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RC Circuits Physics 102:   Lecture 7
Recall …. ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
RC Circuits ,[object Object],[object Object],[object Object],[object Object]
RC Circuits ,[object Object],[object Object],R K C S + + + R Na R Cl ε K ε Na ε Cl
Capacitors ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Charging Capacitors ,[object Object],[object Object], R C S
Charging Capacitors:  t=0 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object], R C S R 
Charging Capacitors:  t>0 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object], R C + - Demo R 
ACT/Preflight 7.1 ,[object Object],2R C  R S 2 1)  I b  = 0 2) I b  =  E   /(3R) 3) I b  =  E   /(2R) 4) I b  =  E   /R S 1 I b + - + + - -
ACT/Preflight 7.3  ,[object Object],1)  I b  = 0 2) I b  =  E /(3R) 3) I b  =  E /(2R) 4) I b  =  E /R 2R C  R S 2 S 1 I b + - + + - -
Discharging Capacitors ,[object Object],[object Object],R C S
Discharging Capacitors ,[object Object],[object Object],[object Object],[object Object],[object Object],R C + - Demo
ACT/Preflight 7.5 ,[object Object],1)  I R  = 0 2) I R  =    /(3R) 3) I R  =    /(2R) 4) I R  =    /R 2R C  R S 2 S 1 I R + - + + - - + -
ACT: RC Circuits ,[object Object],1)  Q = 0 2) Q = C  E  /3 3) Q  = C  E   /2 4) Q = C  E R 2R C  S 2 S 1 I R + - + + - - + -
RC Circuits: Charging ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],C    R S 1 S 2 + + + I - - - The switches are originally open and the capacitor is uncharged. Then switch S 1  is closed. t q RC 2RC 0 q 
RC Circuits: Discharging ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],C  R S 1 - + + I - + - S 2 q RC 2RC t
What is the time constant? ,[object Object],[object Object],[object Object]
Time Constant Demo ,[object Object],[object Object],[object Object],Each circuit has a 1 F capacitor charged to 100 Volts. When the switch is closed: 1 Example 2
Summary of Concepts ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Practice! Calculate current immediately after switch is closed: Calculate current after switch has been closed for 0.5 seconds: Calculate current after switch has been closed for a long time: Calculate charge on capacitor after switch has been closed for a long time: Example E  – I 0 R – q 0 /C = 0 + + + - - - E  – I 0 R – 0 = 0 I 0  =  E /R After a long time current through capacitor is zero! E  – IR – q ∞ /C = 0 E  – 0 – q ∞   /C   = 0 q ∞  =  E  C R C ε S 1 R=10  C=30 mF ε  =20 Volts   I
ACT: RC Challenge ,[object Object],1)  0.368 q 0   2) 0.632  q 0   3)  0.135 q 0   4) 0.865  q 0   R C ε 2R S 1 ε   = 24 Volts R = 2    C = 15 mF
Charging: Intermediate Times  Calculate the charge on the capacitor 3  10 -3  seconds after switch 1 is closed. ,[object Object],= q  (1-e - 3  10 -3   /(20  100  10 -6) ) )  = q   (0.78) Recall  q    =     C   = (50)(100x10 -6 ) (0.78) = 3.9 x10 -3  Coulombs R = 10     V = 50 Volts  C = 100  F Example 2R C R S 2 S 1 I b + - + + - -
RC Summary Charging Discharging q(t) = q  (1-e -t/RC ) q(t) = q 0 e -t/RC V(t) = V  (1-e -t/RC ) V(t) = V 0 e -t/RC I(t) = I 0 e -t/RC I(t) = I 0 e -t/RC Short term:  Charge doesn’t change (often zero or max) Long term:  Current through capacitor is zero. Time Constant    = RC  Large    means long time to charge/discharge

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Lect07 handout

  • 1. RC Circuits Physics 102: Lecture 7
  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7.
  • 8.
  • 9.
  • 10.
  • 11.
  • 12.
  • 13.
  • 14.
  • 15.
  • 16.
  • 17.
  • 18.
  • 19.
  • 20. Practice! Calculate current immediately after switch is closed: Calculate current after switch has been closed for 0.5 seconds: Calculate current after switch has been closed for a long time: Calculate charge on capacitor after switch has been closed for a long time: Example E – I 0 R – q 0 /C = 0 + + + - - - E – I 0 R – 0 = 0 I 0 = E /R After a long time current through capacitor is zero! E – IR – q ∞ /C = 0 E – 0 – q ∞ /C = 0 q ∞ = E C R C ε S 1 R=10  C=30 mF ε =20 Volts I
  • 21.
  • 22.
  • 23. RC Summary Charging Discharging q(t) = q  (1-e -t/RC ) q(t) = q 0 e -t/RC V(t) = V  (1-e -t/RC ) V(t) = V 0 e -t/RC I(t) = I 0 e -t/RC I(t) = I 0 e -t/RC Short term: Charge doesn’t change (often zero or max) Long term: Current through capacitor is zero. Time Constant  = RC Large  means long time to charge/discharge

Editor's Notes

  1. 1
  2. Initial current through battery. Final current; final voltage across C.
  3. Initial current through battery. Final current; final voltage across C.
  4. Initial current through battery. Final current; final voltage across C.
  5. Followup…what is current a long time later? What is charge on capacitor a long time later?