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Unit Hydrograph
Reading: Sections 7.1-7.3, 7.5, 7.7,
03/02/2006
Hydrologic Analysis
Change in storage w.r.t. time = inflow - outflow
In the case of a linear reservoir, S = kQ
Transfer function for a linear system (S = kQ).
Proportionality and
superposition
• Linear system (k is constant in S = kQ)
– Proportionality
• If I1  Q1 then C*I2  C*Q2
– Superposition
• If I1  Q1 and I2  Q2, then I1 +I2 Q1 + Q2
Impulse response function
Impulse input: an input applied instantaneously (spike) at time t and zero
everywhere else
An unit impulse at t produces as
unit impulse response function
u(t-t)
Principle of
proportionality and
superposition
Convolution integral
• For an unit impulse, the response of the system is given
by the unit impulse response function u(t-t)
• An impulse of 3 units produces the 3u(t-t)
• If I(t) is the precipitation intensity occurring for a time
period of dt, the response of the system (direct runoff) is
I(t)u(t-t)dt
• The complete response due to the input function I(t) is
given by convolution integral
• Response of a linear system is the sum (convolution) of
the responses to inputs that have happened in the past.
 

t
d
t
u
I
t
Q
0
)
(
)
(
)
( t
t
t
Step and pulse inputs
• A unit step input is an
input that goes from 0 to
1 at time 0 and
continues indefinitely
thereafter
• A unit pulse is an input
of unit amount occurring
in duration Dt and 0
elsewhere.
Precipitation is a series of pulse inputs!
Unit Hydrograph Theory
• Direct runoff hydrograph resulting from a
unit depth of excess rainfall occurring
uniformly on a watershed at a constant
rate for a specified duration.
• Unit pulse response function of a linear
hydrologic system
• Can be used to derive runoff from any
excess rainfall on the watershed.
Unit hydrograph assumptions
• Assumptions
– Excess rainfall has constant intensity during
duration
– Excess rainfall is uniformly distributed on
watershed
– Base time of runoff is constant
– Ordinates of unit hydrograph are proportional
to total runoff (linearity)
– Unit hydrograph represents all characteristics
of watershed (lumped parameter) and is time
invariant (stationarity)
Discrete Convolution
 

t
d
t
u
I
t
Q
0
)
(
)
(
)
( t
t
t






M
n
m
m
n
m
n U
P
Q
1
1
Continuous
Discrete
Q is flow, P is precipitation and U is unit hydrograph
M is the number of precipitation pulses, n is the number
of flow rate intervals
The unit hydrograph has N-M+1 pulses
Application of
convolution to the
output from a linear
system
Time – Area Relationship
2
A
1
A
3
A
4
A
Isochrone of
Equal time to outlet
hr
5
hr
10
hr
15
j
i
i
n A
R
A
R
A
R
Q 1
2
1
1 ...


 
2
R
1
R
3
R
Time, t
Excess
Rainfall
2
A
1
A
3
A
4
A
0 5 10 15 20
Time, t
Area
Application of UH
• Once a UH is derived, it can be
used/applied to find direct runoff and
stream flow hydrograph from other storm
events.
Ex. 7.5.1
Given:
P1 = 2 in, P2 = 3 in and P3 = 1 in, baseflow = 500 cfs and
watershed area is 7.03 mi2. Given the Unit Hydrograph
below, determine the streamflow hydrograph
7.5.1 solution (cont’d)
See another example at: http://www.egr.msu.edu/~northco2/BE481/UHD.htm
Gauged and ungauged watersheds
• Gauged watersheds
– Watersheds where data on precipitation,
streamflow, and other variables are available
• Ungauged watersheds
– Watersheds with no data on precipitation,
streamflow and other variables.
Need for synthetic UH
• UH is applicable only for gauged
watershed and for the point on the stream
where data are measured
• For other locations on the stream in the
same watershed or for nearby (ungauged)
watersheds, synthetic procedures are
used.
Synthetic UH
• Synthetic hydrographs are derived by
– Relating hydrograph characteristics such as
peak flow, base time etc. with watershed
characteristics such as area and time of
concentration.
– Using dimensionless unit hydrograph
– Based on watershed storage
SCS dimensionless hydrograph
• Synthetic UH in which
the discharge is
expressed by the ratio
of q to qp and time by
the ratio of t to Tp
• If peak discharge and
lag time are known, UH
can be estimated.
c
p T
t 6
.
0

p
r
p t
t
T 

2 p
p
T
CA
q 
Tc: time of concentration
C = 2.08 (483.4 in English
system)
A: drainage area in km2 (mi2)
p
b T
t 67
.
2

Ex. 7.7.3
• Construct a 10-min SCS UH. A = 3.0 km2 and Tc = 1.25 h
h
tr 166
.
0
min
10 

h
T
t c
p 75
.
0
25
.
1
6
.
0
6
.
0 



p
r
p t
t
T 

2
h
Tp 833
.
0
75
.
0
2
166
.
0



cm
s
m
T
CA
q
p
p .
/
49
.
7
833
.
0
3
08
.
2 3




Multiply y-axis of SCS hydrograph by
qp and x-axis by Tp to get the required
UH, or construct a triangular UH
q
t
0.833 h
2.22 h
7.49 m3/s.cm

