Velocity, acceleration, free fall ch4 reg

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Velocity, acceleration, free fall ch4 reg

  1. 1. Constant Velocity<br />Chapter 4<br />Section 4.1-4.3 and 4.7 <br />
  2. 2. What do you think?<br />Is the book on your instructor’s desk in motion?<br />Explain your answer.<br />What are some examples of motion?<br />How would you define motion?<br />
  3. 3. One-Dimensional Motion<br />It is the simplest form of motion<br />This is motion that happens in one direction<br />Example:<br />Train on the tracts moving forward or backward<br />
  4. 4. Displacement (x)<br />Change in position<br />Can be positive or negative<br />It describes the direction of motion<br />You will see me use d instead of xfor displacement<br />
  5. 5. Displacement (x)<br />Displacement is not always equal to the distance traveled<br />A gecko runs up a tree from the 20 cm marker to the 80 cm marker, then he retreats to the 50 cm marker?<br />
  6. 6. Displacement (x)<br />In total it traveled 90 cm, however, the displacement is only 30 cm<br />x or d= 50cm- 20cm = 30 cm<br />If the gecko goes back to the start<br />The displacement is zero<br />
  7. 7. Displacement<br />What is the displacement for the objects shown?<br />Answer: 70 cm<br /><ul><li>Answer: -60 cm</li></li></ul><li>Average Velocity<br /><ul><li>Average velocity is displacement divided by the time interval.</li></ul>d df-di<br />Basically velocity is distance/time<br />
  8. 8. Average Velocity<br />The units can be determined from the equation.<br />SI Units: m/s<br />Other Possible Units: mi/h, km/h, cm/year<br />Velocity can be positive or negative but time must always be positive<br />
  9. 9. Average Velocity<br />You travel 370 km west to a friends house. You left at 10am and arrived at 3pm. What was your average velocity?<br />Vavg = d = -370 km<br />Δt 5.0h<br />Vavg= -74 km/h or 74 km/h west<br />
  10. 10. Classroom Practice Problems <br />Joey rides his bike for 15 min with an average velocity of 12.5 km/h, how far did he ride? <br />Vavg = d <br />Δt<br />d = (12.5 km/h) (0.25h)<br />d = 3.125 km<br />
  11. 11. Speed<br />Speed does not include direction while velocity does.<br />Speed uses distance rather than displacement.<br />In a round trip, the average velocity is zero but the average speed is not zero. <br />
  12. 12. Graphs of Motion<br />On a speed-versus-time graph the slope represents speed per time, or acceleration. <br />
  13. 13. Graphs of Motion<br />Equations and tables are not the only way to describe relationships such as velocity and acceleration. <br />Graphs can visually describe relationships. <br />
  14. 14. Graphs of Motion<br />Speed-Versus-Time<br />On a speed-versus-time graph, the speed v of a freely falling object can be plotted on the vertical axis and time t on the horizontal axis. <br />
  15. 15. Graphs of Motion<br /> This particular linearity is called a direct proportion, and we say that time and speed are directly proportional to each other.<br />
  16. 16. Graphs of Motion<br />The curve is a straight line, so its slope is constant. <br />Slope is the vertical change divided by the horizontal change for any part of the line.<br />
  17. 17. Graphs of Motion<br />Distance-Versus-Time<br />When the distance d traveled by a freely falling object is plotted on the vertical axis and time t on the horizontal axis, the result is a curved line. <br />
  18. 18. Graphs of Motion<br />This distance-versus-time graph is parabolic.<br />
  19. 19. Graphs of Motion<br />The relationship between distance and time is nonlinear. <br />The relationship is quadratic and the curve is parabolic—when we double t, we do not double d; we quadruple it. Distance depends on time squared!<br />
  20. 20. Acceleration<br />Chapter 4<br />Sections 4.4- 4.6 <br />
  21. 21. What do you think?<br />Which of the following cars is accelerating?<br />A car shortly after a stoplight turns green<br />A car approaching a red light<br />A car with the cruise control set at 80 km/h<br />A car turning a curve at a constant speed<br />Based on your answers, what is your definition of acceleration?<br />
  22. 22. Acceleration<br />What are the units?<br />SI Units: m/s2<br />Other Units: (km/h)/s or (mi/h)/s<br />Acceleration = 0 implies a constant velocity (or rest)<br />
  23. 23. Acceleration<br />In physics, the term acceleration applies to decreases as well as increases in speed. <br />The brakes of a car can produce produce a large decrease per second in the speed. This is often called deceleration. <br />
  24. 24. Acceleration<br />A car is accelerating whenever there is a change in its state of motion. <br />
  25. 25. Acceleration<br />A car is accelerating whenever there is a change in its state of motion. <br />
  26. 26. Acceleration<br />A car is accelerating whenever there is a change in its state of motion. <br />
