b- Impact testing was used to assess which property of the materials-.docx
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b. Impact testing was used to assess which property of the materials? For metals, what crystal structure was more susceptible to the ductile-to-brittle transition temperature? Why was this the case? Solution Answer:- The Imapct testing was used to to asses the required energy to fracture the material and it can be measure the toughness of the material. we can also known the yield strength of material by using impact testing but we dont have any analytical formual for. we can also calcualte the strain rate for its effect on fracture of material. There is BCC and FCC type of crystal which is more susceptible to the ductile to brittle transiotion temperature. the low carbon steel BCC metals, which become brittle at low temperature or at very high strain rate. incase of FCC metals its remain ductiule at low temperature. In metals there is plastic deformation at room temperature occurs due to dislocation motion. this dislocation motion required a stress to move and its depend on the atomic bonding which is a crustal structure. In this case brittle fracture occurs at low temperature and ductile fracture occurs at high temperature. ductile-brittle transformation occured in between low and high temperature. .
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Q i.Why is it, in general the fracture toughness of ductile material.pdf
Q i.Why is it, in general the fracture toughness of ductile materials greater than materials with
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Q ii. Explain why BCC metals exhibit a Ductile - Brittle Transition Temperature while FCC
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Solution
1)Ductility is more commonly defined as the ability of a material to deform easily upon the
application of a tensile force, or as the ability of a material to withstand plastic deformation
without rupture. Ductility may also be thought of in terms of bendability and crushability.
Ductile materials show large deformation before fracture. The lack
of ductility is often termed brittleness. Usually, if two materials have the same strength and
hardness, the one that has the higher ductility is more desirable. The ductility of many metals can
change if conditions are altered. An increase in temperature will increase ductility. A decrease in
temperature will cause a decrease in ductility and a change from ductile to brittle behavior.
As the hardness of a material increases the ductility propertry decreases and brittlness increses
therefore toughness dcreases.
2)
The ductile-brittle transition is exhibited in bcc metals, such as low carbon steel, which become
brittle at low temperature or at very high strain rates. Fcc metals, however, generally remain
ductile at low temperatures.
In metals, plastic deformation at room temperature occurs by dislocation motion. The stress
required to move a dislocation depends on the atomic bonding, crystal structure, and obstacles
such as solute atoms, grain boundaries, precipitate particles and other dislocations. If the stress
required to move the dislocation is too high, the metal will fail instead by the propagation of
cracks and the failure will be brittle.
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and the material remains relatively ductile.
In contrast to fcc metal crystals, the yield stress or critical resolved shear stress of bcc single
crystals is markedly temperature dependent, in particular at low temperatures. The temperature
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2)
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Essay answers are limited to about 500 words (3800 characters maximum, including spaces).
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Solution
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2 Fe+3 + 2e- --> 2 Fe+2
Oxidation half cell:
NO2- --> NO3- + 2e-
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2 Fe+3 + NO2- --> 2 Fe+2 + NO3-
Balance Oxygen by adding water
2 Fe+3 + NO2- + H2O --> 2 Fe+2 + NO3-
Balance Hydrogen by adding H+
2 Fe+3 + NO2- + H2O --> 2 Fe+2 + NO3- + 2 H+
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Answer:
2 Fe 3+ + NO 2 - + H 2 O —> 2 Fe 2+ + 2 H + + NO 3 -
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File- LineScrabbleDriver-java -U 4- in-Desktop-Guess this is the death.docx
File: LineScrabbleDriver.java /U 4/ in/Desktop/Guess this is the death of me-GRASP CSD uava. 87% )- 12:19 Q Project Settings Tools Window Help import java.util.Scanner: import java.io.* public class LineScrabbleDriver public static void main(String argsl]) try string fileName; Scanner scan new Scanner (System.in); System.out.println(\"Enter a file name please fileName = scan. nextLine(); Linescrabble anew Linescrabble(fileName) a.readLines) a.doLine(); e.consequence) catch (IOException e) System.out.println( \"Please enter a file name whose file has strings.\" Echo.java LineScrabbleDriver.java LineScrabble.java GRASP Messages | Runl/O | Interactions LineScrabbleDriver . java: 14: doLine( java . 1ang.String) intineserabble cannotbe applied to a dolineOi l error Compile Messages Stop Clear Copy Line:15 Col:1 Code:97 Top:1
Solution
In your LineScrabble.java
instead of public void doLine(String c)
replace with public void processLine(String c)
then it will execute successfully
.
