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PHYSICS – Speed, velocity and
acceleration
LEARNING
OBJECTIVES
1.2 Motion
Core
• Define speed and calculate average
speed from total time / total distance
• Plot and interpret a speed-time graph or
a distance- time graph
• Recognise from the shape of a speed-
time graph when a body is
– at rest
– moving with constant speed
– moving with changing speed
• Calculate the area under a speed-time
graph to work out the distance travelled
for motion with constant acceleration
• Demonstrate understanding that
acceleration and deceleration are related
to changing speed including qualitative
analysis of the gradient of a speed-time
graph
• State that the acceleration of free fall
for a body near to the Earth is constant
Supplement
• Distinguish between speed and velocity
• Define and calculate acceleration using
time taken change of velocity
• Calculate speed from the gradient of a
distance-time graph
• Calculate acceleration from the gradient
of a speed-time graph
• Recognise linear motion for which the
acceleration is constant
• Recognise motion for which the
acceleration is not constant
• Understand deceleration as a negative
acceleration
• Describe qualitatively the motion of
bodies falling in a uniform gravitational field
with and without air resistance (including
reference to terminal velocity)
A
Average speed+= Distance moved
Time taken
A
Average speed+= Distance moved
Time taken
Distance measured in metres (m)
Time measured in seconds (s)
Speed - metres per second (m/s)
A
Average speed+= Distance moved
Time taken
Example:
Car travels 50m
time 2s
speed = 50/2 = 25 m/s
25 m.s-1
So if that’s
speed, what is
velocity?
Velocity is speed in a given
direction.
Velocity is speed in a given
direction.
Velocity is 25m/s due west
Example:
Example:
Example:
Example:
Cyclist +10m/s to the right
Example:
Cyclist +10m/s to the right
-10m/s to the left
What’s your
vector Victor?
What’s your
vector Victor?
Quantities such as
velocity are called
vectors because they
have size and direction
Acceleration is the rate at which an
object increases speed or velocity.
Acceleration is the rate at which an
object increases speed or velocity.
Acceleration = change in velocity
time taken
Acceleration is the rate at which an
object increases speed or velocity.
Acceleration = change in velocity
time taken
Also written as: a = v - u
t
Acceleration is the rate at which an
object increases speed or velocity.
Acceleration = change in velocity
time taken
Velocity measured in m/s
Time measured in s
Acceleration measured in m/s/s or m/s2
Example: a drag car increases its
velocity from zero to 60m/s in 3s.
a = v - u
t
Example: a drag car increases its
velocity from zero to 60m/s in 3s.
a = v - u
t
a = 60 – 0
3
Example: a drag car increases its
velocity from zero to 60m/s in 3s.
a = v - u
t
a = 60 – 0
3
a = 60 = 20m/s-2
3
Example: a drag car increases its
velocity from zero to 60m/s in 3s.
a = v - u
t
a = 60 – 0
3
a = 60 = 20m/s-2
3
Don’t forget that
acceleration is a vector
– it has size and
direction
Deceleration (retardation)
Deceleration
is negative
acceleration –
the object is
slowing down.
Eg. – 4m/s2
Constant acceleration example
A B
6s
Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of
4m/s2. What is the velocity when it passes point B?
Constant acceleration example
A B
6s
Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of
4m/s2. What is the velocity when it passes point B?
Solution: car gains 4m/s of velocity every second. In 6s
it gains an extra 24m/s.
Constant acceleration example
A B
6s
Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of
4m/s2. What is the velocity when it passes point B?
Solution: car gains 4m/s of velocity every second. In 6s
it gains an extra 24m/s.
Final velocity = initial velocity + extra velocity
Constant acceleration example
A B
6s
Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of
4m/s2. What is the velocity when it passes point B?
Solution: car gains 4m/s of velocity every second. In 6s
it gains an extra 24m/s.
