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CHAPTER THREE
UNIFORM FLOW
1
Concept of Uniform Flow
• Uniform flow is referring the steady uniform flow
• Steady flow is characterized by no changes in time.
• Uniform flow is characterized by the water cross section and depth
remaining constant over a certain reach of the channel.
• For any channel of given roughness, cross section and slope, there exists
only one water depth, called the normal depth , at which the flow will be
uniform.
• Uniform equilibrium flow can occur only in a straight channel with a
constant channel slope and cross-sectional shape, and a constant
discharge.
• The energy grade line Sf, water surface slope Sw and channel bed slope S0 are
all parallel, i.e. Sf=Sw=So
2
Concept of Uniform…
• A flow is said to be uniform if its properties remain constant
with respect to distance.
• For steady uniform flow Q=AV, it follows that in uniform flow
V1=V2=V. thus in uniform flow, depth of flow, area of cross section
and velocity of flow remain constant along the channel.
• It is obvious that uniform flow is possible only in prismatic (artificial)
channels.
3
Establishment of uniform flow
• When flow occurs in an open channel, resistance is encountered by the water
as it flows downstream.
• A uniform flow will be developed if the resistance is balanced by the
gravity forces.
• If water enter a channel slowly, velocity and the resistance are small,
and the resistance is out balanced by the gravity forces resulting in an
accelerating flow in the upstream reach.
• The velocity and the resistance will gradually increase until a
balance between resistance and gravity forces is reached. At this
moment and afterward the flow becomes uniform.
• The upstream reach that is required for the establishment of
uniform flow is known as the transitory zone.
4
The Chezy Formula
• There is no acceleration in uniform flow.
• By applying the momentum equation to control volume encompassing
sections 1 and 2, distance L apart as shown in figure below
6
7
The equation expressed in eq above is called Chezy Equation and the coefficient
also called Chezy coefficient
We know the Darcy –Weisbach equation in the pipe flow expressed as
8
Determination of
Chezy resistance
factor
• Several forms of expressions for the Chezy
coefficient C have been proposed by different
investigations in the past. A few selected ones are
selected below:
9
10
11
Example 3.1: A 2.0m wide rectangular channel carries water at 20oc at a depth of 0.5m. The
channel is laid on a slope of 0.0004. Find the hydrodynamic nature of the surface if the channel
is made of
A. Very smooth concrete
B. Rough concrete
C. Estimate the discharges in the channel in both case using Chezy formula with
Dancy-Weisbach f.
Solution:
12
Since Re is known we use the moody chart or iterative trial and
error methods, we get
The MANNING’S
Formula
• The simplest resistance formula and the most
widely used equation for the mean velocity
calculation is the Manning equation which has
been derived by Robert Manning (1890) by
analyzing the experimental data obtained from
his own experiments and from those of others. His
equation is,
13
• In the Manning’s formula, all the terms except n are
capable of direct measurement.
• The roughness coefficient, being a parameter representing
the integrated effect of the channel cross sectional
resistance, is to be estimated.
• The selection of a value for n is subjective, based on
one’s experience and engineering judgments.
• However, a few aids are available which reduce to a certain
extent the subjectiveness in the selection of an
appropriate value of n for a given channel.
• A compressive list of various types of channels, there
descriptions with the associated range of values of n
14
Factors Affecting Manning’s Roughness Coefficient
– Surface Roughness
– Vegetation
– Channel Irregularity
– Channel Alignment
– Silting and Scouring
– Obstruction
– Size and Shape of the Channel
– Stage and Discharge
– Seasonal Change
16
UNIFORM FLOW COMPUTATION
• Discharge and Velocity
• Hydraulic Radius
• Normal Depth
• Hydraulically Efficient Cross-section
• Compound section
• Critical slope
19
Discharge and Velocity
Chezy Equation
Manning equation
Where K= 1/nAR2/3 is called Conveyance of the channel
Or
If equating it as, nk= AR2/3 , it is called the section factor
for uniform, flow
Q  C A R S o
2 / 3 1 / 2
1
n
o
A R S
Q  o
Q  K S
20
Composite roughness of channels
• In some channels different parts of the channel
perimeter may have different roughness.
