he evolution of eukaryotic cells most likely occurred in many steps- O.pdf

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he evolution of eukaryotic cells most likely occurred in many steps. Outline the steps that may have occurred beginning with the formation of biological molecules and ending in compler ructures observed in eukaryotic cells today. rag the terms on the left to the appropriate blanks on the right to complete the sentences. Answers should include phases or steps such as (1) abiotic synthesis of molecules under hot, reducing conditions; (2) polymerization of molecules into nucleic acids and (students also include that may have been the first informational molecule and biological catalyst); (3) encapsulation of polymers in a simple membrane; (4) endosymbiosis of smaller cells (bacteria) inside a larger cell to form membrane- bound organelles such as mitochondria and.

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Having passed your board exam, you are now qualified to work in the pathology lab as the Attending Pathologist. You are given a sample of cells and told that the new COVID-19 assay, using INDO-AM, allows you to measure Ca2+ mobilization, as the cells become infected. The head of medicine has asked you to let her know if the newest isolate is infecting the cells more or less rapidly than the older one. You will use which of the following approaches to detect mobilization of Ca 2 + in the recipient cells? A. Transwell chemotaxis assay B. Luminex C. ELISA D. fluoroskan E. Affinity Measurements QUESTION 3 Recently, scientists have discovered three people with ultra immune systems. It seems that these people are able to ward off diseases due to the ability of their neutrophils to migrate quickly over large distance. Which of the following assays would you used to determine if neutrophils isolated from your patients were able to migrate quickly over long distances as well? A. under agarose chemotaxis assay B. luminex bead assay C. Phospolipase C Na + mobilization assay D. repetitive chemotaxis desensitizing assay E. dominant negative polar migration assay.

Having passed your board exam- you are now qualified to work in the pa.pdf

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Having been lost in the desert for 2 days without water- Marion is bad.pdf

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Harvard Case Study: Humana's Bold Goal: 20 Percent Healthier by 2020 "Beginning in 2013, Humana Inc., headquartered in Louisville, Kentucky, pursued a major organizational transformation, from being an insurance company focused on paying claims to becoming a health and well-being company focused on improving the health of its beneficiaries. The company set a "Bold Goal" of improving the health of the communities it served by 20% by 2020. To achieve this new goal, Humana undertook a multiyear redesign and investment of people, processes, and products in order to gain the trust of consumers and providers, and to partner with communities to improve health. The case focuses on community initiatives, where Humana was developing its new role as "convener of conversations," providing leadership infrastructure and partial funding to spark community planning with a wide range of stakeholders and to design and monitor interventions that were tailored to local health improvement. At the same time, Humana remained a publicly-held corporation accountable to its shareholders for revenue growth and financial return." 1. Describe population health improvement from the perspective of a health insurer. 2. Explain how to design a strategic performance measurement system for community health improvement. 3. Discuss the relationship between traditional business strategy and community health improvement, and the various channels or activities through which business can successfully improve community and worker health..

Harvard Case Study- Humana's Bold Goal- 20 Percent Healthier by 2020 -.pdf

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Harry climbed a ladder to trim some trees- While bending too fast- he.pdf

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HELP, Add button wont work?, i would click on the button and that page would contuine to load but not go anywhere but dont go anywhere. // modules required for routing import \{ Router \} from "express"; import \{ displayAddPage, displayBookList, displayEditPage, processAddPage, processDelete, pr const router = Router(); /* GET books List page. READ */ router.get('/books/list', displayBookList); // GET the Book Details page in order to add a new Book router.get('/add', displayAddPage); // POST process the Book Details page and create a new Book - CREATE router.post('/add', processAddPage); I/ GET the Book Details page in order to edit an existing Book router.get('/books/edit/:id', displayeditPage); I/ POST - process the information passed from the details form and update the document router.post('/books/edit/:id', processeditPage); // GET - process the delete by user id router. get('/books/delete/:id', processDelete);.

