10 이중포인터를이용한삽입
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단일 연결리스트에서 새로운 노드를 삽입하는 insert_node() 함수를 살펴봅니다. 이 기능에서 호출 함수의 포인터변수가 참조하는 객체를 피호출 함수에서 바꾸고자 할 경우 이중 포인터를 사용하게되는데 이중 포인터의 사용법에 대해 알아봅니다. - Youtube 강의동영상 https://youtu.be/B95v3G095js - 코드는 여기에서 다운 받으세요 https://github.com/dongupak/Advanced-C-Programming
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Similar to 10 이중포인터를이용한삽입
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How to do insertion sort on a singly linked list with no header usin.pdf
How to do insertion sort on a singly linked list with no header using C?
Solution
/* C program for insertion sort on a linked list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
// Function to insert a given node in a sorted linked list
void sortedInsert(struct node**, struct node*);
// function to sort a singly linked list using insertion sort
void insertionSort(struct node **head_ref)
{
// Initialize sorted linked list
struct node *sorted = NULL;
// Traverse the given linked list and insert every
// node to sorted
struct node *current = *head_ref;
while (current != NULL)
{
// Store next for next iteration
struct node *next = current->next;
// insert current in sorted linked list
sortedInsert(&sorted, current);
// Update current
current = next;
}
// Update head_ref to point to sorted linked list
*head_ref = sorted;
}
/* function to insert a new_node in a list. Note that this
function expects a pointer to head_ref as this can modify the
head of the input linked list (similar to push())*/
void sortedInsert(struct node** head_ref, struct node* new_node)
{
struct node* current;
/* Special case for the head end */
if (*head_ref == NULL || (*head_ref)->data >= new_node->data)
{
new_node->next = *head_ref;
*head_ref = new_node;
}
else
{
/* Locate the node before the point of insertion */
current = *head_ref;
while (current->next!=NULL &&
current->next->data < new_node->data)
{
current = current->next;
}
new_node->next = current->next;
current->next = new_node;
}
}
/* BELOW FUNCTIONS ARE JUST UTILITY TO TEST sortedInsert */
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* A utility function to insert a node at the beginning of linked list */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node = new node;
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
// Driver program to test above functions
int main()
{
struct node *a = NULL;
push(&a, 5);
push(&a, 20);
push(&a, 4);
push(&a, 3);
push(&a, 30);
printf(\"Linked List before sorting \ \");
printList(a);
insertionSort(&a);
printf(\"\ Linked List after sorting \ \");
printList(a);
return 0;
}
/* C program for insertion sort on a linked list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
// Function to insert a given node in a sorted linked list
void sortedInsert(struct node**, struct node*);
// function to sort a singly linked list using insertion sort
void insertionSort(struct node **head_ref)
{
// Initialize sorted linked list
struct node *sorted = NULL;
// Traverse the given linked list and insert every
// node to sorted
struct node *current = *head_ref;
while (current != NULL)
{
// Store next for next iteration
struct.
Please find the answer to the above problem as follows- Program.pdf
Please find the answer to the above problem as follows:-
/* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
void sortedDelete(struct node** head_ref, int number)
{
struct node *temp = *head_ref;
struct node *prev = NULL;
if(*head_ref != NULL && (*head_ref)->data == number){
*head_ref = (*head_ref)->next;
return;
}
while(temp != NULL)
{
if(temp->data == number){
prev->next = temp->next;
free(temp);
return;
}
prev = temp;
temp = temp->next;
}
}
/* function to insert a new_node in a list. Note that this
* function expects a pointer to head_ref as this can modify the
* head of the input linked list (similar to push())*/
void sortedInsert(struct node** head_ref, struct node* new_node)
{
struct node* current;
/* Special case for the head end */
if (*head_ref == NULL || (*head_ref)->data >= new_node->data)
{
if(*head_ref != NULL&&(*head_ref)->data==new_node->data){
return;
}
new_node->next = *head_ref;
*head_ref = new_node;
}
else
{
/* Locate the node before the point of insertion */
current = *head_ref;
while (current->next!=NULL &&
current->next->data < new_node->data)
{
current = current->next;
}
if(current->next!=NULL && current->next->data == new_node->data){
return;
}
new_node->next = current->next;
current->next = new_node;
}
}
/* BELOW FUNCTIONS ARE JUST UTILITY TO TEST sortedInsert */
/* A utility function to create a new node */
struct node *newNode(int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
new_node->next = NULL;
return new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
if(temp == NULL)
printf(\"\ \");
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Drier program to test count function*/
int main(int argc, char *argv[])
{
/* Start with the empty list */
struct node* head = NULL;
struct node *new_node;
FILE *fp;
fp = fopen(argv[1], \"r+\");
if(!fp){
printf(\"error\");
return 1;
}
char op = \' \';
int number = 0;
while(fscanf(fp, \"%c\\t%d\ \", &op, &number)!=EOF){
if(op==\'i\'){
new_node = newNode(number);
sortedInsert(&head, new_node);
}else if(op==\'d\'){
sortedDelete(&head, number);
}else{
printf(\"error\");
return;
}
}
printList(head);
printf(\"\ \");
return 0;
}
Solution
Please find the answer to the above problem as follows:-
/* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
void sortedDelete(struct node** head_ref, int number)
{
struct node *temp = *head_ref;
struct node *prev = NULL;
if(*head_ref != NULL && (*head_ref)->data == number){
*head_ref = (*head_ref)->next;
return;
}
while(temp != NULL)
{
if(temp->data == number){
prev->next = temp->next;
free(temp);
return;
}
prev = temp;
temp = temp->next;
}
}
/* function to insert a new_node in a list. Note that this
* function expects a point.
Write the following using javaGiven a class ‘Node’ and ‘NodeList’,.pdf
Write the following using java
Given a class ‘Node’ and ‘NodeList’, that contains the below information diagram.
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
NodeList
-size: int
-root: Node
+add(node: Node): void
+size(): int
+findNode(node: Node): boolean
Implement add(Node), findNode(Node) and size methods in the NodeList class which is
provided to you. The methods should work as:
Using the following main method:
public static void main(String[] args)
{
NodeList list = new NodeList();
Node node = new Node(1, \"Book\");
Node node2 = new Node(2, \"Lappy\");
list.add(node);
list.add(node2);
System.out.println(\"Length : \"+list.size());
Node node3 = new Node(3, \"Glass\");
Node node4 = new Node(4, \"Pen\");
list.add(node3);
System.out.println(\"Length : \"+list.size());
if(list.findNode(node3)) System.out.println(\"Node found: \"+ node3.getName());
else
System.out.println(\"Node not found: \"+ node3.getName());
if(list.findNode(node4)) System.out.println(\"Node found: \"+ node4.getName());
else
System.out.println(\"Node not found: \"+ node4.getName());
}
Then it should return the following output:
Length : 2
Length : 3
Node found: Glass
Node not found: Pen
The given Node class is:
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this.name = name;
this.next = null;
}
public Node getNext()
{
return next;
}
public void setNext(Node node)
{
this.next = node
}
public int getId()
{
return id;
{
public void setId(int id)
{
this.id = id;
}
public String getName()
{
return name;
}
public void setName(String name)
{
this.name = name;
}
public String toString()
{
return \"ID : \"+this.id+\" Name : \"+this.name;
}
}
The given NodeList class is:
public class NodeList
{
private int size = 0;
private Node root = null;
/*
* It has to take a new Node and add that to the next address of previous Node.
