NaCN is a salt and it completely gets ionized, .pdf

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NaCN is a salt and it completely gets ionized, NaCN -------------> Na+ +CN- 0.05L * 0.10 M moles =0.005 0.005 0.005 HCl --------------> H+ + Cl- moles 0.020 L * 0.2 M =0.004 0.004 0.004 Chemical reaction: CN- (aq) + H+ (aq) ------------------> HCN Before rxn (moles) 0.005 0.004 0 After rxn (moles) 0.001 0 0.004 [CN-] = 0.001 moles / 0.07 L = 0.01428 M [H+] = 0 M (acid is completelyconsumed) [HCN] = 0.004 moles / 0.07 L = 0.057 M [Cl-] = 0.004 moles / 0.07L = 0.0571 M Solution NaCN is a salt and it completely gets ionized, NaCN -------------> Na+ +CN- 0.05L * 0.10 M moles =0.005 0.005 0.005 HCl --------------> H+ + Cl- moles 0.020 L * 0.2 M =0.004 0.004 0.004 Chemical reaction: CN- (aq) + H+ (aq) ------------------> HCN Before rxn (moles) 0.005 0.004 0 After rxn (moles) 0.001 0 0.004 [CN-] = 0.001 moles / 0.07 L = 0.01428 M [H+] = 0 M (acid is completelyconsumed) [HCN] = 0.004 moles / 0.07 L = 0.057 M [Cl-] = 0.004 moles / 0.07L = 0.0571 M.

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What is an OS? • Interface between application programs and hardware • Ultimate control program – Exploits hardware resources of one or more processors to provide a set of services to users – Coordinates the use of hardware among various application programs for different users – Manages secondary memory and I/O devices on behalf of its users • Two different views of an OS 1. Extended machine view – Virtual machine that is easier to understand and program – Tool to make programmer’s job easy 2. Resource manager view – Tool to facilitate efficient operation of computer system – Provides services to users; processor, memory, I/O, system bus – Must be fair; not partial to any process, specially for process in the same class – Must discriminate between different class of jobs with different service requirements – Do the above efficiently Within the constraints of fairness and efficiency, an OS should attempt to maximize throughput, minimize response time, and accommodate as many users as possible Basic elements • A computer has a number of modules, with possibly more than one instance of each • Processor/CPU – Controls the operations of computer and performs data processing functions – Exchanges data with memory using memory address register and memory buffer register – Exchanges data with I/O devices using I/O address register and I/O buffer register • Main memory/Primary memory – Stores data and programs – Typically volatile – Abstracted as a set of locations, defined by sequentially numbered addresses – Each location contains a bit pattern to be interpreted as either an instruction or data • I/O modules/architecture – Move data between a computer and external environment – Communicate with a variety of devices including secondary memory (disks), communications equipment, and terminals – Data flows between CPUs, RAM and I/O devices over buses – System bus Provides for communications among processors, main memory, and I/O modules Connects most of the internal hardware devices PCI bus, ISA bus, EISA bus, SCSI, USB Solution What is an OS? • Interface between application programs and hardware • Ultimate control program – Exploits hardware resources of one or more processors to provide a set of services to users – Coordinates the use of hardware among various application programs for different users – Manages secondary memory and I/O devices on behalf of its users • Two different views of an OS 1. Extended machine view – Virtual machine that is easier to understand and program – Tool to make programmer’s job easy 2. Resource manager view – Tool to facilitate efficient operation of computer system – Provides services to users; processor, memory, I/O, system bus – Must be fair; not partial to any process, specially for process in the same class – Must discriminate between different class of jobs with different service requirements – Do the above efficiently Within the constraints of fairness and efficiency, an OS should attempt to maximize throughput,.

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Using a broad definition of \"file\" (note that it doesn\'t count hidden files and assumes that file names don\'t contain newline characters). To include hidden files (except . and ..) and avoid problems with newline characters, the canonical way is: Or recursively: Solution Using a broad definition of \"file\" (note that it doesn\'t count hidden files and assumes that file names don\'t contain newline characters). To include hidden files (except . and ..) and avoid problems with newline characters, the canonical way is: Or recursively:.

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The multiplication sign simply means that the molecules have their independent existance in the compound. For example the formula you have given has three species in solution ZnCO3, 2 molecules of Zn(OH)2 and 1 molecule of water H20 for each molecule of your compound. These species are bonded to each other but the bonds between the atoms of the participating molecules are not broken. To get the molar mass of the compound simply add the molar masses of indivisual molecules multiplied by number of molecules they are contributing. Thus for ZnCO3*2Zn(OH)2*1H20 the molar mass would be: Molar mass of ZnCO3 + 2*(Molar mass of Zn(OH)2) + Molar mass of H2O = 125.4 + 2*99.4 + 18 = 342.2 g/mol Solution The multiplication sign simply means that the molecules have their independent existance in the compound. For example the formula you have given has three species in solution ZnCO3, 2 molecules of Zn(OH)2 and 1 molecule of water H20 for each molecule of your compound. These species are bonded to each other but the bonds between the atoms of the participating molecules are not broken. To get the molar mass of the compound simply add the molar masses of indivisual molecules multiplied by number of molecules they are contributing. Thus for ZnCO3*2Zn(OH)2*1H20 the molar mass would be: Molar mass of ZnCO3 + 2*(Molar mass of Zn(OH)2) + Molar mass of H2O = 125.4 + 2*99.4 + 18 = 342.2 g/mol.

