NaCN is a salt and it completely gets ionized, NaCN -------------> Na+ +CN- 0.05L * 0.10 M moles =0.005 0.005 0.005 HCl --------------> H+ + Cl- moles 0.020 L * 0.2 M =0.004 0.004 0.004 Chemical reaction: CN- (aq) + H+ (aq) ------------------> HCN Before rxn (moles) 0.005 0.004 0 After rxn (moles) 0.001 0 0.004 [CN-] = 0.001 moles / 0.07 L = 0.01428 M [H+] = 0 M (acid is completelyconsumed) [HCN] = 0.004 moles / 0.07 L = 0.057 M [Cl-] = 0.004 moles / 0.07L = 0.0571 M Solution NaCN is a salt and it completely gets ionized, NaCN -------------> Na+ +CN- 0.05L * 0.10 M moles =0.005 0.005 0.005 HCl --------------> H+ + Cl- moles 0.020 L * 0.2 M =0.004 0.004 0.004 Chemical reaction: CN- (aq) + H+ (aq) ------------------> HCN Before rxn (moles) 0.005 0.004 0 After rxn (moles) 0.001 0 0.004 [CN-] = 0.001 moles / 0.07 L = 0.01428 M [H+] = 0 M (acid is completelyconsumed) [HCN] = 0.004 moles / 0.07 L = 0.057 M [Cl-] = 0.004 moles / 0.07L = 0.0571 M.