Find the indicated area under the standard normal curve. Between z = 0.12 and z =0.12 Solution Normal Distribution Mean ( u ) =0 Standard Deviation ( sd )=1 Normal Distribution = Z= X- u / sd ~ N(0,1) To find P(a < = Z < = b) = F(b) - F(a) P(X < -0.12) = (-0.12-0)/1 = -0.12/1 = -0.12 = P ( Z <-0.12) From Standard Normal Table = 0.45224 P(X < 0.12) = (0.12-0)/1 = 0.12/1 = 0.12 = P ( Z <0.12) From Standard Normal Table = 0.54776 P(-0.12 < X < 0.12) = 0.54776-0.45224 = 0.0955.