10) Ionic compounds are a combination of metals and non-metals. A covalent compound is a combination of a non-metal and another non-metal An example of an ionic compound would be Na2SO4. An example of a covalent compound would be CO2. 10b.) a. Hydrochloric acid Anytime you have H-nameofanyhalogen and its aqueous (aq), you know it\'s an acid. To name acids (of this type) you just say \"Hydro\" then the prefix name of halogen (ie. chlor) and add \"ic\" to the end So HCL = Hydro chlor ic acid. If you had for instance HBr, it would be Hydro brom ic acid... Hydrobromic Acid b. Hydrogen Chloride This is the same letters as Hydrochloric acid but it\'s NOT (aq). It\'s a gas (g). That\'s how you know it\'s a regular covalent compound and not an acid. And it\'s covalent because it\'s a mix of two non-metals. So therefore it would just be the names Hydrogen, and then chloride. When you have a covalent compound you always say the first element name, just spelled out normally, and then the prefix of the next element with the suffix \"ide.\" So HCl would be Hydrogen Chlor ide. Hydrogen Chloride. c. Methane Many compounds have everyday names that have been given to them. This is an example of that. You just have to memorize them there is no easy way of determining an everyday name for these compounds. d. Methanol Yet another example, you just have to memorize what these formulas are according to their name. 10c.) a. 2H2 + O2 ===> 2H2O b. CH4 + 2O2 ===> CO2 + 2H2O As you can see, for both of these reactions they have the same number of elements on both sides of the equation. Now, remember, you NEVER add subscripts to any of the elements on either side of the equation when you\'re balancing. The subscripts stay the same. What you DO add are coefficients in front of a compound. For instance the unbalanced equation in your question (question a.) \"Hydrogen gas and oxygen gas react to form liquid water.\" would be: H2 + O2 ===> H2O As you can see, it\'s not balanced..... the hydrogens are balanced on both sides (2 on each side) but the oxygens are not. There are 2 oxygens on the left and only 1 on the right. So add a coefficion of 2 to the \"H2O\" so that you can have 2 oxygens. Now our new reaction is: H2 + 02 ===> 2H2O However this is still not balanced. As you can see we have 2 hydrogens on the left, but now we have 4 hydrogens on the right. So, in order to fix this, add 2 in front of H2 on the left, so now we have: 2H2 + O2 ===> 2H2O Now we have a balanced equation with 4 hydrogens on the right, and 4 hydrogens on the left. As well as 2 oxygens on the right and 2 oxygens on the left. This same type of procedure is how you balance any reaction. 10d.) Al2(SO4)3 = Aluminum Sulfate To calculate percent aluminum by mass you first find the mass of the compound. Molar Mass Al2(SO4)3: Al = 27.0(2) = 54g/mol S = 32.1(3) = 96.3g/mol O = 16.0(12) = 192g/mol Add them all together to get the molar mass of Al2(SO4)3 = 342.3g/mol Now, to get the % by mass of Al in Al2(SO4).

1. 10) Ionic compounds are a combination of metals and non-metals. A covalent
compound is a combination of a non-metal and another non-metal An example of an ionic
compound would be Na2SO4. An example of a covalent compound would be CO2. 10b.) a.
Hydrochloric acid Anytime you have H-nameofanyhalogen and its aqueous (aq), you know it's
an acid. To name acids (of this type) you just say "Hydro" then the prefix name of halogen (ie.
chlor) and add "ic" to the end So HCL = Hydro chlor ic acid. If you had for instance HBr, it
would be Hydro brom ic acid... Hydrobromic Acid b. Hydrogen Chloride This is the same letters
as Hydrochloric acid but it's NOT (aq). It's a gas (g). That's how you know it's a regular
covalent compound and not an acid. And it's covalent because it's a mix of two non-metals. So
therefore it would just be the names Hydrogen, and then chloride. When you have a covalent
compound you always say the first element name, just spelled out normally, and then the prefix
of the next element with the suffix "ide." So HCl would be Hydrogen Chlor ide. Hydrogen
Chloride. c. Methane Many compounds have everyday names that have been given to them.
This is an example of that. You just have to memorize them there is no easy way of determining
an everyday name for these compounds. d. Methanol Yet another example, you just have to
memorize what these formulas are according to their name. 10c.) a. 2H2 + O2 ===> 2H2O b.