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Yes. The compound is actively active. It is mainly caused by the carbon to the right of the 2 oxygens. I think i forgot about the stereoisomers when I last answered them. The number of stereoisomers is dependent on the number of chiral centers. Since there are 3 chiral centers, it is 2^3, which is 8 possible stereoisomers. So I mentioned before that the chiral centers are the carbons directly to the right and left of the oxygens. All the bonds in the ring structure are in the plane. The other 2 bonds can be alternated to be pointing inside the page or out of the page. That is why if you have 3 carbon centers, it is just a matter of probability of 2^3 (2 possible choices over 3 possible carbons) which give you 8. And as I previously explained: To be optically active, you need to have chiral center, which is any carbon with 4 different subgroups. There is 3 such centers. The carbons to the left of both oxygens (this makes up 2 carbons) are chirally active since they have 4 different groups. However, since they are mirror images of each other, they cancel each other out. It is the third and final carbon to the right of both oxygens, that makes this compound chirally active. Since it has also 4 different groups attached to the carbon and is not canceled out by anything. One simple way to test if something is optically active is to see if it is a mirror image of itself. If it is not a mirror image and it has at least 1 chiral center, then it is optically active Solution Yes. The compound is actively active. It is mainly caused by the carbon to the right of the 2 oxygens. I think i forgot about the stereoisomers when I last answered them. The number of stereoisomers is dependent on the number of chiral centers. Since there are 3 chiral centers, it is 2^3, which is 8 possible stereoisomers. So I mentioned before that the chiral centers are the carbons directly to the right and left of the oxygens. All the bonds in the ring structure are in the plane. The other 2 bonds can be alternated to be pointing inside the page or out of the page. That is why if you have 3 carbon centers, it is just a matter of probability of 2^3 (2 possible choices over 3 possible carbons) which give you 8. And as I previously explained: To be optically active, you need to have chiral center, which is any carbon with 4 different subgroups. There is 3 such centers. The carbons to the left of both oxygens (this makes up 2 carbons) are chirally active since they have 4 different groups. However, since they are mirror images of each other, they cancel each other out. It is the third and final carbon to the right of both oxygens, that makes this compound chirally active. Since it has also 4 different groups attached to the carbon and is not canceled out by anything. One simple way to test if something is optically active is to see if it is a mirror image of itself. If it is not a mirror image and it has at least 1 chiral center, then it is optically active.

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1) Investment Grade Domestic Bonds As bond bears a fixed rate of interest hence Mutual Fund or ETFS can\'t Represent Bonds as an asset class. 2) High Yield Bonds 3) Domestic stock Both are consist of shares and debentures so Mutual Fund or ETFS can\'t Represent them as an asset class. 4) International Stock 6) Energy Similarly ETF and Mutual fund never meet the defination of these 3 asset class so can\'t represent them 7) Commodities 8) Real Estate 5)E merging Market Stock An emerging market fund is a mutual fund or ETF that invests the bulk of its assets in stocks of developing countries. E merging countries are those which are not developed yet in the stage of development i.e. china, india etc. so invetment in these fund brings highest reurn for prospective investor. So ETF and Mutual fund Represents E merging market stock. Solution 1) Investment Grade Domestic Bonds As bond bears a fixed rate of interest hence Mutual Fund or ETFS can\'t Represent Bonds as an asset class. 2) High Yield Bonds 3) Domestic stock Both are consist of shares and debentures so Mutual Fund or ETFS can\'t Represent them as an asset class. 4) International Stock 6) Energy Similarly ETF and Mutual fund never meet the defination of these 3 asset class so can\'t represent them 7) Commodities 8) Real Estate 5)E merging Market Stock An emerging market fund is a mutual fund or ETF that invests the bulk of its assets in stocks of developing countries. E merging countries are those which are not developed yet in the stage of development i.e. china, india etc. so invetment in these fund brings highest reurn for prospective investor. So ETF and Mutual fund Represents E merging market stock..

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This is quite simple to do. Barium sulfate is insoluble in water and sodium chloride is soluble in water. So this is what you do. Dump them both in water. As I said the NaCl will dissolve. Then do vacuum or suction filtration. That will filter out the barium sulfate from the solution. Now the two are separate. To get the NaCl out of the water just boil it off. Solution This is quite simple to do. Barium sulfate is insoluble in water and sodium chloride is soluble in water. So this is what you do. Dump them both in water. As I said the NaCl will dissolve. Then do vacuum or suction filtration. That will filter out the barium sulfate from the solution. Now the two are separate. To get the NaCl out of the water just boil it off..

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