1)let event 1 is purcahse if item A after the campaign and 2 is be.pdf

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1) let event 1 is purcahse if item A after the campaign and 2 is before the campain so, Ho : p1 > p2 Ha : p1 =< p2 .. so, 1: before campaign n1 = (28+82) = 110 p1 = 28/(28+82) = 0.2545 so, 2: after campaign n2 = (45+93) = 138 p1 = 45/(45+93) = 0.3261 now, pooled sample proportion= p = (p1*n1 + p2*n2) /(n1+n2) ==> p = (0.2545*110+0.3261*138)/(110+138) ==> p= 0.2943 so, standard Error= SE = sqrt( p*(1-p)*(1/n1+1/n2) ) ==> SE = sqrt(0.2943*(1-0.2943)*(1/110+1/138)) ==> SE = 0.05825 so, test statistics : z = (p1-p2)/SE z = (0.2545-0.3261) z= -0.0716 now, P-value = P(Z< z) = P(Z< -0.0716) = 0.4715 significance level = 1-0.95 = 0.05 Interpretation As the P-value = 0.4715 > significance level=0.05 null hypothesis can\'t be rejected. so, yes, the campaign was effective 2) for, Etruscan Head sizes n1= 84 mu1 = 143.774 sd1 = 5.935 for Italian Head sizes n2 = 70 mu2 = 132.443 sd2 = 5.7 so, standard error of the difference = S = sqrt(sd1^2/n1 + sd2^2/n2 ) ==> S = sqrt(5.935^2/84+5.7^2/70) ==> S =0.94 so, degree of freedom = df = (n1-1)+(n2-1) = 84-1+70-1 = 152 so, from t-table for df=152 and CI = 99% t =2.609 so, CI lower limit = (mu1-mu2)-t*S = (143.774-132.443)-2.609*0.94 = 8.878 CI upper limit = (mu1-mu2)+t*S = (143.774-132.443)+2.609*0.94 = 13.783 CI = ( 8.878 to 13.783 ) Solution 1) let event 1 is purcahse if item A after the campaign and 2 is before the campain so, Ho : p1 > p2 Ha : p1 =< p2 .. so, 1: before campaign n1 = (28+82) = 110 p1 = 28/(28+82) = 0.2545 so, 2: after campaign n2 = (45+93) = 138 p1 = 45/(45+93) = 0.3261 now, pooled sample proportion= p = (p1*n1 + p2*n2) /(n1+n2) ==> p = (0.2545*110+0.3261*138)/(110+138) ==> p= 0.2943 so, standard Error= SE = sqrt( p*(1-p)*(1/n1+1/n2) ) ==> SE = sqrt(0.2943*(1-0.2943)*(1/110+1/138)) ==> SE = 0.05825 so, test statistics : z = (p1-p2)/SE z = (0.2545-0.3261) z= -0.0716 now, P-value = P(Z< z) = P(Z< -0.0716) = 0.4715 significance level = 1-0.95 = 0.05 Interpretation As the P-value = 0.4715 > significance level=0.05 null hypothesis can\'t be rejected. so, yes, the campaign was effective 2) for, Etruscan Head sizes n1= 84 mu1 = 143.774 sd1 = 5.935 for Italian Head sizes n2 = 70 mu2 = 132.443 sd2 = 5.7 so, standard error of the difference = S = sqrt(sd1^2/n1 + sd2^2/n2 ) ==> S = sqrt(5.935^2/84+5.7^2/70) ==> S =0.94 so, degree of freedom = df = (n1-1)+(n2-1) = 84-1+70-1 = 152 so, from t-table for df=152 and CI = 99% t =2.609 so, CI lower limit = (mu1-mu2)-t*S = (143.774-132.443)-2.609*0.94 = 8.878 CI upper limit = (mu1-mu2)+t*S = (143.774-132.443)+2.609*0.94 = 13.783 CI = ( 8.878 to 13.783 ).

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test statistics :
z = (p1-p2)/SE
z = (0.2545-0.3261)
z= -0.0716
now,
P-value = P(Z< z) = P(Z< -0.0716) = 0.4715
significance level = 1-0.95 = 0.05
Interpretation
As the P-value = 0.4715 > significance level=0.05 null hypothesis can't be rejected.
so,
yes, the campaign was effective
2)
for,
Etruscan Head sizes
n1= 84
mu1 = 143.774
sd1 = 5.935
for
Italian Head sizes
n2 = 70

mu2 = 132.443
sd2 = 5.7
so,
standard error of the difference = S = sqrt(sd1^2/n1 + sd2^2/n2 )
==> S = sqrt(5.935^2/84+5.7^2/70)
==> S =0.94
so,
degree of freedom = df = (n1-1)+(n2-1) = 84-1+70-1 = 152
so, from t-table for df=152 and CI = 99%
t =2.609
so,
CI lower limit = (mu1-mu2)-t*S = (143.774-132.443)-2.609*0.94 = 8.878
CI upper limit = (mu1-mu2)+t*S = (143.774-132.443)+2.609*0.94 = 13.783
CI = ( 8.878 to 13.783 )
Solution
1)
let event 1 is purcahse if item A after the campaign and 2 is before the campain