* If the list is empty, assign it as the \"root\"
* @Param - Node
*/
public void add(Node node)
{
// Implement this method!!!
}
/*
* It has to return the size of the NodeList
*
* @return size
*/
public int size()
{
// Implement this method!!!
}
/*
* It has to take a Node and checks if the node is in the list.
* If it finds the node, it returns true, otherwise false
*
* @param - Node
* @return boolean true/false
*/
public boolean findNode(Node node)
{
// Implement this method!!!
}
}Node
-id: int
-name: String
-next: Node
+Node(id: int, name: String)
+setId(id: int): void
+getId(): int
+setName(name: String) : void
+getName(): String
+setNext(node: Node): void
+getNext(): Node
Solution
Hi, Please find my implementation.
Please let me know in case of any issue.
############ Node.java #############
public class Node
{
private int id = 0;
private String name = \"\";
private Node next;
public Node(int id, String name)
{
this.id = id;
this..
Data structures cs301 power point slides lecture 03
The document discusses linked lists and C++ code for implementing a linked list. It includes definitions of a Node class to represent individual nodes, with fields for storing data and pointers to other nodes. It also defines a List class for managing the overall linked list, including functions for adding new nodes to the list. Diagrams show how nodes are linked and stored non-contiguously in memory. The code provided implements adding new nodes to the front or end of the linked list by updating pointer references between nodes.
Let n = size of the hash table hashTable = array of size n, w.pdf
//Let n = size of the hash table
// hashTable = array of size n, which represents the hash table
// hashIndex = represents the index of array
// If the list is EMPTY, we add the element into the list
/*If the list is NOT EMPTY then we compare the newNode to the node already in the list in such
a way to get sorted.*/
struct node
{
int key;
T value;
struct node *next;
};
struct node *hashTable[n] = {NULL};
struct node * createNode(int key, char *name, int age)
{
struct node *newnode;
newnode = (struct node *)malloc(sizeof(struct node));
newnode->key = key;
newnode->value = value;
newnode->next = NULL;
return newnode;
}
add(int key, T value)
{
int hashIndex = key % n;
struct node *newNode = creteNode(key,value);
/*Adding new node to the list with No element */
if (hashTable[hashIndex] == NULL)
{
hashTable[hashIndex] = newnode;
return;
}
/*Adding new node to the sorted list */
struct node *temp1;
struct node *temp2 = hashTable[hashIndex];
temp1 = temp2;
while(temp2 -> key < newNode -> key)
{
temp1 = temp2;
temp2 = temp2 ->next;
}
newnode->next = temp2;
temp1->next = newNode;
return;
}
Solution
//Let n = size of the hash table
// hashTable = array of size n, which represents the hash table
// hashIndex = represents the index of array
// If the list is EMPTY, we add the element into the list
/*If the list is NOT EMPTY then we compare the newNode to the node already in the list in such
a way to get sorted.*/
struct node
{
int key;
T value;
struct node *next;
};
struct node *hashTable[n] = {NULL};
struct node * createNode(int key, char *name, int age)
{
struct node *newnode;
newnode = (struct node *)malloc(sizeof(struct node));
newnode->key = key;
newnode->value = value;
newnode->next = NULL;
return newnode;
}
add(int key, T value)
{
int hashIndex = key % n;
struct node *newNode = creteNode(key,value);
/*Adding new node to the list with No element */
if (hashTable[hashIndex] == NULL)
{
hashTable[hashIndex] = newnode;
return;
}
/*Adding new node to the sorted list */
struct node *temp1;
struct node *temp2 = hashTable[hashIndex];
temp1 = temp2;
while(temp2 -> key < newNode -> key)
{
temp1 = temp2;
temp2 = temp2 ->next;
}
newnode->next = temp2;
temp1->next = newNode;
return;
}.
1#include stdio.h#include stdlib.h#include assert.h .pdf
1
#include
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Given a reference (pointer to pointer) to the head
of a list and an int, push a new node on the front
of the list. */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Takes head pointer of the linked list and index
as arguments and return data at index*/
int GetNth(struct node* head, int index)
{
struct node* current = head;
int count = 0; /* the index of the node we\'re currently
looking at */
while (current != NULL)
{
if (count == index)
return(current->data);
count++;
current = current->next;
}
/* if we get to this line, the caller was asking
for a non-existent element so we assert fail */
assert(0);
}
/* Drier program to test above function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
/* Use push() to construct below list
1->12->1->4->1 */
push(&head, 1);
push(&head, 4);
push(&head, 1);
push(&head, 12);
push(&head, 1);
/* Check the count function */
printf(\"Element at index 3 is %d\", GetNth(head, 3));
getchar();
}
2
#include
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Given a reference (pointer to pointer) to the head
of a list and an int, push a new node on the front
of the list. */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Takes head pointer of the linked list and index
as arguments and return data at index*/
int GetNth(struct node* head, int index)
{
struct node* current = head;
int count = 0; /* the index of the node we\'re currently
looking at */
while (current != NULL)
{
if (count == index)
return(current->data);
count++;
current = current->next;
}
/* if we get to this line, the caller was asking
for a non-existent element so we assert fail */
assert(0);
}
/* Drier program to test above function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
/* Use push() to construct below list
1->12->1->4->1 */
push(&head, 1);
push(&head, 4);
push(&head, 1);
push(&head, 12);
push(&head, 1);
/* Check the count function */
printf(\"Element at index 3 is %d\", GetNth(head, 3));
getchar();
}
Solution
1
#include
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Given a reference (pointer to pointer) to the head
of a list and an int, push a new node on the front
of the list. */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node*.
C++ Please write the whole code that is needed for this assignment- wr.docx
Brianca plans to save $5,000, $1,000, and $42,000 a year over the next three years, respectively. How much would you need to deposit in one lump sum today to have the same amount as Brianca three years from now if you both earn 10.9 percent, compounded annually? $36,115 $35,192 $43,282 $41,635 $35,372
.
dynamicList.ppt
The document discusses implementing a sorted linked list data structure in C++. It describes how to insert a new node into the linked list in the correct sorted position by finding the previous and current nodes between which the new node should be inserted. The key steps are to create a new node, find the previous and current nodes using a while loop, and connect the new node by updating the next pointers of the previous and current nodes.