• Canals, in which only the sides are lined, laboratory
flumes with glass walls and rough beds, rivers with a
sand bed in deep water portion and flood plains covered
with vegetation, are some typical examples.
• For such channels it is necessary to determine an
equivalent roughness, a coefficient that can be applied
to the entire cross-sectional perimeter in using the
Manning’s formula.
• This equivalent roughness, also called the composite
roughness, represents a weighted average value for the
roughness coefficient.
• One such method of calculations of equivalent
roughness is given below. 21
• Consider a channel having its perimeter composed of N
types of roughness P1, P2, P3… PN are the lengths of these
N parts and n1, n2 n3 are the respective roughness
coefficients. Let each part Pi be associated with a partial
area Ai such that:
Fig 3.1 multi-roughness type section 22
• It is assumed that the mean velocity in each partial area is
the mean velocity V for the entire flow of the area,
i.e. 𝑉1= 𝑉2= 𝑉3= ⋯ 𝑉𝑖 = 𝑉𝑁= 𝑉
By manning’s formula
Where n is equivalent roughness.
• This equation affords a means of estimating the equivalent
roughness of a channel having multiple roughness types in
its perimeter
23
Example 3.2:An earthen trapezoidal channel (n=0.025) has a bottom width of 5.0 m,
side slopes of 1.5 horizontal: 1 vertical and a uniform flow depth of 1.10 m. In an
economic study to remedy excessive seepage from the canal, two proposals, a) to line
the sides only and, b) to line the bed only are considered. If the lining is of smooth
concrete (n=0.012), calculate the equivalent roughness in the above two cases.
24
Solution:
Earthen (n) = 0.025
B = 5.0m
m= 1.5
y = 1.10m
a). line the sides only
b). line the bed only
lining (n) = 0.012
Case a): Lining on the sides only,
Case b): Lining on the bottom only
25
Hydraulic Radius
Deep Channel Wide Channel
for narrow deep cross-sections
R≈ B/2.
Wide shallow rectangular cross-sections
R≈y
With 𝒚𝟎/𝑩˂ 𝟎. 𝟎𝟐
26
Computation of normal depth
Rectangular Channel
wide Rectangular Channel (y0/B < 0.02 )
• Considering a unit width of a wide rectangular channel,
B = 1.0,  A= yo , and Q/B = q
R = yo
Rectangular Channel with y0/B > 0.02 )
27
Trapezoidal Channel
28
30
Example 3.3 A standard lined trapezoidal cannel section is to be designed to convey
100m3/sec of flow. The side slope is to be 1.5H:1V and the manning’s coefficient n=
0.016. The longitudinal slope of the bed is 1 in 5000m. Ifa bed width of 10m is preferred
what would be the normal depth?
Solution
Q= 100m3/sec
m= 1.5
n= 0.016
So= 0.0002
B= 10m
yo=?
The Hydraulic Efficient Channel Section
The best hydraulic (the most efficient) cross-section for a given Q, n,
and S0 is the one with a minimum excavation and minimum lining
cross-section.
A = Amin  P = Pmin.
In other case the best hydraulic cross-section for a given A, n, and S0 is
the cross-section that conveys maximum discharge.
Thus, the cross-section with the minimum wetted perimeter for a
given discharge Q and area A is consider the best hydraulic cross-
section
31
The Hydraulic Efficient …..
a. Rectangular channel section
32
Trapezoidal Channel Section
33
34
a). For a given side slope m, what will be the water depth y for best hydraulic trapezoidal
cross section?
For a given A, P = Pmin
The hydraulic radius R, channel bottom width B,
and free surface width L may be found as,
35
b). For a given water depth y, what will be the side slope m for best hydraulic trapezoidal
cross section?
