in saturation ca2+ conc = OH- conc as 2 OH- will be there for 1 Ca2+ so its conc
= 2*4.9*10^-6 = 9.8*10^-6
Solution
in saturation ca2+ conc = OH- conc as 2 OH- will be there for 1 Ca2+ so its conc
= 2*4.9*10^-6 = 9.8*10^-6.
in saturation ca2+ conc = OH- conc as 2 OH- will.pdf
1. in saturation ca2+ conc = OH- conc as 2 OH- will be there for 1 Ca2+ so its conc
= 2*4.9*10^-6 = 9.8*10^-6
Solution
in saturation ca2+ conc = OH- conc as 2 OH- will be there for 1 Ca2+ so its conc
= 2*4.9*10^-6 = 9.8*10^-6