacteria like Rhizobium, or the actinomycete Frankia which nodulates members of the plant families Rosaceae and Betulaceae, utilize atmospheric nitrogen and convert it to an inorganic form (usually ammonium, NH4+) that plants can use. The plants then use the fixed nitrogen to produce vital cellular products such as proteins. The plants are then.
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The metal will undergo oxidation forming metal ion and releasing .pdf
The metal will undergo oxidation forming metal ion and releasing electron
K ==============> K+ + e-
HCl will dissociate into
HCl =============> H+ + Cl-
This H+ will get reduced to hydrogen gas by taking the electron released by the metal.
H+ + e- =========> H2 (gas)
Then the metal ion will combine with chloride forming metal chloride
K+ + Cl- ====> Kcl
The over all reaction would be
K + HCl =====> Kcl + H2 [not balanced]
Note: when metal react with acid, it will form metal salt releasing hydrogen gas]
Solution
The metal will undergo oxidation forming metal ion and releasing electron
K ==============> K+ + e-
HCl will dissociate into
HCl =============> H+ + Cl-
This H+ will get reduced to hydrogen gas by taking the electron released by the metal.
H+ + e- =========> H2 (gas)
Then the metal ion will combine with chloride forming metal chloride
K+ + Cl- ====> Kcl
The over all reaction would be
K + HCl =====> Kcl + H2 [not balanced]
Note: when metal react with acid, it will form metal salt releasing hydrogen gas].
Static Keyword Static is a keyword in C++ used to give special chara.pdf
Static Keyword Static is a keyword in C++ used to give special characteristics to an element.
Static elements are allocated storage only once in a program lifetime in static storage area. And
they have a scope till the program lifetime. Static Keyword can be used with following, Static
variable in functions Static Class Objects Static member Variable in class Static Methods in class
Static variables inside Functions Static variables when used inside function are initialized only
once, and then they hold there value even through function calls. These static variables are stored
on static storage area , not in stack. void counter() { static int count=0; cout << count++; } int
main(0 { for(int i=0;i<5;i++) { counter(); } } Output : 0 1 2 3 4 Let\'s se the same program\'s
output without using static variable. void counter() { int count=0; cout << count++; } int main(0
{ for(int i=0;i<5;i++) { counter(); } } Output : 0 0 0 0 0 If we do not use static keyword, the
variable count, is reinitialized everytime when counter() function is called, and gets destroyed
each time when counter() functions ends. But, if we make it static, once initialized count will
have a scope till the end of main() function and it will carry its value through function calls too.
If you don\'t initialize a static variable, they are by default initialized to zero. Static class Objects
Static keyword works in the same way for class objects too. Objects declared static are allocated
storage in static storage area, and have scope till the end of program. Static objects are also
initialized using constructors like other normal objects. Assignment to zero, on using static
keyword is only for primitive datatypes, not for user defined datatypes. class Abc { int i; public:
Abc() { i=0; cout << \"constructor\"; } ~Abc() { cout << \"destructor\"; } }; void f() { static Abc
obj; } int main() { int x=0; if(x==0) { f(); } cout << \"END\"; } Output : constructor END
destructor You must be thinking, why was destructor not called upon the end of the scope of if
condition. This is because object was static, which has scope till the program lifetime, hence
destructor for this object was called when main() exits. Static data member in class Static data
members of class are those members which are shared by all the objects. Static data member has
a single piece of storage, and is not available as separate copy with each object, like other non-
static data members. Static member variables (data members) are not initialied using constructor,
because these are not dependent on object initialization. Also, it must be initialized explicitly,
always outside the class. If not initialized, Linker will give error. class X { static int i; public:
X(){}; }; int X::i=1; int main() { X obj; cout << obj.i; // prints value of i } Once the definition for
static data member is made, user cannot redefine it. Though, arithmetic operations can be
performed on it. Static Member Functions These functions work for the .