so,
Ho : p1 > p2
Ha : p1 =< p2 ..
so,
1: before campaign
n1 = (28+82) = 110
p1 = 28/(28+82) = 0.2545
so, 2: after campaign
n2 = (45+93) = 138
p1 = 45/(45+93) = 0.3261
now,
pooled sample proportion= p = (p1*n1 + p2*n2) /(n1+n2)
==> p = (0.2545*110+0.3261*138)/(110+138)
==> p= 0.2943
so,
standard Error= SE = sqrt( p*(1-p)*(1/n1+1/n2) )
==> SE = sqrt(0.2943*(1-0.2943)*(1/110+1/138))
==> SE = 0.05825
so,
test statistics :
z = (p1-p2)/SE
z = (0.2545-0.3261)
z= -0.0716

now,
P-value = P(Z< z) = P(Z< -0.0716) = 0.4715
significance level = 1-0.95 = 0.05
Interpretation
As the P-value = 0.4715 > significance level=0.05 null hypothesis can't be rejected.
so,
yes, the campaign was effective
2)
for,
Etruscan Head sizes
n1= 84
mu1 = 143.774
sd1 = 5.935
for
Italian Head sizes
n2 = 70
mu2 = 132.443
sd2 = 5.7

so,
standard error of the difference = S = sqrt(sd1^2/n1 + sd2^2/n2 )
==> S = sqrt(5.935^2/84+5.7^2/70)
==> S =0.94
so,
degree of freedom = df = (n1-1)+(n2-1) = 84-1+70-1 = 152
so, from t-table for df=152 and CI = 99%
t =2.609
so,
CI lower limit = (mu1-mu2)-t*S = (143.774-132.443)-2.609*0.94 = 8.878
CI upper limit = (mu1-mu2)+t*S = (143.774-132.443)+2.609*0.94 = 13.783
CI = ( 8.878 to 13.783 )

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1A) One of the best explanation for why we conform/obey in the real world is, generally people are concerned over the thinking of other people. They tend to behave in such manner that they can correlate with others in properties like behaviors, belief, attitudes and feelings. 1B) Participants obey the researcher is also based on the above explanations. The participants obey because the researchers have more knowledge and information than them and the other fact is the participants have to be in norms of research, institute or centre. So they have to obey researchers. 2A) No; such obedience is not always beneficial. There are many examples where pupils are tending to obey the researcher in such a way that they can even forget the ethical rules. Obeying societal norms and expectations sometimes create disturbing behavior. Society is made of people so the welfare of people will create welfare society. 2B) Deviant behavior is the behavior which denies the societal norms and expectations. They are not harmful always. The criminal mind from deviant behavior can be created if it is from abnormal, inappropriate or dysfunctional mental processes. This is relied to individual’s personality. Solution 1A) One of the best explanation for why we conform/obey in the real world is, generally people are concerned over the thinking of other people. They tend to behave in such manner that they can correlate with others in properties like behaviors, belief, attitudes and feelings. 1B) Participants obey the researcher is also based on the above explanations. The participants obey because the researchers have more knowledge and information than them and the other fact is the participants have to be in norms of research, institute or centre. So they have to obey researchers. 2A) No; such obedience is not always beneficial. There are many examples where pupils are tending to obey the researcher in such a way that they can even forget the ethical rules. Obeying societal norms and expectations sometimes create disturbing behavior. Society is made of people so the welfare of people will create welfare society. 2B) Deviant behavior is the behavior which denies the societal norms and expectations. They are not harmful always. The criminal mind from deviant behavior can be created if it is from abnormal, inappropriate or dysfunctional mental processes. This is relied to individual’s personality..

1A) One of the best explanation for why we conformobey in the real .pdf

singhanubhav1234

1. Water supplies are treated with chlorine to kill pathogens. Chlorine reacts well with many other chemicals because it is a strong oxidant. What does this mean? Answer: Option 4 Because chlorine is strongly electronegative and needs one electron to fill its outer shell, it strongly pulls electrons from other substances. Explanation: Chlorine is known to be one of the most electronegative atoms of the periodic table ( with a value of approx 3 in the pauling scale). This means that it has a very strong tendancy to attract electron. Also Chlorine (Atomic number 17, configuration of electrons 2, 8, 7) has seven electrons in the valence shell so it needs one electron to fill its outer shell . 2. Tests to monitor water safety often report the number of fecal coliform bacteria found in samples. Which of the following statements accurately reflects water safety recommendations based upon fecal coliform levels? Answer : Here by mistake the first two options are exactly same, one of them probably needs to be corrected to If the level of fecal coliform bacteria is low, then the water is safe for drinking and recreational purposes. This option will be the correct option. Explanation: Fecal coliforms are bacteria which indicate that the water might have been exposed to fecal matter. They are an excellant proxy to make sure that the water doesn\'t contain any human pathogens. So if the Fecal coliforms count is low it indicates that the chances of water containing any human pathogen is also low and therefore it can be used for drinking and recreational purposes 3. When an individual has severe diarrhea, as can occur with cholera, rehydration solution with glucose, salt, sodium bicarbonate, and potassium chloride can be administered. Why is it important to use a solution like this rather than simply giving the individual water? Answer: Option 1: Diarrhea causes the loss of electrolytes, not just fluids, and it is important to replace the electrolytes as well. Glucose is transported into intestinal epithelial cells, along with sodium, by symporters. It is included as well because glucose is not sufficiently absorbed while sodium is lacking. Explanation: The answer is self explanatory 4.Vibrio cholerae is a human pathogen that causes cholera. It has an unusual shape distinctive of its genus. Considering that it does not have one of the most common bacterial shapes, what is the shape of this species? Answer Option 2 - Curved rod Explanation:Vibrio\'s unique curved rod shape is also called the \"comma\" shape. Just helps to remember it more easily 5. Legionella pneumophilia can grow in water and is transmitted in aerosols. Which of these has an infection NOT been linked to? Answer option 4 -ocean water 6. On a global scale, the most important waterborne bacterial pathogens are __________. Answer Option 4 -Vibrio cholerae and Salmonella enterica serovar Typhi 7. Food that is heavily salted or candied does not need to be refrigerated. Why not? Answer option 2 -E.

