please help show work-explain!! please help thanks- Constants

please help show work-explain!! please help thanks- Constants - Part A.docx

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please help show work/explain!! please help thanks. Constants ? Part A n the figure (Figure 1), if C1-Cs 2Cs 28.7uF, how much charge is stored on each capacitor when V-49.0V? Enter your answers separated by commas. Submit Request Answer Figure 1 of 1 Provide Feedback Next > C1 C3C3 Solution C1 = 28.7 uF, C2 = 28.7 uF, C3 = 14.35 uF equivalent capacitance = Ceq = C1 + C2*C3/(C2 + C3) = 28.7 + 28.7*14.35/(28.7+14.35) = 38.27 uF charge through battery = Q = CV = 38.27*10^(-6)*49 = 1875.23*10^(-6) C = Q1 + Q2 + Q3 Q1 = C1*V = 28.7*49 = 1406.3*10^(-6) C C2 & C3 are in series so Q2 = Q3 Q2 = Q3 = (1875.23*10^(-6) - 1406.3*10^(-6))/2 = 234.46*10^(-6) C .

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Please explain how HDFS provides redundancy for stored data Solution HDFS is designed to reliably store very large files across machines in a large cluster. It stores each file as a sequence of blocks; all blocks in a file except the last block are the same size. The blocks of a file are replicated for fault tolerance. The block size and replication factor are configurable per file. An application can specify the number of replicas of a file. The replication factor can be specified at file creation time and can be changed later. Files in HDFS are write-once and have strictly one writer at any time. The NameNode makes all decisions regarding replication of blocks. HDFS uses rack-aware replica placement policy. In default configuration there are total 3 copies of a datablock on HDFS, 2 copies are stored on datanodes on same rack and 3rd copy on a different rack. .

Please explain how HDFS provides redundancy for stored dataSolutionHDF.docx

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Please describe cash flows from investing activities, and provide three examples of cash inflows and three examples of cash outflows. for discussion *update don\'t answer it posted twice and points will not be awarded. thank you* Solution Cash flow from investment activities deals with either cash inflow or cash outflow due to investment decisions taken up by the company. It deals with acquiring or selling off companies long term / fixed assets. Three examples of cash outflow from investment activites: 1. Buying Land or investment in furnitutes / fixtures 2. investment in stocks and debentures of other companies 3. Buying Another plant or Machinery Three Examples of Cash inflows from investment activities. 1. Selling of old machineries 2. Selling of subsidiaries 3. Selling technology know -how .

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Please clear hand written for the answers Solution 15. (c) An increase in temperature favours the formaiton of more H2S as the given reaction is endothermic. and in the equation heat ( deltaH ) is added at reactants side which means the forward reaction is endothermic in nature. 16. (a) Shifts to a right Increase in temperature favours endothermic reactions and it is given that the forward reaction is endothermic. 17. (a) Shifts to the right Decrease in temperature favours exothermic reaction and it is given that the forward reaction is exothermic. 18. M1 * V1 / n1 = M2 * V2 / n2 M1 * 25.00 / 1= 0.102 * 28.52 / 1 M1 = Molarity of NaOH = 0.116 M (a) .

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please answer the following, thanks!!! Question 3 (1 point) 6 Rutherford\'s experiment was important because it showed that: . The mass of the atom is uniformly distributed throughout the atom An atom is mostly empty space Radioactive elements give off alpha particles Gold foil can be made to be only a few atoms thick. A zinc sulfide screen scintillates when struck by a charged particle Save Solution Rutherford experimet showed that An atom is mostly empty space ( this conclusion indicates atom has mass concentrated at center of atom whose volume is small compared to atom . center area is called nucleus contains protons and neutrons , while electrons lie around nucleus.) .

please answer the following- thanks!!! Question 3 (1 point) 6 Rutherfo.docx

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Please answer questions 1-4, thank you! Solution 1. Acids are the conpounds which give H+ ions in the aquous solution. Bases give OH- ions innthe aquous solutions. Acids are the proton donors and bases are the proton acceptors. 2. Litmus paper is the most common indicator used in the labs. Litmus turns green ti basic and red to acidic. Other is methyl ornage shows pink in acidic medium and shows yellow in basic and phenophthaline etc. 3. HClO is an acid it can give H+ ions i.e proton. Na2CO3 is formed by H2CO3 and NaOH. So it is a neutrilisation of weak acid with strong base so it will be a basic salt. H2O is neutral. H3BO3 is boric acid. As the name suggests its an acid it can donate H+. 4. Anything less than pH=7 is acidic uptill 1. pH=7 is neutral pH>7 is basic uptill 14 .

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Please answer in a clear manner to get the points. Thanks for the help. 1. What are the number of links and number of joints of each planar linkage shown below? Determine the mobility of each mechanism Solution the nof degrees of freedom = no of variables - no of constraint each body has 3 variables ie x y and roration and each joint(revolute and translational) corresponds to 2 constraint equation and high pair forms 1 constraint prob1. number of bodies except ground =9 number of revolute joints =7 number of translatioanl joints= 1 mobility = 3*9 -(2*7+2*1) =11 2. number of bodies except ground =7 number of revolute joints =8 number of translatioanl joints= 2 number of higher pair= 1 mobility =3*7 - (8*2+2*2+1) =1 .

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Please answer both Solution 18 . Nature chose polyamides to form proteins. This is bacause the polamides are made by the condensation of the amino acis with the elimination of the small molecules water. These proteins have different strucures having chains which are stabilized by hydrogen bonding between nitrogen atom of one chain wth oxtgen atom of C=O of another chain. thus the structure gets stabilised.This not possible in esters. 19.The nature chose monosubstituted amides instead disubstituted because conformations in proteins stabilize the protein structures. Due to the disubstitution the steric factor increases destabilising the protein chains. disturbing hydrogen bonding in proteins chains having primary, seconary & quaternary structues. .

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Phe following GC data was obtained on a Polar column. The 10 possible organie compounds are listed in the table. Based on your knowledge orga Gc, label each of the peaks as 1 through 10, based on their Retention Times and explain why. (20 points) 1Acetone 2 Pentane 3 Propanol 4 Methyl ethyl ketone 5 Hexane 6 Butanol 7 3-Pentanone 8 Heptane 9 Pentanol 10 Octane ? 8 10 12 14 16 18 2 4 Time (min) Solution Peaks from left to right: Peak 1: pentane( lowest retention time) Peak 2: hexane Peak 3: heptane Peak 4: octane Peak 5: acetone Peak 6: methyl ethyl ketone Peak 7: pentanone (retention time 4 minutes) Peak 8: propanol (4.5 minutes) Peak 9: butanol (9.5 minutes) Peak 10: pentanol (highest retention time; 18 minutes) .

Phe following GC data was obtained on a Polar column- The 10 possible.docx

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Patients in shock experience decreased delivery of O2 to tissues, decreased activity of the pyruvate dehydrogenase complex, and increased anaerobic metabolism. Excess pyruvate is converted to lactate, which accumulated in tissues and in the blood, causing lactic acidosis. Since O2 is not a reactant or product of the citric acid cycle, why do low levels of O2 decrease the activity of the pyruvate dehydrogenase complex? Solution pyruvate dehydrogenase complex is found in only mitochondria ( we know that mitochondria is the power house of the cell as well as the cell respiration will takes place means what ever the enzymes present in mitochondria they are more active at high oxygen level ) this enzyme requires five cofactors namely TPP,lipoamide,FAD,coenzyme A,and NAD + the conversion of pyruvate to acetyl CoA finished when reduced lipoamide is converted to oxidized lipamide .

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