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In a symbiotic relationship with the soil bacteria known as 'rhizobia', legumes form nodules on their roots (or stems, see figure below) to 'fix' nitrogen into a form usable by plants (and animals). The process of biological nitrogen fixation was discovered by the Dutch microbiologist Martinus Beijerinck. Rhizobia (e.g., Rhizobium, Mesorhizobium, Sinorhizobium) fix atmospheric nitrogen or dinitrogen, N2, into inorganic nitrogen compounds, such as ammonium, NH4+, which is then incorporated into amino acids, which can be utilized by the plant. Plants cannot fix nitrogen on their own, but need it in one form or another to make amino acids and proteins. Because legumes form nodules with rhizobia, they have high levels of nitrogen available to them. Their abundance of nitrogen is beneficial not only to the legumes themselves, but also to the plants around them. There are other sources of nitrogen in the soil, but are not always provided at the levels required by plants, making the symbiotic relationship between legumes and rhizobia highly beneficial. In return for the fixed nitrogen that they provide, the rhizobia are provided shelter inside of the plant's nodules and some of the carbon substrates and micronutrients that they need to generate energy and key metabolites for the cellular processes that sustain life (Sprent, 2001). Nodulation and nitrogen fixation by rhizobia is not exclusive to legumes; rhizobia form root nodules on Parasponis Miq., a genus of five species in the Ulmaceae (see 'Rosales').
The picture on the left shows typical root nodules, these from bur clover (Medicago). The picture on the right shows "stem" nodules on Sesbania rostrata - stem nodules are produced from lateral or adventitious roots and are typically found in those few water-tolerant legume groups (Neptunia, Sesbania) that prefer wet or water-logged soils (Goormachtig et al., 2004).
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Ever since Agriculture came into existence, the hunt to improve it has always taken a key role in human science and society. Here we will discuss about how to improve the ability of microorganisms to fix atmospheric nitrogen in soluble form to be used by plants for growth, yield etc.
Nitrogen assimilation in plants
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NITROGEN FIXATION
Establishing Symbiosis Requires an Exchange of Signals
NODULE FORMATION
NITROGENASE ENZYME
NITRATE ASSIMILATION
AMMONIUM ASSIMILATED BY GS/GOGAT PATHWAY
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The metal will undergo oxidation forming metal ion and releasing .pdf
The metal will undergo oxidation forming metal ion and releasing electron
K ==============> K+ + e-
HCl will dissociate into
HCl =============> H+ + Cl-
This H+ will get reduced to hydrogen gas by taking the electron released by the metal.
H+ + e- =========> H2 (gas)
Then the metal ion will combine with chloride forming metal chloride
K+ + Cl- ====> Kcl
The over all reaction would be
K + HCl =====> Kcl + H2 [not balanced]
Note: when metal react with acid, it will form metal salt releasing hydrogen gas]
Solution
The metal will undergo oxidation forming metal ion and releasing electron
K ==============> K+ + e-
HCl will dissociate into
HCl =============> H+ + Cl-
This H+ will get reduced to hydrogen gas by taking the electron released by the metal.
H+ + e- =========> H2 (gas)
Then the metal ion will combine with chloride forming metal chloride
K+ + Cl- ====> Kcl
The over all reaction would be
K + HCl =====> Kcl + H2 [not balanced]
Note: when metal react with acid, it will form metal salt releasing hydrogen gas].
Static Keyword Static is a keyword in C++ used to give special chara.pdf
Static Keyword Static is a keyword in C++ used to give special characteristics to an element.
Static elements are allocated storage only once in a program lifetime in static storage area. And
they have a scope till the program lifetime. Static Keyword can be used with following, Static
variable in functions Static Class Objects Static member Variable in class Static Methods in class
Static variables inside Functions Static variables when used inside function are initialized only
once, and then they hold there value even through function calls. These static variables are stored
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main(0 { for(int i=0;i<5;i++) { counter(); } } Output : 0 1 2 3 4 Let\'s se the same program\'s
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each time when counter() functions ends. But, if we make it static, once initialized count will
have a scope till the end of main() function and it will carry its value through function calls too.
If you don\'t initialize a static variable, they are by default initialized to zero. Static class Objects
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keyword is only for primitive datatypes, not for user defined datatypes. class Abc { int i; public:
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performed on it. Static Member Functions These functions work for the .
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Periodic table and has most common properties. Good Luck! Please rate.
Solution
Sr2+ is most likely to substitute for Ca2+ because they are in the same group in
Periodic table and has most common properties. Good Luck! Please rate..
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There should only have one singlet resonance for 1,1,2,2-tetrachloroethane. There is
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Solution
There should only have one singlet resonance for 1,1,2,2-tetrachloroethane. There is
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Nicotine has a molecular formula of C10H14N2.
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HClO4 in aqueous medium ionizes as Hydrogen(+1)cation and Chlorate (-1) anion
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Select one answer.
True or false? A tower or minitower PC is a type of all-in-one desktop unit.
True
False
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Fill in the blanks by selecting one option from each menu.
A/an --expansion card internal drive bay processor chip is inserted on the motherboard and
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video games.
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Question 4
Select one answer
What is a peripheral?