HELP- Add button wont work-- i would click on the button and that page.pdf

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Help with this substitution program, line 3 of the output is different than it should be and I can't find the reaso why. Here's the code, the input file, and the output file. #include "cipher.h" /* Cheshire smile implementation. It only contains the cipher alphabet */ struct Cipher::CipherCheshire { string cipher_alpha; }; /* This function checks the cipher alphabet to make sure it's valid */ bool is_valid_alpha(string alpha); // ------------------------------------------------------- // Cipher implementation /* Default constructor This will actually not encrypt the input text because it's using the unscrambled alphabet */ Cipher::Cipher() { // TODO: Implement this default constructor smile = new CipherCheshire(); smile->cipher_alpha = "zyxwvutsrqponmlkjihgfedcba"; } /* This constructor initiates the object with a input cipher key */ Cipher::Cipher(string cipher_alpha) { // TODO: Implement this constructor smile - new CipherCheshire(); if (is_valid_alpha(cipher_alpha)) { smile->cipher_alpha = cipher_alpha; } else { cout << "Invalid alpha" << endl; exit(EXIT_FAILURE); } } /* Destructor */ Cipher::~Cipher() { // TODO: Implement this constructor delete(smile); } /* This member function encrypts the input text using the intialized cipher key */ string Cipher::encrypt(string raw) { cout << "Encrypting..."; string retStr = ""; char ch, tmp; int pos; int i; int size = raw.length(); // TODO: Finish this function for (i = 0; i < size; i++) { tmp = ' '; ch = raw.at(i); if (ch != ' ') { por = find_pos(smile->cipher_alpha, ch) if (ch >= 65 && ch <= 90) { tmp = 65 + pos; } else { tmp = 97 + pos; } } retStr += tmp; } cout << "Done" << endl; return retStr; } /* This member function decrypts the input text using the intialized cipher key */ string Cipher::decrypt(string enc) { string retStr = ""; char ch, tmp; int pos; int i; int size = enc.length(); cout << "Decrypting..."; // TODO: Finish this function for (i = 0; i < size; i++) { tmp = ' '; ch = enc.at(i); if (ch != ' ') { pos = find_pos(smile->cipher_alpha, ch); if (ch >= 65 && ch <= 90) { tmp = 65 + pos; } else { tmp = 97 + pos; } } retStr += tmp; } cout << "Done" << endl; return retStr; } // ------------------------------------------------------- // Helper functions /* Find the character c's position in the cipher alphabet/key */ unsigned int find_pos(string alpha, char c) { unsigned int pos = 0; int i; int size = alpha.length(); // TODO: You will likely need this function. Finish it. char ch = tolower(c); for (i = 0; i < size; i++) { if (ch == alpha.at(i)) { por = i; break; } } return pos; } /* Make sure the cipher alphabet is valid - a) it must contain every letter in the alphabet b) it must contain only one of each letter c) it must be all lower case letters ALL of the above conditions must be met for the text to be a valid cipher alphabet. */ bool is_valid_alpha(string alpha) { bool is_valid = true; if(alpha.size() != ALPHABET_SIZE) { is_valid = false; } else { unsigned int letter_exists[ALPHABET_S.

Help with this substitution program- line 3 of the output is different.pdf

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help The following information pertains to Ming Corp. at January 1, Year 2: Ming Corp. completed the following transactions during Year 2: 1. Issued 2,200 shares of $11 par common stock for $16 per share. 2. Repurchased 1,900 shares of its own common stock for $19 per share. 3. Resold 1,140 shares of treasury stock for $21 per share. 4. Earned $53 , 500 of cash revenue. 5. Paid $40 , 750 of cash operating expenses. Required Prepare the stockholders' equity section of the year- end balance sheet..

help The following information pertains to Ming Corp- at January 1- Ye.pdf

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Help please! 1. You are wanting to know how many sloths are in a population in Costa Rica using the Lincoln Index (capture-mark-recapture) Method. The first time you go out, you capture 15 sloths and mark each with a band. The second time you go out, you capture 10 but 7 of them are recaptures. What is the estimated abundance of this population? 2. There are 400 frogs in a population. 250 are brown (dominant, BB/Bb) and the rest are green (recessive, bb). What are the allele and genotype frequencies?.

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help Required information Use the following information for the Exercises below. (Algo) [The following information applies to the questions displayed below.] On December 1, Jasmin Ernst organized Ernst Consulting. On December 3, the owner contributed $85 , 050 in assets in exchange for its common stock to launch the business. On December 31 , the company's records show the following items and amounts. Exercise 1-19 (Algo) Preparing a statement of retained earnings LO P2 Using the above information prepare a December statement of retained earnings for Ernst Consulting. Hint: Retained Earnings on December 1 was $0 ..

help Required information Use the following information for the Exerci.pdf

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help please thank you! Pedigree of Red-Green Colour Blindness in Humans 30. Which of the following states a valid conclusion based on the pedigree above? A. All children of individual's I 1 and I 2 could be carriers of the red-green colour blindness allele. B. Individual I-2 does not carry the red-green colour blindness allele. C. Individuals II-5 and II-6 are carriers of the red-green colour blindness allele. D. It is not possible to determine whether individuals III-2 and III-3 are carriers of the colour blindness allele. E. Individual II-2 passed on the red-green colour blindness allele to.

