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LMCP 1352 ASAS-ASAS SAINS DATA
DALAM PENGANGKUTAN
MODUL 9:
TugasanPisahragaman
NAMA : SARASVATHI A/P K SIVARAMAN
NO MATRIKS:A168202
PENSYARAH : PROF DR RIZA ATIQ ABDULLAH
Soalan 1
a)Model Fungsi Logistik
𝑃 =
1
1+𝑒𝛼 π‘˜π‘Žπ‘‘π‘Žπ‘Ÿ π‘π‘Žπ‘Ÿπ‘˜π‘–π‘Ÿ +𝐢
1βˆ’π‘ƒ
𝑃
= 𝑒𝛼 π‘˜π‘Žπ‘‘π‘Žπ‘Ÿ π‘π‘Žπ‘Ÿπ‘˜π‘–π‘Ÿ +𝐢
ln
1βˆ’π‘ƒ
𝑃
= 𝛼 π‘˜π‘Žπ‘‘π‘Žπ‘Ÿ π‘π‘Žπ‘Ÿπ‘˜π‘–π‘Ÿ + 𝐢
b)Graf
0.04
0.06
0.10
0.17
0.28
0.39
0.50
0.65
0.75
0.80
0.83
0.86
0.50 1.00 1.50 2.00 2.50 3.00 3.50 4.00 4.50 5.00 5.50 6.00
Kebarangkalian
Peralih
kepada
Pengangkutan
Awam
Kadar Parkir 1 jam
c)Pertukaran Data ke bentuk ln(log e)
Kadar Parkir 1 jam Kebarangkalian(P)
1 βˆ’ 𝑃
𝑃
ln(
1βˆ’π‘ƒ
𝑃
)
0.50 0.04 24.0000 3.1781
1.00 0.06 15.6667 2.7515
1.50 0.10 9.0000 2.1972
2.00 0.17 4.8824 1.5856
2.50 0.28 2.5714 0.9445
3.00 0.39 1.5641 0.4473
3.50 0.50 1.0000 0.0000
4.00 0.65 0.5385 -0.6190
4.50 0.75 0.3333 -1.0986
5.00 0.80 0.2500 -1.3863
5.50 0.83 0.2048 -1.5856
6.00 0.86 0.1628 -1.8153
d) Grag & Persamaan Regressi
y = -0.9623x + 3.5107
RΒ² = 0.9834
-3.0000
-2.0000
-1.0000
0.0000
1.0000
2.0000
3.0000
4.0000
0.00 1.00 2.00 3.00 4.00 5.00 6.00 7.00
LN(1-P)/P
KEBARANGKALIAN
e) Angka-angka parameter fungsi logistik
y = -0.9623(kadar parkir) + 3.5107
𝛼 = 0.9623
C = 3.5107
𝑃 =
1
1+𝑒0.9623 π‘˜π‘Žπ‘‘π‘Žπ‘Ÿ π‘π‘Žπ‘Ÿπ‘˜π‘–π‘Ÿ +3.5107
f) Kebarangkalian Peralihan
Kadar Parkir 1 jam ln(1-P)/P P
0.50 3.1781 0.046109
1.00 2.7515 0.072534
1.50 2.1972 0.112321
2.00 1.5856 0.169933
2.50 0.9445 0.248814
3.00 0.4473 0.348918
3.50 0.0000 0.464398
4.00 -0.6190 0.583826
4.50 -1.0986 0.694162
5.00 -1.3863 0.78597
5.50 -1.5856 0.855937
6.00 -1.8153 0.905775
Soalan 2
a) Fungsi Logistik Sesuai
𝑃 =
1
1+𝑒𝛼 π‘‘π‘Žπ‘šπ‘π‘Žπ‘›π‘” +𝛽(π‘šπ‘Žπ‘ π‘Ž)+𝐢
1βˆ’π‘ƒ
𝑃
= 𝑒𝛼 π‘‘π‘Žπ‘šπ‘π‘Žπ‘›π‘” +𝛽(π‘šπ‘Žπ‘ π‘Ž)+𝐢
ln
1βˆ’π‘ƒ
𝑃
= 𝛼 π‘‘π‘Žπ‘šπ‘π‘Žπ‘›π‘” + 𝛽(π‘šπ‘Žπ‘ π‘Ž) + 𝐢
b)Pertukaran Data kepada ln(log e)
Tambang bas Jimat Masa Kebarangkalian(P)
1 βˆ’ 𝑃
𝑃
ln(
1βˆ’π‘ƒ
𝑃
)
2.90 0 0.10 9.00 2.1972
2.90 5 0.14 6.14 1.8153
2.90 10 0.19 4.26 1.4500
2.90 15 0.25 3.00 1.0986
2.90 20 0.32 2.13 0.7538
2.90 25 0.40 1.50 0.4055
2.90 30 0.48 1.08 0.0800
2.00 20 0.35 1.86 0.6190
2.25 20 0.34 1.94 0.6633