I have been tasked to write a code for a Singly Linked list that inc.pdf
I have been tasked to write a code for a Singly Linked list that includes the following: Implement
a singly linked list class with the following methods: - `void insertAtBeginning(int value)`:
Inserts a new node with the given value at the beginning of the list. - `void insertAtEnd(int
value)`: Inserts a new node with the given value at the end of the list. - `void deleteNode(int
value)`: Deletes the first occurrence of a node with the given value. - `void display()`: Displays
the elements of the linked list. I have everything EXCEPT for the deleteNode. I have it included,
but it is throwing an error....I just need a little extra help to fix that part. My Code: #
#include
using namespace std;
class Node { //user defined type.
public: // public class modifier to access the class node.
int value;
Node* next;
};
void display(Node *head) {
if(head == NULL){
cout << "NULL" << endl;
}
else {
cout << head->value << endl;
display(head->next);
}
}
void insertAtBeginning(Node**head, int newValue){
// Steps to add a Node to the beginning of the linked list
//1. Prepare a newNode
Node * newNode = new Node();
newNode ->value = newValue;
//2. Put it in front of the current head
newNode->next = *head;
//3. Move head of the list to point to the newNode
*head= newNode;
}
void insertAtEnd(Node**head, int newValue) {
//1.Prepare a newNode
Node* newNode= new Node();
newNode ->value = newValue;
newNode->next = NULL;
//2. If Linked list is empty, newNode will be a head node
if(*head ==NULL){
*head = newNode;
return;
}
//3. Find last node
Node* last= *head;
while(last->next!=NULL){
last=last->next;
}
//4. Insert newNode after last node (at the end of List)
last->next =newNode;
}
void deleteNode(Node**before_del){
Node* temp;
temp = before_del->next;
before_del->next = temp->next;
delete temp;
}
int main()
{
Node* head=new Node();
Node* second=new Node();
Node* third=new Node();
Node* fourth=new Node();
head->value = 7;
head->next = second;
second->value = 12;
second->next = third;
third->value = 15;
third->next = fourth;
fourth->value = 20;
fourth->next = NULL;
insertAtBeginning(&head, 4);
insertAtBeginning(&head, 6);
insertAtEnd(&head, 23);
del(&head(15)->next);
display(head);
}.
computer notes - Data Structures - 3
The document discusses linked lists and C++ code for implementing them. It describes how a linked list is structured in memory using nodes that point to the next node. It also shows the Node class definition used to create nodes, and the List class with methods like add() to insert new nodes into the linked list.
C++Write a method Node Nodereverse() which reverses a list..pdf
C++
Write a method Node *Node::reverse() which reverses a list.
Solution
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
/* Function to reverse the linked list */
static void reverse(struct node** head_ref)
{
struct node* prev = NULL;
struct node* current = *head_ref;
struct node* next;
while (current != NULL)
{
next = current->next;
current->next = prev;
prev = current;
current = next;
}
*head_ref = prev;
}
/* Function to push a node */
void push(struct node** head_ref, int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*head_ref);
/* move the head to point to the new node */
(*head_ref) = new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Driver program to test above function*/
int main()
{
/* Start with the empty list */
struct node* head = NULL;
push(&head, 20);
push(&head, 4);
push(&head, 15);
push(&head, 85);
printf(\"Given linked list\ \");
printList(head);
reverse(&head);
printf(\"\ Reversed Linked list \ \");
printList(head);
getchar();
}.
In the class we extensively discussed a generic singly linked list i.pdf
In the class we extensively discussed a generic singly linked list implemented as a node class.
Implement a generic node class called DoublyNode in which each node contains an element of
type E and each node is linked not only forward to the next element in the list but also backward
to the previous element in the list. Your implementation should adapt and implement all the
methods of generic Node including the following methods:
Constructor for DoublyNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
Solution
import java.util.ListIterator;
import java.util.NoSuchElementException;
import java.util.Random;
public class DoublyNode {
private Node head;
private Node tail;
private int size;
public DoublyNode() {
size = 0;
}
private class Node {
E element;
Node getForeNode;
Node getBackNode;
public Node(E element, Node next, Node prev) {
this.element = element;
this.getForeNode = next;
this.getBackNode = prev;
}
}
public int listLength() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.getBackNode = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfter(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.getForeNode = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfterSpecifiedNode(E element, E tobeAddedAfter) {
Node prevTobeAddedAfter = listSearch(element);
Node afterNode = prevTobeAddedAfter.getForeNode;
Node tmpNode = new Node(element,prevTobeAddedAfter,afterNode);
tmpNode = prevTobeAddedAfter.getForeNode;
afterNode = tmpNode.getForeNode;
}
public void listCopy(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getForeNode;
}
}
public Node listSearch(E item){
System.out.println(\"Searching Item \"+item);
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
if(tmp.element == item) {
System.out.println(\"Item found \"+item);
return tmp;
}
tmp = tmp.getForeNode;
}
return null;
}
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getBackNode;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.getForeNode;
head.getBackNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeNodeAfter() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.getBackNode;
tail.getForeNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
}.
C program to insert a node in doubly linked list
This C program implements functions to create and manipulate a doubly linked list. It allows the user to choose from a menu to create a list, insert nodes at the beginning, end, or a specified position, and display the list. Functions are defined to create a list by dynamically allocating nodes and linking them together, insert nodes at different positions by updating next and prev pointers, and display the list by traversing from head to tail.
LINKED LISTS
A singly linked list is a data structure consisting of nodes where each node stores an element and a link to the next node. The document describes algorithms for inserting nodes at the head, tail, and between two nodes of a singly linked list. It also describes doubly linked lists which allow traversing the list in both directions by including a link to the previous node as well as the next node in each node. Linked lists are useful when the number of elements is unknown or varies, and for operations like inserting or removing elements in the middle of the list without shifting other elements.
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Linked List Copy Constructor Help!! Im having trouble doing this how w.docx
Linked List Copy Constructor Help!! Im having trouble doing this how would you do it since mine doesnt want to work.
LinkedList::LinkedList(const LinkedList & alinked_list)
{
head = NULL;
Node* newNode;
Node* nodePtr;
Node* tempPtr;
if (!alinked_list.head)
return;
nodePtr = alinked_list.head;
head = new Node;
head->getData = nodePtr->getData;
head->getLink = NULL;
nodePtr = nodePtr->getLink;
tempPtr = head;
while (nodePtr != NULL)
{
newNode = new Node;
newNode->getData = nodePtr->getData;
newNode->getLink = NULL;
tempPtr->getLink = newNode;
tempPtr = newNode;
nodePtr = nodePtr->getLink;
}
I have 2 classes.
class LinkedList: public Node
{
private:
Node* head; }
class Node {
int data;
Node* link; }
if you want me to provide all of the code i have i can gladly do that.
