Liquid decane because it is heavier and has great.pdf

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Liquid decane because it is heavier and has greater boiling point. Solution Liquid decane because it is heavier and has greater boiling point..

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The number of protons in the nucleus of an elemen.pdf

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Resonance structures are simply alternate Lewis structures for a given ion or molecule. Thus we can draw all resonance structures by drawing all of the possible Lewis structures. However, it is not always easy to see what all these Lewis structures might be. A set of Lewis structures for a give ion or molecule must have the same number of electrons as the Lewis structures are constructed from the same atoms. The only difference between the Lewis structures is the placement of the electrons. The position of the atoms in space is held constant. We can use this facts to assist us in drawing resonance structures. Because the number of electrons is conserved, electrons taken away from one atom must appear somewhere else in the structure. When drawing resonance structures, it is most convenient to shift these electrons between adjacent atoms. Solution Resonance structures are simply alternate Lewis structures for a given ion or molecule. Thus we can draw all resonance structures by drawing all of the possible Lewis structures. However, it is not always easy to see what all these Lewis structures might be. A set of Lewis structures for a give ion or molecule must have the same number of electrons as the Lewis structures are constructed from the same atoms. The only difference between the Lewis structures is the placement of the electrons. The position of the atoms in space is held constant. We can use this facts to assist us in drawing resonance structures. Because the number of electrons is conserved, electrons taken away from one atom must appear somewhere else in the structure. When drawing resonance structures, it is most convenient to shift these electrons between adjacent atoms..

Resonance structures are simply alternate Lewis s.pdf

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only above a certain temperature .pdf

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molecular solids SO2, I2, P4, S8, H2O (ice) cov.pdf

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MnO4- because it is stronger oxidizing agent. .pdf

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D ALL of them .pdf

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//program files //admin.aspx.cs using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; namespace RegistrationUsers { public partial class Admin : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { } protected void Button1_Click(object sender, EventArgs e) { Response.Redirect(\"WebForm1.aspx\"); } protected void Button2_Click(object sender, EventArgs e) { Response.Redirect(\"view users.aspx\"); } } } //view users.aspx.cs using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; namespace RegistrationUsers { public partial class view_users : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { } } } //webform1.aspx.cs using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data.SqlClient; using System.Configuration; namespace RegistrationUsers { public partial class WebForm1 : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { /* if (IsPostBack) { String cs = ConfigurationManager.ConnectionStrings[\"Data Source = ADMINIB - 83V87D2; Initial Catalog = employee; Integrated Security = True; Connect Timeout = 15; Encrypt = False; TrustServerCertificate = True; ApplicationIntent = ReadWrite; MultiSubnetFailover = False\"].ConnectionString; SqlConnection connection = new SqlConnection(cs); connection.Open(); string checkuser = \"select count(*) from Users where Username=\" + TextBox1.Text + \"\'\"; SqlCommand com = new SqlCommand(checkuser, connection); int temp = Convert.ToInt32(com.ExecuteScalar().ToString()); if (temp == 1) { Console.WriteLine(\"user already exists\"); } connection.Close(); }*/ } protected void Button2_Click1(object sender, EventArgs e) { try { string cs = ConfigurationManager.ConnectionStrings[\"employeeConnectionString\"].ConnectionString; SqlConnection conn = new SqlConnection(cs); conn.Open(); string insertquery = \"insert into Users(Username,Password,Email,Cell,Location)values(@username,@password,@email,@cell, @location)\"; SqlCommand comm = new SqlCommand(insertquery, conn); comm.Parameters.AddWithValue(\"@username\", TextBox1.Text); comm.Parameters.AddWithValue(\"@password\", TextBox2.Text); comm.Parameters.AddWithValue(\"@email\", TextBox3.Text); comm.Parameters.AddWithValue(\"@cell\", TextBox4.Text); comm.Parameters.AddWithValue(\"@Location\", DropDownList1.SelectedValue); comm.ExecuteNonQuery(); Response.Write(\"Registration Sucessful\"); conn.Close(); } catch (Exception ex) { Console.WriteLine(\"error:\" + ex.ToString()); } } protected void Button1_Click(object sender, EventArgs e) { Response.Redirect(\"Login.aspx\"); } } } //login.aspx.cs using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Data.

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C is best methode Bromination of alkane is most favourable due to lessbond disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives alkenes Solution C is best methode Bromination of alkane is most favourable due to lessbond disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives alkenes.