2.50 20 0.33 2.03 0.7082
2.75 20 0.32 2.13 0.7538
3.00 20 0.31 2.23 0.8001
3.25 20 0.31 2.23 0.8001
3.50 20 0.30 2.33 0.8473
3.75 20 0.29 2.45 0.8954
c) Analisis Regressi
SUMMARY OUTPUT
Regression Statistics
Multiple R 0.99964068
R Square 0.99928149
Adjusted R Square 0.99916174
Standard Error 0.01548873
Observations 15
ANOVA
df SS MS F Significance F
Regression 2 4.00378234 2.001891 8344.664 1.37588E-19
Residual 12 0.002878809 0.00024
Total 14 4.006661149
Coefficients Standard Error t Stat P-value Lower 95% Upper 95%
Lower
95.0% Upper 95.0%
Intercept 1.73347185 0.029611002 58.54148 4.08E-16 1.668955015 1.797988677
1.66895501
5 1.797988677
X Variable 1 0.15117974 0.009556105 15.82023 2.11E-09 0.130358776 0.172000703
0.13035877
6 0.172000703
X Variable 2 -0.0704171 0.000549934 -128.046 3.45E-20
-
0.071615309 -0.069218902 -0.07161531 -0.069218902
d)Model logistic dengan parameter
y = 0.15118(tambang) - 0.07042(masa) + 1.73347
𝛼 = 0.15118
𝛽 = βˆ’0.07042
C = 1.73347
𝑃 =
1
1+𝑒0.15118 π‘‘π‘Žπ‘šπ‘π‘Žπ‘›π‘” βˆ’0.07042 π‘šπ‘Žπ‘ π‘Ž +1.,73347

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Tugasan 9 Pisah Ragaman (A168202)

  • 1. LMCP 1352 ASAS-ASAS SAINS DATA DALAM PENGANGKUTAN MODUL 9: TugasanPisahragaman NAMA : SARASVATHI A/P K SIVARAMAN NO MATRIKS:A168202 PENSYARAH : PROF DR RIZA ATIQ ABDULLAH
  • 3. a)Model Fungsi Logistik 𝑃 = 1 1+𝑒𝛼 π‘˜π‘Žπ‘‘π‘Žπ‘Ÿ π‘π‘Žπ‘Ÿπ‘˜π‘–π‘Ÿ +𝐢 1βˆ’π‘ƒ 𝑃 = 𝑒𝛼 π‘˜π‘Žπ‘‘π‘Žπ‘Ÿ π‘π‘Žπ‘Ÿπ‘˜π‘–π‘Ÿ +𝐢 ln 1βˆ’π‘ƒ 𝑃 = 𝛼 π‘˜π‘Žπ‘‘π‘Žπ‘Ÿ π‘π‘Žπ‘Ÿπ‘˜π‘–π‘Ÿ + 𝐢
  • 4. b)Graf 0.04 0.06 0.10 0.17 0.28 0.39 0.50 0.65 0.75 0.80 0.83 0.86 0.50 1.00 1.50 2.00 2.50 3.00 3.50 4.00 4.50 5.00 5.50 6.00 Kebarangkalian Peralih kepada Pengangkutan Awam Kadar Parkir 1 jam
  • 5. c)Pertukaran Data ke bentuk ln(log e) Kadar Parkir 1 jam Kebarangkalian(P) 1 βˆ’ 𝑃 𝑃 ln( 1βˆ’π‘ƒ 𝑃 ) 0.50 0.04 24.0000 3.1781 1.00 0.06 15.6667 2.7515 1.50 0.10 9.0000 2.1972 2.00 0.17 4.8824 1.5856 2.50 0.28 2.5714 0.9445 3.00 0.39 1.5641 0.4473 3.50 0.50 1.0000 0.0000 4.00 0.65 0.5385 -0.6190 4.50 0.75 0.3333 -1.0986 5.00 0.80 0.2500 -1.3863 5.50 0.83 0.2048 -1.5856 6.00 0.86 0.1628 -1.8153