Solution
//Corrected Program
LinkedList::LinkedList(const LinkedList & alinked_list)
{
head = NULL;
Node* newNode;
Node* nodePtr;
Node* tempPtr;
if (alinked_list.head==NULL)
return;
nodePtr = alinked_list.head;
head = new Node;
head->setData(nodePtr->getData());
head->setLink(NULL);
nodePtr = nodePtr->getLink();
tempPtr = head;
while (nodePtr != NULL)
{
newNode = new Node;
newNode->setData(nodePtr->getData());
newNode->setLink(NULL);
tempPtr->setLink(newNode);
tempPtr = newNode;
nodePtr = nodePtr->getLink();
}
class LinkedList: public Node
{
private:
Node* head;
public:
LinkedList(const LinkedList & alinked_list);
} ;
class Node {
int data;
Node* link;
public:
setData(int d)
{
data=d;
}
setLink(Node * p)
{
link=p;
}
getLink()
{
retrun link;
}
getData()
{
return data;
}
}
;
.
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED .pdf
THE CODE HAS A SEGMENTATION FAULT BUT I CANNOT FIND OUT WHERE. NEED
HELP FIXING THIS CODE?
THIS IS THE PROBLEM
Write a program that allows the user to enter two positive integers and outputs their sum. Sounds
simple? Here\'s the catch: The numbers may be any size! They may be way too large to store in a
single variable. You may not assume any particular maximum number of digits.
HERE IS THE CODE
#include
#include
struct node /* Linked list node*/
{
int data;
struct node* next;
};
struct node *newNode(int data) /* Function to create a new node with giving the data*/
{
struct node *new_node = (struct node *) malloc(sizeof(struct node));
new_node->data = data;
new_node->next = NULL;
return new_node;
}
void push(struct node** head_ref, int new_data) /* Function to insert a node at the beginning of
the Doubly Linked List*/
{
struct node* new_node = newNode(new_data); /*allocate a node*/
new_node->next = (*head_ref); /* link the old list off to the new node*/
(*head_ref) = new_node; /*move the head to point to the new node*/
}
/* Adding the contents of two linked lists and return the head node of resultant list*/
struct node* addTwoLists (struct node* first, struct node* second)
{
struct node* res = NULL; /* res is head node of the resultant list*/
struct node *temp, *prev = NULL;
int carry = 0, sum;
while (first != NULL || second != NULL) /*while both the lists exists*/
{
/* Calculate value of next digit in resultant list.
// The next digit is sum of following things
// (i) Carry
// (ii) Next digit of first list (if there is a next digit)
// (ii) Next digit of second list (if there is a next digit)*/
sum = carry + (first? first->data: 0) + (second? second->data: 0);
carry = (sum >= 10)? 1 : 0; /* update carry for next calulation*/
sum = sum % 10; /*update sum if it is greater than 10*/
temp = newNode(sum); /*Create a new node with sum as data*/
if(res == NULL) /*if this is the first node then set it as head of the resultant list*/
res = temp;
else /* If this is not the first node then connect it to the rest.*/
prev->next = temp;
prev = temp; /* Set prev for next insertion*/
if (first) first = first->next; /* Move first pointers to next node*/
if (second) second = second->next; /*Move second pointer to the next node*/
}
if (carry > 0)
temp->next = newNode(carry);
return res; /* return head of the resultant list*/
}
void printList(struct node *node) /* function to print a linked list*/
{
while(node != NULL)
{
printf(\"%d \", node->data);
node = node->next;
}
printf(\"\ \");
}
int main(void) /* program to test above function*/
{
struct node* res = NULL;
struct node* first = NULL;
struct node* second = NULL;
printf(\"Enter first positive integer: \");
scanf(\"%d\",&first);
printList(first);
printf(\"Enter second positive integer: \");
scanf(\"%d\",&second);
printList(second);
/*Add the two lists and see result*/
res = addTwoLists(first, second);
printf(\"Sum is: %d\");
printList(res);
return 0;
}
Solution
#include
#include
typedef struct Node
{
int da.
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
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Mobile Healthcare Application
The document provides information about Park DongGyu, a professor at Changwon National University in South Korea. It discusses his work developing mobile healthcare applications, including applications for hearing tests/hearing aids, sleep monitoring, tinnitus treatment, and augmentative and alternative communication (AAC). Recent projects involve using smartphones to create affordable audiometers for hearing tests and personal sound amplification products tailored to individual hearing profiles.
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20 2 강의를 마치며
이번 강의에서는 지난 7개월간 이어진 강의의 마지막 편으로 파이썬이 각광받고 있는 이유와 장점에 대해서 다루어 봅니다.
그리고 저의 개인적인 강의 경험도 알려드릴까 합니다.
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20 1 코딩스타일
코딩 스타일은 파이썬의 아주 중요한 요소중 하나입니다.
이번 강의에서는 PEP-8 의 코딩 스타일 가이드 라인에 대해 자세히 살펴보고 pyCharm의 리포맷 기능에 대해서도 알아보겠습니다.
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18 2 파이썬표준라이브러리
이번 강의에서는 방대한 파이썬 표준 라이브러리의 내용과 기능을 살펴보고 파이썬 외부 라이브러리에 대해서도 살펴보겠습니다.
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18 1 파이썬패키지
이번 강의에서는 파이썬의 패키지를 만들고 활용하는 방법을 알아보겠습니다.
대규모 프로젝트를 수행하기 위해서는 이미 잘 만들어진 코드를 활용하는 것이 중요한데요, 잘 만들어진 코드를 활용하는 방법이 모듈을 사용하는 것입니다.
그러나 모듈의 수가 많아지면 폴더(디렉토리) 아래에 계층적으로 두는 것이 더욱 편리합니다.
한 폴더에 유사한 성격의 여러 모듈을 두고 이 폴더를 가져오는 방식으로 개발을 하는데 이 폴더를 패키지라고 합니다. 본 강의에서는 예제를 통해서 파이썬의 패키지 만드는 방법을 살펴보도록 하겠습니다.
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17 2 필터함수와 맵함수
이번 강의에서는 람다함수를 필터 함수와 맵 함수에서 사용하는 방법에 대해 살펴보겠습니다.
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17 1 람다함수
이번 강의에서는 람다함수에 대해 알아보겠습니다.