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C. CH3Br note like dissolves like. All the othe.pdf

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Organelle participates in intracellular digestion is\'\'Lysosomes\'\'. These are produced by Golgi appartus. Primary functions are 1.Intracellaular digestion 2.Recycling of cell\'s organic material. Lysosomes contains hydrolytic digestive enzymes. Solution Organelle participates in intracellular digestion is\'\'Lysosomes\'\'. These are produced by Golgi appartus. Primary functions are 1.Intracellaular digestion 2.Recycling of cell\'s organic material. Lysosomes contains hydrolytic digestive enzymes..

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In the stratosphere ozone molecules are absorbing the uvlight. The Oxygen molecules present in the stratosphere will dissociatedto two O atoms by absorbing uv light photon O2 + hv ----> O + O These atomic oxygen then combines with O2to form O3. This ozone molecules absorb UV light between 300 - 200nm Now this ozone splits into O2 and anoxygen atom. O3 + hv ---> O2 + O The formed oxygen atom then reacts with an oxygen molecule toregenerate ozone. O2 + O ---> O3 which is a continous process So the answer is B (O3 ) Solution In the stratosphere ozone molecules are absorbing the uvlight. The Oxygen molecules present in the stratosphere will dissociatedto two O atoms by absorbing uv light photon O2 + hv ----> O + O These atomic oxygen then combines with O2to form O3. This ozone molecules absorb UV light between 300 - 200nm Now this ozone splits into O2 and anoxygen atom. O3 + hv ---> O2 + O The formed oxygen atom then reacts with an oxygen molecule toregenerate ozone. O2 + O ---> O3 which is a continous process So the answer is B (O3 ).

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Information technology (IT) is dramatically changing the business landscape. Although organization cultures and business strategies shape the use of IT in organizations, more often the influence is stronger the other way round. IT significantly affects strategic options and creates opportunities and issues that managers need to address in many aspects of their business. Business strategy - collapsing time and distance, enabling electronic commerce There is also the outline of an executive presentation, that has been used to increase awareness of these issues. Business Strategy IT creates new opportunities for innovation in products and services. Services which used to be delivered in person can now be delivered over networks. Among the key levers are: Organization Culture Newer types of IT such as electronic mail and groupware are creating significant changes in the way that information flows around group ware, and between them and their customers and suppliers. It can hasten the development of more open and innovative cultures. However, as experts like Davenport warns, and surveys from companies like Reuters confirm, the notion that \"information is power\" still reigns large in many orggroup warelso, our experience shows that many new systems fail to become accepted by their users, because the systems developers have not been culturally sensitive to the department or group ware, in which the new systems are to be used. Organization Structures For many years it has been argued that IT will enable larger spans of control and the flattening of group ware. This has at last happened, but due as much to initiatives like BPR (business process reengineering) and the drive to cut costs. Research on whether IT encourages cencentralization decdecentralizations produced ambivalent results. Many companies have cencentralizedckroom operations (for efficiency) while at the same time decdecentralizingher activities. It now seems clear that IT enables a greater variety of structures. In particular it enables more flexible and fluid structures - networked structures, dispersed team and teams that come and go as needs change (as in the virtual corporation). Management Processes IT is rapidly entering the era where it supports unstructured management processes as well as highly routinized business processes (see I3 UPDATE No. 4). It provides more effective ways of accessing information from multiple sources, including use of external information on databases and the Internet. However, group decision support systems that operate in a meeting room environment can help enhance decision making, but it does need someone who is an expert facilitator to help the group master the technique of structured discussion. Work IT is dramatically changing the nature of professional work. There are few offices where professional do not make use of personal computers, and in many jobs involving extensive information and knowledge based work, the use of the computer is often a c.

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In other words, this is asking you how to write a proper delta H reaction for formation. Rules: 1. only one mole on product side... so balance reactant side accordingly to get to this. This may mean putting in fractions that look sort of strange. 2. only elemental forms on product side... no compounds! 3. reactants are in standard states of matter for their respective element (i.e. oxygen should be a gas, not a solid, and iron should be a solid, not a liquid, etc.) So... not A because 2 mol product B is good not C because compounds are on reactant side same for D E is good F is no because F2 is usually a gas, not a liquid under standard conditions. I hope this helps! :) Solution In other words, this is asking you how to write a proper delta H reaction for formation. Rules: 1. only one mole on product side... so balance reactant side accordingly to get to this. This may mean putting in fractions that look sort of strange. 2. only elemental forms on product side... no compounds! 3. reactants are in standard states of matter for their respective element (i.e. oxygen should be a gas, not a solid, and iron should be a solid, not a liquid, etc.) So... not A because 2 mol product B is good not C because compounds are on reactant side same for D E is good F is no because F2 is usually a gas, not a liquid under standard conditions. I hope this helps! :).

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