  • 6. d) Grag & Persamaan Regressi y = -0.9623x + 3.5107 RΒ² = 0.9834 -3.0000 -2.0000 -1.0000 0.0000 1.0000 2.0000 3.0000 4.0000 0.00 1.00 2.00 3.00 4.00 5.00 6.00 7.00 LN(1-P)/P KEBARANGKALIAN
  • 7. e) Angka-angka parameter fungsi logistik y = -0.9623(kadar parkir) + 3.5107 𝛼 = 0.9623 C = 3.5107 𝑃 = 1 1+𝑒0.9623 π‘˜π‘Žπ‘‘π‘Žπ‘Ÿ π‘π‘Žπ‘Ÿπ‘˜π‘–π‘Ÿ +3.5107
  • 8. f) Kebarangkalian Peralihan Kadar Parkir 1 jam ln(1-P)/P P 0.50 3.1781 0.046109 1.00 2.7515 0.072534 1.50 2.1972 0.112321 2.00 1.5856 0.169933 2.50 0.9445 0.248814 3.00 0.4473 0.348918 3.50 0.0000 0.464398 4.00 -0.6190 0.583826 4.50 -1.0986 0.694162 5.00 -1.3863 0.78597 5.50 -1.5856 0.855937 6.00 -1.8153 0.905775
  • 10. a) Fungsi Logistik Sesuai 𝑃 = 1 1+𝑒𝛼 π‘‘π‘Žπ‘šπ‘π‘Žπ‘›π‘” +𝛽(π‘šπ‘Žπ‘ π‘Ž)+𝐢 1βˆ’π‘ƒ 𝑃 = 𝑒𝛼 π‘‘π‘Žπ‘šπ‘π‘Žπ‘›π‘” +𝛽(π‘šπ‘Žπ‘ π‘Ž)+𝐢 ln 1βˆ’π‘ƒ 𝑃 = 𝛼 π‘‘π‘Žπ‘šπ‘π‘Žπ‘›π‘” + 𝛽(π‘šπ‘Žπ‘ π‘Ž) + 𝐢
  • 11. b)Pertukaran Data kepada ln(log e) Tambang bas Jimat Masa Kebarangkalian(P) 1 βˆ’ 𝑃 𝑃 ln( 1βˆ’π‘ƒ 𝑃 ) 2.90 0 0.10 9.00 2.1972 2.90 5 0.14 6.14 1.8153 2.90 10 0.19 4.26 1.4500 2.90 15 0.25 3.00 1.0986 2.90 20 0.32 2.13 0.7538 2.90 25 0.40 1.50 0.4055 2.90 30 0.48 1.08 0.0800 2.00 20 0.35 1.86 0.6190 2.25 20 0.34 1.94 0.6633 2.50 20 0.33 2.03 0.7082 2.75 20 0.32 2.13 0.7538 3.00 20 0.31 2.23 0.8001 3.25 20 0.31 2.23 0.8001 3.50 20 0.30 2.33 0.8473 3.75 20 0.29 2.45 0.8954
  • 12. c) Analisis Regressi SUMMARY OUTPUT Regression Statistics Multiple R 0.99964068 R Square 0.99928149 Adjusted R Square 0.99916174 Standard Error 0.01548873 Observations 15 ANOVA df SS MS F Significance F Regression 2 4.00378234 2.001891 8344.664 1.37588E-19 Residual 12 0.002878809 0.00024 Total 14 4.006661149 Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0% Intercept 1.73347185 0.029611002 58.54148 4.08E-16 1.668955015 1.797988677 1.66895501 5 1.797988677 X Variable 1 0.15117974 0.009556105 15.82023 2.11E-09 0.130358776 0.172000703 0.13035877 6 0.172000703 X Variable 2 -0.0704171 0.000549934 -128.046 3.45E-20 - 0.071615309 -0.069218902 -0.07161531 -0.069218902
  • 13. d)Model logistic dengan parameter y = 0.15118(tambang) - 0.07042(masa) + 1.73347 𝛼 = 0.15118 𝛽 = βˆ’0.07042 C = 1.73347 𝑃 = 1 1+𝑒0.15118 π‘‘π‘Žπ‘šπ‘π‘Žπ‘›π‘” βˆ’0.07042 π‘šπ‘Žπ‘ π‘Ž +1.,73347