앞서 배운 함수를 이용하면 필요한 기능의 재사용이 가능하기 때문에, 함수를 정의한 후 필요할 때마다 호출하여 사용하면 편리한데 이러한 방식으로 프로그램을 하는 방식을 모듈화 프로그래밍 이라고 한다.
그러나 가끔씩은 함수를 만들지 않고 함수화된 기능만을 불러 사용하고자 할 경우가 있는데, 이렇게 하면 프로그램을 단순하게 만들 수 있다.
즉 1회용으로 함수를 만들고 싶은데 def xxx(): 과 같은 이름을 짓는 것이 번거롭게 느껴질 경우에 사용하는 것이 람다함수 혹은 람다표현식이다.
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16 1 상속과super()
이번 강의에서는 파이썬 클래스의 상속에 대해 알아보겠습니다. 소프트웨어 개발시에는 예전에 만들어진 코드를 이용하여 새로운 기능을 개발하는 경우가 많은데요, 클래스의 상속 기능을 사용하면 부모 클래스에서 만들어둔 기능과 속성을 물려받을 수 있습니다.
상속은 객체지향 프로그래밍의 매우 뛰어난 기능으로 이 강의에서는 상속에 대해 알아봅니다. 또한 상속받은 자식이 부모 클래스를 호출하기 위해 사용하는 super() 함수에 대해서도 알아봅니다.
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15 2 클래스정의와self
이번 강의에서는 파이썬에서 클래스를 정의하는 문법과 self 에 대해 살펴보도록 하겠습니다.
그리고 .(마침표)연산자를 이용하여 인스턴스에서 메소드를 호출하는 방법도 살펴보겠습니다.
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14 4 슬라이싱
슬라이싱(slicing)이란 리스트나 튜플, 문자열의 항목을 잘라서 일부만을 가져오는 기능을 말합니다.
보통 list[시작 : 끝] 과 같이 시작항목과 끝 항목의 인덱스를 지정하는 방식으로 사용하는데요, 시작 항목은 포함되지만 끝 항목은 포함되지 않습니다.
이번 강의에서는 파이썬의 슬라이싱을 이용하는 방법을 다양한 예제와 애니메이션으로 살펴보도록 하겠습니다.
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14 2 iterator
이번 강의에서는 파이썬의 iterator에 대해 알아보겠습니다.
리스트, 집합, 딕셔너리와 같은 타입이나, 문자열은 for - in 구문을 통해서 반복적으로 하나씩 데이터를 꺼내서 처리할 수 있는데, 이와 같이 여러 개의 데이터를 포함한 타입중에서 반복적으로 하나하나 꺼내어 처리가능한 컬렉션이나 Sequence 들을 순환가능(Iterable) 객체라고 합니다.
iterator는 next() 함수를 구현한 객체를 말하며 next() 함수는 순환가능한 객체의 다음 원소를 반환하는 일을 합니다.
파이썬은 list, dict, set, bytes, tuple, range형이 iterable 형 객체입니다.
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14 3 리스트함수
이번 동영상 강의에서는 리스트 함수에 대해 살펴보도록 하겠습니다. 앞 장 강의에서 min(), max()와 같은 간단한 리스트 함수를 살펴보았는데요, 이번 강의에서는 all(), any(), bool(), filter() 등의 고급 함수의 기능과 그 사용예를 살펴봅니다.
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14 1 리스트의 메소드
이번 강의에서는 파이썬의 리스트 메소드에 대해 살펴보겠습니다.
파이썬의 리스트는 다양한 메소드를 제공하는데, 이 메소드를 통해 리스트의 원소를 변경하거나, 삭제, 추가, 병합, 정렬등의 기능을 할 수 있습니다.
또한, 파이썬의 기본 함수에서는 리스트의 원소의 길이, 최대값, 최소값, 분할을 위한 다양한 함수가 제공됩니다. 예제와 실습을 통해 index(), extend(), insert(), sort(), reverse()등의 메소드와 사용법을 알아보겠습니다.
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1.高仿业务:【本科硕士】毕业证,成绩单（GPA修改）,学历认证（教育部认证）,大学Offer,,ID,留信认证,使馆认证,雅思,语言证书等高仿类证书；
2.认证服务: 学历认证（教育部认证）,大使馆认证（回国人员证明）,留信认证（可查有编号证书）,大学保录取,雅思保分成绩单。
3.技术服务：钢印水印烫金激光防伪凹凸版设计印刷激凸温感光标底纹镭射速度快。
办理加利福尼亚艺术学院加利福尼亚艺术学院毕业证文凭证书流程：
1客户提供办理信息：姓名生日专业学位毕业时间等（如信息不确定可以咨询顾问：我们有专业老师帮你查询）；
2开始安排制作毕业证成绩单电子图；
3毕业证成绩单电子版做好以后发送给您确认；
4毕业证成绩单电子版您确认信息无误之后安排制作成品；
5成品做好拍照或者视频给您确认；
6快递给客户（国内顺丰国外DHLUPS等快读邮寄）
-办理真实使馆公证（即留学回国人员证明）
-办理各国各大学文凭（世界名校一对一专业服务,可全程监控跟踪进度）
-全套服务：毕业证成绩单真实使馆公证真实教育部认证。让您回国发展信心十足！
（详情请加一下 文凭顾问+微信:95270640）欢迎咨询！子小伍玩小伍比山娃小一岁虎头虎脑的很霸气父亲让山娃跟小伍去夏令营听课山娃很高兴夏令营就设在附近一所小学山娃发现那所小学比自己的学校更大更美操场上还铺有塑胶跑道呢里面很多小朋友一班一班的快快乐乐原来城里娃都藏这儿来了怪不得平时见不到他们山娃恍然大悟起来吹拉弹唱琴棋书画山娃都不懂却什么都想学山娃怨自己太笨什么都不会斟酌再三山娃终于选定了学美术当听说每月要交元时父亲犹豫了山娃也说爸算了吧咱学校一学期才转
Blood finder application project report (1).pdf
Blood Finder is an emergency time app where a user can search for the blood banks as
well as the registered blood donors around Mumbai. This application also provide an
opportunity for the user of this application to become a registered donor for this user have
to enroll for the donor request from the application itself. If the admin wish to make user
a registered donor, with some of the formalities with the organization it can be done.
Specialization of this application is that the user will not have to register on sign-in for
searching the blood banks and blood donors it can be just done by installing the
application to the mobile.
The purpose of making this application is to save the user’s time for searching blood of
needed blood group during the time of the emergency.
This is an android application developed in Java and XML with the connectivity of
SQLite database. This application will provide most of basic functionality required for an
emergency time application. All the details of Blood banks and Blood donors are stored
in the database i.e. SQLite.
This application allowed the user to get all the information regarding blood banks and
blood donors such as Name, Number, Address, Blood Group, rather than searching it on
the different websites and wasting the precious time. This application is effective and
user friendly.