CH4 + 2O2 ===> CO2 + 2H2O As you can see, for both of these reactions they have the same
number of elements on both sides of the equation. Now, remember, you NEVER add subscripts
to any of the elements on either side of the equation when you're balancing. The subscripts stay
the same. What you DO add are coefficients in front of a compound. For instance the
unbalanced equation in your question (question a.) "Hydrogen gas and oxygen gas react to form
liquid water." would be: H2 + O2 ===> H2O As you can see, it's not balanced..... the
hydrogens are balanced on both sides (2 on each side) but the oxygens are not. There are 2
oxygens on the left and only 1 on the right. So add a coefficion of 2 to the "H2O" so that you
can have 2 oxygens. Now our new reaction is: H2 + 02 ===> 2H2O However this is still not
balanced. As you can see we have 2 hydrogens on the left, but now we have 4 hydrogens on the
right. So, in order to fix this, add 2 in front of H2 on the left, so now we have: 2H2 + O2 ===>
2H2O Now we have a balanced equation with 4 hydrogens on the right, and 4 hydrogens on the
left. As well as 2 oxygens on the right and 2 oxygens on the left. This same type of procedure is
how you balance any reaction. 10d.) Al2(SO4)3 = Aluminum Sulfate To calculate percent
aluminum by mass you first find the mass of the compound. Molar Mass Al2(SO4)3: Al =
27.0(2) = 54g/mol S = 32.1(3) = 96.3g/mol O = 16.0(12) = 192g/mol Add them all together to
get the molar mass of Al2(SO4)3 = 342.3g/mol Now, to get the % by mass of Al in Al2(SO4)3
divide the mass Aluminum by the mass of the compound % Al = 54g / 342.3g * 100 = 16.1% I
hope this is more detailed for you and you can give it a lifesaver rating ;).

2. Solution
10) Ionic compounds are a combination of metals and non-metals. A covalent
compound is a combination of a non-metal and another non-metal An example of an ionic
compound would be Na2SO4. An example of a covalent compound would be CO2. 10b.) a.
Hydrochloric acid Anytime you have H-nameofanyhalogen and its aqueous (aq), you know it's
an acid. To name acids (of this type) you just say "Hydro" then the prefix name of halogen (ie.
chlor) and add "ic" to the end So HCL = Hydro chlor ic acid. If you had for instance HBr, it
would be Hydro brom ic acid... Hydrobromic Acid b. Hydrogen Chloride This is the same letters
as Hydrochloric acid but it's NOT (aq). It's a gas (g). That's how you know it's a regular
covalent compound and not an acid. And it's covalent because it's a mix of two non-metals. So
therefore it would just be the names Hydrogen, and then chloride. When you have a covalent
compound you always say the first element name, just spelled out normally, and then the prefix
of the next element with the suffix "ide." So HCl would be Hydrogen Chlor ide. Hydrogen
Chloride. c. Methane Many compounds have everyday names that have been given to them.
This is an example of that. You just have to memorize them there is no easy way of determining
an everyday name for these compounds. d. Methanol Yet another example, you just have to
memorize what these formulas are according to their name. 10c.) a. 2H2 + O2 ===> 2H2O b.
CH4 + 2O2 ===> CO2 + 2H2O As you can see, for both of these reactions they have the same
number of elements on both sides of the equation. Now, remember, you NEVER add subscripts
to any of the elements on either side of the equation when you're balancing. The subscripts stay
the same. What you DO add are coefficients in front of a compound. For instance the
unbalanced equation in your question (question a.) "Hydrogen gas and oxygen gas react to form
liquid water." would be: H2 + O2 ===> H2O As you can see, it's not balanced..... the
hydrogens are balanced on both sides (2 on each side) but the oxygens are not. There are 2
oxygens on the left and only 1 on the right. So add a coefficion of 2 to the "H2O" so that you
can have 2 oxygens. Now our new reaction is: H2 + 02 ===> 2H2O However this is still not
balanced. As you can see we have 2 hydrogens on the left, but now we have 4 hydrogens on the
right. So, in order to fix this, add 2 in front of H2 on the left, so now we have: 2H2 + O2 ===>
2H2O Now we have a balanced equation with 4 hydrogens on the right, and 4 hydrogens on the
left. As well as 2 oxygens on the right and 2 oxygens on the left. This same type of procedure is
how you balance any reaction. 10d.) Al2(SO4)3 = Aluminum Sulfate To calculate percent
aluminum by mass you first find the mass of the compound. Molar Mass Al2(SO4)3: Al =
27.0(2) = 54g/mol S = 32.1(3) = 96.3g/mol O = 16.0(12) = 192g/mol Add them all together to
get the molar mass of Al2(SO4)3 = 342.3g/mol Now, to get the % by mass of Al in Al2(SO4)3
divide the mass Aluminum by the mass of the compound % Al = 54g / 342.3g * 100 = 16.1% I
hope this is more detailed for you and you can give it a lifesaver rating ;).