• B is equal to one third of P
• Sides length and B are
equal since α= 600, i.e. the
cross-section is half of the
hexagon.
36
Table: values of parameters in Efficient (best) hydraulic section
Compound Sections
37
• Some channel sections may be formed as a combination of
elementary sections. Typical natural channels, such as rivers,
have flood plains which are wide and shallow compared to the
deep main Channel.
• The figure below represents a simplified section of a stream
with flood banks in which channel of such kind is known as
compound sections.
Figure: compound section
• Longitudinal slope to be same for all subsections
• Subsections will have different mean velocities depending upon the
depth and roughness of the boundaries
• If the depth of flow is confined to the deep channel only (y < h),
calculation of discharge by using Manning’s equation is very simple.
• However, when the flow spills over the flood plain (y > h), the problem
of discharge calculation is complicated 38
• Consider the compound section to be divided into subsections by
arbitrary lines.
• These can be either extensions for the deep channel boundaries
as in the figure above or vertical lines drawn at the edge of the
deep channels.
Thus, to compute the discharge when Y < h
– Calculate wetted perimeter for each sub-areas, but the imaginary
divisions (FJ and CK in the Figure) are considered as boundaries for
the deeper portion only
– Calculate the discharge as the sum of the partial discharges in the
sub-areas
– The discharge is also calculated by considering the whole section
as one unit, (ABCDEFGH area in Figure), say Qw
– The larger of the above discharges, Qp and Qw, is adopted as the
discharge at the depth y 39
Critical slope (Sc)
Critical slope is the slope of a specified channel necessary to have
uniform flow of a given discharge with critical depth as normal
depth
If we consider rectangular
channel
If Sc > So  Yo > Yc  Subcritical flow  mild slope channel
If Sc < So  Yo < Yc  Supercritical flow  Steep slope channel
If Sc = So  Yo = Yc  Critical flow  Critical slope channel
2 4/3
n2
Q2
2/3 1/ 2
c
1
n
Ac Rc
Sc 
c c S
A R
Q 
q2/9
n2
g10/ 9
c
S 
40
Design of Irrigation Canal
• Designed based on rules and equations uniform flow
• A and R the geometric elements that must consider in the
design process
• General the design of the canal governed with the
relation below which has six variables one dependent
and other independent.
• Each variables should be known either explicitly or
implicitly, or as inequalities, mostly in terms of empirical
relationships
41
Design of Irrigation …
• Roughness coefficient ( n )
– Procedures for selecting n are discussed and values of n can be
taken from Table (4.4)
• Longitudinal Slope (So)
– The longitudinal slope is fixed on the basis of topography to
command as much area as possible with the limiting velocities
acting as constraints. Usually, the slopes are of the order of
0.0001.
• Canal Section (m)
– Normally a trapezoidal section is adopted. The side slope,
expressed as m horizontal: 1 vertical, depends on the type of
canal, (i.e. lined or unlined, nature and type of soil through
which the canal is laid).
– m can be in the range of 0.25 -2 based on the material it is
recommended 1.0 -1.5 for natural soil.
42
Design of Irrigation …
• Width to Depth Ratio (B/y)
– The relationship between width and depth varies widely
depending upon the design practice. If the hydraulically most-
efficient channel cro ss-section is adopted,
– For other section
– Usually, depths higher than 4.0 m is not recommended unless it is it is necessary.
• Free Board
yo
B
 2( 1 m2
 m)
43
Design of Irrigation …
• Procedures
 Start with B/y ratio and compute width (B), area (A), and
hydraulics radius (R) , interims of depth (y)
 substitute the values in discharge equation
 Solve the equation for y, if the value of y < 4 acceptable
 Compute the area and the velocity, if the V < Vp acceptable
If not take the maximum permissible velocity
and then compute the area.