Final velocity = initial velocity + extra velocity
Final velocity = 10 + 24 = 34m/s
Motion graphs
Travelling at constant speed
Travelling at constant speed
Stationary
Travelling at constant speed
Stationary
Travelling at constant
speed
Speed = distance
time
Speed = distance
time
Speed = distance
time
Speed = distance
time
Speed = 8 = 1 km/h
8
Acceleration from velocity : time graph
Acceleration from velocity : time graph
Steady acceleration
Acceleration from velocity : time graph
Steady acceleration
Steady velocity
Acceleration from velocity : time graph
Steady acceleration
Steady velocity
Steady deceleration
Acceleration from velocity : time graph
Acceleration = V - U
t
Acceleration from velocity : time graph
Acceleration = V - U
t
Acceleration from velocity : time graph
Acceleration = 3 – 0 / 2
= 1.5 m/s/s (m.s-2)
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
Acceleration can be calculated by the gradient of a velocity:time graph. (Remember
gradient is the difference up divided by the difference across)
Calculate the acceleration for each
of the 4 sections of the graph.
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
Acceleration can be calculated by the gradient of a velocity:time graph. (Remember
gradient is the difference up divided by the difference across)
Calculate the acceleration for each
of the 4 sections of the graph.
Acceleration = V - U
t
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
Acceleration can be calculated by the gradient of a velocity:time graph. (Remember
gradient is the difference up divided by the difference across)
Calculate the acceleration for each
of the 4 sections of the graph.
Acceleration = 40 - 0 = 4m/s2
10
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
Acceleration can be calculated by the gradient of a velocity:time graph. (Remember
gradient is the difference up divided by the difference across)
Calculate the acceleration for each
of the 4 sections of the graph.
Acceleration = 0 (no change in
velocity)
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
Acceleration can be calculated by the gradient of a velocity:time graph. (Remember
gradient is the difference up divided by the difference across)
Calculate the acceleration for each
of the 4 sections of the graph.
Acceleration = 20 - 0 = 2m/s2
10
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
Acceleration can be calculated by the gradient of a velocity:time graph. (Remember
gradient is the difference up divided by the difference across)
Calculate the acceleration for each
of the 4 sections of the graph.
Acceleration = 0 - 60 = -3m/s2
20
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
On a velocity – time (or speed – time) graph, the area under the line is numerically
equal to the distance travelled.
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
On a velocity – time (or speed – time) graph, the area under the line is numerically
equal to the distance travelled.
Remember that the area of a
triangle is ½ x base x height.
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
On a velocity – time (or speed – time) graph, the area under the line is numerically
equal to the distance travelled.
Remember that the area of a
triangle is ½ x base x height.
Area =
200m2
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
On a velocity – time (or speed – time) graph, the area under the line is numerically
equal to the distance travelled.
Remember that the area of a
triangle is ½ x base x height.
Area =
200m2
Area =
400m2
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
On a velocity – time (or speed – time) graph, the area under the line is numerically
equal to the distance travelled.
Remember that the area of a
triangle is ½ x base x height.
Area =
200m2
Area =
400m2
Area =
400m2
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
On a velocity – time (or speed – time) graph, the area under the line is numerically
equal to the distance travelled.
Remember that the area of a
triangle is ½ x base x height.
Area =
200m2
Area =
400m2
Area =
400m2
Area =
100m2
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
On a velocity – time (or speed – time) graph, the area under the line is numerically
equal to the distance travelled.
Remember that the area of a
triangle is ½ x base x height.
Area =
200m2
Area =
400m2
Area =
400m2
Area =
100m2
Area =
600m2
Velocity-time graphs
80
60
40
20
0
10 20 30 40 50
Velocity
m/s
Time/s
On a velocity – time (or speed – time) graph, the area under the line is numerically
equal to the distance travelled.
Remember that the area of a
triangle is ½ x base x height.
Area =
200m2
Area =
400m2
Area =
400m2
Area =
100m2
Area =
600m2
The total distance travelled = 200 + 400 + 400 + 100 + 600 = 1700m
Free fall
Acceleration of free fall (g)
Which object
will hit the
ground first?
Acceleration of free fall (g)
Which object
will hit the
ground first?
Obviously the
brick (because the
feather is slowed
much more by the
air)
Acceleration of free fall (g)
No air
resistance,
objects both
fall with the
same downward
acceleration.