help please thank you! Pedigree of Red-Green Colour Blindness in Hu.pdf

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Help me to do those question I don't know how to do those questions. Thanks! Where do midlatitude cyclones form? Between troughs and ridges in the polar jet stream Underneath the ascending branch of the Hadley cell Underneath ridges in the polar jet stream Underneath troughs in the polar jet stream Question 4 1 pts Why do midlatitude cyclones form in the region from question 3 ? Upper-level convergence releases latent heat, creating a region of low surface pressure Upper-level divergence causes upward motion of air and creates a region of low surface pressure Upper-level divergence enhances the greenhouse effect, heating air near the surface and creating a region of high surface pressure Upper-level convergence causes subsidence and creates a region of high surface pressure Divergence is observed to the [blank] of upper level troughs, while convergence is observed to the [blank] of upper level troughs. north; south south; north west; east east; west The midlatitude jet streams... are stronger in winter and weaker in summer because there is a larger temperature contrast from tropics to poles in winter are stronger in summer and weaker in winter because there is more incoming solar radiation and hence more heating in summer are stronger in winter and weaker in summer because there is a weaker temperature contrast from tropics to poles in winter have the same magnitude in winter and summer because the average temperature in the tropics does not vary significantly from winter to summer Question 8 1 pts How do midlatitude cyclones affect the planet's heat budget? They do not contribute to the heat budget because friction dissipates cyclones quickly They transport heat poleward by moving warm air poleward and cold air equatorward They transport heat equatorward by moving the polar front to the south They transport heat poleward by temporarily dissipating the jet stream.

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HELP LETTERS ABC Pen Corporation paid P558,000 for 70% of Arenn Corporation's P10 par common share on December 31, 2015 when Arenn Corporation's stockholders' equity was made up of P 400 , 000 share capital, P 120 , 000 share premium, and P 80 , 000 retained earnings. Arenn's identifiable assets and liabilities reflected fair values on December 31, 2015, except for Arenn's inventory which was undervalued by P50,000 and land which was undervalued by P20,000. The balance sheets for Pen and Arenn immediately after the business combination are presented in the partially completed working papers. The non-controlling interest is to be measured at fair value amounting to P 220 , 000 on the date of business combination. Pen Corporation and Subsidiary Consolidated Statement of Financial Position Working Papers on December 31, 2015 Required: a. Prepare consolidation working paper entries. b. Complete the working papers for Pen Corporation and its subsidiary. c. Prepare a consolidated statement of financial position..

HELP LETTERS ABC Pen Corporation paid P558-000 for 70- of Arenn Corpor.pdf

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Help create the kcipher.h and kcipher.cc files for the running key cipher which MUST inherit from substitution. Please follow the instructions and complete the provided code: Substitution cipher (implemented in cipher.h and cipher.cc) class has already been defined (but not implemented) for you. The other cipher classes MUST a) inherit from the substitution cipher, or b) inherit from one of the four other cipher classes (e.g., Caesar inherits from Substitution, ROT13 inherits from Caesar). 4. Each new cipher class MUST have a constructor, a default constructor (except the ROT13 cipher, as described below), and a destructor . a) Each constructor should accept the input appropriate for the cipher: i) substitution - cipher alphabet - must contain every letter in the alphabet, and only once, and they must all be lower case. It should contain no other characters (e.g., no space, punctuation, etc.). Cipher alphabet length should always be 26. ii) Caesar - positive shift/rotation/offset integer. This value can be larger than 26, in which case it has rotated completely one or more times. iii) ROT13 - no input required for constructor (see default constructor below). iv) Running Key - a vector of strings. The vector represents the cipher "book," and each element in the vector is a "page" from the book. Each page should be a non-empty string. This string should consist of only lower case letter or spaces. v) Vigenere - a string representing the key word. The key word should consist of only lower case letters. b) Each default constructor should not accept any inputs. i) ROT13: ROT13 should only have a default constructor, and it should function properly as a ROT13 cipher with the default constructor. ii) Other ciphers: default constructor should initialize the object so that encrypting any plain text should return a cipher text that is identical to the plain text. For example, for Caesar, setting the shift to 0 will achieve this. YOU CANNOT SIMPLY RETURN THE PLAIN TEXT - IT MUST STILL ENCRYPT THE TEXT using the proper method. b) the destructor should free all memory. Valgrind will be used to make sure there are no memory leaks. 5. Each cipher must also provide encrypt and decrypt functions. They can either be implemented explicitly, or implicitly using inheritance. This is a design decision, but the decision should be made to minimize/modularize your code. i) Encrypt: Assume that the input plain text will always be a) lower case letter, b) upper case letter, or c) a space. Space should not be encrypted (i.e., if the plain text is "hello world", the encrypted text should look something like "abcde fghij". Upper case letter should be encrypted to an upper case letter (you don't have to, but you will find that meeting the decrypt requirement below will be difficult otherwise). ii) Decrypt: This should take in the encrypted text and return the origin plain text. It should a) retain the case (i.e., if the input plain text has an upper case letter, the decryp.

Help create the kcipher-h and kcipher-cc files for the running key cip.pdf

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