Using the area compute the depth if it in the
acceptable
range
Compute the width and the side slope to fix the design elements
If not proceed to adjust the side slop of the canal
If doesn’t work test on the longitudinal slope
44

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3.uniform flow.pptx

  • 2. Concept of Uniform Flow • Uniform flow is referring the steady uniform flow • Steady flow is characterized by no changes in time. • Uniform flow is characterized by the water cross section and depth remaining constant over a certain reach of the channel. • For any channel of given roughness, cross section and slope, there exists only one water depth, called the normal depth , at which the flow will be uniform. • Uniform equilibrium flow can occur only in a straight channel with a constant channel slope and cross-sectional shape, and a constant discharge. • The energy grade line Sf, water surface slope Sw and channel bed slope S0 are all parallel, i.e. Sf=Sw=So 2
  • 3. Concept of Uniform… • A flow is said to be uniform if its properties remain constant with respect to distance. • For steady uniform flow Q=AV, it follows that in uniform flow V1=V2=V. thus in uniform flow, depth of flow, area of cross section and velocity of flow remain constant along the channel. • It is obvious that uniform flow is possible only in prismatic (artificial) channels. 3
  • 4. Establishment of uniform flow • When flow occurs in an open channel, resistance is encountered by the water as it flows downstream. • A uniform flow will be developed if the resistance is balanced by the gravity forces. • If water enter a channel slowly, velocity and the resistance are small, and the resistance is out balanced by the gravity forces resulting in an accelerating flow in the upstream reach. • The velocity and the resistance will gradually increase until a balance between resistance and gravity forces is reached. At this moment and afterward the flow becomes uniform. • The upstream reach that is required for the establishment of uniform flow is known as the transitory zone. 4
  • 5. The Chezy Formula • There is no acceleration in uniform flow. • By applying the momentum equation to control volume encompassing sections 1 and 2, distance L apart as shown in figure below 6
  • 6. 7
  • 7. The equation expressed in eq above is called Chezy Equation and the coefficient also called Chezy coefficient We know the Darcy –Weisbach equation in the pipe flow expressed as 8
  • 8. Determination of Chezy resistance factor • Several forms of expressions for the Chezy coefficient C have been proposed by different investigations in the past. A few selected ones are selected below: 9
  • 9. 10
  • 10. 11 Example 3.1: A 2.0m wide rectangular channel carries water at 20oc at a depth of 0.5m. The channel is laid on a slope of 0.0004. Find the hydrodynamic nature of the surface if the channel is made of A. Very smooth concrete B. Rough concrete C. Estimate the discharges in the channel in both case using Chezy formula with Dancy-Weisbach f. Solution:
  • 11. 12 Since Re is known we use the moody chart or iterative trial and error methods, we get
  • 12. The MANNING’S Formula • The simplest resistance formula and the most widely used equation for the mean velocity calculation is the Manning equation which has been derived by Robert Manning (1890) by analyzing the experimental data obtained from his own experiments and from those of others. His equation is, 13
  • 13. • In the Manning’s formula, all the terms except n are capable of direct measurement. • The roughness coefficient, being a parameter representing the integrated effect of the channel cross sectional resistance, is to be estimated. • The selection of a value for n is subjective, based on one’s experience and engineering judgments. • However, a few aids are available which reduce to a certain extent the subjectiveness in the selection of an appropriate value of n for a given channel. • A compressive list of various types of channels, there descriptions with the associated range of values of n 14
  • 14. Factors Affecting Manning’s Roughness Coefficient – Surface Roughness – Vegetation – Channel Irregularity – Channel Alignment – Silting and Scouring – Obstruction – Size and Shape of the Channel – Stage and Discharge – Seasonal Change 16
