1. (with APA reference )Describe in detail the roles that the follow.pdf

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1. (with APA reference )Describe in detail the roles that the following play in implementing persistence in a Java EE application: a. TheJava Persistence API b. The query language JPQL c. The Java Persistence Criteria API d. Entity Beans e. Object/relational mapping metadata. Solution A) The persistance API:It is a java application programming language interface statement that tells the deceit of relational data in applications with java programm, standard version and java programm ,enterprise edition.it is interpreted in java.persistence package.this java persistance API started as a fragment of the service of JSR 220 expert of java community task. the tchniques used in it are system images and juornals. B)The query language JPQL:It is an individualistic programm object oriented programming language.it is laboriously stimulated by SQL and their queries look like SQL queries syntactically.it is depending on the hybernate query language.their manipulation is across the entity objects preferably than straightly with thw database tanbles. C)The java persistance criteria AP: This criteria was included in API 2.0 version. It is mainly to sense dynamic queries with the erection of object form query interpretation objects. It is for energetic queries hardly. it allows the dynamic queries to construct programmitically providing good integration using the java language instead of string based 4th GL approach. D)Entuty beans: It is a venture of endeavour of java beans.it is a server side constituent.if in the receptacle the entity bean is arranged impacts ,the primary key and any of the near mentioned will continue the impact.The constituents of the entity bean applys the javax.ejb.entitiyBean E) Object/relational mapping metadata:It preserves the dta of the programmer and moreover the database itself.almost DBMS habe a many tables that enumerates the tables in database and columns in every table primary and foreign keys ans also stored procedures JDBC offers the interface databasemetadata,that a driver should apply suchntrhat its methods must retrieve details regarding the driver .the interface offers the tools and a systemized procedure to apprehend the metadata..

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match the following attributes to the parts of a compiler strips out the comments and whitespace converts text into lexemes generates an Abstrat Symbol Tree recursive descent or table driven uses BNF or EBNF definitions a. lexer b. parser Solution The Program and Portfolio Management Maturity Model is an effective tool for organizations to decide quickly what PPM improvements they should make to enhance their organization\'s ability to optimize investments, execute big changes and deliver value. Overview Key Findings Real project, program and portfolio management, when operating at the level of well-integrated practices, is the key enabler that allows organizations to identify and execute strategic change. Any meaningful undertakings to enhance or evolve the program and portfolio management (PPM) function must pay more than lip service to organizational structure, business model and culture to have any chance of success. Competitive pressures and changing market conditions are forcing organizations toward Level 3, and most organizations still aren\'t ready to make the leap. Recommendations At any level of PPM maturity, focus first on helping the organization make well-informed investment choices. This will improve the odds of project success more than any other factor. For organizations that require enterprisewide change and capabilities, it is worth the effort to pursue Level 4, where enterprise PPM practices are built. Identify objectives for your enterprise, and use them to identify the most salient improvement opportunities for your enterprise. Meticulously manage the change involved in maturing/improving your PPM capabilities. Analysis Project/program/portfolio management office (PMO) leaders, program managers and portfolio managers are frequently challenged by ineffective processes, lack of stakeholder engagement and difficult-to-quantify value. 1 Part of the problem is failure to match their processes, people and technology approaches to the maturity level of their organizations. 2 The Gartner Program and Portfolio Management (PPM) Maturity Model assessment is designed to help PPM leaders understand best practices around large project management, as well as PPM to handle delivery of strategic value. This model assumes that organizations progress through a maturity curve and that each level of organizational maturity directly affects the level of investment and types of PPM approaches organizations choose to adopt. arsing A parser is an algorithm that determines whether a given input string is in a language and, as a side-effect, usually produces a parse tree for the input. There is a procedure for generating a parser from a given context-free grammar. Recursive-Descent Parsing Recursive-descent parsing is one of the simplest parsing techniques that is used in practice. Recursive-descent parsers are also called top-down parsers, since they construct the parse tree top down (rather than bottom up). The basic idea of recursive-descent par.