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1)let event 1 is purcahse if item A after the campaign and 2 is be.pdf

1. 1) let event 1 is purcahse if item A after the campaign and 2 is before the campain so, Ho : p1 > p2 Ha : p1 =< p2 .. so, 1: before campaign n1 = (28+82) = 110 p1 = 28/(28+82) = 0.2545 so, 2: after campaign n2 = (45+93) = 138 p1 = 45/(45+93) = 0.3261 now, pooled sample proportion= p = (p1*n1 + p2*n2) /(n1+n2) ==> p = (0.2545*110+0.3261*138)/(110+138) ==> p= 0.2943 so, standard Error= SE = sqrt( p*(1-p)*(1/n1+1/n2) ) ==> SE = sqrt(0.2943*(1-0.2943)*(1/110+1/138)) ==> SE = 0.05825 so,

2. test statistics : z = (p1-p2)/SE z = (0.2545-0.3261) z= -0.0716 now, P-value = P(Z< z) = P(Z< -0.0716) = 0.4715 significance level = 1-0.95 = 0.05 Interpretation As the P-value = 0.4715 > significance level=0.05 null hypothesis can't be rejected. so, yes, the campaign was effective 2) for, Etruscan Head sizes n1= 84 mu1 = 143.774 sd1 = 5.935 for Italian Head sizes n2 = 70

3. mu2 = 132.443 sd2 = 5.7 so, standard error of the difference = S = sqrt(sd1^2/n1 + sd2^2/n2 ) ==> S = sqrt(5.935^2/84+5.7^2/70) ==> S =0.94 so, degree of freedom = df = (n1-1)+(n2-1) = 84-1+70-1 = 152 so, from t-table for df=152 and CI = 99% t =2.609 so, CI lower limit = (mu1-mu2)-t*S = (143.774-132.443)-2.609*0.94 = 8.878 CI upper limit = (mu1-mu2)+t*S = (143.774-132.443)+2.609*0.94 = 13.783 CI = ( 8.878 to 13.783 ) Solution 1) let event 1 is purcahse if item A after the campaign and 2 is before the campain

4. so, Ho : p1 > p2 Ha : p1 =< p2 .. so, 1: before campaign n1 = (28+82) = 110 p1 = 28/(28+82) = 0.2545 so, 2: after campaign n2 = (45+93) = 138 p1 = 45/(45+93) = 0.3261 now, pooled sample proportion= p = (p1*n1 + p2*n2) /(n1+n2) ==> p = (0.2545*110+0.3261*138)/(110+138) ==> p= 0.2943 so, standard Error= SE = sqrt( p*(1-p)*(1/n1+1/n2) ) ==> SE = sqrt(0.2943*(1-0.2943)*(1/110+1/138)) ==> SE = 0.05825 so, test statistics : z = (p1-p2)/SE z = (0.2545-0.3261) z= -0.0716

5. now, P-value = P(Z< z) = P(Z< -0.0716) = 0.4715 significance level = 1-0.95 = 0.05 Interpretation As the P-value = 0.4715 > significance level=0.05 null hypothesis can't be rejected. so, yes, the campaign was effective 2) for, Etruscan Head sizes n1= 84 mu1 = 143.774 sd1 = 5.935 for Italian Head sizes n2 = 70 mu2 = 132.443 sd2 = 5.7

6. so, standard error of the difference = S = sqrt(sd1^2/n1 + sd2^2/n2 ) ==> S = sqrt(5.935^2/84+5.7^2/70) ==> S =0.94 so, degree of freedom = df = (n1-1)+(n2-1) = 84-1+70-1 = 152 so, from t-table for df=152 and CI = 99% t =2.609 so, CI lower limit = (mu1-mu2)-t*S = (143.774-132.443)-2.609*0.94 = 8.878 CI upper limit = (mu1-mu2)+t*S = (143.774-132.443)+2.609*0.94 = 13.783 CI = ( 8.878 to 13.783 )

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