  • 15. UNIFORM FLOW COMPUTATION • Discharge and Velocity • Hydraulic Radius • Normal Depth • Hydraulically Efficient Cross-section • Compound section • Critical slope 19
  • 16. Discharge and Velocity Chezy Equation Manning equation Where K= 1/nAR2/3 is called Conveyance of the channel Or If equating it as, nk= AR2/3 , it is called the section factor for uniform, flow Q  C A R S o 2 / 3 1 / 2 1 n o A R S Q  o Q  K S 20
  • 17. Composite roughness of channels • In some channels different parts of the channel perimeter may have different roughness. • Canals, in which only the sides are lined, laboratory flumes with glass walls and rough beds, rivers with a sand bed in deep water portion and flood plains covered with vegetation, are some typical examples. • For such channels it is necessary to determine an equivalent roughness, a coefficient that can be applied to the entire cross-sectional perimeter in using the Manning’s formula. • This equivalent roughness, also called the composite roughness, represents a weighted average value for the roughness coefficient. • One such method of calculations of equivalent roughness is given below. 21
  • 18. • Consider a channel having its perimeter composed of N types of roughness P1, P2, P3… PN are the lengths of these N parts and n1, n2 n3 are the respective roughness coefficients. Let each part Pi be associated with a partial area Ai such that: Fig 3.1 multi-roughness type section 22
  • 19. • It is assumed that the mean velocity in each partial area is the mean velocity V for the entire flow of the area, i.e. 𝑉1= 𝑉2= 𝑉3= ⋯ 𝑉𝑖 = 𝑉𝑁= 𝑉 By manning’s formula Where n is equivalent roughness. • This equation affords a means of estimating the equivalent roughness of a channel having multiple roughness types in its perimeter 23
  • 20. Example 3.2:An earthen trapezoidal channel (n=0.025) has a bottom width of 5.0 m, side slopes of 1.5 horizontal: 1 vertical and a uniform flow depth of 1.10 m. In an economic study to remedy excessive seepage from the canal, two proposals, a) to line the sides only and, b) to line the bed only are considered. If the lining is of smooth concrete (n=0.012), calculate the equivalent roughness in the above two cases. 24 Solution: Earthen (n) = 0.025 B = 5.0m m= 1.5 y = 1.10m a). line the sides only b). line the bed only lining (n) = 0.012 Case a): Lining on the sides only,
  • 21. Case b): Lining on the bottom only 25
  • 22. Hydraulic Radius Deep Channel Wide Channel for narrow deep cross-sections R≈ B/2. Wide shallow rectangular cross-sections R≈y With 𝒚𝟎/𝑩˂ 𝟎. 𝟎𝟐 26
  • 23. Computation of normal depth Rectangular Channel wide Rectangular Channel (y0/B < 0.02 ) • Considering a unit width of a wide rectangular channel, B = 1.0,  A= yo , and Q/B = q R = yo Rectangular Channel with y0/B > 0.02 ) 27
  • 25. 30 Example 3.3 A standard lined trapezoidal cannel section is to be designed to convey 100m3/sec of flow. The side slope is to be 1.5H:1V and the manning’s coefficient n= 0.016. The longitudinal slope of the bed is 1 in 5000m. Ifa bed width of 10m is preferred what would be the normal depth? Solution Q= 100m3/sec m= 1.5 n= 0.016 So= 0.0002 B= 10m yo=?
  • 26. The Hydraulic Efficient Channel Section The best hydraulic (the most efficient) cross-section for a given Q, n, and S0 is the one with a minimum excavation and minimum lining cross-section. A = Amin  P = Pmin. In other case the best hydraulic cross-section for a given A, n, and S0 is the cross-section that conveys maximum discharge. Thus, the cross-section with the minimum wetted perimeter for a given discharge Q and area A is consider the best hydraulic cross- section 31
  • 27. The Hydraulic Efficient ….. a. Rectangular channel section 32
  • 29. 34 a). For a given side slope m, what will be the water depth y for best hydraulic trapezoidal cross section? For a given A, P = Pmin The hydraulic radius R, channel bottom width B, and free surface width L may be found as,
  • 30. 35 b). For a given water depth y, what will be the side slope m for best hydraulic trapezoidal cross section? • B is equal to one third of P • Sides length and B are equal since α= 600, i.e. the cross-section is half of the hexagon.