SCALING OF MOS CIRCUITS m .pptx
this ppt explains about scaling parameters of the mosfet it is basically vlsi subject
Digital Twins Computer Networking Paper Presentation.pptx
A Digital Twin in computer networking is a virtual representation of a physical network, used to simulate, analyze, and optimize network performance and reliability. It leverages real-time data to enhance network management, predict issues, and improve decision-making processes.
一比一原版(uofo毕业证书)美国俄勒冈大学毕业证如何办理
原版一模一样【微信：741003700 】【(uofo毕业证书)美国俄勒冈大学毕业证成绩单】【微信：741003700 】学位证，留信认证（真实可查，永久存档）原件一模一样纸张工艺/offer、雅思、外壳等材料/诚信可靠,可直接看成品样本，帮您解决无法毕业带来的各种难题！外壳，原版制作，诚信可靠，可直接看成品样本。行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备。十五年致力于帮助留学生解决难题，包您满意。
本公司拥有海外各大学样板无数，能完美还原。
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微741003700
【主营项目】
一.毕业证【q微741003700】成绩单、使馆认证、教育部认证、雅思托福成绩单、学生卡等！
二.真实使馆公证(即留学回国人员证明,不成功不收费)
三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
◇在校期间，因各种原因未能顺利毕业……拿不到官方毕业证【q/微741003700】
◇面对父母的压力，希望尽快拿到；
◇不清楚认证流程以及材料该如何准备；
◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
◇需要报考公务员、购买免税车、落转户口
◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
办理(uofo毕业证书)美国俄勒冈大学毕业证【微信：741003700 】外观非常简单，由纸质材料制成，上面印有校徽、校名、毕业生姓名、专业等信息。
办理(uofo毕业证书)美国俄勒冈大学毕业证【微信：741003700 】格式相对统一，各专业都有相应的模板。通常包括以下部分：
校徽：象征着学校的荣誉和传承。
校名:学校英文全称
授予学位：本部分将注明获得的具体学位名称。
毕业生姓名：这是最重要的信息之一，标志着该证书是由特定人员获得的。
颁发日期：这是毕业正式生效的时间，也代表着毕业生学业的结束。
其他信息：根据不同的专业和学位，可能会有一些特定的信息或章节。
办理(uofo毕业证书)美国俄勒冈大学毕业证【微信：741003700 】价值很高，需要妥善保管。一般来说，应放置在安全、干燥、防潮的地方，避免长时间暴露在阳光下。如需使用，最好使用复印件而不是原件，以免丢失。
综上所述，办理(uofo毕业证书)美国俄勒冈大学毕业证【微信：741003700 】是证明身份和学历的高价值文件。外观简单庄重，格式统一，包括重要的个人信息和发布日期。对持有人来说，妥善保管是非常重要的。
AI + Data Community Tour - Build the Next Generation of Apps with the Einstei...
AI + Data Community Tour - Build the Next Generation of Apps with the Einstei...Paris Salesforce Developer Group
Build the Next Generation of Apps with the Einstein 1 Platform.
Rejoignez Philippe Ozil pour une session de workshops qui vous guidera à travers les détails de la plateforme Einstein 1, l'importance des données pour la création d'applications d'intelligence artificielle et les différents outils et technologies que Salesforce propose pour vous apporter tous les bénéfices de l'IA.NATURAL DEEP EUTECTIC SOLVENTS AS ANTI-FREEZING AGENT
NATURAL DEEP EUTECTIC SOLVENTS AS ANTI-FREEZING AGENT
Data Driven Maintenance | UReason Webinar
Discover the latest insights on Data Driven Maintenance with our comprehensive webinar presentation. Learn about traditional maintenance challenges, the right approach to utilizing data, and the benefits of adopting a Data Driven Maintenance strategy. Explore real-world examples, industry best practices, and innovative solutions like FMECA and the D3M model. This presentation, led by expert Jules Oudmans, is essential for asset owners looking to optimize their maintenance processes and leverage digital technologies for improved efficiency and performance. Download now to stay ahead in the evolving maintenance landscape.
Height and depth gauge linear metrology.pdf
Height gauges may also be used to measure the height of an object by using the underside of the scriber as the datum. The datum may be permanently fixed or the height gauge may have provision to adjust the scale, this is done by sliding the scale vertically along the body of the height gauge by turning a fine feed screw at the top of the gauge; then with the scriber set to the same level as the base, the scale can be matched to it. This adjustment allows different scribers or probes to be used, as well as adjusting for any errors in a damaged or resharpened probe.
一比一原版(USF毕业证)旧金山大学毕业证如何办理
原件一模一样【微信：95270640】【旧金山大学毕业证USF学位证成绩单】【微信：95270640】（留信学历认证永久存档查询）采用学校原版纸张、特殊工艺完全按照原版一比一制作（包括：隐形水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠，文字图案浮雕，激光镭射，紫外荧光，温感，复印防伪）行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备，十五年致力于帮助留学生解决难题，业务范围有加拿大、英国、澳洲、韩国、美国、新加坡，新西兰等学历材料，包您满意。
【业务选择办理准则】
一、工作未确定，回国需先给父母、亲戚朋友看下文凭的情况，办理一份就读学校的毕业证【微信：95270640】文凭即可
二、回国进私企、外企、自己做生意的情况，这些单位是不查询毕业证真伪的，而且国内没有渠道去查询国外文凭的真假，也不需要提供真实教育部认证。鉴于此，办理一份毕业证【微信：95270640】即可
三、进国企，银行，事业单位，考公务员等等，这些单位是必需要提供真实教育部认证的，办理教育部认证所需资料众多且烦琐，所有材料您都必须提供原件，我们凭借丰富的经验，快捷的绿色通道帮您快速整合材料，让您少走弯路。
留信网认证的作用:
1:该专业认证可证明留学生真实身份【微信：95270640】
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
→ 【关于价格问题（保证一手价格）
我们所定的价格是非常合理的，而且我们现在做得单子大多数都是代理和回头客户介绍的所以一般现在有新的单子 我给客户的都是第一手的代理价格，因为我想坦诚对待大家 不想跟大家在价格方面浪费时间
对于老客户或者被老客户介绍过来的朋友，我们都会适当给一些优惠。
选择实体注册公司办理，更放心，更安全！我们的承诺：可来公司面谈，可签订合同，会陪同客户一起到教育部认证窗口递交认证材料，客户在教育部官方认证查询网站查询到认证通过结果后付款，不成功不收费！
办理旧金山大学毕业证毕业证学位证USF学位证【微信：95270640 】外观非常精致，由特殊纸质材料制成，上面印有校徽、校名、毕业生姓名、专业等信息。
办理旧金山大学毕业证USF学位证毕业证学位证【微信：95270640 】格式相对统一，各专业都有相应的模板。通常包括以下部分：
校徽：象征着学校的荣誉和传承。
校名:学校英文全称
授予学位：本部分将注明获得的具体学位名称。
毕业生姓名：这是最重要的信息之一，标志着该证书是由特定人员获得的。
颁发日期：这是毕业正式生效的时间，也代表着毕业生学业的结束。
其他信息：根据不同的专业和学位，可能会有一些特定的信息或章节。
办理旧金山大学毕业证毕业证学位证USF学位证【微信：95270640 】价值很高，需要妥善保管。一般来说，应放置在安全、干燥、防潮的地方，避免长时间暴露在阳光下。如需使用，最好使用复印件而不是原件，以免丢失。
综上所述，办理旧金山大学毕业证毕业证学位证USF学位证【微信：95270640 】是证明身份和学历的高价值文件。外观简单庄重，格式统一，包括重要的个人信息和发布日期。对持有人来说，妥善保管是非常重要的。
Null Bangalore | Pentesters Approach to AWS IAM
#Abstract:
- Learn more about the real-world methods for auditing AWS IAM (Identity and Access Management) as a pentester. So let us proceed with a brief discussion of IAM as well as some typical misconfigurations and their potential exploits in order to reinforce the understanding of IAM security best practices.