Fill out the following table for four different IT systems- Note two.docx
Fill out the following table for four different IT systems.
·       Note two enterprise systems they connect with and their connection type.
·       Note two security vulnerabilities the connection may have and two to four ways each vulnerability could be potentially exploited.
Additional Comments:
An example row has been entered into the table in blue. This is only an example and should not limit what you do.
Keep in mind that enterprise systems cover a certain task in the enterprise (HR, CRM, Identity Management, etc.). They are not the components of a system (such as servers).
Connections can often be a direct connection/pipe, a file, a common database, or something else.
The vulnerability is what would make the connection vulnerable to an attack.
The related risk is an attack that could target the weakness.
Solution
When securing the modern enterprise, consider that IT systems do not operate alone. Securing them involves securing their interfaces with other systems as well. It is important to know the different interconnections each system may have.two security vulnerabilities the system may have and 2 to 4 ways each vulnerability could be potentially exploited. IT System Target System Connection Type Possible Security.
Vulnerability Related Risk
1. WMOS
2. WCS
3. network(database)
4.Incorrect accessibility
5.System Failures
6. Users accessing items not allowed
7.Users not having access to needed items
8.Loss of data and reboot time
9.Downtime of production
A first step to developing an enterprise security plan is to identify the specific vulnerabilities and related risks facing an organization. This list should be fairly exhaustive. Many vulnerability and threat pairs will not make the final cut for remediation, but an organization can only properly prioritize these if it has fully covered all of the risks.
.
Figure 9-3 shows an energy diagram for the dissolving of an ionic comp.docx
Figure 9.3 shows an energy diagram for the dissolving of an ionic compound. Discuss what factors are going to tend to make this process more favorable-in other words would likely make the com pound more soluble.
Solution
Factors that increases the solubility of ionic compounds:
Higher the solvent-solute interaction, higher the solubility of ionic compounds in the solvent. As polar solvent dissolve polar solute, ionic compounds are more soluble in polar solvent like water. Polar solvent strongly attract the ions of the solid compound.
Common ion effect decrease the solubility of the ionic compounds if the salts ion is already present in the solvent. For example CaSO?(s) ? Ca²?(aq) + SO?²?(aq)
If either of Ca 2+ and SO 4 2- is already present in the solvent the solubility of CaSO4 in the solvent decrease due to common ion effect.
For an endothermic reaction increase in temperature increases the solubility of the ionic compound in the solvent as predicted by Le Chatelier Principle.
For an exothermic reaction increase in temperature decreases the solubility of ionic compound in the according to Le Chatelier Principle.
.
FakeArrayList first - new FakeArrayl_ist(3)- first-set(2- 7-1)- first-.docx
FakeArrayList first = new FakeArrayl_ist(3); first.set(2, 7.1); first.set(l, 4.9); FakeArrayList second = new FakeArrayList(5); second.set(0, 9.1); second.set(1, 8.4);
Solution
class main_stack_frame
{ int identifier;
int address;
float contents;
public:
void set(int id,float cont)
{identifier=id;
contents=cont;
address=address;
}
}
class heap extends main_stack_frame
{ int identifier1;
int address1;
float contents1;
public:
void set(int id1,float cont1)
{identifier1=id1;
contents1=cont1;
address1=address1;
}
}
class test
{ public static void main(String args[])
main_stack_frame first= new main_stack_frame(3); // object of stack_frame class
heap second = new heap(5);// object of heap class
first.set(2,7.1);// calling set function of main_stack_frame
first.set(1,4.9)
second.set(0,9.1);// invoking set methd of heap class
second.set(1,8.4);
}
}
.
