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2.4  The Chain Rule Derivatives of Composite Functions Using the General Power Rule
The key to success is identifying the outside function and the inside function! Take the derivative of the outside function evaluated at the inside function, then chain on the derivative of the inside function with respect to x.
Think of the composite function as having two parts – the outside and the inside.  y = f( g(x) ) = f(u) and y’ = f’(u) ٠ u’ Ex. 2 p. 132  Decomposition of a Composite Function – identifying inside parts and outside parts!
Ex 3 p 132  Using the Chain Rule Find dy/dx for y = (3x 2  + 1) 7 Solution:  inside function is  u = 3x 2  + 1  and outside is y = u 7 For  f(g(x)):  Differentiate the “outside” function  f  and evaluate it at the “inside” function  g(x)  left alone, then multiply by the derivative of the inside function .
Ex 4 p. 133 Applying the General Power Rule Find the derivative of f(x) = (3x – 2x 2 ) 3  Hint:  f(x) = u 3  ,[object Object],[object Object],[object Object],[object Object],[object Object]
Ex 5 p. 133  Differentiating Functions with radicals Find all points on the graph of for which f’(x) = 0 and those for which f’(x) does not exist. Rewrite: Apply chain rule: f’(x) = 0 when the numerator = 0  so when x = 0 f‘(x) does not exist when denominator = 0 so when x = 3, -3
Ex 6 p. 133  Differentiating Quotients with Constant Numerators Differentiate  Rewrite as  Then apply General Power Rule:
Ex 7 p134  Simplifying by Factoring Out the Least Powers Way 1 Way 2
Ex 8 p. 134  Simplifying the Derivative of a Quotient Way 1 Way 2
Example 9 p. 134  Simplifying the Derivative of a Power
2.4a  p. 137 #1-3 all, 7-35 EOO, 59-67 EOO, 91-97

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Calc 2.4a

  • 1. 2.4 The Chain Rule Derivatives of Composite Functions Using the General Power Rule
  • 2. The key to success is identifying the outside function and the inside function! Take the derivative of the outside function evaluated at the inside function, then chain on the derivative of the inside function with respect to x.
  • 3. Think of the composite function as having two parts – the outside and the inside. y = f( g(x) ) = f(u) and y’ = f’(u) ٠ u’ Ex. 2 p. 132 Decomposition of a Composite Function – identifying inside parts and outside parts!
  • 4. Ex 3 p 132 Using the Chain Rule Find dy/dx for y = (3x 2 + 1) 7 Solution: inside function is u = 3x 2 + 1 and outside is y = u 7 For f(g(x)): Differentiate the “outside” function f and evaluate it at the “inside” function g(x) left alone, then multiply by the derivative of the inside function .
  • 5.
  • 6. Ex 5 p. 133 Differentiating Functions with radicals Find all points on the graph of for which f’(x) = 0 and those for which f’(x) does not exist. Rewrite: Apply chain rule: f’(x) = 0 when the numerator = 0 so when x = 0 f‘(x) does not exist when denominator = 0 so when x = 3, -3
  • 7. Ex 6 p. 133 Differentiating Quotients with Constant Numerators Differentiate Rewrite as Then apply General Power Rule:
  • 8. Ex 7 p134 Simplifying by Factoring Out the Least Powers Way 1 Way 2
  • 9. Ex 8 p. 134 Simplifying the Derivative of a Quotient Way 1 Way 2
  • 10. Example 9 p. 134 Simplifying the Derivative of a Power
  • 11. 2.4a p. 137 #1-3 all, 7-35 EOO, 59-67 EOO, 91-97