A high-speed storage location that temporarily holds data and instructions for future use
A component of the system board that controls the timing of computer activities
A slot on the motherboard that holds memory modules and helps speed computer processes
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Fill in the blanks by selecting one option from each menu.
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The weight and size of your PC
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You can always get to your data from anywhere.
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CaCO3 is a polar ionic compound that is insoluble in water. Ionic compounds are insoluble in
nonpolar organic solvents like benzene.
NaNO3 - soluble in water, insoluble in benzene
NaNO3 is a polar ionic compound that is soluble in water. Ionic compounds are insoluble in
nonpolar organic solvents like benzene.
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K2SO4 is a polar ionic compound that is soluble in water. Ionic compounds are insoluble in
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Petroleum jelly is a paraffin and a nonpolar organic compound. Thus it is insoluble in water but
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Butane is a nonpolar organic compound. Thus it is insoluble in water but soluble in benzene.
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Solution
Water is a polar inorganic solvent. Benzene is a nonpolar organic solvent. The solvents will
generally dissolve solutes with similar polarity (with certain exceptions).
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CaCO3 is a polar ionic compound that is insoluble in water. Ionic compounds are insoluble in
nonpolar organic solvents like benzene.
NaNO3 - soluble in water, insoluble in benzene
NaNO3 is a polar ionic compound that is soluble in water. Ionic compounds are insoluble in
nonpolar organic solvents like benzene.
K2SO4 - soluble in water, insoluble in benzene
K2SO4 is a polar ionic compound that is soluble in water. Ionic compounds are insoluble in
nonpolar organic solvents like benzene.
Petroleum jelly - insoluble in water, soluble in benzene
Petroleum jelly is a paraffin and a nonpolar organic compound. Thus it is insoluble in water but
soluble in benzene.
Butane - insoluble in water, soluble in benzene
Butane is a nonpolar organic compound. Thus it is insoluble in water but soluble in benzene.
Acetone - soluble in water, soluble in benzene
Acetone is a polar organic compound. Thus it is soluble in both water and benzene..
viruses which have single strande DNA in their genome come under cat.pdf
viruses which have single strande DNA in their genome come under category of paroviridae
which generally includes animal pathogens. These viruses when infect the host, the single
stranded DNA is first converted into double stranded DNA, and then using the host machinary
for transcription, ds DNA transcribes into viral mRNA.
For transcription, RNA polymerase, transcription factors , enzymes are acquired from the host
and divided into initiation, elongation and termaination. For gene expression in viruses
transcription is generally not coupled with translation in ssDNA virus. The virus instructs
transcription machinary to make viral components in the host cell.
Solution
viruses which have single strande DNA in their genome come under category of paroviridae
which generally includes animal pathogens. These viruses when infect the host, the single
stranded DNA is first converted into double stranded DNA, and then using the host machinary
for transcription, ds DNA transcribes into viral mRNA.
For transcription, RNA polymerase, transcription factors , enzymes are acquired from the host
and divided into initiation, elongation and termaination. For gene expression in viruses
transcription is generally not coupled with translation in ssDNA virus. The virus instructs
transcription machinary to make viral components in the host cell..
This word problem is about a triangle whose perimeter is 47 miles. S.pdf
This word problem is about a triangle whose perimeter is 47 miles. Since it\'s asking to find the
length of each side, then there are 3 unknowns. So here\'s what we do:
Let the variables S1 be the length of side 1 in miles,
S2 be the length of side 2 in miles,
and S3 be the length of side 3 in miles.
Now, the next thing to do with these variables is to set up equations that follow the word
problem. Here they are as follows:
S1+S2+S3=47 the perimeter of the triangle by adding the lengths of all three sides
S1=(2*S2)-5 1st side (represented by S1) is (represented by =) 5 less (represented by -5) than
twice the 2nd side (represented by 2*S2).
S3=S1+2 3rd side (represented by S3) is 2 more (represented by +2) than the 1st side.
Next, since we have more than one unknown, we should express one equation in terms of one
variable. Since only one variable has a coefficient which is S2 in the term, 2*S2, I suggest that
we express the other variable equations of S1 and S3 in terms of S2. Here\'s how it goes:
S1=(2*S2)-5 as S1 is already expressed in terms of S2
S3=S1+2=[(2*S2)-5]+2 I plugged in the S1 equation to express S3 in terms of S2.
=(2*S2)-5+2 I combined like terms.
=(2*S2)-3.
Now that I have expressed both S1 and S3 in terms of S2, I can plug those equations into that for
the triangle perimeter:
[(2*S2)-5]+S2+[(2*S2)-3]=47
(2*S2)-5+S2+(2*S2)-3=47 Again, I combined like terms.
