The two integers sum to 19. The larger is 5 less than twice the smaller. Let the smaller be Y=8. Then the larger is X=2*8-5=11. Therefore, the two integers are 11 and 8.

1. The sum of two integers is 19. The larger integer is 5 less than twice the smaller. Find the two
integers.
Solution
Let the larger integer be X and smaller integer be Y
Given sum of two integers is 19 i.e., X+Y=19
The larger integer is 5 less than twice the smaller i.e., X=2Y-5
X+Y=19
By plugging X=2Y-5 in X+Y=19 we get
2Y-5+Y=19
3Y=24
Y=24/3=8
X+Y=19
X+8=19
X=19-8=11
Therefore the two integers are 11,8