Explain why workplace spirituality seems to be an important concern-So.docx
Explain why workplace spirituality seems to be an important concern.
Solution
A culture that is most likely to shape high ethical standards is high in risk tolerance, low to moderate in aggressiveness, and focuses on means as well as outcomes. An innovative culture is characterized by the following: challenge and involvement, freedom, trust and openness, idea time, playfulness/humor, conflict resolution, debates, and risk-taking. A customer-responsive culture has six characteristics: employees who are outgoing and friendly; few rigid rules, procedures, and regulations; widespread use of empowerment; clear roles and expectations; and employees who are conscientious in their desire to please the customer.
Workplace spirituality is important for the following reasons: employees are looking for ways to counterbalance the stresses and pressures of a turbulent pace of life; people are looking for involvement and connection that they often don
.
Explanation of the similarities and differences between the Income Sta.docx
Explanation of the similarities and differences between the Income Statement and
Operating Activities section of the Statement of Cash Flows
a. What type of information is each statement conveying? Be specific and provide at least
two examples.
Solution
Cash flow from operating activities is a section of the cash flow statement that provides information regarding the cash-generating abilities of a company\'s core activities.
Example:
Cash flow from operating activities is generally calculated according to the following formula:
Cash Flow from Operating Activities = Net income + Noncash Expenses + Changes in Working Capital
The noncash expenses are usually the depreciation and/or amortization expenses listed on the firm\'sincome statement.
A statement of cash flows typically breaks out a company\'s cash sources and uses for the period into three categories: cash flows from operations, cash flows from investing activities, and cash flows from financing activities. Cash flows from operations primarily measures the cash-generating abilities of the company\'s core operations rather than from its ability to raise capital or purchase assets
The income statement is one of the three primary financial statements used to assess a company
.
Explain why Windows- Linux- and Solaris implement multiple locking mec.docx
Explain why Windows, Linux, and Solaris implement multiple locking mechanisms.
Describe the circumstances under which they use spin-locks, mutex locks, semaphores, adaptive mutex locks, and condition variables.
In each case, explain why the mechanism is needed.
I have already posted this question once before and there is an answer on the internet for this question. Please do not post that paragraph I need something a little more in depth then that. I am just wondering what Windows Linux and Solaris use do they use all these ( spin-locks, mutex locks, semaphores, adaptive mutex locks, and condition variables. ) or not and what is their purpse in each operating system.
Thank you so much for your time I really appreciate it.
Solution
In various operating systems windows, linux or solaris, we have multiprogramming as well as multiprocessing. Here we are doing multiple things at a same time. Here we have various threads working simultaniously to perfrom the task. We have a multiple threads working on a shared memory. So its improtant to maintain the data atomicity, which says if some one is working on any memory address then no other access it.
To achive it, we comes up with the multiple locking mechanisms. Various types of locks are being used on the bases of the requirement. But the main purpose of all the locks are same, which says that if one thread is working on any memory location then, first it will take a lock on the location, then perform its task and after that it will release the lock, so that other thread can access it.
.
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- 1. b. Impact testing was used to assess which property of the materials? For metals, what crystal structure was more susceptible to the ductile-to-brittle transition temperature? Why was this the case? Solution Answer:- The Imapct testing was used to to asses the required energy to fracture the material and it can be measure the toughness of the material. we can also known the yield strength of material by using impact testing but we dont have any analytical formual for. we can also calcualte the strain rate for its effect on fracture of material. There is BCC and FCC type of crystal which is more susceptible to the ductile to brittle transiotion temperature. the low carbon steel BCC metals, which become brittle at low temperature or at very high strain rate. incase of FCC metals its remain ductiule at low temperature. In metals there is plastic deformation at room temperature occurs due to dislocation motion. this dislocation motion required a stress to move and its depend on the atomic bonding which is a crustal structure. In this case brittle fracture occurs at low temperature and ductile fracture occurs at high temperature. ductile-brittle transformation occured in between low and high temperature.