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in saturation ca2+ conc = OH- conc as 2 OH- will be there for 1 Ca2+ so its conc
= 2*4.9*10^-6 = 9.8*10^-6
Solution
in saturation ca2+ conc = OH- conc as 2 OH- will be there for 1 Ca2+ so its conc
= 2*4.9*10^-6 = 9.8*10^-6

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in saturation ca2+ conc = OH- conc as 2 OH- will.pdf

  • 1. in saturation ca2+ conc = OH- conc as 2 OH- will be there for 1 Ca2+ so its conc = 2*4.9*10^-6 = 9.8*10^-6 Solution in saturation ca2+ conc = OH- conc as 2 OH- will be there for 1 Ca2+ so its conc = 2*4.9*10^-6 = 9.8*10^-6