How does an open source operating system like Linux® affect Internet.pdf

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jyothimuppasani1

How does an open source operating system like Linux® affect Internet security and safety? Solution Since open source operating system\'s code is available to all,it\'s provides an easy access to hackers and potential misusers which affects safety of such systems. The non stable nature of Open source operating system also can be considered an important factor that affects the Security.This is because Developers all over the globe modify the code and thus the code is not stable and it becomes vulnerable to security threats. Even if patches are introduced from time to time,mostly after an attack or so but due to large flavours or distributions of open source software, some flavours are left without patches that makes them vulnerable to attacks. Also,The administration of open source operating system Servers also plays an important factor in Internet Security. Since it is known that for example,Linux Server administration is more difficult and when multiple ports are open it is sometimes not possible to handle an attack or security threat immediately. But then as it is said that every coin has two sides, Sometimes it is considered that Open Source Systems like Linux are more secure because of the following reasons :.

How does an open source operating system like Linux® affect Internet security and safety?
Solution
Since open source operating system's code is available to all,it's provides an easy access to
hackers and potential misusers which affects safety of such systems.
The non stable nature of Open source operating system also can be considered an important
factor that affects the Security.This is because Developers all over the globe modify the code and
thus the code is not stable and it becomes vulnerable to security threats.
Even if patches are introduced from time to time,mostly after an attack or so but due to large
flavours or distributions of open source software, some flavours are left without patches that
makes them vulnerable to attacks.
Also,The administration of open source operating system Servers also plays an important factor
in Internet Security. Since it is known that for example,Linux Server administration is more
difficult and when multiple ports are open it is sometimes not possible to handle an attack or
security threat immediately.
But then as it is said that every coin has two sides, Sometimes it is considered that Open Source
Systems like Linux are more secure because of the following reasons :

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jyothimuppasani1

Discuss the importance of recognizing and implementing different entry strategies and organizational arrangements which result in shared control and oversight through collaborative relationships Solution Entry strategies are explained as a well planned method through which the company decide to delivery its good and services to the targeted market. The different types of market entry strategies and organizational arrangement and its importance are discussed below: 1 .Exporting: when goods/Product are produced in one country and marketed in another country then it is known as exporting. 2. Licensing: When a firm permit the company operating in another company to use its manufacturing process, copyrights, and trademark with specific and determined payment. 3. Franchising: It’s an agreement between two companies, where a company (the franchiser) gives all its rights to another company (the franchisee) to use its trademark, manufacturing process and market to certain specification. 4. Joint venturing: In this two companies or investors share ownership and control over the finance and operations of the firm. 5. Contract Manufacturing: In this the company operating in foreign countries gets into contract to with the country operating there for manufacturing or assembling of the product. 6. Merger & Acquisitions: It is defined as restructuring of organization, for positive growth and value. Merger means to ‘merge’ in which two companies legally merge into one into one entity, whereas an acquisition means when one company takes over another and completely become new owner. All the entry strategies discussed above results in shared control through collaborative relationships..

Discuss the importance of recognizing and implementing different ent.pdf

Discuss the importance of recognizing and implementing different ent.pdf

Discuss the importance of recognizing and implementing different ent.pdf

jyothimuppasani1

Considering the challenges she is facing, what Anita\'s plan before the strategic planning retreat? How would you reformulate the art center mission, has the center need a new strategy? why or why not? Solution Anitha wants to bring some new innovation arts to the Arts center. This also brings more profit for her. People who are crazy of arts expect more attractive and interesting arts,so she has to increase her quality of arts to entertain the art lovers. Few people who don\'t have any knowledge about arts also started trying out with arts. The art center mission can be reformulated by inspiring them in participating in performances and they have to feel that what time they have towards arts must be meaningful. The strategy that can be used by sponsoring and contributing. This work can get help by adding partners also. Through this they can teach others and also bring their talents out. By performing like this the whole community gets attracted and her dream comes true. Through this they can bring out the most hidden artists in the community and many artists are come out showing their excellence in their art..