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Looking for some help with this assignment. 1. Define distributed computing and the impact it has had on organizations. 2. Why should you be concerned about the innovation butterfly is you are an IT professional? 3. What is the difference between single threading and multithreading and how would I use it in a Distributed system? 4. What is a mobile architecture and what are some of the design considerations? 5. Explain why naming conventions are important in large enterprise organizations. 6. What is the difference between a disruptive and a sustaining technology? 7. Describe the difference amongst Mobile, Cloud and Embedded systems. 8. Explain the role time plays in distributed systems and why it is difficult to manage. 9. What are the major challenges IOT plays in a distributed system? 10. How does mobility, ubiquity and PAN increase the complexity of distributed systems. Solution 1) sol:defnition: it is a one type of model where software components are shared with mutliple computer to make work easier and gives more effieciency and performance impact of distributed computing 1)at present it keeps a main roles in organizations ,all the organizations are converting to distributed system 2)we can process data at one place and access data at one place so there is lot of availability 3)many organization doing thier business process in remote computer and accesing their database 2)differenece between sustaining and disruptive technology 1)by using sustaining technology improves performance for products which had been established with the dimension of the product which gives market to the mainstream customers 2) coming to the disruptive technology bring to market in diffrent praportions of values which had been available previously,these disruptive techonolgy underperform which had been established in main steram market.

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Introduction and Background In recent lectures we discussed using arrays, classes and interfaces (see newly added course notes if you want to read ahead about interfaces – we will cover them this week in lecture). In this lab you will utilize all of these topics to build a simple yet useful new class. Consider the following interface describing the methods for a simple double ended queue (or deque): public interface SimpleDeque { public void addFront(Object X); // Add Object X at front of list public void addRear(Object X); // Add Object X at rear of list // If array is full, add methods should do nothing public Object removeFront(); // Remove and return Object X from // front of list public Object removeRear(); // Remove and return Object X from // rear of list // If array is empty, remove methods should return null public boolean isEmpty(); // Return true if the list is empty // Return false otherwise } A queue has the behavior such that items are added at the rear and removed from the front, thereby giving a First In First Out (FIFO) access to the items added and subsequently removed from the list. No other manipulations of the data are permitted (for example, we cannot add or remove anywhere in the middle). Looking at it \"in reverse\", we could add new items at the front of the queue and remove them from the rear. This is still providing FIFO access, but just from a different point of view. Now consider both adding and removing items at the rear of the list (without ever accessing the front). This is called stack access and gives us Last In First Out (LIFO) access to the items (the data is removed in reverse order). The same behavior occurs if we both add and remove at the front without ever accessing the rear of the list. The simple deque above is expressed as an interface rather than a class, because we are not describing the data or how it is represented -- we are simply describing its access behavior. However, to actually build a working deque, we need a class that implements the interface above. For example: public class MyDeque implements SimpleDeque { Object [] theData; int numItems; public MyDeque(int maxItems) { theData = new Object[maxItems]; numItems = 0; } // Implementation of the five methods of SimpleDeque, plus // perhaps other methods as well } Note that the implementation above uses an array of Object to store the items in the deque. Since Object is the base class to all other Java classes, an array of Object can thus be used to store any Java class types (we can even store primitive values if we utilize their wrapper classes). Also note that nothing in the SimpleDeque interface requires an array to be used to store the data. You will see in your CS 0445 course that a linked list may in fact be a better implementation than an array in this case. However, for this implementation we will use an array because it is simple and easy to understand. Another important thing to notice about the partial implementation above is tha.

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In the binary search, if the array being searched has 32 elements in it, how many elements of the array must be examined to be certain that the array does not contain the key? What about 1024 elements? Note: the answer is the same regardless of whether the algorithm is recursive or iterative. Solution Binary Search Algorithm- Fundamentals, Implementation and Analysis Hitesh Garg | May 15, 2015 | algorithms | 5 Comments Binary Search Algorithm and its Implementation In our previous tutorial we discussed about Linear search algorithm which is the most basic algorithm of searching which has some disadvantages in terms of time complexity,so to overcome them to a level an algorithm based on dichotomic (i.e. selection between two distinct alternatives) divide and conquer technique is used i.e. Binarysearch algorithm and it is used to find an element in a sorted array (yes, it is a prerequisite for this algorithm and a limitation too). In this algorithm we use the sorted array so as to reduce the time complexity to O(log n). In this, size of the elements reduce to half after each iteration and this is achieved by comparing the middle element with the key and if they are unequal then we choose the first or second half, whichever is expected to hold the key (if available) based on the comparison i.e. if array is sorted in an increasing manner and the key is smaller than middle element than definitely if key exists, it will be in the first half, we chose it and repeat same operation again and again until key is found or no more elements are left in the array. Recursive Pseudocode: 1 2 3 4 5 6 7 8 9 10 11 12 // initially called with low = 0, high = N – 1 BinarySearch_Right(A[0..N-1], value, low, high) { // invariants: value >= A[i] for all i < low value < A[i] for all i > high if (high < low) return low mid = low +((high – low) / 2) // THIS IS AN IMPORTANT STEP TO AVOID BUGS if (A[mid] > value) return BinarySearch_Right(A, value, low, mid-1) else return BinarySearch_Right(A, value, mid+1, high) } Iterative Pseudocode: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 BinarySearch_Right(A[0..N-1], value) { low = 0 high = N - 1 while (low <= high) { // invariants: value >= A[i] for all i < low value < A[i] for all i > high mid = low +((high – low) / 2) // THIS IS AN IMPORTANT STEP TO AVOID BUGS if (A[mid] > value) high = mid - 1 else low = mid + 1 } return low } Asymptotic Analysis Since this algorithm halves the no of elements to be checked after every iteration it will take logarithmic time to find any element i.e. O(log n) (where n is number of elements in the list) and its expected cost is also proportional to log n provided that searching and comparing cost of all the elements is same Data structure used -> Array Worst case performance -> O(log n) Best case performance -> O(1) Average case performance -> O(log n) Worst case space complexity -> O(1) So the idea is- RECURSIVE Implementation of Binary search in C programming language 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 .

