The compounds of interest are Na2S and H2SO4. The molecular equation then is:
Na2S + H2SO4 ---> Na2SO4 + H2S. Just exchange one anion for the other. Now, we need to
know a little bit about the properties of these compounds. Almost all sodium salts are soluble, so
both Na2S and Na2SO4 are fully dissociated: 2 Na+ + S2- + 2 H+ + SO42- ---> 2 Na+ + SO42-
+ H2S. Crossing out terms that appear on both sides, we obtain the net ionic equation: 2 H+ +
S2- ----> H2S. Conveniently, H2S is a gas, and escapes from solution. Thus, it selectively
removes H+ and S2- ions from the equilibrium, driving the reaction to completion (favoring
Na2SO4)
Solution
The compounds of interest are Na2S and H2SO4. The molecular equation then is:
Na2S + H2SO4 ---> Na2SO4 + H2S. Just exchange one anion for the other. Now, we need to
know a little bit about the properties of these compounds. Almost all sodium salts are soluble, so
both Na2S and Na2SO4 are fully dissociated: 2 Na+ + S2- + 2 H+ + SO42- ---> 2 Na+ + SO42-
+ H2S. Crossing out terms that appear on both sides, we obtain the net ionic equation: 2 H+ +
S2- ----> H2S. Conveniently, H2S is a gas, and escapes from solution. Thus, it selectively
removes H+ and S2- ions from the equilibrium, driving the reaction to completion (favoring
Na2SO4).
Andreas Schleicher presents at the launch of What does child empowerment mean...
The compounds of interest are Na2S and H2SO4. Th.pdf
1. The compounds of interest are Na2S and H2SO4. The molecular equation then is:
Na2S + H2SO4 ---> Na2SO4 + H2S. Just exchange one anion for the other. Now, we need to
know a little bit about the properties of these compounds. Almost all sodium salts are soluble, so
both Na2S and Na2SO4 are fully dissociated: 2 Na+ + S2- + 2 H+ + SO42- ---> 2 Na+ + SO42-
+ H2S. Crossing out terms that appear on both sides, we obtain the net ionic equation: 2 H+ +
S2- ----> H2S. Conveniently, H2S is a gas, and escapes from solution. Thus, it selectively
removes H+ and S2- ions from the equilibrium, driving the reaction to completion (favoring
Na2SO4)
Solution
The compounds of interest are Na2S and H2SO4. The molecular equation then is:
Na2S + H2SO4 ---> Na2SO4 + H2S. Just exchange one anion for the other. Now, we need to
know a little bit about the properties of these compounds. Almost all sodium salts are soluble, so
both Na2S and Na2SO4 are fully dissociated: 2 Na+ + S2- + 2 H+ + SO42- ---> 2 Na+ + SO42-
+ H2S. Crossing out terms that appear on both sides, we obtain the net ionic equation: 2 H+ +
S2- ----> H2S. Conveniently, H2S is a gas, and escapes from solution. Thus, it selectively
removes H+ and S2- ions from the equilibrium, driving the reaction to completion (favoring
Na2SO4)