Considering the challenges she is facing, what Anitas plan before .pdf

Considering the challenges she is facing, what Anitas plan before .pdf

Considering the challenges she is facing, what Anitas plan before .pdf

jyothimuppasani1

Data Structure in C++ Doubly Linked Lists of ints http://staffwww.fullcoll.edu/aclifton/courses/cs133_fa16/files/dlist.h This is my code below: dlist.cc ------------------------------------------------------------------------------------------------------- #include #include \"dlist.h\" dlist::node* dlist::at(int n){ node* c = _head; while(n > 0 && c){ c = c->next; n--; } return c; } void dlist::insert(node* previous, int value){ node* n = new node{value, previous->next}; previous->next = n; }//update tail void dlist::del(node* which){ node* nn = which->next; which->next = nn->next; delete nn; } void dlist::push_back(int value){ node* n = new node{value, nullptr}; _tail->next = n; _tail-> n; } void dlist::push_front(int value){ node* n = new node(value, nullptr); _head->prev = n; _head-> n; } void dlist::pop_front(){ node* n = _head; _head = _head->next; delete n; } void dlist::pop_back(){ node* n = _tail; _tail = _tail->prev; delete n; } int dlist::size() { node* c = _head; int s = 0; while(c){ s++; c = c->next; } return s; } -------------------------------------------------------------------------------- Please fix and complete my code, and I also need whole code contatining main function for testing dlist.cc In this assignment, you will implement a doubly-linked list class. together with some list operations. To make things easier, you\'ll implement a list of int rather than a template class pragma once dlist. h Doubly linked lists of ints include Kostream class dlist public: d list struct node int value node next node prev; node\' head() const return -head; node\" tail() const t return -tail Implement ALL the following methods Returns the node at a particular index (0 is the head node at(int) Insert a new value, after an existing one void insert(node *previous int value Delete the given node void del (node which) Solution #include #include #include /* * Node Declaration */ using namespace std; struct node { int value; string name; struct node *next; struct node *prev; }*start; /*class declaration class dlist { public: void create_list(int value); void push_front(int value); void push_back(int value, int position); void pop_front(int value); void pop_back(int value); void display_dlist(); void reverse(); dlist() { start = NULL; head=NULL; last=NULL; } bool empty() const { return head==NULL; } friend ostream& operator<<(ostream& ,const dlist& ); void insert(const string& ); void remove(const string& ); private: node* head() const { return _head; } node* tail() const { return _tail; } }; dlist.cc: /* Create Double Link List*/ void dlist::create_list(int value) { struct node *s, *temp; temp = new(struct node); temp->info = value; temp->next = NULL; if (start == NULL) { temp->prev = NULL; start = temp; } else { s = start; while (s->next != NULL) s = s->next; s->next = temp; temp->prev = s; } } /* * Insertion at the beginning */ void dlist::add_begin(int value) { if (start == NULL) { cout<<\"First Create the list.\"<prev = NULL; temp->info = val.

Data Structure in C++Doubly Linked Lists of ints httpstaffwww.pdf

Data Structure in C++Doubly Linked Lists of ints httpstaffwww.pdf

Data Structure in C++Doubly Linked Lists of ints httpstaffwww.pdf

jyothimuppasani1

Conceptual skills are most important at the Solution Conceptual skills relate to the managers\' mental ability to coordinate and integrate all of the organization\'s interests and activities. It is about thinking in the abstract and observing relationships between forces that many others may not be able to see and to take a global perspective of the organization and its environment. This is not so relevant at the lower level of management and is most important at the top management level because the senior managers must look for and exploit unseen opportunities for their organizations..

Conceptual skills are most important at theSolutionConceptual .pdf

Conceptual skills are most important at theSolutionConceptual .pdf

Conceptual skills are most important at theSolutionConceptual .pdf

jyothimuppasani1

A variable whose scope is restricted to the method where it was declared is known as a(n) parameter global variable local variable public instance data private instance data parameter global variable local variable public instance data private instance data Solution Answer is \"Local Variable\" Parameter: parameter is something which is passed to the method, and not declared in the method. Global Variable: Global Variable is accessible from anywhere in the program. And not just restricted to a certain method..

