An experiment was conducted to determine whether a deficiency of carbon in the soil affects
the phenotype of pass . Listed below are the phenotype codes where .
Solution
Here,
n = number of observations = 14
mean = sum of observations / total number of observations.
mean = 29 / 14 = 2.071429 = 2.1
Median procedure :
Arrange observations in ascending order.
n = 14 (even)
median = [ (n/2)th observation + (n/2 + 1)th observation ] / 2
n/2 = 14/2 = 7th observation
n/2 + 1 = 8th observation
median =[ 7th observation + 8th observation ] / 2
= ( 2 + 2 ) / 2 =2
mode is the most repeated value in the data set.
Mode = 2
because 2 occures 5 times.
Mode is 2.
All the measures of center make sense since the data is numerical.
Mid range = (maximum of data + minimum of data) / 2
Mid range = ( 4 + 1 ) / 2 = 5 / 2 = 2.5
Which of the following is not a characteristic of the mean.
the mean is sensitive to outliers..
Andreas Schleicher presents at the launch of What does child empowerment mean...
An experiment was conducted to determine whether a deficiency of carb.pdf
1. An experiment was conducted to determine whether a deficiency of carbon in the soil affects
the phenotype of pass . Listed below are the phenotype codes where .
Solution
Here,
n = number of observations = 14
mean = sum of observations / total number of observations.
mean = 29 / 14 = 2.071429 = 2.1
Median procedure :
Arrange observations in ascending order.
n = 14 (even)
median = [ (n/2)th observation + (n/2 + 1)th observation ] / 2
n/2 = 14/2 = 7th observation
n/2 + 1 = 8th observation
median =[ 7th observation + 8th observation ] / 2
= ( 2 + 2 ) / 2 =2
mode is the most repeated value in the data set.
Mode = 2
because 2 occures 5 times.
Mode is 2.
All the measures of center make sense since the data is numerical.
Mid range = (maximum of data + minimum of data) / 2
Mid range = ( 4 + 1 ) / 2 = 5 / 2 = 2.5
Which of the following is not a characteristic of the mean.
the mean is sensitive to outliers.
![An experiment was conducted to determine whether a deficiency of carbon in the soil affects
the phenotype of pass . Listed below are the phenotype codes where .
Solution
Here,
n = number of observations = 14
mean = sum of observations / total number of observations.
mean = 29 / 14 = 2.071429 = 2.1
Median procedure :
Arrange observations in ascending order.
n = 14 (even)
median = [ (n/2)th observation + (n/2 + 1)th observation ] / 2
n/2 = 14/2 = 7th observation
n/2 + 1 = 8th observation
median =[ 7th observation + 8th observation ] / 2
= ( 2 + 2 ) / 2 =2
mode is the most repeated value in the data set.
Mode = 2
because 2 occures 5 times.
Mode is 2.
All the measures of center make sense since the data is numerical.
Mid range = (maximum of data + minimum of data) / 2
Mid range = ( 4 + 1 ) / 2 = 5 / 2 = 2.5
Which of the following is not a characteristic of the mean.
the mean is sensitive to outliers.](https://image.slidesharecdn.com/anexperimentwasconductedtodeterminewhetheradeficiencyofcarb-230703122031-2ea46e8e/85/An-experiment-was-conducted-to-determine-whether-a-deficiency-of-carb-pdf-1-320.jpg)
