Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleo.pdf

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Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleotides in case of DNA and RNA structures respectively. C3\' endo sugar pucker is exclusively seen. D Ribose structure which varies at C2 deoxy form in DNA, Ribo form in RNA. The C1 of the ribose forms the glycosidic linkage with the N 1 of the nitrogenous base. 14) MONO NUCLEOTIDES are Adenine, Guanine, Cytosine and Thymidine are linked by the diphosphopyridine molecules, which having significant function in the cell. Functions of Mono nucleotides: Other functions used in molecular research studies like : Solution Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleotides in case of DNA and RNA structures respectively. C3\' endo sugar pucker is exclusively seen. D Ribose structure which varies at C2 deoxy form in DNA, Ribo form in RNA. The C1 of the ribose forms the glycosidic linkage with the N 1 of the nitrogenous base. 14) MONO NUCLEOTIDES are Adenine, Guanine, Cytosine and Thymidine are linked by the diphosphopyridine molecules, which having significant function in the cell. Functions of Mono nucleotides: Other functions used in molecular research studies like :.

Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleotides in case of DNA and
RNA structures respectively. C3' endo sugar pucker is exclusively seen. D Ribose structure
which varies at C2 deoxy form in DNA, Ribo form in RNA. The C1 of the ribose forms the
glycosidic linkage with the N 1 of the nitrogenous base.
14) MONO NUCLEOTIDES are Adenine, Guanine, Cytosine and Thymidine are linked by the
diphosphopyridine molecules, which having significant function in the cell.
Functions of Mono nucleotides:
Other functions used in molecular research studies like :
Solution
Ribose sugar puckers adopt for both Deoxy nucleotides and ribonucleotides in case of DNA and
RNA structures respectively. C3' endo sugar pucker is exclusively seen. D Ribose structure
which varies at C2 deoxy form in DNA, Ribo form in RNA. The C1 of the ribose forms the
glycosidic linkage with the N 1 of the nitrogenous base.
14) MONO NUCLEOTIDES are Adenine, Guanine, Cytosine and Thymidine are linked by the
diphosphopyridine molecules, which having significant function in the cell.
Functions of Mono nucleotides:
Other functions used in molecular research studies like :

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package DataStructures; public class HelloWorld > { public HelloWorld( ) { root = null; } public void insert( AnyType x ) { root = insert( x, root ); } public void remove( AnyType x ) { root = remove( x, root ); } public AnyType findMin( ) { if( isEmpty( ) ) System.out.println(\"tree is empty\"); return findMin( root ).element; } public AnyType findMax( ) { if( isEmpty( ) ) System.out.println(\"tree is empty\"); return findMax( root ).element; } public boolean contains( AnyType x ) { return contains( x, root ); } public void makeEmpty( ) { root = null; } public boolean isEmpty( ) { return root == null; } public void printTree( ) { if( isEmpty( ) ) System.out.println( \"Empty tree\" ); else printTree( root ); } private BinaryNode insert( AnyType x, BinaryNode t ) { if( t == null ) return new BinaryNode( x, null, null ); int compareResult = x.compareTo( t.element ); if( compareResult < 0 ) t.left = insert( x, t.left ); else if( compareResult > 0 ) t.right = insert( x, t.right ); else ; // Duplicate; do nothing return t; } private BinaryNode remove( AnyType x, BinaryNode t ) { if( t == null ) return t; // Item not found; do nothing int compareResult = x.compareTo( t.element ); if( compareResult < 0 ) t.left = remove( x, t.left ); else if( compareResult > 0 ) t.right = remove( x, t.right ); else if( t.left != null && t.right != null ) // Two children { t.element = findMin( t.right ).element; t.right = remove( t.element, t.right ); } else t = ( t.left != null ) ? t.left : t.right; return t; } private BinaryNode findMin( BinaryNode t ) { if( t == null ) return null; else if( t.left == null ) return t; return findMin( t.left ); } private BinaryNode findMax( BinaryNode t ) { if( t != null ) while( t.right != null ) t = t.right; return t; } private boolean contains( AnyType x, BinaryNode t ) { if( t == null ) return false; int compareResult = x.compareTo( t.element ); if( compareResult < 0 ) return contains( x, t.left ); else if( compareResult > 0 ) return contains( x, t.right ); else return true; // Match } private void printTree( BinaryNode t ) { if( t != null ) { printTree( t.left ); System.out.println( t.element ); printTree( t.right ); } } private int height( BinaryNode t ) { if( t == null ) return -1; else return 1 + Math.max( height( t.left ), height( t.right ) ); } // Basic node stored in unbalanced binary search trees private static class BinaryNode { // Constructors BinaryNode( AnyType theElement ) { this( theElement, null, null ); } BinaryNode( AnyType theElement, BinaryNode lt, BinaryNode rt ) { element = theElement; left = lt; right = rt; } AnyType element; // The data in the node BinaryNode left; // Left child BinaryNode right; // Right child } /** The tree root. */ private BinaryNode root; public static void main( String [ ] args ) { HelloWorld t = new HelloWorld( ); final int NUMS = 4000; final int GAP = 37; System.out.println( \"Checking... (no more output means success)\" ); for( int i = GAP; i != 0; i = ( i + GAP ) % NUMS ) t.insert.