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Heliconius melpomene is a species of butterfly with ZW sex determination. H. melpomene\'s wing spots are normally orange, but a recessive Z-linked mutation causes the spots to be yellow, while a recessive autosomal mutation causes the spots to be red. Butterflies homozygous (or hemizygous) for both mutations have no wing spots. What are the expected F1 and F2 phenotypes from a cross between a red-spotted female and a yellow-spotted male? Solution The Heliconius melpomene butterfly having sex determination ZW have normally orange wing spots. Given Recessive Z linked mutation causes the spots to be yellow, if Y is the dominant gene the y represents the recessive gene. The recessive autosomal mutation causes the spot to be red,the recessive autosomal mutation represented by rr. a) WX represents female b) WW represents male Given-: F1 generation The red spotted female is crossed with yellow spotted male ZWrr X ZZy ZZ, WrrZ, ZZy, WrrZy It gives 1 hemizygous butterfly, 1red spotted female butterfly, 1 yellow spotted male and 1 normal orange wing male butterfly. The F2 generation gives the same result..

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Identify the key mechanism that determines which X remains active and which X becomes inactive. Solution In normal human females, only one X chromosome is transcriptionally active, the other X chromosome remains condensed as heterochromatin and is called as sex chromatin or Barr body. Formation of Barr body ensures that cells of both males and females have same number of active X chromosomes and thus synthesise equal amount of products encoded by X linked genes. This inactivation of one of the two X chromosome in each cell is called Lyonization, after the name of British researcher Mary Lyon. She proposed that; Inactivation of X chromosome in females occurs during early stages of embryonic development and this Inactivation of X chromosome in embryo is a random process, so that paternally derived and maternally derived X chromosomes stands equal chance of becoming inactivated in any given cell. MECHANISM OF INACTIVATION : The mechanism of Inactivation is initiated by a non coding RNA molecule called XIST RNA. There is a region on X chromosome called as X-Inactivation center (XIC) located on proximal end of X chromosome. Genetic expression of this region occurs only on chromosome that is inactivated. This region carries about 4 genes one of which is X-Inactivation specific transcript (XIST). The RNA transcribed by this gene is called XIST RNA. This RNA is large (about 17kb long) and is not translated. It does not diffuse into nucleoplasm,but accumulates along the length of chromosome just before it is Inactivated. Thus RNA product of XIST gene spread over and coat the X chromosome bearing the gene that produced it ,creating some sort of molecular \"cage\" that entraps it leading to its Inactivation. Thus X chromosome in which XIST gene is transcribed to form XIST RNA becomes inactive (due to coating of this X chromsome by XIST RNA) while as the other X chromosome remains active..

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Given to girls born in the U.S. in the years The tables below give the ten most popular names 1974 and 1999 and the percentages of girls given those names. Consider group of 20 girls born in 1974. and another group of 20 bom in 1999. Use the data in the tables to do problems 22-25 regarding these groups. The name Jennifer was approximately 3 times as popular in 1974 as Emily was in 1999, despite each being the #1 name in their respective years. Determine by calculation if you are 3 times as likely to have more than one Jennifer in the 1974 group of 20 as you are to have multiple Emilys in the 1999 group of 20. Solution.

