C is best methode Bromination of alkane is most f.pdf

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C is best methode Bromination of alkane is most favourable due to lessbond disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives alkenes Solution C is best methode Bromination of alkane is most favourable due to lessbond disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives alkenes.

C is best methode Bromination of alkane is most favourable due to lessbond
disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has
less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives
alkenes
Solution
C is best methode Bromination of alkane is most favourable due to lessbond
disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has
less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives
alkenes

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Resonance structures are simply alternate Lewis structures for a given ion or molecule. Thus we can draw all resonance structures by drawing all of the possible Lewis structures. However, it is not always easy to see what all these Lewis structures might be. A set of Lewis structures for a give ion or molecule must have the same number of electrons as the Lewis structures are constructed from the same atoms. The only difference between the Lewis structures is the placement of the electrons. The position of the atoms in space is held constant. We can use this facts to assist us in drawing resonance structures. Because the number of electrons is conserved, electrons taken away from one atom must appear somewhere else in the structure. When drawing resonance structures, it is most convenient to shift these electrons between adjacent atoms. Solution Resonance structures are simply alternate Lewis structures for a given ion or molecule. Thus we can draw all resonance structures by drawing all of the possible Lewis structures. However, it is not always easy to see what all these Lewis structures might be. A set of Lewis structures for a give ion or molecule must have the same number of electrons as the Lewis structures are constructed from the same atoms. The only difference between the Lewis structures is the placement of the electrons. The position of the atoms in space is held constant. We can use this facts to assist us in drawing resonance structures. Because the number of electrons is conserved, electrons taken away from one atom must appear somewhere else in the structure. When drawing resonance structures, it is most convenient to shift these electrons between adjacent atoms..

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In the stratosphere ozone molecules are absorbing the uvlight. The Oxygen molecules present in the stratosphere will dissociatedto two O atoms by absorbing uv light photon O2 + hv ----> O + O These atomic oxygen then combines with O2to form O3. This ozone molecules absorb UV light between 300 - 200nm Now this ozone splits into O2 and anoxygen atom. O3 + hv ---> O2 + O The formed oxygen atom then reacts with an oxygen molecule toregenerate ozone. O2 + O ---> O3 which is a continous process So the answer is B (O3 ) Solution In the stratosphere ozone molecules are absorbing the uvlight. The Oxygen molecules present in the stratosphere will dissociatedto two O atoms by absorbing uv light photon O2 + hv ----> O + O These atomic oxygen then combines with O2to form O3. This ozone molecules absorb UV light between 300 - 200nm Now this ozone splits into O2 and anoxygen atom. O3 + hv ---> O2 + O The formed oxygen atom then reacts with an oxygen molecule toregenerate ozone. O2 + O ---> O3 which is a continous process So the answer is B (O3 ).

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C is best methode Bromination of alkane is most f.pdf

1. C is best methode Bromination of alkane is most favourable due to lessbond disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives alkenes Solution C is best methode Bromination of alkane is most favourable due to lessbond disassoction energy between C and Br moleculesafter substution of halogens ( Acctuvally I2 has less butit is revesable reaction) Order of I2 ? 2I* Alkylhalide on treated with NaOCH3 gives alkenes