- Gain actionable insights into AWS IAM policies and roles, using hands on approach.
#Prerequisites:
- Basic understanding of AWS services and architecture
- Familiarity with cloud security concepts
- Experience using the AWS Management Console or AWS CLI.
- For hands on lab create account on [killercoda.com](https://killercoda.com/cloudsecurity-scenario/)
# Scenario Covered:
- Basics of IAM in AWS
- Implementing IAM Policies with Least Privilege to Manage S3 Bucket
- Objective: Create an S3 bucket with least privilege IAM policy and validate access.
- Steps:
- Create S3 bucket.
- Attach least privilege policy to IAM user.
- Validate access.
- Exploiting IAM PassRole Misconfiguration
-Allows a user to pass a specific IAM role to an AWS service (ec2), typically used for service access delegation. Then exploit PassRole Misconfiguration granting unauthorized access to sensitive resources.
- Objective: Demonstrate how a PassRole misconfiguration can grant unauthorized access.
- Steps:
- Allow user to pass IAM role to EC2.
- Exploit misconfiguration for unauthorized access.
- Access sensitive resources.
- Exploiting IAM AssumeRole Misconfiguration with Overly Permissive Role
- An overly permissive IAM role configuration can lead to privilege escalation by creating a role with administrative privileges and allow a user to assume this role.
- Objective: Show how overly permissive IAM roles can lead to privilege escalation.
- Steps:
- Create role with administrative privileges.
- Allow user to assume the role.
- Perform administrative actions.
- Differentiation between PassRole vs AssumeRole
Try at [killercoda.com](https://killercoda.com/cloudsecurity-scenario/)
一比一原版(uoft毕业证书)加拿大多伦多大学毕业证如何办理
原版一模一样【微信：741003700 】【(uoft毕业证书)加拿大多伦多大学毕业证成绩单】【微信：741003700 】学位证，留信认证（真实可查，永久存档）原件一模一样纸张工艺/offer、雅思、外壳等材料/诚信可靠,可直接看成品样本，帮您解决无法毕业带来的各种难题！外壳，原版制作，诚信可靠，可直接看成品样本。行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备。十五年致力于帮助留学生解决难题，包您满意。
本公司拥有海外各大学样板无数，能完美还原。
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微741003700
【主营项目】
一.毕业证【q微741003700】成绩单、使馆认证、教育部认证、雅思托福成绩单、学生卡等！
二.真实使馆公证(即留学回国人员证明,不成功不收费)
三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
◇在校期间，因各种原因未能顺利毕业……拿不到官方毕业证【q/微741003700】
◇面对父母的压力，希望尽快拿到；
◇不清楚认证流程以及材料该如何准备；
◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
◇需要报考公务员、购买免税车、落转户口
◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
办理(uoft毕业证书)加拿大多伦多大学毕业证【微信：741003700 】外观非常简单，由纸质材料制成，上面印有校徽、校名、毕业生姓名、专业等信息。
办理(uoft毕业证书)加拿大多伦多大学毕业证【微信：741003700 】格式相对统一，各专业都有相应的模板。通常包括以下部分：
校徽：象征着学校的荣誉和传承。
校名:学校英文全称
授予学位：本部分将注明获得的具体学位名称。
毕业生姓名：这是最重要的信息之一，标志着该证书是由特定人员获得的。
颁发日期：这是毕业正式生效的时间，也代表着毕业生学业的结束。
其他信息：根据不同的专业和学位，可能会有一些特定的信息或章节。
办理(uoft毕业证书)加拿大多伦多大学毕业证【微信：741003700 】价值很高，需要妥善保管。一般来说，应放置在安全、干燥、防潮的地方，避免长时间暴露在阳光下。如需使用，最好使用复印件而不是原件，以免丢失。
综上所述，办理(uoft毕业证书)加拿大多伦多大学毕业证【微信：741003700 】是证明身份和学历的高价值文件。外观简单庄重，格式统一，包括重要的个人信息和发布日期。对持有人来说，妥善保管是非常重要的。
Object Oriented Analysis and Design - OOAD
This ppt gives detailed description of Object Oriented Analysis and design.
smart pill dispenser is designed to improve medication adherence and safety f...