A variable whose scope is restricted to the method where it was decl.pdf

A variable whose scope is restricted to the method where it was decl.pdf

A variable whose scope is restricted to the method where it was decl.pdf

jyothimuppasani1

•Design (create) 3 questions for a quiz show game and design regular expressions that validate the answers. The challenge is to be no more and no less exacting than a human checker. I have the sample quiz done already.email me for code Solution Database design • Not easy! • Will discuss formal methods next week • Review: databases are made up of – Tables: tables made up of • Records: records made up of fields • Speaking of rows and columns is misleading • Critical issue: fixed number of fields, though a specific field may be optional (aka not required) – NOT NULL in MySQL jargon means required! – MySQL does support variable length strings. Data types • Terminology varies for different DBMS products • Performance (speed) of operations varies with different datatypes • Size varies with different datatypes • Performance and size limits are points of competition among the different products MySQL datatypes: numbers • INT (aka INTEGER), can be UNSIGNED (Size 4 bytes = 32 bits) • TINYINT, SMALLINT, MEDIUMINT, BIGINT – Different sizes • float (4 bytes), double (8 bytes), can specify precision within these limits • more MySQL datatypes, strings • CHAR(specified length) • VARCHAR(maximum length) • TINYBLOB short, variable length string, up to 255 characters • BLOB, TEXT variable length string • MEDIUMBLOB, MEDIUMTEXT, LONGBLOB, LONGTEXT MySQL datatypes: enum • ENUM – Specify one of a set of values – Stored as an integer, with 0 indicated unset or not in the specified set – Doing this may be more efficient because built-in MySQL routines do the searching MySQL datatypes: date/time • DATE • TIME • DATETIME • YEAR • TIMESTAMP Tables • Specify one field as the primary key • Primary keys are unique IN THAT TABLE – Let the DBMS create the primary key OR – Depend on intrinsic value that is guaranteed to be unique • Email addresses • ISBN numbers • ? • A field in one table may be a foreign key. This is a reference to a primary key in another table (or this table). MORE ON THIS LATER. Database • Assume database itself is created for us AND we have permissions to create new tables. • NOTE: permissions can be set by MySQL commands, including queries sent by php. • Start off talking general SQL and then specific php and MySQL Create table example • CREATE TABLE movies ( mid INT NOT NULL AUTO_INCREMENT PRIMARY KEY, mname CHAR(30), mdesc TEXT, myear YEAR ) Create table example CREATE TABLE players ( pid INT NOT NULL AUTO_INCREMENT PRIMARY KEY, pname CHAR(30), score INT NOT NULL, lastplayed DATE ) Create example CREATE TABLE games ( gid INT NOT NULL AUTO_INCREMENT PRIMARY KEY, pid INT, gtime TIMESTAMP, score INT ) The pid field will refer to / have the value of the pid field (the primary key) of a specific player. Here in this table, it is called a foreign key. Foreign keys • Some versions of MySQL (and other DBMS) have ways to specify the the pid value is a foreign key pid INT REFERENCE players • The DBMS will check to make sure it is a valid value. • Since the php.

•Design (create) 3 questions for a quiz show game and design regular.pdf

•Design (create) 3 questions for a quiz show game and design regular.pdf

•Design (create) 3 questions for a quiz show game and design regular.pdf

jyothimuppasani1

You are to write a GUI program that will allow a user to buy, sell and view stocks in a stock portfolio. Objective: Write a GUI program that maintains a cash balance, list of stock holdings, supports buying and selling of stocks and displays the current portfolio inventory. Program Capabilities: 1. Allow a user to buy a stock with a given number of shares and price per share. 2. Display the current portfolio (stock ticker, number of shares, initial price). 3. Update the portfolio display for purchases and sales. 4. Allow the user to sell all of the shares of a given stock. 5. Give the user an initial cash balance, and update and display the balance according to the user\'s purchases and sales. 6. Ignore any transaction that causes the cash position to go below $0. USE OF PREVIOUS StockHolding and PortfolioList LABS IS ADVISED. (I\'ve including my solutions to these below) This is my written code from earlier homework: public class StockHolding { private String ticker; private int numShares; private double initialSharePrice; private double currentSharePrice; public StockHolding(String ticker, int numberShares, double initialPrice) { this.ticker = ticker; numShares = numberShares; initialSharePrice = initialPrice; currentSharePrice = initialPrice; } public double getCurrentValue() { return numShares * getCurrentSharePrice(); } public double getInitialCost() { return numShares * getInitialSharePrice(); } public double getCurrentProfit() { return getCurrentValue() - getInitialCost(); } public double getCurrentSharePrice() { return currentSharePrice; } public void setCurrentSharePrice(double currentSharePrice) { this.currentSharePrice = currentSharePrice; } public String getTicker() { return ticker; } public int getShares() { return numShares; } public double getInitialSharePrice() { return initialSharePrice; } @Override public String toString() { return \"Stock \" + ticker + \", \" + numShares + \", shares bought at \" + initialSharePrice + \", current price \" + currentSharePrice; } } AND import java.util.ArrayList; public class PortfolioList { private ArrayList portfolio; public PortfolioList() { portfolio = new ArrayList(); } public void add(StockHolding stock) { portfolio.add(stock); } public StockHolding find(String ticker) { for (int i = 0; i < portfolio.size(); i++) { StockHolding sh = portfolio.get(i); if (sh.getTicker().equals(ticker)) { return sh; } } return null; } public void remove(String ticker) { int pos = -1; for (int i = 0; i < portfolio.size(); i++) { StockHolding sh = portfolio.get(i); if (sh.getTicker().equals(ticker)) { pos = i; } } if (pos != -1) { portfolio.remove(pos); } } I\'ve been staring at this for two days, and I am lost. Please, any guidance/help would be greatly appreciated. Honestly don\'t even need a full solution, just need something to kick start. A comment skeleton would help a ton. Thanks! Solution SOURCE CODE: package stock; public class StockHolding { private String ticker; private int numShares; private do.