package DataStructures; public class HelloWorld AnyType extends.pdf

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it always attacks oxygen.the image doesnot workSolutionit alwa.pdf

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import java.util.Scanner; public class Fraction { /** * instance variable */ private int numerator; /** * instance variable */ private int denominator; /** * param args */ public static void main(String[] args) { // TODO Auto-generated method stub final Fraction f1 = new Fraction(); final Fraction f2 = new Fraction(10, 15); final Fraction f3 = new Fraction(); Fraction f4 = new Fraction(); Fraction f5; f3.setNumerator(14); f3.setDenominator(16); f1.print(); f2.print(); f3.print(); // f1.get(); // f1.print(); f4.assign(12, 50); f4.print(); f5 = Fraction.multiply(f2, f4); f5.print(); System.out.println(\"\ f2: \"); f2.print(); f2.multiply(f4); System.out.println(\"\ f2: \"); f2.print(); } /** * default constructor * initlizing numerator with 0 and denominator with 1 */ public Fraction() { // System.out.println(\"In default construction\"); numerator = 0; denominator = 1; } /** * param n * param d */ public Fraction(final int n, final int d) { // System.out.println(\"In Parameter construction\"); numerator = n; denominator = d; } /** * return numerator */ public int getNumerator() { return numerator; } /** * param numerator */ public void setNumerator(final int numerator) { this.numerator = numerator; } /** * return denominator */ public int getDenominator() { return denominator; } /** * param denominator */ public void setDenominator(final int denominator) { this.denominator = denominator; } /** * print fraction */ public void print() { System.out.print(numerator + \"/\" + denominator + \" \"); } /** * */ public void get() { final Scanner kb = new Scanner(System.in); System.out.print(\"\ Enter numerator: \"); numerator = kb.nextInt(); System.out.print(\"Enter denominator: \"); denominator = kb.nextInt(); kb.close(); } /** * param n * param d */ public void assign(final int n, final int d) { if (d == 0) { throw new IllegalArgumentException(\"denominator can not be 0\"); } if (n < 0 || d < 0) { throw new IllegalArgumentException(\"values must be positive\"); } numerator = n; denominator = d; reduce(); } /** * it reduce numerator and denominator by GCD of numerator and denominator */ private void reduce() { int min = numerator; int gcd; if (numerator > denominator) { min = denominator; } for (gcd = min; gcd > 1; gcd--) { if (numerator % gcd == 0 && denominator % gcd == 0) { break; } } numerator = numerator / gcd; denominator = denominator / gcd; } /** * param f1 * param f2 * return f */ public static Fraction multiply(Fraction f1, Fraction f2) { Fraction f = new Fraction(); int num; int den; num = f1.getNumerator() * f2.getNumerator(); den = f1.getNumerator() * f2.getDenominator(); f.assign(num, den); f.reduce(); return f; } /** * param f */ public void multiply(Fraction f) { this.numerator = this.numerator * f.getNumerator(); this.denominator = this.denominator * f.getDenominator(); this.reduce(); return; } } Solution import java.util.Scanner; public class Fraction { /** * instance variable */ private int numerator; /** * instance variable */ priv.