Smart Pill Dispenser that boosts medication adherence, empowers patients, enables remote monitoring, enhances safety, reduces healthcare costs, and contributes to data-driven healthcare improvements
一比一原版(osu毕业证书)美国俄勒冈州立大学毕业证如何办理
原版一模一样【微信：741003700 】【(osu毕业证书)美国俄勒冈州立大学毕业证成绩单】【微信：741003700 】学位证，留信认证（真实可查，永久存档）原件一模一样纸张工艺/offer、雅思、外壳等材料/诚信可靠,可直接看成品样本，帮您解决无法毕业带来的各种难题！外壳，原版制作，诚信可靠，可直接看成品样本。行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备。十五年致力于帮助留学生解决难题，包您满意。
本公司拥有海外各大学样板无数，能完美还原。
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微741003700
【主营项目】
一.毕业证【q微741003700】成绩单、使馆认证、教育部认证、雅思托福成绩单、学生卡等！
二.真实使馆公证(即留学回国人员证明,不成功不收费)
三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
◇在校期间，因各种原因未能顺利毕业……拿不到官方毕业证【q/微741003700】
◇面对父母的压力，希望尽快拿到；
◇不清楚认证流程以及材料该如何准备；
◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
◇需要报考公务员、购买免税车、落转户口
◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
办理(osu毕业证书)美国俄勒冈州立大学毕业证【微信：741003700 】外观非常简单，由纸质材料制成，上面印有校徽、校名、毕业生姓名、专业等信息。
办理(osu毕业证书)美国俄勒冈州立大学毕业证【微信：741003700 】格式相对统一，各专业都有相应的模板。通常包括以下部分：
校徽：象征着学校的荣誉和传承。
校名:学校英文全称
授予学位：本部分将注明获得的具体学位名称。
毕业生姓名：这是最重要的信息之一，标志着该证书是由特定人员获得的。
颁发日期：这是毕业正式生效的时间，也代表着毕业生学业的结束。
其他信息：根据不同的专业和学位，可能会有一些特定的信息或章节。
办理(osu毕业证书)美国俄勒冈州立大学毕业证【微信：741003700 】价值很高，需要妥善保管。一般来说，应放置在安全、干燥、防潮的地方，避免长时间暴露在阳光下。如需使用，最好使用复印件而不是原件，以免丢失。
综上所述，办理(osu毕业证书)美国俄勒冈州立大学毕业证【微信：741003700 】是证明身份和学历的高价值文件。外观简单庄重，格式统一，包括重要的个人信息和发布日期。对持有人来说，妥善保管是非常重要的。
一比一原版(爱大毕业证书)爱荷华大学毕业证如何办理
原版一模一样【微信：741003700 】【(爱大毕业证书)爱荷华大学毕业证成绩单】【微信：741003700 】学位证，留信认证（真实可查，永久存档）原件一模一样纸张工艺/offer、雅思、外壳等材料/诚信可靠,可直接看成品样本，帮您解决无法毕业带来的各种难题！外壳，原版制作，诚信可靠，可直接看成品样本。行业标杆！精益求精，诚心合作，真诚制作！多年品质 ,按需精细制作，24小时接单,全套进口原装设备。十五年致力于帮助留学生解决难题，包您满意。
本公司拥有海外各大学样板无数，能完美还原。
1:1完美还原海外各大学毕业材料上的工艺：水印，阴影底纹，钢印LOGO烫金烫银，LOGO烫金烫银复合重叠。文字图案浮雕、激光镭射、紫外荧光、温感、复印防伪等防伪工艺。材料咨询办理、认证咨询办理请加学历顾问Q/微741003700
【主营项目】
一.毕业证【q微741003700】成绩单、使馆认证、教育部认证、雅思托福成绩单、学生卡等！
二.真实使馆公证(即留学回国人员证明,不成功不收费)
三.真实教育部学历学位认证（教育部存档！教育部留服网站永久可查）
四.办理各国各大学文凭(一对一专业服务,可全程监控跟踪进度)
如果您处于以下几种情况：
◇在校期间，因各种原因未能顺利毕业……拿不到官方毕业证【q/微741003700】
◇面对父母的压力，希望尽快拿到；
◇不清楚认证流程以及材料该如何准备；
◇回国时间很长，忘记办理；
◇回国马上就要找工作，办给用人单位看；
◇企事业单位必须要求办理的
◇需要报考公务员、购买免税车、落转户口
◇申请留学生创业基金
留信网认证的作用:
1:该专业认证可证明留学生真实身份
2:同时对留学生所学专业登记给予评定
3:国家专业人才认证中心颁发入库证书
4:这个认证书并且可以归档倒地方
5:凡事获得留信网入网的信息将会逐步更新到个人身份内，将在公安局网内查询个人身份证信息后，同步读取人才网入库信息
6:个人职称评审加20分
7:个人信誉贷款加10分
8:在国家人才网主办的国家网络招聘大会中纳入资料，供国家高端企业选择人才
办理(爱大毕业证书)爱荷华大学毕业证【微信：741003700 】外观非常简单，由纸质材料制成，上面印有校徽、校名、毕业生姓名、专业等信息。
办理(爱大毕业证书)爱荷华大学毕业证【微信：741003700 】格式相对统一，各专业都有相应的模板。通常包括以下部分：
校徽：象征着学校的荣誉和传承。
校名:学校英文全称
授予学位：本部分将注明获得的具体学位名称。
毕业生姓名：这是最重要的信息之一，标志着该证书是由特定人员获得的。
颁发日期：这是毕业正式生效的时间，也代表着毕业生学业的结束。
其他信息：根据不同的专业和学位，可能会有一些特定的信息或章节。
办理(爱大毕业证书)爱荷华大学毕业证【微信：741003700 】价值很高，需要妥善保管。一般来说，应放置在安全、干燥、防潮的地方，避免长时间暴露在阳光下。如需使用，最好使用复印件而不是原件，以免丢失。
综上所述，办理(爱大毕业证书)爱荷华大学毕业证【微信：741003700 】是证明身份和学历的高价值文件。外观简单庄重，格式统一，包括重要的个人信息和发布日期。对持有人来说，妥善保管是非常重要的。
Tools & Techniques for Commissioning and Maintaining PV Systems W-Animations ...
Join us for this solutions-based webinar on the tools and techniques for commissioning and maintaining PV Systems. In this session, we'll review the process of building and maintaining a solar array, starting with installation and commissioning, then reviewing operations and maintenance of the system. This course will review insulation resistance testing, I-V curve testing, earth-bond continuity, ground resistance testing, performance tests, visual inspections, ground and arc fault testing procedures, and power quality analysis.
Fluke Solar Application Specialist Will White is presenting on this engaging topic:
Will has worked in the renewable energy industry since 2005, first as an installer for a small east coast solar integrator before adding sales, design, and project management to his skillset. In 2022, Will joined Fluke as a solar application specialist, where he supports their renewable energy testing equipment like IV-curve tracers, electrical meters, and thermal imaging cameras. Experienced in wind power, solar thermal, energy storage, and all scales of PV, Will has primarily focused on residential and small commercial systems. He is passionate about implementing high-quality, code-compliant installation techniques.
Software Engineering and Project Management - Introduction, Modeling Concepts...
Introduction, Modeling Concepts and Class Modeling: What is Object orientation? What is OO development? OO Themes; Evidence for usefulness of OO development; OO modeling history. Modeling
as Design technique: Modeling, abstraction, The Three models. Class Modeling: Object and Class Concept, Link and associations concepts, Generalization and Inheritance, A sample class model, Navigation of class models, and UML diagrams
Building the Analysis Models: Requirement Analysis, Analysis Model Approaches, Data modeling Concepts, Object Oriented Analysis, Scenario-Based Modeling, Flow-Oriented Modeling, class Based Modeling, Creating a Behavioral Model.
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10 이중포인터를이용한삽입
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