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Throw energy in white and black
1. Name: Hammad Ur Rehman
Reg. no.: me131013
Teacher’s name: Dr. Eng. kashif khan
THROW ENERGY IN WHITE AND BLACK
Abstract:
A daily life observation for an engineer is not just as simple as it is for a non-engineer personal an engineer perceive different physical phenomenon’s as with some certain first principle laws in actions.
For example the boat floating over the sea water is the balance between buoyant force and weight of the boat to an engineer, a cooking food is a combustion process for an engineer, throwing something on a curved path is the projectile motion to the engineer.
Observations as an engineer:
An engineer while observing the dynamical system first of all think about the energies related to the motion because this limits the “how much of a motion”, then he go further in analyzing the path , acceleration and velocity….
Examples:
Cricketer shoaib Akhtar:
He is the fastest bowler in the history of cricket. He has the record of 161.3 kmph of bowling speed against England in 2003 world cup , as an engineer I would like to estimate the amount of work that shoaib Akhtar could have done to achieve this remarkable speed in that particular bowling action.
I perceive it as the kinetic energy change of the ball from rest to 161kmph in air, neglecting frictional effects.
푖푛푖푡푖푎푙 푐표푛푑.+푤표푟푘 푑표푛푒=푓푖푛푎푙 푐표푛푑. 푊= 푚푣22− 푚푢22
Where,
V= final velocity u= initial velocity mass of the ball
M=163 gm
Final velocity V=44.8055 m/s
U=0 푊=163610.274 푗표푢푙푒푠 푊=163.61 퐾퐽
Usain bolt:
To be the world fastest man is indeed a great achievement but again for an engineer it’s only the matter of intense energy deception, the world’s fastest man Usain bolt who ran 100m race in 9.58 sec.
An assumption that Usain bolt runs so fast that he has almost zero contact between his shoes and track.
2. 푊표푟푘+푖푛푖푡푖푎푙 푐표푛푑.=푓푖푛푎푙 푐표푛푑. 푊= 푚푣22− 푚푢22
Where,
V=st , s here 100 m track and track time is t=9.58 sec.
U=0, mass of Usain bolt m=94Kg
푊= 94(100∗9.58)22 푊=4.3134908푥1010 푗표푢푙푒푠
Talking about some dark side of the picture:
Protestor’s chaos management:
Now as the engineer we have to take actions in the chaos like protests, or aggressive rock throwers, then engineers have to see this as the energy packets thrown to the protestors, an engineer finding the solution for the cop’s tactic shield manufacturing he will at once go analyze the situation as the stones energy: 푊표푟푘+푖푛푖푡푖푎푙 푐표푛푑.=푓푖푛푎푙 푐표푛푑. 푊= 푚푣22− 푚푢22
Where,
V=final velocity of stone.
m= mass of stone
1. Now for this situation an engineer can use his previous knowledge of controlled state as of a bowler throwing the ball or a weight throw.
2. He then estimate that how much a normal person as compares to athlete could throw things.
Now we know that this particular example could be more accurately extracted from the weight throwing in which an athlete throw weight to a particular distance, we will make that weight a 1/8-1/4 amount of weight thrown by athlete and take the same distance for that.
Taking the distance for the stone to be 19m – 20 m, as in the game.
Therefore. 푊= 500(20∗4)22 푊=16000000 푗표푢푙푒푠 Now in the protest there are 10s of such rocks are thrown towards the cops shield so engineer will just multiply the above energy by the no. of rocks and could estimate the material requirements for the shield.
3. Conclusion:
Engineer is someone who finds the mechanisms out of the simple physical phenomenon and device them in such way that they could then perform the same task in more efficient, meaningful and right way.