A saturated sample has a mass 0.69 kilograms when wet and 0.5 kg when dry. Assuming that the specific gravity is 2.7, compute the void ratio, porosity and dry density of this material. Solution water content (w) = (wet weight -dry weigt)/dry weight =(0.69-0.5)/0.5 =0.38 void ratio(e) = (wG)/s =0.38*2.7/1 =1.026 porosity=(e/(1+e)) =1.026/(1+1.026) =0.51 dry density=G*unit weight of water(1+e) =2.7*62.43/(1+1.026) =83.2 lb/ft3.