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Hi, Please find the Ansswer below. //PLAYLIST.h #include #include #include #include using namespace std; class Playlist { private: string uniqueID; string songName; string artistName; int songLength; public: Playlist() { uniqueID = \"\", songName = \"\", artistName = \"\", songLength = 0; }; Playlist(string auniqueId, string asongName, string aArtistName, int aSongLength); void InsertAfter(); void SetNext(); string GetID(); string GetSongName(); string GetArtistName(); int GetSongLength(); string GetNext(); void PrintPlaylistNode(); }; //PLAYLIST.CPP #include \"Playlist.h\" Playlist::Playlist(string auniqueId, string asongName, string aArtistName, int aSongLength) { uniqueID = auniqueId; songName = asongName; artistName = aArtistName; songLength = aSongLength; } string Playlist::GetArtistName() { return artistName; } string Playlist::GetID() { return uniqueID; } string Playlist::GetSongName() { return songName; } int Playlist::GetSongLength() { return songLength; } void Playlist::SetNext() { } string Playlist::GetNext() { return \"\"; } void Playlist::InsertAfter() { } void Playlist::PrintPlaylistNode() { cout << \"Unique ID:\" << uniqueID << endl ; cout << \"Song Name:\" << songName << endl; cout << \"Artist Name:\" << artistName << endl; cout << \"Song Length (in seconds):\" << songLength << endl; } //PLAYSLITSNODE.h #pragma once #include \"Playlist.h\" #include class PlaylistNode { private: std::list library; Playlist get(list _list, int _i); void PrintPlaylist(Playlist aPlayList); public: void Addsong(Playlist aPlayslist); void Removesong(string aUnwiid); void Changeposition(int oldPostion, int anewPostion); void PrintSongByartist(string aAstist); void PrintSongtotalLen(); void PrintFullPlayList(); }; //PLAYLIST.CPP #include \"PlaylistNode.h\" void PlaylistNode::Addsong(Playlist aPlaylist) { library.push_back(aPlaylist); } void PlaylistNode::Removesong(string aUnwiid) { if (library.size > 0) { for (it = library.begin(); it != library.end(); ++it) { if (it->GetID() == aUnwiid) { cout << it->GetSongName() << endl; library.remove(*it); break; } } } } Playlist PlaylistNode::get(list _list, int _i) { list::iterator it = _list.begin(); for (int i = 0; i<_i; i++) { ++it; } return *it; } std::list::iterator it; void PlaylistNode::PrintFullPlayList() { for (it = library.begin(); it != library.end(); ++it) { PrintPlaylist(*it); } } void PlaylistNode::PrintSongByartist(string aartiename) { for (it = library.begin(); it != library.end(); ++it) { if(it->GetArtistName() == aartiename) PrintPlaylist(*it); } } void PlaylistNode::PrintSongtotalLen() { int TotalSonglengst = 0; for (it = library.begin(); it != library.end(); ++it) { TotalSonglengst += it->GetSongLength(); } cout << \"Total songs Length (in seconds):\" << TotalSonglengst << endl; } void PlaylistNode::PrintPlaylist(Playlist aPlayList) { cout << \"Unique ID:\" << aPlayList.GetID() << endl; cout << \"Song Name:\" << aPlayList.GetSongName() << endl; cout << \"Artist Name:\" << aPlayList.GetArtis.