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UnitHydrograph.ppt

  • 1. Unit Hydrograph Reading: Sections 7.1-7.3, 7.5, 7.7, 03/02/2006
  • 2. Hydrologic Analysis Change in storage w.r.t. time = inflow - outflow In the case of a linear reservoir, S = kQ Transfer function for a linear system (S = kQ).
  • 3. Proportionality and superposition • Linear system (k is constant in S = kQ) – Proportionality • If I1  Q1 then C*I2  C*Q2 – Superposition • If I1  Q1 and I2  Q2, then I1 +I2 Q1 + Q2
  • 4. Impulse response function Impulse input: an input applied instantaneously (spike) at time t and zero everywhere else An unit impulse at t produces as unit impulse response function u(t-t) Principle of proportionality and superposition
  • 5. Convolution integral • For an unit impulse, the response of the system is given by the unit impulse response function u(t-t) • An impulse of 3 units produces the 3u(t-t) • If I(t) is the precipitation intensity occurring for a time period of dt, the response of the system (direct runoff) is I(t)u(t-t)dt • The complete response due to the input function I(t) is given by convolution integral • Response of a linear system is the sum (convolution) of the responses to inputs that have happened in the past.    t d t u I t Q 0 ) ( ) ( ) ( t t t
  • 6. Step and pulse inputs • A unit step input is an input that goes from 0 to 1 at time 0 and continues indefinitely thereafter • A unit pulse is an input of unit amount occurring in duration Dt and 0 elsewhere. Precipitation is a series of pulse inputs!
  • 7. Unit Hydrograph Theory • Direct runoff hydrograph resulting from a unit depth of excess rainfall occurring uniformly on a watershed at a constant rate for a specified duration. • Unit pulse response function of a linear hydrologic system • Can be used to derive runoff from any excess rainfall on the watershed.
  • 8. Unit hydrograph assumptions • Assumptions – Excess rainfall has constant intensity during duration – Excess rainfall is uniformly distributed on watershed – Base time of runoff is constant – Ordinates of unit hydrograph are proportional to total runoff (linearity) – Unit hydrograph represents all characteristics of watershed (lumped parameter) and is time invariant (stationarity)
  • 9. Discrete Convolution    t d t u I t Q 0 ) ( ) ( ) ( t t t       M n m m n m n U P Q 1 1 Continuous Discrete Q is flow, P is precipitation and U is unit hydrograph M is the number of precipitation pulses, n is the number of flow rate intervals The unit hydrograph has N-M+1 pulses
  • 10. Application of convolution to the output from a linear system
  • 11. Time – Area Relationship 2 A 1 A 3 A 4 A Isochrone of Equal time to outlet hr 5 hr 10 hr 15 j i i n A R A R A R Q 1 2 1 1 ...     2 R 1 R 3 R Time, t Excess Rainfall 2 A 1 A 3 A 4 A 0 5 10 15 20 Time, t Area
  • 12. Application of UH • Once a UH is derived, it can be used/applied to find direct runoff and stream flow hydrograph from other storm events. Ex. 7.5.1 Given: P1 = 2 in, P2 = 3 in and P3 = 1 in, baseflow = 500 cfs and watershed area is 7.03 mi2. Given the Unit Hydrograph below, determine the streamflow hydrograph
  • 13. 7.5.1 solution (cont’d) See another example at: http://www.egr.msu.edu/~northco2/BE481/UHD.htm
  • 14. Gauged and ungauged watersheds • Gauged watersheds – Watersheds where data on precipitation, streamflow, and other variables are available • Ungauged watersheds – Watersheds with no data on precipitation, streamflow and other variables.
  • 15. Need for synthetic UH • UH is applicable only for gauged watershed and for the point on the stream where data are measured • For other locations on the stream in the same watershed or for nearby (ungauged) watersheds, synthetic procedures are used.
  • 16. Synthetic UH • Synthetic hydrographs are derived by – Relating hydrograph characteristics such as peak flow, base time etc. with watershed characteristics such as area and time of concentration. – Using dimensionless unit hydrograph – Based on watershed storage
  • 17. SCS dimensionless hydrograph • Synthetic UH in which the discharge is expressed by the ratio of q to qp and time by the ratio of t to Tp • If peak discharge and lag time are known, UH can be estimated. c p T t 6 . 0  p r p t t T   2 p p T CA q  Tc: time of concentration C = 2.08 (483.4 in English system) A: drainage area in km2 (mi2) p b T t 67 . 2 
  • 18. Ex. 7.7.3 • Construct a 10-min SCS UH. A = 3.0 km2 and Tc = 1.25 h h tr 166 . 0 min 10   h T t c p 75 . 0 25 . 1 6 . 0 6 . 0     p r p t t T   2 h Tp 833 . 0 75 . 0 2 166 . 0    cm s m T CA q p p . / 49 . 7 833 . 0 3 08 . 2 3     Multiply y-axis of SCS hydrograph by qp and x-axis by Tp to get the required UH, or construct a triangular UH q t 0.833 h 2.22 h 7.49 m3/s.cm