CCS355 Neural Network & Deep Learning UNIT III notes and Question bank .pdf
Analyzing the Motion of a Bicyclist
1. ABSTRACT:
To analyze the motion of a bicyclist as described in the above problem. I will be making explicit relation
of time with the given velocity-distance relation, and plotting the acceleration, velocity and distance
against time.
ANALYSIS:
S=0 to 40 meters:
Velocity is dependent on distance as follows:
V=0.25*s
푑푠
푑푡
= 0.25 ∗ 푠, => 1
0.25
∫
푑푠
푠
푡
푡0
= ∫ 푑푡
푠
푠0
t-t0 =
1
0.25
(ln(s)-ln(s0))
s-s0 =0.25*(푒푡 − 푒푡0
) =>> @s0=0, t0
t=4*ln(s)
S=0.25*푒푡 − 0.25
푑푠
푑푡
= 0.25*et =V
푑^2푠
푑푡^2
=0.25*et =a
2. To get the time for bicyclist to travel 40 meters :
t40=4*(ln(40))
t40=14.755 sec
GRAPH:
15
10
5
0
v-s
0 10 20 30 40 50
velocity
distance
Series1
800000
600000
400000
200000
0
v-t(s)
-5 0 5 10 15 20
-200000
velocity
time
Series1
3. 30
25
20
15
10
5
0
a-s
0 10 20 30 40 50
700000
600000
500000
400000
300000
200000
100000
0
a-t(s)
-5 0 5 10 15 20
Observations:
Here the distance of very infinitesimal range is being covered before the infinitesimal time interval.
The motion of this bicyclist seems to be recorded as a sudden motion due to which the time
factor is defined at the velocity of 0.25m/s not when the distance was one meter.
This motion depicts the motion with variable velocity and acceleration at some time t and some
distance s.
The motion is depicting a very rapid increase of velocity and acceleration which seems
impossible for a human to ride or even a robot cannot run a cycle with this characteristics.
This motion can be valid for limited time and short distance, as then it could depict the
motion of an Olympian cyclist competing in the event.
acceleration
distance
Series1
-100000
acceleration
time
Series1