  27. 27. Classroom Practice Problem<br />A bus slows down with an average acceleration of -1.8m/s2. how long does it take the bus to slow from 9.0m/s to a complete stop?<br />Find the acceleration of an amusement park ride that falls from rest to a velocity of 28 m/s downward in 3.0 s.<br />9.3 m/s2 downward<br />
  28. 28. Acceleration<br />Displacement with constant acceleration<br />d = ½ (vi + vf) Δt<br />Displacement= ½ (initial velocity + final velocity) (time)<br />
  29. 29. Example<br />A racecar reaches a speed of 42m/s. it uses its parachute and breaks to stop 5.5s later. Find the distance that the car travels during breaking. <br />Given: vi = 42 m/s vf= 0 m/s<br />t = 5.5 sec d = ?? <br />
  30. 30. Example<br />d = ½ (vi + vf) Δt<br />d = ½ (42+0) (5.5)<br />d = 115.5 m<br />
  31. 31. Acceleration<br />Final velocity<br />Depends on initial velocity, acceleration and time<br />Velocity with constant acceleration<br />vf = vi + aΔt<br />Final velocity = initial velocity + (acceleration X time)<br />
  32. 32. Acceleration<br />Displacement with constant acceleration<br />d = viΔt + ½ a (Δt)2<br />Displacement = (initial velocity X time) + ½ acceleration X time2<br />
  33. 33. Example<br />A plane starting at rest at one end of a runway undergoes uniform acceleration of 4.8 m/s2 for 15s before takeoff. What is its speed at takeoff? How long must the runway be for the plane to be able to take off?<br />Given: vi = 0 m/s a= 4.8m/sst= 15s<br />vf = ?? d= ??<br />
  34. 34. Example<br />What do we need to figure out?<br />Speed at takeoff<br />How long the runway needs to be<br />vf = vi + aΔt<br />vf = 0m/s + (4.8 m/s2)(15 s)<br />vf = 72m/s<br />
  35. 35. Example<br />d = viΔt + ½ a (Δt)2<br />d = (0m/s)(15s) + ½ (4.8m/s2)(15s)2<br />d = 540 m<br />
  36. 36. Acceleration<br />Final velocity after any displacement<br />vf2 = vi2 +2ad<br />Final velocity2 = initial velocity2 + 2(acceleration)(displacement)<br />
  37. 37. Example<br />An aircraft has a landing speed of 83.9 m/s. The landing area of an aircraft carrier is 195 m long. What is the minimum uniform acceleration required for safe landing?<br />
  38. 38. Example<br />vf2 = vi2 +2ad<br />02= (83.9)2 + 2a (195)<br />0= 7039.21 + 390a<br />-7039.21 = 390a<br />a = -18.0 m/s2<br />
  39. 39. Classroom Practice Problems<br />A bicyclist accelerates from 5.0 m/s to 16 m/s in 8.0 s. Assuming uniform acceleration, what distance does the bicyclist travel during this time interval?<br />Answer: 84 m<br />
  40. 40. 2.3 Falling Objects<br />and section 6.6<br />
  41. 41. Free Fall<br />The motion of a body when only the force due to gravity is acting<br />Acceleration is constant for the entire fall<br />Acceleration due to gravity (ag or g)<br />Has a value of -9.81 m/s2 (we will use 10m/s2)<br />Negative for downward<br />Roughly equivalent to -22 (mi/h)/s<br />
  42. 42. Free Fall<br />In Galileo’s famous demonstration, a 10-kg cannonball and a 1-kg stone strike the ground at practically the same time.<br />
  43. 43. 6.6 Free Fall Explained<br />The ratio of weight (F) to mass (m) is the same for the 10-kg cannonball and the 1-kg stone.<br />
  44. 44. 6.6 Free Fall Explained<br />The weight of a 1-kg stone is 10 N at Earth’s surface. Using Newton’s second law, the acceleration of the stone is<br />The weight of a 10-kg cannonball is 100 N at Earth’s surface and the acceleration of the cannonball is<br />
  45. 45.
  46. 46. Free Fall<br />Acceleration is constant during upward and downward motion<br />Objects thrown into the air have a downward acceleration as soon as they are released. <br />
  47. 47. Free Fall<br />The instant the velocity of the ball is equal to 0 m/s is the instant the ball reaches the peak of its upward motion and is about to begin moving downward.<br />REMEMBER!!! <br />Although the velocity is 0m/s the acceleration is still equal to 10 m/s2<br />
  48. 48. Example<br />Jason hits a volleyball so that it moves with an initial velocity of 6m/s straight upward. If the volleyball starts from 2.0m above the floor how long will it be in the air before it strikes the floor?<br />We want to use our velocity and acceleration equations<br />
  49. 49. Example<br />Given: vi = 6m/s a= 10m/s2<br />d= -2.0m t = ?? vf = ??<br />vf2= vi2 + 2ad<br />vf= at + vi<br />
  50. 50. Free Fall<br />For a ball tossed upward, make predictions for the sign of the velocity and acceleration to complete the chart.<br />
  51. 51. Graphing Free Fall<br />Based on your present understanding of free fall, sketch a velocity-time graph for a ball that is tossed upward (assuming no air resistance).<br />Is it a straight line?<br />If so, what is the slope?<br />Compare your predictions to the graph to the right.<br />

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