In air
In a
vacuum
Acceleration of free fall (g)
No air
resistance,
objects both
fall with the
same downward
acceleration.
In air
In a
vacuum
Acceleration of
free fall =
9.8m/s2
Given the
symbol ‘g’
Acceleration of free fall (g)
No air
resistance,
objects both
fall with the
same downward
acceleration.
In air
In a
vacuum
Acceleration of
free fall =
9.8m/s2
Given the
symbol ‘g’
Acceleration and gravity
Acceleration and gravity
Falling objects
accelerate towards
the ground at
10m/s2 due to
gravity. The force
of gravity always
acts towards the
centre of the
Earth.
The atmosphere
creates an upward
force that slows
down falling
objects. This is
known as air
resistance or drag.
Acceleration and gravity
Falling objects
accelerate towards
the ground at
10m/s2 due to
gravity. The force
of gravity always
acts towards the
centre of the
Earth.
The atmosphere
creates an upward
force that slows
down falling
objects. This is
known as air
resistance or drag.
Acceleration and gravity
Falling objects
accelerate towards
the ground at
10m/s2 due to
gravity. The force
of gravity always
acts towards the
centre of the
Earth.
The atmosphere
creates an upward
force that slows
down falling
objects. This is
known as air
resistance or drag.
The larger the surface area of the
object, the larger the drag force
Acceleration and gravity
Speed
(m/s)
Time (s)
Drag
Weight
A
At first the force of
gravity is larger than the
drag force, so the object
accelerates.
Acceleration and gravity
Speed
(m/s)
Time (s)
Drag
Weight
B As speed increases, so
does drag; the acceleration
decreases
Acceleration and gravity
Speed
(m/s)
Time (s)
Drag
Weight
C
When drag equals the
force due to gravity there
is no resultant force and
the acceleration is zero.
The object continues at
terminal velocity.
Terminal velocity
LEARNING
OBJECTIVES
1.2 Motion
Core
• Define speed and calculate average
speed from total time / total distance
• Plot and interpret a speed-time graph or
a distance- time graph
• Recognise from the shape of a speed-
time graph when a body is
– at rest
– moving with constant speed
– moving with changing speed
• Calculate the area under a speed-time
graph to work out the distance travelled
for motion with constant acceleration
• Demonstrate understanding that
acceleration and deceleration are related
to changing speed including qualitative
analysis of the gradient of a speed-time
graph
• State that the acceleration of free fall
for a body near to the Earth is constant
Supplement
• Distinguish between speed and velocity
• Define and calculate acceleration using
time taken change of velocity
• Calculate speed from the gradient of a
distance-time graph
• Calculate acceleration from the gradient
of a speed-time graph
• Recognise linear motion for which the
acceleration is constant
• Recognise motion for which the
acceleration is not constant
• Understand deceleration as a negative
acceleration
• Describe qualitatively the motion of
bodies falling in a uniform gravitational field
with and without air resistance (including
reference to terminal velocity)
PHYSICS – Speed, velocity and
acceleration
(a) The speed decreases/stone decelerates to
rest/zero at 1.25 s. The speed then
increases/stone accelerates (in opposite
direction)
Speed, velocity and acceleration

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Speed, velocity and acceleration

  • 1. PHYSICS – Speed, velocity and acceleration
  • 2. LEARNING OBJECTIVES 1.2 Motion Core • Define speed and calculate average speed from total time / total distance • Plot and interpret a speed-time graph or a distance- time graph • Recognise from the shape of a speed- time graph when a body is – at rest – moving with constant speed – moving with changing speed • Calculate the area under a speed-time graph to work out the distance travelled for motion with constant acceleration • Demonstrate understanding that acceleration and deceleration are related to changing speed including qualitative analysis of the gradient of a speed-time graph • State that the acceleration of free fall for a body near to the Earth is constant Supplement • Distinguish between speed and velocity • Define and calculate acceleration using time taken change of velocity • Calculate speed from the gradient of a distance-time graph • Calculate acceleration from the gradient of a speed-time graph • Recognise linear motion for which the acceleration is constant • Recognise motion for which the acceleration is not constant • Understand deceleration as a negative acceleration • Describe qualitatively the motion of bodies falling in a uniform gravitational field with and without air resistance (including reference to terminal velocity)
  • 3. A Average speed+= Distance moved Time taken
  • 4. A Average speed+= Distance moved Time taken Distance measured in metres (m) Time measured in seconds (s) Speed - metres per second (m/s)
  • 5. A Average speed+= Distance moved Time taken Example: Car travels 50m time 2s speed = 50/2 = 25 m/s 25 m.s-1
  • 6. So if that’s speed, what is velocity?