Hi,Please find the Ansswer below.PLAYLIST.h#include iostrea.pdf

Hi,Please find the Ansswer below.PLAYLIST.h#include iostrea.pdf

Hi,Please find the Ansswer below.PLAYLIST.h#include iostrea.pdf

Family as a Social Institution: A family can be defined as group of two or more people living in a household and connected to each other by blood or adoption or marriage. Family as social constitution serves to create and maintain the family life in correct ways which are considered good by a society. It is not an objective institution as it serves to give shape to feeling and emotions of family memberns in fundamental ways. Predominance of nuclear families: Smaller sized nuclear families indulge individualism in its members. These small families are supported by increasingly reducing sized homes and are easier to relocate. Further, small sized nuclear families can support the expensive education, medication and other services to their children in a much better way as compared to the large sized joint families. Existence and characteristics of family structures: Some of the common family structures with their characteristic features are as follows: 1: Nuclear family: The family with two generations i.e. parents and their children 2: Extended family: The family with three generations i.e. grandparents, parents and their children constitutes an extended family. 3: Single parent family: The family in which one parent and children are residing in same household is called as single parent family. 4: Reconstituted family: The family in which either or both of the parents have children from their previous marriage living together are called as reconstituted family. Characters of a family: A family is established by mating relation between man and woman through marriage institution. Marriage is foundation of family irrespetive of mating relationship without marriage. A family always resides in a common household wherein each family member has his own name. Hence, marriage, common household, nomenclature of family members, mode of interaction and communication and an economic provision are some of the characteristics of a family. Solution Family as a Social Institution: A family can be defined as group of two or more people living in a household and connected to each other by blood or adoption or marriage. Family as social constitution serves to create and maintain the family life in correct ways which are considered good by a society. It is not an objective institution as it serves to give shape to feeling and emotions of family memberns in fundamental ways. Predominance of nuclear families: Smaller sized nuclear families indulge individualism in its members. These small families are supported by increasingly reducing sized homes and are easier to relocate. Further, small sized nuclear families can support the expensive education, medication and other services to their children in a much better way as compared to the large sized joint families. Existence and characteristics of family structures: Some of the common family structures with their characteristic features are as follows: 1: Nuclear family: The family with two generations i.e. parents and t.

Family as a Social Institution A family can be defined as group of .pdf

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Dependent Variable. A variable that depends on one or more other variables The dependent variable responds to the independent variable. It is called dependent because it \"depends\" on the independent variable. So Answer Is D Solution Dependent Variable. A variable that depends on one or more other variables The dependent variable responds to the independent variable. It is called dependent because it \"depends\" on the independent variable. So Answer Is D.

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C is correct. While all Layer 2 devices split collision domains, switches create a separate collision domain for each port. A, B, and D are incorrect. A is incorrect because hubs are Layer 1 devices and extend collision domains. B is incorrect because a bridge is a Layer 2 device, but can split the network only into two collision domains. D is incorrect. Solution C is correct. While all Layer 2 devices split collision domains, switches create a separate collision domain for each port. A, B, and D are incorrect. A is incorrect because hubs are Layer 1 devices and extend collision domains. B is incorrect because a bridge is a Layer 2 device, but can split the network only into two collision domains. D is incorrect..

C is correct. While all Layer 2 devices split collision domains, swi.pdf

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Answer: The mobile elements are the elerments move form one place to other place, where the particular element is deficient. The deficiency of mobile elements first appear in older leave whereas the deficency of the immobile elements first appear in the younger leaves The immobile elements are iron, calcium, manganese, zinc, copper and boron Solution Answer: The mobile elements are the elerments move form one place to other place, where the particular element is deficient. The deficiency of mobile elements first appear in older leave whereas the deficency of the immobile elements first appear in the younger leaves The immobile elements are iron, calcium, manganese, zinc, copper and boron.

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