Type your question hereSuppose that in a particular game two dice are tossed, and various amounts are paid according to the outcome. Find the requested probability Solution there are 36 possible outcomes on the roll of a pair of fair dice. These outcomes are: 1,1 1,2 1,3 1,4 1,5 1,6 2,1 2,2 2,3 2,4 2,5 2,6 3,1 3,2 3,3 3,4 3,5 3,6 4,1 4,2 4,3 4,4 4,5 4,6 5,1 5,2 5,3 5,4 5,5 5,6 6,1 6,2 6,3 6,4 6,5 6,6 Out of the 36 possible outcomes, how many of the dice rolls total 6 or 9. Count them up. You should find there are 9 of these \"winners\" beginning with 1,5 and ending with 6,3. So the probability of winning on the first roll by rolling a 6 or a 9 is the number of winners (9 of them) divided by the total number of possible outcomes (36). 9 divided by 36 reduces to 1 divided by 4 which has a decimal equivalent of 0.25 (or 25%). You have a one in four chance of winning on the first roll. This suggests that in the long run on every 4 rolls you are likely to be a winner for one of those rolls..

1. Type your question hereSuppose that in a particular game two dice are tossed, and various
amounts are paid according to the outcome. Find the requested probability
Solution
there are 36 possible outcomes on the roll of a pair of fair dice. These outcomes are:
1,1
1,2
1,3
1,4
1,5
1,6
2,1
2,2
2,3
2,4
2,5
2,6
3,1
3,2
3,3
3,4
3,5
3,6
4,1
4,2
4,3
4,4
4,5
4,6
5,1
5,2
5,3

2. 5,4
5,5
5,6
6,1
6,2
6,3
6,4
6,5
6,6
Out of the 36 possible outcomes, how many of the dice rolls total 6 or 9. Count them up. You
should find there are 9 of these "winners" beginning with 1,5 and ending with 6,3. So the
probability of winning on the first roll by rolling a 6 or a 9 is the number of winners (9 of them)
divided by the total number of possible outcomes (36). 9 divided by 36 reduces to 1 divided by 4
which has a decimal equivalent of 0.25 (or 25%). You have a one in four chance of winning on
the first roll. This suggests that in the long run on every 4 rolls you are likely to be a winner for
one of those rolls.