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How do open source projects work? How is it different from closed source projects? Discus the creation of a database. Explain its working. (E.g, what you need to use to create tables and relationship? What you do to modify a database?) Explain what\'s SaaS, PaaS and laaS? Distinguish among these three. Solution 31) In open source project the source code of the project is made available to anyone for free. The code can be studied, modified and even redistributed for any purpose.Many of the open source projects are developed in an open collaberative manner. People volunteer to develop the projects.Where as in closed source projects the source code is not developed by an organization and the source code is not openly available. 32) A database consists of many tables created for a project. In mysql it is created using the command \'create database sample_database;\'. We generally use a RDBMS(Relational Database Management System). The data is stored in RDBMS database objects called tables. You can create a table by specifying the number of rows, names of each row and the type of data that will be stored in each of them. 33) SaaS means software as a service in which a software is provided as a serive. Generally the service is centrally hosted, but this many not always be the case. The consumer is charged on a one time basis or in a subscription model. PaaS stands for platform as a service. The service provides platform as a service for customers to develop, manage and run applications. This is generally referred for cloud computing applications. LaaS stands for logging as a serivce. This represents a architechture used for collection of log files from a specific location or source..

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Ferdinand is affected by hemophilia, a recessive x-linked condition. He mates with an unaffected woman with no history of hemophilia in her family. Their first child is a girl with Turner Syndrome (XO sex chromosomes), who is also hemophiliac. You infer that she resulted from the following sperm and egg (answers listed in the order of sperm, egg):normal, normal Solution Answer: Because Ferdinand has hemophilia which is X-linked ressesive disease. Daughters produced by mating of ferdinand and a normal female would be carriers of hemophilia. In this case however, the daughter is having Turners\' syndrome (XO) and is heophilic as well. This implies that the X came from sperm of Ferdinand and the O is beacuse the X chromosome from the female was nondisjunct at meiosis I, as non-disjunction at meiosis II would result in two gaetes being normal, One being trisomic and one being monosomic. whereas nondysjunction at meiosis I would give rise to 50% trisomic and 50% monosomic gametes. Hence raising the possibility of turners\' syndrome after nondysjunction at meiosis I. Therefore answer is: c. Normal and non-dysjunction at meiosis I..

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Explain whether you think IFRS and GAAP will be fully converged. What is the current status of convergence projects? Solution There has been a concerted convergence effort between the Generally Accepted Accounting Principles (GAAP) and the International Financial Reporting Standards (IFRS) in order to avoid conflict and confusion, promote simplicity, streamlining, consistency and transparency, and avoid any future financial crises or meltdowns. Despite the research-indicated evidence of a higher accounting quality being experienced by firms that either apply the IFRS standards or have switched to them from the GAAP, the convergence process has not proven to be an easy task, mostly because of the differences in approach between the two accounting bodies. The GAAP is a rules-based methodology, while the IFRS takes a principle-based approach. The rules-based approach is comprised of a complex set of guidelines that establishes criteria for every possible contingency and provides the rules required for specified transactions, thus promoting uniformity. The principle-based methodology lays out the key objectives of good reporting in each subject area and then provides guidance, explaining the objective, and relates it to common examples, thus promoting transparency. If these methodological differences between the two approaches cannot be resolved, they may prolong the process of compiling a true set of international accounting standards and increase the costs required to maintain two sets of books. So from the above discussion it is clear that, IFRS and GAAP will be fully converged, but it will took a time. current status of convergence projects One of the main concerns in the United States business world is how the convergence process and its results will impact the future evolution of the accounting profession. This specific concern, simply stated, is about uniformity over transparency, and it has a serious impact on the standards development process. Could the goals of uniformity and transparency be achieved? Are they incompatible or mutually exclusive? This incompatibility - real or perceived - is grounded in the conflicts existing among the constructs of rules-based and principle-based shareholder and stakeholder primacy theories, which are recognized by the Financial Accounting Standards Board (FASB), the International Accounting Standards Board (IASB) and the European and Asian Accounting Standards Boards, and which have an impact on the standards development methodology. Transparency has a direct impact on the areas of business combinations (Phase I and II), revenue recognition and financial performance of business enterprises reporting. hence they are still in process..

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Does the following picture depict a function? It so, is it a one to one function? Solution The given picture depict the function.Every element of set x mapping into set y\'s exactly one element.so it is called a function. A function is said to be one-to-one if every y value has exactly one x value mapped onto it.So the given picture is not one-to-one function.because two elements of set x mapping to one set y\'s element..