You are to write a GUI program that will allow a user to buy, sell a.pdf

You are to write a GUI program that will allow a user to buy, sell a.pdf

You are to write a GUI program that will allow a user to buy, sell a.pdf

jyothimuppasani1

write the To Do\'s to get the exact output: NOte: A valid Fraction number has a non-negative numerator and a positive denominator. Default constructor initializes the object to safe empty state (an object with denom equals -1). The two-argument constructor also validates the parameters and sets the object to the safe empty state if the parameters are not valid. Write the definitions and prototypes of following functions in Fraction.cpp and Fraction.h respectively (They are indicated in the files by //TODO tag): Define isEmpty function as a member function, which returns true if the object is in safe empty state (an object is in the safe empty state if denominator (denom) equals -1). Define display function, which sends a Fraction number to the output stream (with the “Numerator/denominator” format). This function just prints \"Invalid Fraction Object!\" in the screen if the object is in the safe empty state. In case that object denominator equals 1, it just print the numerator. Define the operator functions for the following operators: “+=”, “+”, “*” The overload of the above operators should make the following code possible: The member operator+ : Adds two Fraction numbers and returns a Fraction number as the result. This function returns an object with the safe empty state if either of Fraction numbers (operands) is in safe empty state. It makes following code possible: A+B ( where A and B are Fraction objects) The member operator+= : Adds two Fraction numbers and assigns the result to the left operand, then returns a reference to the left operand. If either of Fraction numbers (operands) is in safe empty state, it initializes the left operand to the safe empty state, then returns a reference to the left operand. It makes following code possible: A+=B ( where A and B are Fraction objects) The member operator* : Multiplies two Fraction numbers and returns a Fraction number as the result. This function returns an object with the safe empty state if either of Fraction numbers (operands) is in safe empty state. It makes following code possible: A*B ( where A and B are Fraction objects) fraction.cpp #include \"Fraction.h\" using namespace std; namespace sict{ Fraction::Fraction(){ denom =-1; // safe empty state } Fraction::Fraction(int n, int d) // n: numerator, d: denominator { if(n >= 0 && d > 0){ num = n; denom = d; reduce(); } else denom =-1; // set to safe empty state } int Fraction::gcd() // returns the greatest common divisor of num and denom { int mn = min(); // min of num and denom int mx = max(); // mX of num and denom for (int x=mn ; x > 0 ; x--) // find the greatest common divisor if( mx % x == 0 && mn % x == 0) return x; return 1; } void Fraction::reduce() // simplify the Fraction number { int tmp = gcd(); num /= tmp; denom /= tmp; } int Fraction::max () { return (num >= denom) ? num : denom; } int Fraction::min() { return (num >= denom) ? denom : num; } // in_lab // TODO: write the implementation of display function HERE // TODO: w.

write the To Dos to get the exact outputNOte A valid Fraction .pdf

write the To Dos to get the exact outputNOte A valid Fraction .pdf

write the To Dos to get the exact outputNOte A valid Fraction .pdf

jyothimuppasani1

What are the factors that contribute to H+ gain or loss? How do lungs and the kidneys balance or regulate the changes in pH? Solution Answer= Factors that contribute to loss or gain of H ions are= CO2 concentration O2 concentration bicarbonate concentration in urine The lungs regulate the changes in PH = Acid base imbalances in the bloods pH can be altered by changes in breathing to expel ,ore CO2 & raise the pH back to normal Hydrogen ions are carried in the blood along with oxygen & carbon dioxide 60 % CO2 is carried as a dissolved bicarbonate A small amount of CO2 is carried on Haemoglobin as carbaminohaemoglobin which is transported to the lungs for removal Acid base imbalances that overcome the buffer system can be compensated in the short term by changing the rate of ventilation When pH of blood drops too low ,the body compensates by increasing breathing to expel more CO2 & during alkalemia the inspiration occurs Regulation of pH by kidneys = kidneys have 2 important roles in maintaining the acid -base balance 1]They reabsorb bicarbonate from urine 2] they excrete hydrogen ions into urine The major homeostatic control point for maintaining a stable pH balance is renal excretion Bicarbonate does not have transporter ,so its reabsorption involves a series of reactions in the tubule lumen & tubular epithelium . In response tyo acidosis the tubular cells reabsorb more bicarbonate from the tubular fluid ,& the collecting cells secrete more hydrogen & generate more bicarbonate In response to alkalosis ,the kidneys may excrete more bicarbonate by decreasing Hydrogen ion secretion from tubular epithelial cells ,& lowering the rates of glutamine metabolism & ammonium excretion.