(5*S2)-8=47
+8=+8 I added 8 on both sides of the equation to eliminate -8 on the left side.
5*S2=55
5*S2/5=55/5
S2=11
S1=(2*11)-5=22-5=17 Now that I have found the value of S2, I can plug it into the S1 equation.
S3=17+2=19 Now that I have found the value of S1, I can plug it into the S3 equation.
So now here are the lengths of each side of the triangle. Side 1 is 17 miles, side 2 is 11 miles, and
side 3 is 19 miles.
Solution
This word problem is about a triangle whose perimeter is 47 miles. Since it\'s asking to find the
length of each side, then there are 3 unknowns. So here\'s what we do:
Let the variables S1 be the length of side 1 in miles,
S2 be the length of side 2 in miles,
and S3 be the length of side 3 in miles.
Now, the next thing to do with these variables is to set up equations that follow the word
problem. Here they are as follows:
S1+S2+S3=47 the perimeter of the triangle by adding the lengths of all three sides
S1=(2*S2)-5 1st side (represented by S1) is (represented by =) 5 less (represented by -5) than
twice the 2nd side (represented by 2*S2).
S3=S1+2 3rd side (represented by S3) is 2 more (represented by +2) than the 1st side.
Next, since we have more than one unknown, we should express one equation in terms of one
variable. Since only one variable has a coefficient which is S2 in the term, 2*S2, I suggest that
we express the other variable equations of S1 and S3 in terms of S2. Here\'s how it goes:
S1=(2*S2)-5 as S1 is already expressed in terms of S2
S3=S1+2=[(2*S2)-5]+2 I plugged in the S1 equation to express S3 in terms of S2.
=(2*S2)-5+2 I combined l.
CH4 + 2O2 -- CO2 + 2H2O note CH4 combustion is.pdf
CH4 + 2O2 --> CO2 + 2H2O note: CH4 combustion is a process to react with O2.
Solution
CH4 + 2O2 --> CO2 + 2H2O note: CH4 combustion is a process to react with O2..
Carbon 2 is where D and L differ for all sugars. .pdf
Carbon 2 is where D and L differ for all sugars. For D and L glucose they will have
the same chirality everywhere cept at 2.
Solution
Carbon 2 is where D and L differ for all sugars. For D and L glucose they will have
the same chirality everywhere cept at 2..
Program to print the Diamond Shape -#include stdio.h int ma.pdf
Program to print the Diamond Shape :-
#include
int main()
{
int i, j, n;
printf(\"Enter a positive int number greater than one to print the Diamond Shape : \");
scanf(\"%d\", &n);
//To Print the upper pyramid
for(i=1; i<=n; i++)
{
for(j=i; j=1; i--)
{
for(j=i; j<=n; j++)
{
printf(\" \");
}
for(j=2; j<(2*i-1); j++)
{
printf(\"*\");
}
printf(\"\ \");
}
return 0;
}
Solution
Program to print the Diamond Shape :-
#include
int main()
{
int i, j, n;
printf(\"Enter a positive int number greater than one to print the Diamond Shape : \");
scanf(\"%d\", &n);
//To Print the upper pyramid
for(i=1; i<=n; i++)
{
for(j=i; j=1; i--)
{
for(j=i; j<=n; j++)
{
printf(\" \");
}
for(j=2; j<(2*i-1); j++)
{
printf(\"*\");
}
printf(\"\ \");
}
return 0;
}.
Part D option 4 is answerUnless untill they are exposed by some me.pdf
Part D option 4 is answer
Unless untill they are exposed by some means we can not find them
PArt E option 1 is answer as they hypo... teraposed in rocks
Solution
Part D option 4 is answer
Unless untill they are exposed by some means we can not find them
PArt E option 1 is answer as they hypo... teraposed in rocks.
Isomers which have their atoms connected in the same sequence but di.pdf
Isomers which have their atoms connected in the same sequence but differ in the way the atoms
are oriented in space - i.e. the difference between two stereoisomers lies only in the three
dimensional arrangement of atoms.
since Cis-3-hexene to trans-3-hexene differs in three dimensional arrangement of atoms and
arrangement is same in 2D space , they are stereo isomers
Solution
Isomers which have their atoms connected in the same sequence but differ in the way the atoms
are oriented in space - i.e. the difference between two stereoisomers lies only in the three
dimensional arrangement of atoms.
since Cis-3-hexene to trans-3-hexene differs in three dimensional arrangement of atoms and
arrangement is same in 2D space , they are stereo isomers.
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