  • 31. 36 Table: values of parameters in Efficient (best) hydraulic section
  • 32. Compound Sections 37 • Some channel sections may be formed as a combination of elementary sections. Typical natural channels, such as rivers, have flood plains which are wide and shallow compared to the deep main Channel. • The figure below represents a simplified section of a stream with flood banks in which channel of such kind is known as compound sections. Figure: compound section
  • 33. • Longitudinal slope to be same for all subsections • Subsections will have different mean velocities depending upon the depth and roughness of the boundaries • If the depth of flow is confined to the deep channel only (y < h), calculation of discharge by using Manning’s equation is very simple. • However, when the flow spills over the flood plain (y > h), the problem of discharge calculation is complicated 38 • Consider the compound section to be divided into subsections by arbitrary lines. • These can be either extensions for the deep channel boundaries as in the figure above or vertical lines drawn at the edge of the deep channels.
  • 34. Thus, to compute the discharge when Y < h – Calculate wetted perimeter for each sub-areas, but the imaginary divisions (FJ and CK in the Figure) are considered as boundaries for the deeper portion only – Calculate the discharge as the sum of the partial discharges in the sub-areas – The discharge is also calculated by considering the whole section as one unit, (ABCDEFGH area in Figure), say Qw – The larger of the above discharges, Qp and Qw, is adopted as the discharge at the depth y 39
  • 35. Critical slope (Sc) Critical slope is the slope of a specified channel necessary to have uniform flow of a given discharge with critical depth as normal depth If we consider rectangular channel If Sc > So  Yo > Yc  Subcritical flow  mild slope channel If Sc < So  Yo < Yc  Supercritical flow  Steep slope channel If Sc = So  Yo = Yc  Critical flow  Critical slope channel 2 4/3 n2 Q2 2/3 1/ 2 c 1 n Ac Rc Sc  c c S A R Q  q2/9 n2 g10/ 9 c S  40
  • 36. Design of Irrigation Canal • Designed based on rules and equations uniform flow • A and R the geometric elements that must consider in the design process • General the design of the canal governed with the relation below which has six variables one dependent and other independent. • Each variables should be known either explicitly or implicitly, or as inequalities, mostly in terms of empirical relationships 41
  • 37. Design of Irrigation … • Roughness coefficient ( n ) – Procedures for selecting n are discussed and values of n can be taken from Table (4.4) • Longitudinal Slope (So) – The longitudinal slope is fixed on the basis of topography to command as much area as possible with the limiting velocities acting as constraints. Usually, the slopes are of the order of 0.0001. • Canal Section (m) – Normally a trapezoidal section is adopted. The side slope, expressed as m horizontal: 1 vertical, depends on the type of canal, (i.e. lined or unlined, nature and type of soil through which the canal is laid). – m can be in the range of 0.25 -2 based on the material it is recommended 1.0 -1.5 for natural soil. 42
  • 38. Design of Irrigation … • Width to Depth Ratio (B/y) – The relationship between width and depth varies widely depending upon the design practice. If the hydraulically most- efficient channel cro ss-section is adopted, – For other section – Usually, depths higher than 4.0 m is not recommended unless it is it is necessary. • Free Board yo B  2( 1 m2  m) 43
  • 39. Design of Irrigation … • Procedures  Start with B/y ratio and compute width (B), area (A), and hydraulics radius (R) , interims of depth (y)  substitute the values in discharge equation  Solve the equation for y, if the value of y < 4 acceptable  Compute the area and the velocity, if the V < Vp acceptable If not take the maximum permissible velocity and then compute the area. Using the area compute the depth if it in the acceptable range Compute the width and the side slope to fix the design elements If not proceed to adjust the side slop of the canal If doesn’t work test on the longitudinal slope 44