  • 7. Velocity is speed in a given direction.
  • 8. Velocity is speed in a given direction. Velocity is 25m/s due west
  • 13. Example: Cyclist +10m/s to the right -10m/s to the left
  • 15. What’s your vector Victor? Quantities such as velocity are called vectors because they have size and direction
  • 16. Acceleration is the rate at which an object increases speed or velocity.
  • 17. Acceleration is the rate at which an object increases speed or velocity. Acceleration = change in velocity time taken
  • 18. Acceleration is the rate at which an object increases speed or velocity. Acceleration = change in velocity time taken Also written as: a = v - u t
  • 19. Acceleration is the rate at which an object increases speed or velocity. Acceleration = change in velocity time taken Velocity measured in m/s Time measured in s Acceleration measured in m/s/s or m/s2
  • 20. Example: a drag car increases its velocity from zero to 60m/s in 3s. a = v - u t
  • 21. Example: a drag car increases its velocity from zero to 60m/s in 3s. a = v - u t a = 60 – 0 3
  • 22. Example: a drag car increases its velocity from zero to 60m/s in 3s. a = v - u t a = 60 – 0 3 a = 60 = 20m/s-2 3
  • 23. Example: a drag car increases its velocity from zero to 60m/s in 3s. a = v - u t a = 60 – 0 3 a = 60 = 20m/s-2 3 Don’t forget that acceleration is a vector – it has size and direction
  • 24. Deceleration (retardation) Deceleration is negative acceleration – the object is slowing down. Eg. – 4m/s2
  • 25. Constant acceleration example A B 6s Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of 4m/s2. What is the velocity when it passes point B?
  • 26. Constant acceleration example A B 6s Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of 4m/s2. What is the velocity when it passes point B? Solution: car gains 4m/s of velocity every second. In 6s it gains an extra 24m/s.
  • 27. Constant acceleration example A B 6s Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of 4m/s2. What is the velocity when it passes point B? Solution: car gains 4m/s of velocity every second. In 6s it gains an extra 24m/s. Final velocity = initial velocity + extra velocity
  • 28. Constant acceleration example A B 6s Car passes point A with a velocity of 10m/s. It has a steady (constant) acceleration of 4m/s2. What is the velocity when it passes point B? Solution: car gains 4m/s of velocity every second. In 6s it gains an extra 24m/s. Final velocity = initial velocity + extra velocity Final velocity = 10 + 24 = 34m/s
  • 30.
  • 32. Travelling at constant speed Stationary
  • 33. Travelling at constant speed Stationary Travelling at constant speed
  • 37. Speed = distance time Speed = 8 = 1 km/h 8
  • 39. Acceleration from velocity : time graph Steady acceleration
  • 40. Acceleration from velocity : time graph Steady acceleration Steady velocity
  • 41. Acceleration from velocity : time graph Steady acceleration Steady velocity Steady deceleration
  • 42. Acceleration from velocity : time graph Acceleration = V - U t
  • 43. Acceleration from velocity : time graph Acceleration = V - U t
  • 44. Acceleration from velocity : time graph Acceleration = 3 – 0 / 2 = 1.5 m/s/s (m.s-2)
  • 45. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph.
  • 46. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = V - U t
  • 47. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = 40 - 0 = 4m/s2 10
  • 48. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = 0 (no change in velocity)
  • 49. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = 20 - 0 = 2m/s2 10
  • 50. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s Acceleration can be calculated by the gradient of a velocity:time graph. (Remember gradient is the difference up divided by the difference across) Calculate the acceleration for each of the 4 sections of the graph. Acceleration = 0 - 60 = -3m/s2 20
  • 51. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled.