What are the factors that contribute to H+ gain or loss How do lung.pdf

What are the factors that contribute to H+ gain or loss How do lung.pdf

What are the factors that contribute to H+ gain or loss How do lung.pdf

jyothimuppasani1

Write down the four (4) nonlinear regression models covered in class, i.e. both the name of the model and their functional form showing their respective regression coefficients. A rapidly growing bacteria has been discovered with a growth rate as shown in the table. Analyze this date using a power law model. First linearize the data in the table based on the power law model, call this new linearized data x and y. Next, determine the coefficients a_0 and a_1 of a linear regression y = a_0 + a_1x for the linearized power law data x and y, and compute the correlation coefficient for the liner regression. Note that you are not being asked to do a linear regression of the data in the table but rather a linear regression of the linearized version of that data. Once you compute a_0 and a_1 use these to determine the coefficients of the power law model. Write a Matlab script that uses the polyfit function to determine the regression coefficients of a second order polynomial fit to data in the table. In the same script, write down the code for using the polyval command to determine the value of the regression curve at the observed times. Solution Nonlinear regression is a statistical technique that helps describe nonlinear relationships in experimental data. A nonlinear regression model can be written Yn = f(xn, ) + Zn where f is the expectation function and xn is a vector of associated regressor variables or independent variables for the nth case. A nonlinear model is one in which at least one of the parameters appears nonlinearly. More formally, in a nonlinear model, at least one derivative with respect to a parameter should involve that parameter. Examples of a nonlinear model are: Y(t) = exp(at+bt2) Y(t) = at + exp(-bt). Important non linear growth models 1.Logistic Model This model is represented by the differential equation dN/dt = rN (1-N/K). Integrating, we get N(t) = K / [1+(K/No-1) exp(-rt)] The graph of N(t) versus t is elongated S-shaped and the curve is symmetrical about its point of inflexion. 2.Malthus Model If N(t) denotes the population size or biomass at time t and r is the intrinsic growth rate, then the rate of growth of population size is given by dN/dt = rN. Integrating, we get N(t) = No exp (rt), where No denotes the population size at t=0. Thus this law entails an exponential increase for r>0. Furthermore, N(t) à as t à , which cannot happen in reality. 3. Monomolecular Model This model describes the progress of a growth situation in which it is believed that the rate of growth at any time is proportional to the resources yet to be achieved, i.e. dN/dt = r(K-N), where K is the carrying size of the system. Integrating (3.3), we get N(t) = K-(K-No) exp (-rt). 4. Richards Model. This model is given by dN/dt = rN (KN – Nm)/mKm which, on integration, gives N(t )=K N0 /[ N0+ (KN – N0m) exp (-rt)]1/m. Unlike the earlier models, this model has four parameters Hours (H) 10 20 40 50 No fo bacteria (N) 25 70 380 550 610 b) N = b H m Log10.

Write down the four (4) nonlinear regression models covered in class,.pdf

Write down the four (4) nonlinear regression models covered in class,.pdf

Write down the four (4) nonlinear regression models covered in class,.pdf

jyothimuppasani1

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Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx

COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx

COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx

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Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

Analyzing and resolving a communication crisis in Dhaka textiles LTD.pptx

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COMMUNICATING NEGATIVE NEWS - APPROACHES .pptx

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How does an open source operating system like Linux® affect Internet.pdf

1. How does an open source operating system like Linux® affect Internet security and safety? Solution Since open source operating system's code is available to all,it's provides an easy access to hackers and potential misusers which affects safety of such systems. The non stable nature of Open source operating system also can be considered an important factor that affects the Security.This is because Developers all over the globe modify the code and thus the code is not stable and it becomes vulnerable to security threats. Even if patches are introduced from time to time,mostly after an attack or so but due to large flavours or distributions of open source software, some flavours are left without patches that makes them vulnerable to attacks. Also,The administration of open source operating system Servers also plays an important factor in Internet Security. Since it is known that for example,Linux Server administration is more difficult and when multiple ports are open it is sometimes not possible to handle an attack or security threat immediately. But then as it is said that every coin has two sides, Sometimes it is considered that Open Source Systems like Linux are more secure because of the following reasons :