Please help me solve this I already asked this question and someone solved it incorrectly. Thank you.
Solution
given,
concentration of NH 4 NO 2 = 1.10 M
in volume = 2.20 L
step1
thus, moles of NH 4 NO 2 = 1.10 x 2.20 = 2.42 moles
step2
1 mole of NH 4 NO 2 can form 1 mol of N 2
2.42 moles of NH 4 NO 2 can form 2.42 moles of N 2
step3
pressure is only due to N 2 gas
p = nRT / v
p = 2.42 x 0.0821 x 298 / 2.20
p = 26.91 atm
step4
pressure in 10 L
p = nRT / v
p = 2.42 x 0.0821 x 25 /10
p = 5.92 atm
step5
change in pressure = 26.91 - 5.92 = 20.99 atm or (21 atm)
.
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Please help me solve this I already asked this question and someone so.docx
1. Please help me solve this I already asked this question and someone solved it incorrectly. Thank
you.
Solution
given,
concentration of NH 4 NO 2 = 1.10 M
in volume = 2.20 L
step1
thus, moles of NH 4 NO 2 = 1.10 x 2.20 = 2.42 moles
step2
1 mole of NH 4 NO 2 can form 1 mol of N 2
2.42 moles of NH 4 NO 2 can form 2.42 moles of N 2
step3
pressure is only due to N 2 gas
p = nRT / v
p = 2.42 x 0.0821 x 298 / 2.20
p = 26.91 atm
step4
pressure in 10 L
p = nRT / v
2. p = 2.42 x 0.0821 x 25 /10
p = 5.92 atm
step5
change in pressure = 26.91 - 5.92 = 20.99 atm or (21 atm)