  • 52. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height.
  • 53. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2
  • 54. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2
  • 55. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2 Area = 400m2
  • 56. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2 Area = 400m2 Area = 100m2
  • 57. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2 Area = 400m2 Area = 100m2 Area = 600m2
  • 58. Velocity-time graphs 80 60 40 20 0 10 20 30 40 50 Velocity m/s Time/s On a velocity – time (or speed – time) graph, the area under the line is numerically equal to the distance travelled. Remember that the area of a triangle is ½ x base x height. Area = 200m2 Area = 400m2 Area = 400m2 Area = 100m2 Area = 600m2 The total distance travelled = 200 + 400 + 400 + 100 + 600 = 1700m
  • 60. Acceleration of free fall (g) Which object will hit the ground first?
  • 61.
  • 62. Acceleration of free fall (g) Which object will hit the ground first? Obviously the brick (because the feather is slowed much more by the air)
  • 63. Acceleration of free fall (g) No air resistance, objects both fall with the same downward acceleration. In air In a vacuum
  • 64. Acceleration of free fall (g) No air resistance, objects both fall with the same downward acceleration. In air In a vacuum Acceleration of free fall = 9.8m/s2 Given the symbol ‘g’
  • 65. Acceleration of free fall (g) No air resistance, objects both fall with the same downward acceleration. In air In a vacuum Acceleration of free fall = 9.8m/s2 Given the symbol ‘g’
  • 67. Acceleration and gravity Falling objects accelerate towards the ground at 10m/s2 due to gravity. The force of gravity always acts towards the centre of the Earth. The atmosphere creates an upward force that slows down falling objects. This is known as air resistance or drag.
  • 68. Acceleration and gravity Falling objects accelerate towards the ground at 10m/s2 due to gravity. The force of gravity always acts towards the centre of the Earth. The atmosphere creates an upward force that slows down falling objects. This is known as air resistance or drag.
  • 69. Acceleration and gravity Falling objects accelerate towards the ground at 10m/s2 due to gravity. The force of gravity always acts towards the centre of the Earth. The atmosphere creates an upward force that slows down falling objects. This is known as air resistance or drag. The larger the surface area of the object, the larger the drag force
  • 70. Acceleration and gravity Speed (m/s) Time (s) Drag Weight A At first the force of gravity is larger than the drag force, so the object accelerates.
  • 71. Acceleration and gravity Speed (m/s) Time (s) Drag Weight B As speed increases, so does drag; the acceleration decreases
  • 72. Acceleration and gravity Speed (m/s) Time (s) Drag Weight C When drag equals the force due to gravity there is no resultant force and the acceleration is zero. The object continues at terminal velocity. Terminal velocity
  • 73. LEARNING OBJECTIVES 1.2 Motion Core • Define speed and calculate average speed from total time / total distance • Plot and interpret a speed-time graph or a distance- time graph • Recognise from the shape of a speed- time graph when a body is – at rest – moving with constant speed – moving with changing speed • Calculate the area under a speed-time graph to work out the distance travelled for motion with constant acceleration • Demonstrate understanding that acceleration and deceleration are related to changing speed including qualitative analysis of the gradient of a speed-time graph • State that the acceleration of free fall for a body near to the Earth is constant Supplement • Distinguish between speed and velocity • Define and calculate acceleration using time taken change of velocity • Calculate speed from the gradient of a distance-time graph • Calculate acceleration from the gradient of a speed-time graph • Recognise linear motion for which the acceleration is constant • Recognise motion for which the acceleration is not constant • Understand deceleration as a negative acceleration • Describe qualitatively the motion of bodies falling in a uniform gravitational field with and without air resistance (including reference to terminal velocity)
  • 74. PHYSICS – Speed, velocity and acceleration
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  • 83. (a) The speed decreases/stone decelerates to rest/zero at 1.25 s. The speed then increases/stone accelerates (in opposite direction)