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Do patients have health care rights that are not legal or statuatory rights? Explain your answer. Solution Legal Conceptualization: it supplies that a patient has a right to realize potential benefits, risks, and option a of proposed therapy; duty of physician to reveal to the patient a full apprehension of the suggested care before patient assent to it. Statuatory Rights: when a patient is clinically unfit to give assent to a lifesaving emergency therapy. The law implicit assent (exigency in most states abolish need for assent).

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Describe the authentication process in the figure below: Solution Authentication begins when a user tries to access information. First, the user must prove his access rights and identity. When logging into a computer, users commonly enter usernames and passwords for authentication purposes. This login combination, which must be assigned to each user, authenticates access. However, this type of authentication can be circumvented by hackers. A better form of authentication, biometrics, depends on the user’s presence and biological makeup (i.e., retina or fingerprints). This technology makes it more difficult for hackers to break into computer systems. The Public Key Infrastructure (PKI) authentication method uses digital certificates to prove a user’s identity. There are other authentication tools, too, such as key cards and USB tokens. One of the greatest authentication threats occurs with email, where authenticity is often difficult to verify. For example, unsecured emails often appear legitimate..

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Discuss the history of bureaucratic and administrative management. Solution 1. History of Bureaucratic Management: There was time before 1800 when the organisations operated like a family. Supervisors, workers and employees did not have proper defined work. Every one did everything. During late 1800, Max Weber brought about changes in this system of organisational operation. He believed that having an informal organisation decreases the productivity of the employees as they are not focussed and goal-driven. Max Weber created the idea of bureaucratic management which made the organisation more rigid, authorative and structured. He believed that employees do not follow the organisation but they follow their bosses. He defined supervisors and workers role properly. The workers were supposed to take their immediate bosses orders and cannot operate beyond that capacity. Max Weber\'s theory of bureaucratic management has two important elements. First, it involves structuring an organization into a hierarchy system. Secondly, the organization as well as its employees operate through clearly defined rational-legal decision-making rules. Both the elements help the organisation to achieve its goals. 2. History of Administrative Mangement During 1900, the management expert Jules Henri Fayol, came to the conclusion that management is an activity that is followed by all the human undertakings. Management is needed at school, housework, business, government services, etc. All these human undertakings need five basic administrative functions to operate. They are: i. Planning ii. Organizing iii. Commanding iv. Coordinating v. Controlling Henri Fayol rejected the notion that \"Managers are born and not made.\" Instead he believed that management is a skill that can be developed over the time through proper training and enthusiasm. Managemnt skills can be acquired if its principles are understood. Henri Fayol was of the belief that since management is an all-encompassing activity, the management skills should be taught in schools, colleges and universities..

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Describe or explain how SNPs in genes at evolutionary conserved breakpoints can lead to dramatic phenotypic differences between species like chimpanzees and humans even though their genomes are 98% similar? Provide and describe or explain an example of one gene with SNP differences between gorillas and humans that might have resulted changes between humans and apes. Solution SNP ( Single nucleotide polymorphism) is a type of genetic variation among living beings. SNP represents a difference in a single DNA building block i.e, nucleotide. SNP replaces the nucleotide cytosine ( C) With ghe nucleotide thymine (T) in a stetch of DNA. The difference between the two genomes of humans and chimpanzees is actually 4% approximately. This msinly contributes to the phenotypic differences in various species. Humans differbfrom other primates like chimpanzees and apes in cognitive abilities and a significantly larger brain. These correlate with metabolic changes, etc. Example of such genes with SNP differences is 90 TF genes with significant expression levels in humans and chimpanzee brain. Among these KRAB-Zinc finger genes are markedly important. The differentially expressed TFs cluster within robust regulatory network consisting of two distinct but interlinked modules, strongly associated with energy metabolism functions and the others with transcription, vesticular transport and ubiquitination..

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Can Variance Inflation factors be used to detect Heteroscedasticity problem in the regression analysis Solution Variance inflation factors (VIF) measure how much the variance of the estimated regression coefficients are inflated as compared to when the predictor variables are not linearly related. Use to describe how much multicollinearity (correlation between predictors) exists in a regression analysis. Multicollinearity is problematic because it can increase the variance of the regression coefficients, making them unstable and difficult to interpret. Use the following guidelines to interpret the VIF:VIFStatus of predictorsVIF = 1Not correlated1 < VIF < 5Moderately correlatedVIF > 5 to 10Highly correlated.

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