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9th class Physics problems 2.1, 2.2
The document contains kinematics problems from a 9th-grade physics chapter focusing on linear motion. Problem 2.1 calculates the distance traveled by a train moving at 36 km/h for 10 seconds, resulting in a distance of 100 meters. Problem 2.2 analyzes a train that accelerates from rest to cover 1 km in 100 seconds, concluding with a final speed of 20 m/s.
9th class Physics problems 2.1, 2.2
- 1. Class 9th Physics Chapter#2,Kinematics Problem #2.1-2.2 By: Muhammad Zeeshan Easy learning
- 2. Given data: Velocity(V) = 36Km/h = 𝟑𝟔𝟎𝟎𝟎 𝟑𝟔𝟎𝟎 = 𝟏𝟎 𝒎/𝒔 Time (T) = 10sec Find. Distance S=? Formula: S=VT S=(10)(10) 𝒎 𝒔 × 𝒔 S= 100m P#2.1. A train moves with a uniform velocity of 36Km/h for 10s. Find the distance traveled by it
- 3. Data: initial velocityVi =0 Distance (S) = 1Km = 1000m Time t =100sec Find: Final velocity Vf=? Formula: Vf=Vi+at -------- (i) We need the value of “a” so we first find it then put in this equation. For a, S=Vit +1/2 at2 ⇒1000=0+1/2(a)(10000) a=𝟐 × 𝟏𝟎𝟎𝟎 𝟏𝟎𝟎𝟎𝟎 = 𝟎. 𝟐m/s2 Now put values in eq. (i) Vf = 0+(0.2)(100) Vf = 20 m/s P#2.2. A train starts from rest. It moves through 1Km in 100s with uniform acceleration. What will be its speed at the end of 100s.