14.5.5 Example 1 Part 2

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The document calculates the reactive power (Q) in kilovolt-amperes reactive (kVAR) from measurements of apparent power (S), true power (P), and the formula that reactive power is equal to the square root of the difference between the square of apparent power and the square of true power. It finds that with an apparent power of 2.308 kVA and a true power of 1.5 kW, the reactive power is 1.754 kVAR.

Business Technology

Apparent power (S) Reactive power (Q)
2.308 kVA

49.46°

True power (P) 1.5 kW

S2 = P2 + Q2

Q2 = S2 - P2

Q= √(S2 - P2)

Reactive Power (Q) = √ (S² - P²)

Q = √ (2308² - 1500²)
= √(5326864 -2250000)
= √3076864 =1754 VAR

Reactive Power (Q) = 1.754 kVAR

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Set off and carry forward of losses and assessment of individuals.pptx

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14.5.5 Example 1 Part 2

1. Apparent power (S) Reactive power (Q) 2.308 kVA 49.46° True power (P) 1.5 kW

2. S2 = P2 + Q2 Q2 = S2 - P2 Q= √(S2 - P2)

3. Reactive Power (Q) = √ (S² - P²) Q = √ (2308² - 1500²) = √(5326864 -2250000) = √3076864 =1754 VAR Reactive Power (Q) = 1.754 kVAR